An iron nail, CuSO4.5H2O, NaCl, and H2O are placed in a test tube. List all reactions that occur.?
Q. Can anyone help me answer this question for my AP Chemistry class? I've researched for hours on the web and can't seem to find very many answers. So far I have the following reactions. Are these correct? Am I missing any? HELP!!! Fe + CuSO4 -> FeSO4, Iron (II) reacts with Copper (II) in an oxidation-reduction reaction. Na + SO4 -> Na2SO4, a colorless solution. The color change in the salt layer and the appearance of solid copper on the nails are indicators of how the copper ions have moved. pH doesn t change, it remains constant at 5, slightly acidic. Cu2+ + 4Cl- -> CuCl42-. As the copper ions migrate slowly into the salt layer, the green complex ion CuCl42- forms. As the copper ions continue to move upwards they come in contact… [cont.]
Asked by hft3229 - Fri Nov 3 15:32:37 2006 - - 1 Answers - 0 Comments
A. It's also possible that the water will react with the iron nail and cause oxidation. Perhaps the ferric chloride would be produced in solution with the dissociated Cl- ion reacting with the iron in the nail.
Answered by ralphwaldo45 - Fri Nov 3 18:38:59 2006
Q. Can anyone help me answer this question for my AP Chemistry class? I've researched for hours on the web and can't seem to find very many answers. So far I have the following reactions. Are these correct? Am I missing any? HELP!!! Fe + CuSO4 -> FeSO4, Iron (II) reacts with Copper (II) in an oxidation-reduction reaction. Na + SO4 -> Na2SO4, a colorless solution. The color change in the salt layer and the appearance of solid copper on the nails are indicators of how the copper ions have moved. pH doesn t change, it remains constant at 5, slightly acidic. Cu2+ + 4Cl- -> CuCl42-. As the copper ions migrate slowly into the salt layer, the green complex ion CuCl42- forms. As the copper ions continue to move upwards they come in contact… [cont.]
Asked by hft3229 - Fri Nov 3 15:32:37 2006 - - 1 Answers - 0 Comments
A. It's also possible that the water will react with the iron nail and cause oxidation. Perhaps the ferric chloride would be produced in solution with the dissociated Cl- ion reacting with the iron in the nail.
Answered by ralphwaldo45 - Fri Nov 3 18:38:59 2006
Which of the following salts forms a basic solution when dissolved in water? NaCl , (NH4)2SO4, . CuSO4 ,.K2CO3?
Q. Which of the following salts forms a basic solution when dissolved in water? NaCl , (NH4)2SO4, . CuSO4 ,.K2CO3?
Asked by micky - Sat Aug 1 04:04:49 2009 - - 6 Answers - 0 Comments
A. I can help u Salt+Acid= Water Salt=water-acid Hence disssolved it in water d u hav to calculate the ph of all salts if its ph exceeds 7 then its an acid if its ph is below 7 then its a basic salt
Answered by Ragu a - Sat Aug 1 04:50:43 2009
Q. Which of the following salts forms a basic solution when dissolved in water? NaCl , (NH4)2SO4, . CuSO4 ,.K2CO3?
Asked by micky - Sat Aug 1 04:04:49 2009 - - 6 Answers - 0 Comments
A. I can help u Salt+Acid= Water Salt=water-acid Hence disssolved it in water d u hav to calculate the ph of all salts if its ph exceeds 7 then its an acid if its ph is below 7 then its a basic salt
Answered by Ragu a - Sat Aug 1 04:50:43 2009
why it CuSo4 absorbs water and why Nacl can't?
Q. why it CuSo4 absorbs water and why Nacl can't?
Asked by seher_azad - Fri Mar 2 09:21:54 2007 - - 1 Answers - 0 Comments
A. This is not true, sodium chloride readily absorbs water vapour in the air. For example, if you leave pure sodium chloride open to the air, it will start to cake due to it absorbing water from the air. The reason why you do not see this with table salt is because they use anti-caking agents (such as magnesium carbonate) which prevent cakes formation and keep it free flowing. Also if you add salt into water it readily dissolves, so in fact we can say that salt has an affinity for water.
