(2x^4 + 9x^3 + 5x^2 - 4x + 3) / (x + 3/2)?
Q. (2x^4 + 9x^3 + 5x^2 - 4x + 3) / (x + 3/2) Write the division algorithm
Asked by beeboroachgoingon197 - Tue Oct 30 01:55:03 2007 - - 3 Answers - 0 Comments
A. This one's gonna have to be long division (a little hard to write here, but I'll do my best to make it understandable). Set it up like any other long division question, with (x + 3/2) as your divisor and (2x^4 + 9x^3 + 5x^2 - 4x + 3) as your dividend: First, the first 2 terms (first term of the quotient is 2x^3): (2x^4 + 9x^3) - 2x^3(x + 3/2) = 6x^3 Bring down the next term (second term of the quotient is 6x^2) : (6x^3 + 5x^2) - 6x^2(x + 3/2) = -4x^2 Bring down the 3rd term (third term of the quotient is -4x): (-4x^2 - 4x) - (-4x)(x + 3/2) = 2x Bring down the final term (final term of the quotient is 2): (2x + 3) - 2(x + 3/2) = 0 Remainder is 0, thus (x + 3/2) is a factor. Thus: (2x^4 + 9x^3 + 5x^2 - 4x + 3) / (x + 3/2) = 2x^3 + 6x^2 - [cont.]
Answered by QEChem - Tue Oct 30 02:12:28 2007
Q. (2x^4 + 9x^3 + 5x^2 - 4x + 3) / (x + 3/2) Write the division algorithm
Asked by beeboroachgoingon197 - Tue Oct 30 01:55:03 2007 - - 3 Answers - 0 Comments
A. This one's gonna have to be long division (a little hard to write here, but I'll do my best to make it understandable). Set it up like any other long division question, with (x + 3/2) as your divisor and (2x^4 + 9x^3 + 5x^2 - 4x + 3) as your dividend: First, the first 2 terms (first term of the quotient is 2x^3): (2x^4 + 9x^3) - 2x^3(x + 3/2) = 6x^3 Bring down the next term (second term of the quotient is 6x^2) : (6x^3 + 5x^2) - 6x^2(x + 3/2) = -4x^2 Bring down the 3rd term (third term of the quotient is -4x): (-4x^2 - 4x) - (-4x)(x + 3/2) = 2x Bring down the final term (final term of the quotient is 2): (2x + 3) - 2(x + 3/2) = 0 Remainder is 0, thus (x + 3/2) is a factor. Thus: (2x^4 + 9x^3 + 5x^2 - 4x + 3) / (x + 3/2) = 2x^3 + 6x^2 - [cont.]
Answered by QEChem - Tue Oct 30 02:12:28 2007
(3 -x^3 - 5x^2) + (x + 2x^3 - 3)?
Q. (3 -x^3 - 5x^2) + (x + 2x^3 - 3)?
Asked by Pinky X - Thu Nov 27 18:47:04 2008 - - 1 Answers - 0 Comments
A. (3 -x - 5x ) + (x + 2x - 3) = 3 -x - 5x + x + 2x - 3 = x - 5x + x
Answered by Jerome J - Thu Nov 27 18:54:05 2008
Q. (3 -x^3 - 5x^2) + (x + 2x^3 - 3)?
Asked by Pinky X - Thu Nov 27 18:47:04 2008 - - 1 Answers - 0 Comments
A. (3 -x - 5x ) + (x + 2x - 3) = 3 -x - 5x + x + 2x - 3 = x - 5x + x
Answered by Jerome J - Thu Nov 27 18:54:05 2008
Find the product (5x - 3) (x^3 - 5x + 2) .?
