chem equation?
Q. is this balanced equation right? CuSO4. 5H2O + H2O ---> CuSO4 + 6H2O and what type of chemical reaction is this because I really dont get hydrates when it comes to its type of reaction? tnx copper(II) sulfate pentahydrate and water produces copper(II) sulfate and water
Asked by curiousmoi - Wed Jan 14 23:05:22 2009 - - 1 Answers - 0 Comments
A. Because this reaction is a hydration reaction, it can go either way. As given I would assume that you would add the water to the salt, but if it was indicated that heat was aded, then the hydrate would lose water. The correct version is: CuSO4 * 5H2O ---> CuSO4 * 6H2O So just replace the + with a *, According to the above equation, the salt (CuSO4) is becoming more hydrated (gaining H2O). But it can also be possible for it to lose water, if heated or placed in a dry environment.
Answered by unknown - Wed Jan 14 23:19:12 2009
Q. is this balanced equation right? CuSO4. 5H2O + H2O ---> CuSO4 + 6H2O and what type of chemical reaction is this because I really dont get hydrates when it comes to its type of reaction? tnx copper(II) sulfate pentahydrate and water produces copper(II) sulfate and water
Asked by curiousmoi - Wed Jan 14 23:05:22 2009 - - 1 Answers - 0 Comments
A. Because this reaction is a hydration reaction, it can go either way. As given I would assume that you would add the water to the salt, but if it was indicated that heat was aded, then the hydrate would lose water. The correct version is: CuSO4 * 5H2O ---> CuSO4 * 6H2O So just replace the + with a *, According to the above equation, the salt (CuSO4) is becoming more hydrated (gaining H2O). But it can also be possible for it to lose water, if heated or placed in a dry environment.
Answered by unknown - Wed Jan 14 23:19:12 2009
What is the balanced equation and the word equation of the following?
Q. What is the balanced equation and the word equation of the following? The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:18:47 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O + heat >> CuSO4 + 5H2O CuSO4 + 5H2O - heat >> CuSO4.5H2O
Answered by Dr.A - Sun Dec 16 12:31:42 2007
Q. What is the balanced equation and the word equation of the following? The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:18:47 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O + heat >> CuSO4 + 5H2O CuSO4 + 5H2O - heat >> CuSO4.5H2O
Answered by Dr.A - Sun Dec 16 12:31:42 2007
Complete and Balance this Chemical Equation?
Q. can u please complete and balance this equation? I'm really lost with this one...(the dot between CuSO4 and 5H2O means "multiply") Mg + CuSO4 5H2O = I also have one more question... What is the Chemical Formula for Stainless Steel?
Asked by miz*india - Sun Oct 21 11:26:52 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O is solid, must dissolve in water to form solution and then reacts with Mg Mg + CuSO4 = MgSO4 + Cu (ppt) Stainless steel do not have an exact formula. Its formula depends on its compositions; stainless steel is defined as an iron-carbon alloy with a minimum of 10.5% chromium content
Answered by jenkyd - Sun Oct 21 11:58:46 2007
Q. can u please complete and balance this equation? I'm really lost with this one...(the dot between CuSO4 and 5H2O means "multiply") Mg + CuSO4 5H2O = I also have one more question... What is the Chemical Formula for Stainless Steel?
Asked by miz*india - Sun Oct 21 11:26:52 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O is solid, must dissolve in water to form solution and then reacts with Mg Mg + CuSO4 = MgSO4 + Cu (ppt) Stainless steel do not have an exact formula. Its formula depends on its compositions; stainless steel is defined as an iron-carbon alloy with a minimum of 10.5% chromium content
Answered by jenkyd - Sun Oct 21 11:58:46 2007
Chemistry help? (percent weight)?
Q. Is this a balanced equation: CuSO4 + (CuSO4 * 5H2O) ---(heat)---> 2CuSO4 + 5H2O And how do I go about figuring the weight percent of the hydrate in the reactant side (please don't do the math for me, just tell me verbally)?