Answered by The exclamation mark - Fri Mar 2 09:30:28 2007
Q. why it CuSo4 absorbs water and why Nacl can't?
Asked by seher_azad - Fri Mar 2 09:21:54 2007 - - 1 Answers - 0 Comments
A. This is not true, sodium chloride readily absorbs water vapour in the air. For example, if you leave pure sodium chloride open to the air, it will start to cake due to it absorbing water from the air. The reason why you do not see this with table salt is because they use anti-caking agents (such as magnesium carbonate) which prevent cakes formation and keep it free flowing. Also if you add salt into water it readily dissolves, so in fact we can say that salt has an affinity for water.
Answered by The exclamation mark - Fri Mar 2 09:30:28 2007
NaCl+KNO3= NaCl+AgNO3= Na2CO3+HCL= BaCl2+H2SO4= NH4OH+H2SO4= CuSO4+Zn(NO3)2= Na2CO3+CaCl2= CuSO4+NHCl2=
Q. NaOH+HNO3= FeCl3+NH4OH= Na2SO3+HCl= These are double displacement reactions. I do not understand how to do these. Please explain this to me!
Asked by chem gal - Mon Oct 2 15:28:18 2006 - - 1 Answers - 1 Comments
A. Double displacement reactions basically have the metals of a compound (or the organic anion such as NH3+) to do a switch. You just need to make sure you have the correct number according to their valence. e.g. Na+, Mg++ etc. The first ones are easy because they all are 1+ (Na, H, Ag) NaCl+KNO3 KCl + NaNO3 NaCl+AgNO3 AgCl + Na NO3 Na2CO3+HCL H2CO3 + NaCl Here Ba is 2+ and H is 1+, so you have to balance the equation to make sure the same number of atoms as reactants are also in the products. BaCl2+H2SO4 = BaCl2+H2SO4 BaSO4 + 2HCl 2(NH4OH)+H2SO4 2(HOH) + NH4SO4 (note HOH is also H2O) so 2(H2O) + NH4SO4 CuSO4+Zn(NO3)2 ZnSO4 + Cu(NO3)2 Na2CO3+CaCl2 2NaCl + CaCO3 CuSO4+NHCl2 NHSO4 + CuCl2 NaOH+HNO3 H2O + NaNO3 FeCl3+3 [cont.]
Answered by borscht - Mon Oct 2 17:51:58 2006
Q. NaOH+HNO3= FeCl3+NH4OH= Na2SO3+HCl= These are double displacement reactions. I do not understand how to do these. Please explain this to me!
Asked by chem gal - Mon Oct 2 15:28:18 2006 - - 1 Answers - 1 Comments
A. Double displacement reactions basically have the metals of a compound (or the organic anion such as NH3+) to do a switch. You just need to make sure you have the correct number according to their valence. e.g. Na+, Mg++ etc. The first ones are easy because they all are 1+ (Na, H, Ag) NaCl+KNO3 KCl + NaNO3 NaCl+AgNO3 AgCl + Na NO3 Na2CO3+HCL H2CO3 + NaCl Here Ba is 2+ and H is 1+, so you have to balance the equation to make sure the same number of atoms as reactants are also in the products. BaCl2+H2SO4 = BaCl2+H2SO4 BaSO4 + 2HCl 2(NH4OH)+H2SO4 2(HOH) + NH4SO4 (note HOH is also H2O) so 2(H2O) + NH4SO4 CuSO4+Zn(NO3)2 ZnSO4 + Cu(NO3)2 Na2CO3+CaCl2 2NaCl + CaCO3 CuSO4+NHCl2 NHSO4 + CuCl2 NaOH+HNO3 H2O + NaNO3 FeCl3+3 [cont.]
Answered by borscht - Mon Oct 2 17:51:58 2006
How do I identify unknown solutions?
Q. How do I identify unknown solutions? Identifying Unknown Solutions You will be provided with 4 solutions labelled with a letter only. The solutions can be any of the following: Copper sulphate CuSO4, Soduim cloried NaCl, Soduim nitrate NaNO3, Soduim sulphate Na2SO4 You have the following chemicals to do your test: Silver nitrate solution Barium chloride solution Can you please give me a method to identify the unknown solutions.