Q. Algebra
Asked by Msbg - Fri Jan 11 15:57:24 2008 - - 7 Answers - 0 Comments
A. You want multiply it out. Multiply the 5x by each of the factors in the second set of parentheses: 5x^4-25x^2+10x When multiplying variables that have powers, just add the powers, if the letter is the same. Now, multiply -3 by each of the factors: -3x^3+15x-6 Multiplying or dividing two negatives will yield a positive. So, you need to add those two sets together like so: 5x^4-25x^2+10x+-3x^3+15x- 6 Add them to get: 5x^4-3x^3-25x^2+25x-6 The only one that had similar variables is the x, so you add the 15 and 10 to get 25.
Answered by Zena - Fri Jan 11 16:03:52 2008
Q. Algebra
Asked by Msbg - Fri Jan 11 15:57:24 2008 - - 7 Answers - 0 Comments
A. You want multiply it out. Multiply the 5x by each of the factors in the second set of parentheses: 5x^4-25x^2+10x When multiplying variables that have powers, just add the powers, if the letter is the same. Now, multiply -3 by each of the factors: -3x^3+15x-6 Multiplying or dividing two negatives will yield a positive. So, you need to add those two sets together like so: 5x^4-25x^2+10x+-3x^3+15x- 6 Add them to get: 5x^4-3x^3-25x^2+25x-6 The only one that had similar variables is the x, so you add the 15 and 10 to get 25.
Answered by Zena - Fri Jan 11 16:03:52 2008
Use the Remainder Theorem to find the remainder of (x^3 - 5x^2 + 7x +3) (x-2). State whether the binomial is
Q. a factor of the polynomial...I think the remainder is 5
Asked by aisha1230 - Tue Feb 19 13:45:11 2008 - - 3 Answers - 0 Comments
A. P(x)=x^3 - 5x^2 + 7x +3 P(2)=8-5 4+7 2+3= 8 -20+14+3= 5 --> Rest divition is 5 --> (x-2) isn't a factor of the polynomial. --- Saludos.
Answered by lou h - Tue Feb 19 13:52:17 2008
Q. a factor of the polynomial...I think the remainder is 5
Asked by aisha1230 - Tue Feb 19 13:45:11 2008 - - 3 Answers - 0 Comments
A. P(x)=x^3 - 5x^2 + 7x +3 P(2)=8-5 4+7 2+3= 8 -20+14+3= 5 --> Rest divition is 5 --> (x-2) isn't a factor of the polynomial. --- Saludos.
Answered by lou h - Tue Feb 19 13:52:17 2008
find y" of the following equation 4x^3 + 5x^2 - 8x + 4 + (3/x)?
Q. The fraction is what is throwing me off y'=12x^2+10x-8+(3/x) y"=24x+10 + (3/x) I dont know how to simplify the fraction
Asked by Angela - Thu Oct 8 09:37:58 2009 - - 4 Answers - 0 Comments
A. the derivative of 3/x is 3/x =3x^-1 =-3x^-2 =-3/x^2 now its 2nd derivative =-3x^-2 =6x^-3 =6/x^3 so the second derivative of 4x^3 + 5x^2 - 8x + 4 + (3/x) will be y''=24x+10+6/x^3 answer//
Answered by Engr. Ronald - Thu Oct 8 09:58:28 2009
Q. The fraction is what is throwing me off y'=12x^2+10x-8+(3/x) y"=24x+10 + (3/x) I dont know how to simplify the fraction
Asked by Angela - Thu Oct 8 09:37:58 2009 - - 4 Answers - 0 Comments
A. the derivative of 3/x is 3/x =3x^-1 =-3x^-2 =-3/x^2 now its 2nd derivative =-3x^-2 =6x^-3 =6/x^3 so the second derivative of 4x^3 + 5x^2 - 8x + 4 + (3/x) will be y''=24x+10+6/x^3 answer//
Answered by Engr. Ronald - Thu Oct 8 09:58:28 2009
can anyone factor this? 2x^1/3(x-2)^2/3-5x^4/3(x- 2)^-1/3?