Asked by teeheequeen - Sun Jul 19 23:27:17 2009 - - 2 Answers - 0 Comments
A. 1) calculate mass H2O... = mass before heating - mass after heating 2) convert that to MOLES H2O 3) convert moles H2O to moles CuSO4 5H2O...5:1 ratio right? 4) convert moles CuSO4 5H2O to mass CuSO4 5H2O 5) mass % CuSO4 5H2O = mass CuSO4 5H2O / mass sample x 100% *** questions? I worked it out for you here.
Answered by m w - Sun Jul 19 23:35:32 2009
Q. Is this a balanced equation: CuSO4 + (CuSO4 * 5H2O) ---(heat)---> 2CuSO4 + 5H2O And how do I go about figuring the weight percent of the hydrate in the reactant side (please don't do the math for me, just tell me verbally)?
Asked by teeheequeen - Sun Jul 19 23:27:17 2009 - - 2 Answers - 0 Comments
A. 1) calculate mass H2O... = mass before heating - mass after heating 2) convert that to MOLES H2O 3) convert moles H2O to moles CuSO4 5H2O...5:1 ratio right? 4) convert moles CuSO4 5H2O to mass CuSO4 5H2O 5) mass % CuSO4 5H2O = mass CuSO4 5H2O / mass sample x 100% *** questions? I worked it out for you here.
Answered by m w - Sun Jul 19 23:35:32 2009
what happens when copper(II) sulfate pentahydrate (CuSO4 5H2O) reacts with Iron (Fe) ??
Q. what happen when dissolved copper (II) sulfate pentahydrate is react with Iron? How can i work out the balanced equation?
Asked by Labuuu* - Fri May 18 23:59:18 2007 - - 3 Answers - 0 Comments
A. reaction: CuSO4 5H2O+ Fe---> FeSO4.5H2O +Cu when copper(II) sulfate pentahydrate reacts with Iron, Fe metal goes into the solution and the pinkish metal(Cu) is formed upon reaction. this is a metal displacement reaction, where the more reactive metal(Fe) displaces the les reactive metal(Cu)
Answered by 1-man-show - Sat May 19 00:07:20 2007
Q. what happen when dissolved copper (II) sulfate pentahydrate is react with Iron? How can i work out the balanced equation?
Asked by Labuuu* - Fri May 18 23:59:18 2007 - - 3 Answers - 0 Comments
A. reaction: CuSO4 5H2O+ Fe---> FeSO4.5H2O +Cu when copper(II) sulfate pentahydrate reacts with Iron, Fe metal goes into the solution and the pinkish metal(Cu) is formed upon reaction. this is a metal displacement reaction, where the more reactive metal(Fe) displaces the les reactive metal(Cu)
Answered by 1-man-show - Sat May 19 00:07:20 2007
How do would you balance these equations?
Q. CuSO4*5H2O ---> CuSO4 + H2O C8H18 + O2 ---> CO2 + H2O P2O5 + H2O ---> H3PO4 HN3 + Zn ---> Zn(NO3)2 + NO2 + H2O
Asked by SICK MY DUCK! - Wed Jan 24 01:03:19 2007 - - 2 Answers - 0 Comments
A. CuSO4*5(H2O) ---> CuSO4 + 5(H2O) 2(C8H18) + 25O2 ---> 16(CO2) + 18(H2O) P2O5 + 3(H2O) ---> 2(H3PO4) The last one doesn't balance because there is oxygen on the right side but none on the left.
Answered by Northstar - Wed Jan 24 01:13:36 2007
Q. CuSO4*5H2O ---> CuSO4 + H2O C8H18 + O2 ---> CO2 + H2O P2O5 + H2O ---> H3PO4 HN3 + Zn ---> Zn(NO3)2 + NO2 + H2O
Asked by SICK MY DUCK! - Wed Jan 24 01:03:19 2007 - - 2 Answers - 0 Comments
A. CuSO4*5(H2O) ---> CuSO4 + 5(H2O) 2(C8H18) + 25O2 ---> 16(CO2) + 18(H2O) P2O5 + 3(H2O) ---> 2(H3PO4) The last one doesn't balance because there is oxygen on the right side but none on the left.
Answered by Northstar - Wed Jan 24 01:13:36 2007
Does anyone have the time to explain how to do this? I don't want just answers I really need to know this.?