Asked by Stefan - Mon Oct 27 17:07:14 2008 - - 1 Answers - 0 Comments
A. looking at it,... will ID Copper sulphate CuSO4 , it will be blue adding AgNO3,... will ID NaCl , it will give a white ppt adding BaSO4... will ID Na2SO4,... it will give a white ppt...(assuming that the solution was not blue) if it was not blue, & no reaction happened with AgNO3 or BaCl2, it ID's NaNO3 by default
Answered by Steve O - Mon Oct 27 18:10:53 2008
Q. How do I identify unknown solutions? Identifying Unknown Solutions You will be provided with 4 solutions labelled with a letter only. The solutions can be any of the following: Copper sulphate CuSO4, Soduim cloried NaCl, Soduim nitrate NaNO3, Soduim sulphate Na2SO4 You have the following chemicals to do your test: Silver nitrate solution Barium chloride solution Can you please give me a method to identify the unknown solutions.
Asked by Stefan - Mon Oct 27 17:07:14 2008 - - 1 Answers - 0 Comments
A. looking at it,... will ID Copper sulphate CuSO4 , it will be blue adding AgNO3,... will ID NaCl , it will give a white ppt adding BaSO4... will ID Na2SO4,... it will give a white ppt...(assuming that the solution was not blue) if it was not blue, & no reaction happened with AgNO3 or BaCl2, it ID's NaNO3 by default
Answered by Steve O - Mon Oct 27 18:10:53 2008
Is burning a candle a physical or chemical reaction. Also dissolving NaCl, mixing NaCl and AgNO3?
Q. Also, tearing Mg ribbon, adding HCl to Mg, grinding CuSO4 + 5H20, heating CuSO4 + 5H20, and mixing NaHCO3 + vinegar
Asked by jboxman7 - Tue Sep 26 16:49:49 2006 - - 2 Answers - 0 Comments
A. The wax that actually burns is a chemical reaction (rapid oxidation). Some wax simply melts and drips down the candle. That's a physical change. Tearing, grinding, heating, and dissolving are physical changes. HCl+Mg, NaHCO2+vinegar, and NaCl+AgNO3 are chemical reactions.
Answered by PaulCyp - Tue Sep 26 17:57:46 2006
Q. Also, tearing Mg ribbon, adding HCl to Mg, grinding CuSO4 + 5H20, heating CuSO4 + 5H20, and mixing NaHCO3 + vinegar
Asked by jboxman7 - Tue Sep 26 16:49:49 2006 - - 2 Answers - 0 Comments
A. The wax that actually burns is a chemical reaction (rapid oxidation). Some wax simply melts and drips down the candle. That's a physical change. Tearing, grinding, heating, and dissolving are physical changes. HCl+Mg, NaHCO2+vinegar, and NaCl+AgNO3 are chemical reactions.
Answered by PaulCyp - Tue Sep 26 17:57:46 2006
which of these compounds dissociate in water and which compounds ionize in water?
Q. sugar, NACl, KNO3, CUSO4, HCl, Ethanol, Vinegar. What are the ions that are in the solutions.
Asked by someone - Mon Oct 12 08:45:55 2009 - - 1 Answers - 0 Comments
A. dissociation-NaCl,KNO3,Cu SO4,HCl, ionisation-sugar,ethanol, vinegar (in fact most organic compounds).
Answered by Sagar - Mon Oct 12 09:14:51 2009
Q. sugar, NACl, KNO3, CUSO4, HCl, Ethanol, Vinegar. What are the ions that are in the solutions.
Asked by someone - Mon Oct 12 08:45:55 2009 - - 1 Answers - 0 Comments
A. dissociation-NaCl,KNO3,Cu SO4,HCl, ionisation-sugar,ethanol, vinegar (in fact most organic compounds).
Answered by Sagar - Mon Oct 12 09:14:51 2009
A student finds two unlabeled flasks of clear liquids. One is believed to be 0.1 M NaCl and the other to be 0.?