Q. can anyone factor this? 2x^1/3(x-2)^2/3-5x^4/3(x- 2)^-1/3?
Asked by Misterman - Fri May 29 21:22:23 2009 - - 2 Answers - 0 Comments
A. Do your own dang homework.
Answered by Jeff C - Fri May 29 21:29:37 2009
Q. can anyone factor this? 2x^1/3(x-2)^2/3-5x^4/3(x- 2)^-1/3?
Asked by Misterman - Fri May 29 21:22:23 2009 - - 2 Answers - 0 Comments
A. Do your own dang homework.
Answered by Jeff C - Fri May 29 21:29:37 2009
find all 0s of each polynomial function 1. x^3-5x^2+9x-45 2. x^3+2x^2-16 3. x^4-5x^3+5x^2-5x+4?
Q. find all 0s of each polynomial function 1. x^3-5x^2+9x-45 2. x^3+2x^2-16 3. x^4-5x^3+5x^2-5x+4?
Asked by GEREMY D - Mon Feb 4 20:48:28 2008 - - 2 Answers - 0 Comments
A. I suggest you break them down by trying the factors of the whole number at the end of your polynomial. For #2, try plugging in +-1,+-2, +-4 etc. If it equals zero you are in business. Each of these should have a Y= , but that is a minor detail.
Answered by MIKE YANTREE - Mon Feb 4 21:01:09 2008
Q. find all 0s of each polynomial function 1. x^3-5x^2+9x-45 2. x^3+2x^2-16 3. x^4-5x^3+5x^2-5x+4?
Asked by GEREMY D - Mon Feb 4 20:48:28 2008 - - 2 Answers - 0 Comments
A. I suggest you break them down by trying the factors of the whole number at the end of your polynomial. For #2, try plugging in +-1,+-2, +-4 etc. If it equals zero you are in business. Each of these should have a Y= , but that is a minor detail.
Answered by MIKE YANTREE - Mon Feb 4 21:01:09 2008
(x^3+5x^2+5x-3)/(x^2+3x-1 )?
Q. (x^3+5x^2+5x-3)/(x^2+3x-1 )?
Asked by cori g - Tue May 27 13:05:17 2008 - - 2 Answers - 0 Comments
A. To simplify this, we're going to have to factor the cubic in the numerator and the quadratic in the denominator, and hopefully, some of the factors will cancel out. First, let's use the quadratic formula to factor the denominator: a = 1, b = 3, c = -1 x = [-b SQRT(b^2 - 4ac)] / [2a] x = [-3 SQRT(9 + 4)] / 2 x = [-3 SQRT(13)] / 2 x = -3/2 SQRT(13)/2 Therefore, we can factor the denominator as follows: (x + 3/2 + SQRT(13)/2)(x + 3/2 - SQRT(13)/2) The cubic formula is nowhere near as convenient as the quadratic formula, so we won't use it. Instead, we'll simply use polynomial long division, checking each of the two factors we found to see if it divides the numerator. If it does, we know it's a factor of the numerator, too, so it… [cont.]
Answered by spumn - Tue May 27 13:19:06 2008
Q. (x^3+5x^2+5x-3)/(x^2+3x-1 )?
Asked by cori g - Tue May 27 13:05:17 2008 - - 2 Answers - 0 Comments
A. To simplify this, we're going to have to factor the cubic in the numerator and the quadratic in the denominator, and hopefully, some of the factors will cancel out. First, let's use the quadratic formula to factor the denominator: a = 1, b = 3, c = -1 x = [-b SQRT(b^2 - 4ac)] / [2a] x = [-3 SQRT(9 + 4)] / 2 x = [-3 SQRT(13)] / 2 x = -3/2 SQRT(13)/2 Therefore, we can factor the denominator as follows: (x + 3/2 + SQRT(13)/2)(x + 3/2 - SQRT(13)/2) The cubic formula is nowhere near as convenient as the quadratic formula, so we won't use it. Instead, we'll simply use polynomial long division, checking each of the two factors we found to see if it divides the numerator. If it does, we know it's a factor of the numerator, too, so it… [cont.]