Q. Empirical Formula Lab Report: CuSO4.5H2O and CuO 1. Data (a) mass of copper powder used (g): 25g (b) mass of copper powder and beaker (g): 72.420g (c) mass of copper oxide and beaker (g): 78.714g 2. Calculate the following for the copper: (a) The number of moles of copper powder, given a molecular weight of copper equal to 63.55 g/mole. (1 pt) {Convert the value from 1(a) to moles} 3. Calculate the following for the oxygen: (a) The mass of the beaker (g) {1(b) - 1(a)}47.42g (b) The final mass of copper oxide (g) {1(c) - 3(a)}31.3g (c) The gain in mass in the beaker which is equal to the added mass of oxygen (g) {3(b) - 1(a)}6.3g (d) The number of moles of oxygen in the copper oxide, given a… [cont.]
Asked by pickle - Sat Oct 4 00:11:25 2008 - - 1 Answers - 0 Comments
Q. Empirical Formula Lab Report: CuSO4.5H2O and CuO 1. Data (a) mass of copper powder used (g): 25g (b) mass of copper powder and beaker (g): 72.420g (c) mass of copper oxide and beaker (g): 78.714g 2. Calculate the following for the copper: (a) The number of moles of copper powder, given a molecular weight of copper equal to 63.55 g/mole. (1 pt) {Convert the value from 1(a) to moles} 3. Calculate the following for the oxygen: (a) The mass of the beaker (g) {1(b) - 1(a)}47.42g (b) The final mass of copper oxide (g) {1(c) - 3(a)}31.3g (c) The gain in mass in the beaker which is equal to the added mass of oxygen (g) {3(b) - 1(a)}6.3g (d) The number of moles of oxygen in the copper oxide, given a… [cont.]
Asked by pickle - Sat Oct 4 00:11:25 2008 - - 1 Answers - 0 Comments
the synthesis of copper (II) sulfate pentahydrate?
Q. we are asked to determine the overall balanced equation. It says: assume the reactions in the synthesis were those shown below: 3CU + 2HNO3 --> 3 CuO + H2O + 2NO CuO + H2SO4 --> CuSO4 + H2O CuSO4 + 5H2O --> CuSO4.5H2O I think I just take everything from the left hand sides and put them together, draw and arrow, and take everything from the right hand sides and put them together: 3Cu + 2HNO3 + CuO + H2SO4 + CuSO4 + 5H2O --> 3CuO + H2O + 2NO + CuSO4 + H2O + CuSO4.5H2O The problem is that we are also asked to find the limiting reagent. I know the amount (ml or g) of all of them except CuO and CuSO4 - there's nothing in the procedure of our lab that told us to measure them. This makes me think my equation for this reaction is wrong. Also, I… [cont.]
Asked by sccrsweetie - Mon Oct 27 22:19:13 2008 - - 1 Answers - 0 Comments
Q. we are asked to determine the overall balanced equation. It says: assume the reactions in the synthesis were those shown below: 3CU + 2HNO3 --> 3 CuO + H2O + 2NO CuO + H2SO4 --> CuSO4 + H2O CuSO4 + 5H2O --> CuSO4.5H2O I think I just take everything from the left hand sides and put them together, draw and arrow, and take everything from the right hand sides and put them together: 3Cu + 2HNO3 + CuO + H2SO4 + CuSO4 + 5H2O --> 3CuO + H2O + 2NO + CuSO4 + H2O + CuSO4.5H2O The problem is that we are also asked to find the limiting reagent. I know the amount (ml or g) of all of them except CuO and CuSO4 - there's nothing in the procedure of our lab that told us to measure them. This makes me think my equation for this reaction is wrong. Also, I… [cont.]
Asked by sccrsweetie - Mon Oct 27 22:19:13 2008 - - 1 Answers - 0 Comments
Chemistry ,Someone Please help me!! Im desperate PLEASE!!!?
Q. Hi everybody, I am having some problems with trying to figure out these kind of questions, and there is a ton of them exactly like this, so i was wodnering if anyone could help me with this one, with steps so I know how to do my other ones ?!?! I like explanations too if you have any, that way I can totally undersand, but if not I am sure I can figure out how you did it following the steps! Thanks sooo much! greatly appreciated!!! Reactants : Copper sulfate pentahydrate Potassium Oxalate hydrate CuSO4 * 5H2O K2C2O4 *H2O Mass weighed: 3.147g 5.042g Molar Mass: Moles Used: Physical properties: 1a) Calculation for limiting reagent- b) Balanced chemical equation- c) Ratio of reactants (or equivalence)- d)Moles of reactants- e) Limiting… [cont.]