Q. -Add CuSO4 solution to each, CuCl2 will precipitate from NaCl -cannot easily tell the difference -Add CaSO4 solution to each, Ca(ClO3)2 will precipitate from NaClO3 -Add CuSO4 solution to each, Cu(ClO3)2 will precipitate from NaClO3 -Add AgNO3 solution to each, AgCl will precipitate from NaCl -Add CaSO4 solution to each, CaCl2 will precipitate from NaCl -Add AgNO3 solution to each, NaNO3 will precipitate from NaClO3
Asked by mb - Thu Sep 24 16:06:02 2009 - - 1 Answers - 0 Comments
Q. -Add CuSO4 solution to each, CuCl2 will precipitate from NaCl -cannot easily tell the difference -Add CaSO4 solution to each, Ca(ClO3)2 will precipitate from NaClO3 -Add CuSO4 solution to each, Cu(ClO3)2 will precipitate from NaClO3 -Add AgNO3 solution to each, AgCl will precipitate from NaCl -Add CaSO4 solution to each, CaCl2 will precipitate from NaCl -Add AgNO3 solution to each, NaNO3 will precipitate from NaClO3
Asked by mb - Thu Sep 24 16:06:02 2009 - - 1 Answers - 0 Comments
Determine the number of grams in each of the quantities?
Q. 2.5 moles of NaCl 3.2 moles of CuSO4 x5H2O Please show work otherwise I dont understand! thanks!
Asked by Alyssia S - Wed Oct 11 23:29:48 2006 - - 1 Answers - 0 Comments
A. What is the mass of NaCl? whatever the mass of NaCl is, it is the mass of 1 mole of it. Then multiply it by 2.5 Na = 23 and Cl = 35 23 +35 = 58gr 58 X 2.5 = 145gr now you do the second one.
Answered by smarties - Wed Oct 11 23:36:59 2006
Q. 2.5 moles of NaCl 3.2 moles of CuSO4 x5H2O Please show work otherwise I dont understand! thanks!
Asked by Alyssia S - Wed Oct 11 23:29:48 2006 - - 1 Answers - 0 Comments
A. What is the mass of NaCl? whatever the mass of NaCl is, it is the mass of 1 mole of it. Then multiply it by 2.5 Na = 23 and Cl = 35 23 +35 = 58gr 58 X 2.5 = 145gr now you do the second one.
Answered by smarties - Wed Oct 11 23:36:59 2006
There are two unlabeled jars of white, solid substances. What are the quick means of telling them apart?
Q. One of the jars contains K2SO4 and the other, BaSO4. What is a a way of telling them apart? -can't easily tell the difference -Add water to each solid, K2SO4 is insoluble and BaSO4 is soluble -Add water to each solid, K2SO4 is soluble and BaSO4 is insoluble -Add NaCl to each, BaCl2 will precipitate from BaSO4 -Add LiNO3 to each, Ba(NO3)2 will precipitate from BaSO4 -Add LiNO3 to each, KNO3 will precipitate from K2SO4 -Add NaCl to each, KCl will precipitate from K2SO4 There are two unlabeled flasks of clear liquids. One is 0.1 M NaCl and the other is 0.1 M NaClO3. What is a way of determing what is in each flask? -Add AgNO3 to each, NaNO3 will precipitate from NaClO3 -Add CaSO4 to each, CaCl2 will precipitate from NaCl -Add CuSO4 to each, [cont.]
Asked by jc - Fri Sep 29 23:25:15 2006 - - 4 Answers - 0 Comments
A. The difference in K2SO4 and BaSO4 is their solubility in water. K2SO4 is soluble in water but BaSO4 is not. Also note that soluble salts will not precipitate out in solution, as in your suggestions in adding NaCl or LiNO3. So adding those will not result in any visible change I am not sure about the second question. However a good way is to add a reducing agent (e.g. potassium iodide, KI) to both solutions. (NaClO3 is a strong oxidizing agent). NaClO3 will yield a brown solution as ClO3- will oxidize the iodide ions to iodine. There will be no visible change for NaCl as it cannot oxidize iodide ions.