Answered by spumn - Tue May 27 13:19:06 2008
3{x^ -5 [x+2(3-5x)] } = !??
Q. how can i solve this ??
Asked by elssa - Thu Dec 7 16:45:07 2006 - - 4 Answers - 0 Comments
A. 3{x^-5[x+6-10x]} =3{x^-5[-9x+6]} =-27x^-4+18x^-5
Answered by raj - Thu Dec 7 16:54:17 2006
Q. how can i solve this ??
Asked by elssa - Thu Dec 7 16:45:07 2006 - - 4 Answers - 0 Comments
A. 3{x^-5[x+6-10x]} =3{x^-5[-9x+6]} =-27x^-4+18x^-5
Answered by raj - Thu Dec 7 16:54:17 2006
put this into standard polynomial form: (4x^3-5x+1)(x^2+2)(3-x)?
Q. the up arrows mean it is like squared or cubed in case you didn't know :)
Asked by Lisa - Mon Jun 8 15:03:25 2009 - - 5 Answers - 0 Comments
A. (4x^3 - 5x + 1)(x^2 + 2)(3 - x) = (4x^3 - 5x + 1) (-x^3 + 3x^2 - 2x + 6) = -4x^6 + 12x^5 - 3x^4 + 8x^3 + 13x^2 - 32x + 6 Answer: -4x^6 + 12x^5 - 3x^4 + 8x^3 + 13x^2 - 32x + 6
Answered by intc_escapee - Mon Jun 8 15:10:23 2009
Q. the up arrows mean it is like squared or cubed in case you didn't know :)
Asked by Lisa - Mon Jun 8 15:03:25 2009 - - 5 Answers - 0 Comments
A. (4x^3 - 5x + 1)(x^2 + 2)(3 - x) = (4x^3 - 5x + 1) (-x^3 + 3x^2 - 2x + 6) = -4x^6 + 12x^5 - 3x^4 + 8x^3 + 13x^2 - 32x + 6 Answer: -4x^6 + 12x^5 - 3x^4 + 8x^3 + 13x^2 - 32x + 6
Answered by intc_escapee - Mon Jun 8 15:10:23 2009
3(x + 2) = 4(x-6), -4(x+3) -(-5x-3)=-6, 2[5x + 3 (x + 2)] = 6x + 22,?
Q. 3(x + 2) = 4(x-6), -4(x+3) -(-5x-3)=-6, 2[5x + 3 (x + 2)] = 6x + 22,?
Asked by princesazoe2003 - Wed Mar 26 22:18:39 2008 - - 2 Answers - 0 Comments
A. 3(x + 2) = 4(x - 6) Use the distributive property 3x + 6 = 4x - 24 Subtract 3x and add 24 to both sides 30 = x --- -4(x + 3) - (-5x - 3) = -6 Distribute -4x - 12 + 5x + 3 = -6 Add like terms x - 9 = -6 Add 9 x = 3 --- 2[5x + 3(x + 2)] = 6x + 22 Distribute 2[5x + 3x + 6] = 6x + 22 Add like terms 2[8x + 6] = 6x + 22 Distribute again 16x + 12 = 6x + 22 Subtract 6x and subtract 12 10x = 10 Divide by 24 x = 1