Asked by chemfailure - Thu Oct 1 12:01:29 2009 - - 1 Answers - 0 Comments
A. CuSO4 * 5 H2O + K2C2O4 * H2O = CuC2O4 + K2SO4 + 6 H2O moles = 3.147 / 249.68 g/mol=0.01260 moles = 5.042 / 184.2 = 0.02737 copper (II) sulphate pentahydrate = limiting reactant hope this helps
Answered by Dr.A - Thu Oct 1 12:26:32 2009
Q. Hi everybody, I am having some problems with trying to figure out these kind of questions, and there is a ton of them exactly like this, so i was wodnering if anyone could help me with this one, with steps so I know how to do my other ones ?!?! I like explanations too if you have any, that way I can totally undersand, but if not I am sure I can figure out how you did it following the steps! Thanks sooo much! greatly appreciated!!! Reactants : Copper sulfate pentahydrate Potassium Oxalate hydrate CuSO4 * 5H2O K2C2O4 *H2O Mass weighed: 3.147g 5.042g Molar Mass: Moles Used: Physical properties: 1a) Calculation for limiting reagent- b) Balanced chemical equation- c) Ratio of reactants (or equivalence)- d)Moles of reactants- e) Limiting… [cont.]
Asked by chemfailure - Thu Oct 1 12:01:29 2009 - - 1 Answers - 0 Comments
A. CuSO4 * 5 H2O + K2C2O4 * H2O = CuC2O4 + K2SO4 + 6 H2O moles = 3.147 / 249.68 g/mol=0.01260 moles = 5.042 / 184.2 = 0.02737 copper (II) sulphate pentahydrate = limiting reactant hope this helps
Answered by Dr.A - Thu Oct 1 12:26:32 2009
Chemistry help -If some one could help me figure out how to answer this!!! PLEASE! PLEASE PLEASE! SOOO LOST?
Q. the top part is just a chart, just need to answer the 1a-c thing, just wasnt sure if the chart was necessary, i have 3 more of these to do, so it would be awesome if i had something to lookat and helpme get the others done Reactants : Copper sulfate pentahydrate Potassium Oxalate hydrate CuSO4 * 5H2O K2C2O4 *H2O Mass weighed: 3.147g 5.042g Molar Mass: Moles Used: Physical properties: 1a) Calculation for limiting reagent- b) Balanced chemical equation- c) Ratio of reactants (or equivalence)- d)Moles of reactants- e) Limiting reagent -
Asked by chrissypissie - Thu Oct 1 12:08:29 2009 - - 1 Answers - 0 Comments
A. CuSO4+ K2C2O4---> CuC2O4 + K2SO4 Molar mass of CuSO4.5H2O = 249.5 grams/mole Molar mass of K2C2O4.H2O = 184 grams/mole 3.147 grams CuSO4.5H2O = 3.147/249.5 = 0.0126 moles 5.042 grams K2C2O4.H2O = 5.04/184 = 0.0274 moles as they react in a 1:1 ratio there is less than half the amount of CuSO4.5H2O present ( 0.0126moles ) to react with all the K2C2O4.H2O ( 0.0274 moles ) so the CuSO4.5H2O is the limiting reactant. So after reaction of the two there will be 0.0148 moles of unreacted K2C2O4.H2O remaining as well as 0.0126 moles each of CuC2O4 and K2SO4
Answered by Merlin's Feline - Thu Oct 1 13:29:44 2009
Q. the top part is just a chart, just need to answer the 1a-c thing, just wasnt sure if the chart was necessary, i have 3 more of these to do, so it would be awesome if i had something to lookat and helpme get the others done Reactants : Copper sulfate pentahydrate Potassium Oxalate hydrate CuSO4 * 5H2O K2C2O4 *H2O Mass weighed: 3.147g 5.042g Molar Mass: Moles Used: Physical properties: 1a) Calculation for limiting reagent- b) Balanced chemical equation- c) Ratio of reactants (or equivalence)- d)Moles of reactants- e) Limiting reagent -
Asked by chrissypissie - Thu Oct 1 12:08:29 2009 - - 1 Answers - 0 Comments
A. CuSO4+ K2C2O4---> CuC2O4 + K2SO4 Molar mass of CuSO4.5H2O = 249.5 grams/mole Molar mass of K2C2O4.H2O = 184 grams/mole 3.147 grams CuSO4.5H2O = 3.147/249.5 = 0.0126 moles 5.042 grams K2C2O4.H2O = 5.04/184 = 0.0274 moles as they react in a 1:1 ratio there is less than half the amount of CuSO4.5H2O present ( 0.0126moles ) to react with all the K2C2O4.H2O ( 0.0274 moles ) so the CuSO4.5H2O is the limiting reactant. So after reaction of the two there will be 0.0148 moles of unreacted K2C2O4.H2O remaining as well as 0.0126 moles each of CuC2O4 and K2SO4
Answered by Merlin's Feline - Thu Oct 1 13:29:44 2009
Grade 11 Chemistry Question?