Answered by cleo - Sat Sep 30 01:00:13 2006
Q. One of the jars contains K2SO4 and the other, BaSO4. What is a a way of telling them apart? -can't easily tell the difference -Add water to each solid, K2SO4 is insoluble and BaSO4 is soluble -Add water to each solid, K2SO4 is soluble and BaSO4 is insoluble -Add NaCl to each, BaCl2 will precipitate from BaSO4 -Add LiNO3 to each, Ba(NO3)2 will precipitate from BaSO4 -Add LiNO3 to each, KNO3 will precipitate from K2SO4 -Add NaCl to each, KCl will precipitate from K2SO4 There are two unlabeled flasks of clear liquids. One is 0.1 M NaCl and the other is 0.1 M NaClO3. What is a way of determing what is in each flask? -Add AgNO3 to each, NaNO3 will precipitate from NaClO3 -Add CaSO4 to each, CaCl2 will precipitate from NaCl -Add CuSO4 to each, [cont.]
Asked by jc - Fri Sep 29 23:25:15 2006 - - 4 Answers - 0 Comments
A. The difference in K2SO4 and BaSO4 is their solubility in water. K2SO4 is soluble in water but BaSO4 is not. Also note that soluble salts will not precipitate out in solution, as in your suggestions in adding NaCl or LiNO3. So adding those will not result in any visible change I am not sure about the second question. However a good way is to add a reducing agent (e.g. potassium iodide, KI) to both solutions. (NaClO3 is a strong oxidizing agent). NaClO3 will yield a brown solution as ClO3- will oxidize the iodide ions to iodine. There will be no visible change for NaCl as it cannot oxidize iodide ions.
Answered by cleo - Sat Sep 30 01:00:13 2006
Can someone help me solve these double displacement reactions?
Q. NaCl+KNO3 --> NaCl+AgNO3--> Na2CO3+HCl--> NaOH+HCl--> BaCl2+H2SO4--> NH4OH+H2SO4--> CuSO4+NH4Cl--> Na2CO3+CaCl2--> CuSO4+NH4Cl--> NaOH+HNO3--> FeCl3+NH4OH--> Na2SO3+HCl-->
Asked by jessica h - Mon Mar 10 02:36:30 2008 - - 1 Answers - 0 Comments
A. 1)Na NO3+KCl 2)NaNO3+AgCl 4)NaCl+H2O 5)BaSO4+2HCl 6)(NH4)2SO4+H2O 7)(NH4)2SO4+Cu2Cl2 8)NaCl+CaCO3
Answered by RINU - Mon Mar 10 05:27:47 2008
Q. NaCl+KNO3 --> NaCl+AgNO3--> Na2CO3+HCl--> NaOH+HCl--> BaCl2+H2SO4--> NH4OH+H2SO4--> CuSO4+NH4Cl--> Na2CO3+CaCl2--> CuSO4+NH4Cl--> NaOH+HNO3--> FeCl3+NH4OH--> Na2SO3+HCl-->
Asked by jessica h - Mon Mar 10 02:36:30 2008 - - 1 Answers - 0 Comments
A. 1)Na NO3+KCl 2)NaNO3+AgCl 4)NaCl+H2O 5)BaSO4+2HCl 6)(NH4)2SO4+H2O 7)(NH4)2SO4+Cu2Cl2 8)NaCl+CaCO3
Answered by RINU - Mon Mar 10 05:27:47 2008
How do you determine if a bond is ionic or covalent?
Q. e.g. NaCl (sodium chloride) CuSO4 (copper II sulfate)
Asked by pat m - Sun Nov 23 21:17:23 2008 - - 3 Answers - 0 Comments
A. an ionic bond occurs between a metal and a non metal and a covalent bond occurs between two nonmetals. the two compounds have ionic bonding
Answered by @YD@y - Sun Nov 23 21:20:54 2008
Q. e.g. NaCl (sodium chloride) CuSO4 (copper II sulfate)
Asked by pat m - Sun Nov 23 21:17:23 2008 - - 3 Answers - 0 Comments
A. an ionic bond occurs between a metal and a non metal and a covalent bond occurs between two nonmetals. the two compounds have ionic bonding
Answered by @YD@y - Sun Nov 23 21:20:54 2008
Balancing and writing chemical equations??