Answered by Son Gok on the Flying Nimbus - Wed Mar 26 22:23:59 2008
Q. 3(x + 2) = 4(x-6), -4(x+3) -(-5x-3)=-6, 2[5x + 3 (x + 2)] = 6x + 22,?
Asked by princesazoe2003 - Wed Mar 26 22:18:39 2008 - - 2 Answers - 0 Comments
A. 3(x + 2) = 4(x - 6) Use the distributive property 3x + 6 = 4x - 24 Subtract 3x and add 24 to both sides 30 = x --- -4(x + 3) - (-5x - 3) = -6 Distribute -4x - 12 + 5x + 3 = -6 Add like terms x - 9 = -6 Add 9 x = 3 --- 2[5x + 3(x + 2)] = 6x + 22 Distribute 2[5x + 3x + 6] = 6x + 22 Add like terms 2[8x + 6] = 6x + 22 Distribute again 16x + 12 = 6x + 22 Subtract 6x and subtract 12 10x = 10 Divide by 24 x = 1
Answered by Son Gok on the Flying Nimbus - Wed Mar 26 22:23:59 2008
Add or subtract as indicated: -6x^5 + 2x^3 x^2 + (8x^5 2x^3 + 5x^2)?
Q. Add or subtract as indicated: -6x^5 + 2x^3 x^2 + (8x^5 2x^3 + 5x^2)?
Asked by jared r - Tue Jun 17 23:42:43 2008 - - 4 Answers - 0 Comments
A. Combine terms (same exponent) 8x^5-6x^5=2x^5 2x^3-2x^3=0 5x^2-x^2=4x^2 Final answer: 2x^5+4x^2 since the sign in front of the parenthesis is positive, you can drop the parenthesis, if that was a subtraction sign, then you would change the sign of all of the expressions in the parenthesis.
Answered by Festsgrber - Tue Jun 17 23:53:11 2008
Q. Add or subtract as indicated: -6x^5 + 2x^3 x^2 + (8x^5 2x^3 + 5x^2)?
Asked by jared r - Tue Jun 17 23:42:43 2008 - - 4 Answers - 0 Comments
A. Combine terms (same exponent) 8x^5-6x^5=2x^5 2x^3-2x^3=0 5x^2-x^2=4x^2 Final answer: 2x^5+4x^2 since the sign in front of the parenthesis is positive, you can drop the parenthesis, if that was a subtraction sign, then you would change the sign of all of the expressions in the parenthesis.
Answered by Festsgrber - Tue Jun 17 23:53:11 2008
Can anyone help me with these I,m stuck. Multiply. (a) (0.5x+3)(6x-0.4)?
Q. (b) (5x+3)(x^3-5x^2+x-2)
Asked by Elizabeth S - Thu May 14 13:06:26 2009 - - 4 Answers - 0 Comments
A. Use FOIL... a) 3x^2 - .2x + 18x - 1.2 3x^2 + 17.8x - 1.2 b) For this one multiply each variable by each other variable, 5x times x^3, then 5x times -5x^2, etc. So, 5x^4 - 25x^3 + 5x^2 - 10x + 3x^3 - 15x^2 + 3x - 6 5x^4 - 22x^3 - 10x^2 - 7x - 6
Answered by hirshnoc - Thu May 14 13:12:39 2009
Q. (b) (5x+3)(x^3-5x^2+x-2)
Asked by Elizabeth S - Thu May 14 13:06:26 2009 - - 4 Answers - 0 Comments
A. Use FOIL... a) 3x^2 - .2x + 18x - 1.2 3x^2 + 17.8x - 1.2 b) For this one multiply each variable by each other variable, 5x times x^3, then 5x times -5x^2, etc. So, 5x^4 - 25x^3 + 5x^2 - 10x + 3x^3 - 15x^2 + 3x - 6 5x^4 - 22x^3 - 10x^2 - 7x - 6
Answered by hirshnoc - Thu May 14 13:12:39 2009
for what value of k is f continuous at x=3?
Q. f(x)= 5e^x + kx^2 + x .., x>or equal to 3 x^3 + 5x^2 - 3... x<3 for what value of k is f continuous at x=3? and could someone please explain the 5e^x part also. Thank you!
Asked by milkshaker - Fri Apr 17 16:10:00 2009 - - 3 Answers - 0 Comments
A. subs x=3 in first and second term: 5*e^(3) + k*(3)^2 + (3) = 5*e^3 + 9*k + 3 (3)^3 + 5*(3)^2 - 3 = 27 + 45 - 3 = 69 both term should be equal: 5*e^3 + 9*k + 3 = 69 9*k = 66 - 5*e^3 k = (66 - 5*e^3)/9 k= -3.8253 e^x is exponential function. the value of "e" is 2.7183...