Q. I was just wondering if anyone could help me predict the products / write the formula for this equation... Aqueous Barium Nitrate + Aqueous Copper (II) Sulfate Pentahydrate --> ___ They react in water... so I'm not sure if you have to add H2O into the equation? And how would I balance this?? So far I have...: Ba(NO3)2 (aq) + CuSO4.5H2O (aq) --> Thanks so much for your help!!! I really appreciate it :) please helppp!
Asked by LARRY K - Sun Nov 15 18:00:50 2009 - - 0 Answers - 0 Comments
Q. I was just wondering if anyone could help me predict the products / write the formula for this equation... Aqueous Barium Nitrate + Aqueous Copper (II) Sulfate Pentahydrate --> ___ They react in water... so I'm not sure if you have to add H2O into the equation? And how would I balance this?? So far I have...: Ba(NO3)2 (aq) + CuSO4.5H2O (aq) --> Thanks so much for your help!!! I really appreciate it :) please helppp!
Asked by LARRY K - Sun Nov 15 18:00:50 2009 - - 0 Answers - 0 Comments
Can someone check my chemistry answers? (balancing equations)?
Q. H202 ---> H2O + O2 (decomposition) KI + Pb(NO3)2 ---> KNO3 + PbI2 (single replacement???) 2 Na + CuSO4 ---> Na2SO4 + Cu (single replacement???) Na2CO3 X (times) 10 H20 ---> Na2CO3 +10 H20 (double replacement???) 2 Sb + 3 Br2 ---> 2 SbBr3 (what type of reaction is this???) F2 + 2 NaCl ---> 2 NaF + Cl2 (single replacement???) Mg(NO3)2 + Na2CO3 ---> MgCO3 + 2 NaNO3 (what type of rxn is this?) 2 CaCO3 ---> 2 CaO + 3 CO2 (decomp) CuSO4 + 5 H2O ---> CuSO4 X (times) 5H2O (single replacement???) CH4 + 2 O2 ---> 2 CO2 + H2O (what type of rxn?) thannk you so much !
Asked by areyoujellin00 - Tue Feb 26 23:44:11 2008 - - 4 Answers - 0 Comments
A. You seem to be having some trouble balancing these. You must have the same number of atoms of each type on both sides of the equation. I am copying your answers and commenting as I go: H202 ---> H2O + O2 (decomposition) This is not balanced because you have 2O on the left and 3O on the right. Its a bit tricky to figure out how to balance it, so look at it this way: Every H2O2 gives one H2O plus an O left over To get an O2 requires 2 O, so you will need another H2O2 (which will also give another H2O) 2H202 ---> 2H2O + O2 Decomposition is correct KI + Pb(NO3)2 ---> KNO3 + PbI2 (single replacement???) This is not balanced either. You have 1 I on the left and 2 on the right, also 2 NO3 on the left and one on the right. Start on the… [cont.]