Answered by unknown - Fri Apr 17 16:21:28 2009
Q. f(x)= 5e^x + kx^2 + x .., x>or equal to 3 x^3 + 5x^2 - 3... x<3 for what value of k is f continuous at x=3? and could someone please explain the 5e^x part also. Thank you!
Asked by milkshaker - Fri Apr 17 16:10:00 2009 - - 3 Answers - 0 Comments
A. subs x=3 in first and second term: 5*e^(3) + k*(3)^2 + (3) = 5*e^3 + 9*k + 3 (3)^3 + 5*(3)^2 - 3 = 27 + 45 - 3 = 69 both term should be equal: 5*e^3 + 9*k + 3 = 69 9*k = 66 - 5*e^3 k = (66 - 5*e^3)/9 k= -3.8253 e^x is exponential function. the value of "e" is 2.7183...
Answered by unknown - Fri Apr 17 16:21:28 2009
help!!i've got some doubt...Solve the following for x: a) 3 (x +- 4) = 2x 6 + 5x?
Q. its very east but i'm not sure...it's my assignment here's some more... b) Solve the following for x: 3/5x-4=12 c)Solve for x: 2(x 4) = 5x + 7 3x d)Solve for r : I = P( 1 + rt) e)Solve for t: A = P + Prt thanks, thanks a lot
Asked by ur_smile1991 - Tue Feb 19 19:18:55 2008 - - 1 Answers - 0 Comments
A. a) 3 - (x +- 4) = 2x - 6 + 5x 3 - x + 4 = 7x - 6 -x + 7 = 7x - 6 Subtract 7x from both sides and subtract 7 from both sides. -8x = -13 Divide both sides by -8. x = 13/8 b) Solve the following for x: 3/5x-4=12 Multiply both sides by 5. 3x - 20 = 60 Add 20 to each side. 3x = 80 Divide both sides by 3. x = 80/3 c) This is similar to the first two. d)Solve for r : I = P( 1 + rt) Multiply through by P I = P + Prt Subtract P from each side. I - P = Prt Divide both sides by Pt (I-P) / (Pt) = r e) This is similar to d)
Answered by MsMath - Tue Feb 19 22:04:04 2008
Q. its very east but i'm not sure...it's my assignment here's some more... b) Solve the following for x: 3/5x-4=12 c)Solve for x: 2(x 4) = 5x + 7 3x d)Solve for r : I = P( 1 + rt) e)Solve for t: A = P + Prt thanks, thanks a lot
Asked by ur_smile1991 - Tue Feb 19 19:18:55 2008 - - 1 Answers - 0 Comments
A. a) 3 - (x +- 4) = 2x - 6 + 5x 3 - x + 4 = 7x - 6 -x + 7 = 7x - 6 Subtract 7x from both sides and subtract 7 from both sides. -8x = -13 Divide both sides by -8. x = 13/8 b) Solve the following for x: 3/5x-4=12 Multiply both sides by 5. 3x - 20 = 60 Add 20 to each side. 3x = 80 Divide both sides by 3. x = 80/3 c) This is similar to the first two. d)Solve for r : I = P( 1 + rt) Multiply through by P I = P + Prt Subtract P from each side. I - P = Prt Divide both sides by Pt (I-P) / (Pt) = r e) This is similar to d)
Answered by MsMath - Tue Feb 19 22:04:04 2008
in algebra x=1/3(x)+1/4(p)+3...?