Answered by gladys - Wed Feb 27 00:20:41 2008
Q. H202 ---> H2O + O2 (decomposition) KI + Pb(NO3)2 ---> KNO3 + PbI2 (single replacement???) 2 Na + CuSO4 ---> Na2SO4 + Cu (single replacement???) Na2CO3 X (times) 10 H20 ---> Na2CO3 +10 H20 (double replacement???) 2 Sb + 3 Br2 ---> 2 SbBr3 (what type of reaction is this???) F2 + 2 NaCl ---> 2 NaF + Cl2 (single replacement???) Mg(NO3)2 + Na2CO3 ---> MgCO3 + 2 NaNO3 (what type of rxn is this?) 2 CaCO3 ---> 2 CaO + 3 CO2 (decomp) CuSO4 + 5 H2O ---> CuSO4 X (times) 5H2O (single replacement???) CH4 + 2 O2 ---> 2 CO2 + H2O (what type of rxn?) thannk you so much !
Asked by areyoujellin00 - Tue Feb 26 23:44:11 2008 - - 4 Answers - 0 Comments
A. You seem to be having some trouble balancing these. You must have the same number of atoms of each type on both sides of the equation. I am copying your answers and commenting as I go: H202 ---> H2O + O2 (decomposition) This is not balanced because you have 2O on the left and 3O on the right. Its a bit tricky to figure out how to balance it, so look at it this way: Every H2O2 gives one H2O plus an O left over To get an O2 requires 2 O, so you will need another H2O2 (which will also give another H2O) 2H202 ---> 2H2O + O2 Decomposition is correct KI + Pb(NO3)2 ---> KNO3 + PbI2 (single replacement???) This is not balanced either. You have 1 I on the left and 2 on the right, also 2 NO3 on the left and one on the right. Start on the… [cont.]
Answered by gladys - Wed Feb 27 00:20:41 2008
BALANCING CHEMICAL EQUATIONS?
Q. A. KNO3 ---> KNO2 + O2 B. Cu + H2SO4 + H2O ---> CuSO4 times 5H2O C. HCl + Ca(HCO3)2 ---> H2O + CO2 + CaCl
Asked by Anonymous - Sun Nov 15 19:17:21 2009 - - 0 Answers - 0 Comments
Q. A. KNO3 ---> KNO2 + O2 B. Cu + H2SO4 + H2O ---> CuSO4 times 5H2O C. HCl + Ca(HCO3)2 ---> H2O + CO2 + CaCl
Asked by Anonymous - Sun Nov 15 19:17:21 2009 - - 0 Answers - 0 Comments
What is the balanced equation and the word equation of the following?
Q. The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:06:33 2007 - - 1 Answers - 0 Comments
A. Well you just said it. The word equation is Copper (II) Sulfate and water yields hydrated copper sulfate. The hydrated molecule forms Copper sulfate and water when exposed to excess heat. CuSO4.5H2O + heat <==> CuSO4 + 5H2O
Answered by David Feldman - Sun Dec 16 12:20:01 2007
Q. The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:06:33 2007 - - 1 Answers - 0 Comments
A. Well you just said it. The word equation is Copper (II) Sulfate and water yields hydrated copper sulfate. The hydrated molecule forms Copper sulfate and water when exposed to excess heat. CuSO4.5H2O + heat <==> CuSO4 + 5H2O
Answered by David Feldman - Sun Dec 16 12:20:01 2007
What is the balanced equation and the word equation of the following?
Q. The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:17:47 2007 - - 1 Answers - 0 Comments
A. I just answered this on your previoius question =)
Answered by David Feldman - Sun Dec 16 12:22:00 2007
Q. The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:17:47 2007 - - 1 Answers - 0 Comments
A. I just answered this on your previoius question =)
Answered by David Feldman - Sun Dec 16 12:22:00 2007
From Yahoo Answer Search: 'Balance equation of CuSO4 5H2O'
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Fri, 06 Mar 2009 10:38:00 GM
Find the Relative Formula Mass of hydrated copper sulphate crystals, . CuSO4. .. 5H2O. . 1 atom of copper Cu = 64.0 1 atom of sulphur S = 32.0 10 atoms of hydrogen H = 10.0 9 atoms of oxygen O = 144. TOTAL = 250 R.F.M. hydrated copper sulphate ...
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