Q. 12x=4x+3x+3 5x=3 x=3/5?
Asked by opi - Tue Sep 25 04:53:41 2007 - - 3 Answers - 0 Comments
Q. 12x=4x+3x+3 5x=3 x=3/5?
Asked by opi - Tue Sep 25 04:53:41 2007 - - 3 Answers - 0 Comments
Change the following product to a sum or a difference.Example: 5(x + 3) = 5 x + 5 3 = 5x + 15 !thats for 1-6
Q. 1. 6(x + 4) 2. 7(A - 6) 3. 12(A - B) 4. 10(N + 3) 5. 3(x+2) 6. 5(x - 6) Place the letter of the correct sum or difference next to its corresponding product.(mathc the right letter w/ the right #) and all the things that look like this 5n2 mean 5n squared the 2 means squared. the same thing with like none of the x's are time they are letters 1. 8(p2 + 3p - 4)---A. 5N2 + 10N - 5 2. 5(N2 + 2N - 1)---B. 4x2 + 4x + 4 3. 9(y2 + 5y + 6)---C. 8p2 + 24p - 32 4. (x2 + 2x)---D. 6A2 - 6A - 24 5. 16(4 - 2K + k2)---E. 16k2 - 32K + 64 6. 4(x2 + x + 1)---F. 9y2 + 45y + 54 7. 6(A2 - A - 4)---G. x3 + 2x2 8. 15x(5x2 + 6x + 3)---H. p3 - 3p2 9. x2(x2 + 2x + 1) ---I. N3 + 2N2 +N 10. R(3R2 - 2R - 1) ---J. 3R3 - 2R2 - R 11. 6x(2x2 [cont.]
Asked by nicholas_alex_bailey - Fri Aug 3 09:53:40 2007 - - 2 Answers - 0 Comments
A. Here's for the second part of your question: 1. C. 2. A. 3. F. 4. G 5. E. 6. B. 7. D. 8. M. 9. N. 10. J. 11. L 12. K 13. H 14. I Please note that I believe the 4 was mistyped. It should probably be x(x2 + 2x) which will give you the answer in G, x3 + 2x2. And also, I believe that N is incomplete. It should be x4 + 2x3 + x2 which would be the answer to 9. I am guessing these because these two were the only ones left without an answer when I went through them, and this seems to be the most logical scenario. Just double check your question. Kia
Answered by Kia - Fri Aug 3 14:15:37 2007
Q. 1. 6(x + 4) 2. 7(A - 6) 3. 12(A - B) 4. 10(N + 3) 5. 3(x+2) 6. 5(x - 6) Place the letter of the correct sum or difference next to its corresponding product.(mathc the right letter w/ the right #) and all the things that look like this 5n2 mean 5n squared the 2 means squared. the same thing with like none of the x's are time they are letters 1. 8(p2 + 3p - 4)---A. 5N2 + 10N - 5 2. 5(N2 + 2N - 1)---B. 4x2 + 4x + 4 3. 9(y2 + 5y + 6)---C. 8p2 + 24p - 32 4. (x2 + 2x)---D. 6A2 - 6A - 24 5. 16(4 - 2K + k2)---E. 16k2 - 32K + 64 6. 4(x2 + x + 1)---F. 9y2 + 45y + 54 7. 6(A2 - A - 4)---G. x3 + 2x2 8. 15x(5x2 + 6x + 3)---H. p3 - 3p2 9. x2(x2 + 2x + 1) ---I. N3 + 2N2 +N 10. R(3R2 - 2R - 1) ---J. 3R3 - 2R2 - R 11. 6x(2x2 [cont.]
Asked by nicholas_alex_bailey - Fri Aug 3 09:53:40 2007 - - 2 Answers - 0 Comments
A. Here's for the second part of your question: 1. C. 2. A. 3. F. 4. G 5. E. 6. B. 7. D. 8. M. 9. N. 10. J. 11. L 12. K 13. H 14. I Please note that I believe the 4 was mistyped. It should probably be x(x2 + 2x) which will give you the answer in G, x3 + 2x2. And also, I believe that N is incomplete. It should be x4 + 2x3 + x2 which would be the answer to 9. I am guessing these because these two were the only ones left without an answer when I went through them, and this seems to be the most logical scenario. Just double check your question. Kia
Answered by Kia - Fri Aug 3 14:15:37 2007
3=5x-3y+10 and y=2x+4?
Q. I have the answer, 3=5x-6x-12+10 3=-x-2 5=-x x=-5 y=2(-5)+4 y=-10+4 y=-6 how would a person check this answer? sorry i learn best by examples, once i have an example for one i can solve a book of them
Asked by In love w/a soldier B2B 09-23-10 - Mon Aug 31 16:58:07 2009 - - 2 Answers - 0 Comments
Q. I have the answer, 3=5x-6x-12+10 3=-x-2 5=-x x=-5 y=2(-5)+4 y=-10+4 y=-6 how would a person check this answer? sorry i learn best by examples, once i have an example for one i can solve a book of them
Asked by In love w/a soldier B2B 09-23-10 - Mon Aug 31 16:58:07 2009 - - 2 Answers - 0 Comments
7x=3(5x-8)????please help answer?
Q. please help and explain and if you want these answers too: -2x+6=-x 7x=3(5x-8) 9(2x+10)=24x 2(x-9)=3(x-6)
Asked by Lisette - Tue Oct 27 22:19:50 2009 - - 3 Answers - 0 Comments
A. Distribute the 3 to the numbers in the parenthesis which would give you 7x=15x-24 Subtract 15x from 7x which leads to -8x=-24 divide by 8 on both sides x=3 It's basically the same format for all these questions so just review the first one and I'm sure you can get the rest :) good luck
Answered by kimmy((: - Tue Oct 27 22:31:17 2009
Q. please help and explain and if you want these answers too: -2x+6=-x 7x=3(5x-8) 9(2x+10)=24x 2(x-9)=3(x-6)
Asked by Lisette - Tue Oct 27 22:19:50 2009 - - 3 Answers - 0 Comments
A. Distribute the 3 to the numbers in the parenthesis which would give you 7x=15x-24 Subtract 15x from 7x which leads to -8x=-24 divide by 8 on both sides x=3 It's basically the same format for all these questions so just review the first one and I'm sure you can get the rest :) good luck
Answered by kimmy((: - Tue Oct 27 22:31:17 2009
How do you solve 3(x + 2) = 5(x - 2)?
Q. EXAMPLE: 2x - 2 = -3x + 3. 2x + 3x - 2 = -3x + 3x + 3. 5x - 2 = 3. 5x - 2 + 2 = 3 + 2. 5x = 5. 1/5 x 5x = 1/5 x 5. x = 1. please show all work. Thanks :)
Asked by Tay Tay - Sun Sep 28 17:31:21 2008 - - 8 Answers - 0 Comments
A. first distribute the 3 and the 5 through the parentheses. you should have 3x+6=5x-10. then add 10 to each side and subtract 3x. after that divide and you have your answer. if your not sure of your answer, check by plugging in what you got into the original equation, and you have your answer.
Answered by smarticalbrunet59 - Sun Sep 28 17:38:23 2008
Q. EXAMPLE: 2x - 2 = -3x + 3. 2x + 3x - 2 = -3x + 3x + 3. 5x - 2 = 3. 5x - 2 + 2 = 3 + 2. 5x = 5. 1/5 x 5x = 1/5 x 5. x = 1. please show all work. Thanks :)
Asked by Tay Tay - Sun Sep 28 17:31:21 2008 - - 8 Answers - 0 Comments
A. first distribute the 3 and the 5 through the parentheses. you should have 3x+6=5x-10. then add 10 to each side and subtract 3x. after that divide and you have your answer. if your not sure of your answer, check by plugging in what you got into the original equation, and you have your answer.
Answered by smarticalbrunet59 - Sun Sep 28 17:38:23 2008
From Yahoo Answer Search: '3=x 3-5x'
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