Q. I need the English translation of the equation too!!! CuSO4 + NaCl= CuSO4+NaOH= CuSO4+Na3PO4= AgNO3+NaCl= AgNO3+NaOH= AgNO3+Na3PO4= MgSO4+NaCl= MgSO4+NaOH= MgSO4+Pb(NO3)2= Pb(NO3)2+Na3PO4= Pb(NO3)2+NaOH= Pb(NO3)2+CuSO4= Oh and by the way, they are all (aq) Please include physical state symbols for the reactants and products!!! I'm not just getting the answers, I'm checking and I don't get how to write the equation in english...
Asked by So, Awesome!!!! - Thu Nov 13 19:37:25 2008 - - 1 Answers - 0 Comments
A. Perhaps you should try learning on your own or ask a teacher for help instead of just getting answers. It will certainly be more beneficial later in the year! I'll start you off, though. You need to know the charges on each ion. All of the stuff in this list of equations or ionic compounds, so there's a cation and an anion. For example, CuSO4 is made up of (Cu)2+ and (SO4)2- When balancing the equation, you want the overall charge to be 0.
Answered by samswebsite - Thu Nov 13 19:46:04 2008
Q. I need the English translation of the equation too!!! CuSO4 + NaCl= CuSO4+NaOH= CuSO4+Na3PO4= AgNO3+NaCl= AgNO3+NaOH= AgNO3+Na3PO4= MgSO4+NaCl= MgSO4+NaOH= MgSO4+Pb(NO3)2= Pb(NO3)2+Na3PO4= Pb(NO3)2+NaOH= Pb(NO3)2+CuSO4= Oh and by the way, they are all (aq) Please include physical state symbols for the reactants and products!!! I'm not just getting the answers, I'm checking and I don't get how to write the equation in english...
Asked by So, Awesome!!!! - Thu Nov 13 19:37:25 2008 - - 1 Answers - 0 Comments
A. Perhaps you should try learning on your own or ask a teacher for help instead of just getting answers. It will certainly be more beneficial later in the year! I'll start you off, though. You need to know the charges on each ion. All of the stuff in this list of equations or ionic compounds, so there's a cation and an anion. For example, CuSO4 is made up of (Cu)2+ and (SO4)2- When balancing the equation, you want the overall charge to be 0.
Answered by samswebsite - Thu Nov 13 19:46:04 2008
CuSO4 help! please!!!!!?
Q. with this bank, which make a blue precipitate I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH with this bank, which make a blue precipitate reacting with CuSO4 I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH with this bank, which make a blue precipitate reacting with CuSO4 I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH
Asked by jim.bore - Thu Dec 18 21:38:42 2008 - - 1 Answers - 0 Comments
A. Na3PO4 will form a blue precipitate of copper (II) phosphate. None of the other will form a precipitate, except NaOH, which will form a white precipitate of copper (II) hydroxide.
Answered by Robinson Cruz - Fri Dec 19 07:58:53 2008
Q. with this bank, which make a blue precipitate I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH with this bank, which make a blue precipitate reacting with CuSO4 I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH with this bank, which make a blue precipitate reacting with CuSO4 I dont need the top 2 answered if you dont have enough time! Ba(NO3)2 Pb(NO3)2 MnSO4 KI Na3PO4 NaCl NaOH
Asked by jim.bore - Thu Dec 18 21:38:42 2008 - - 1 Answers - 0 Comments
A. Na3PO4 will form a blue precipitate of copper (II) phosphate. None of the other will form a precipitate, except NaOH, which will form a white precipitate of copper (II) hydroxide.
Answered by Robinson Cruz - Fri Dec 19 07:58:53 2008
How do you solve these science Q.'s?
Q. 1. HCL+Na25 yeilds H2S+ NaCl? 2. Al + CuSO4 yeilds Al2(SO4)3 + Cu? 3. Fe + 02 yeilds Fe203?
Asked by pinkpanther014 - Tue Dec 12 23:38:23 2006 - - 2 Answers - 0 Comments
A. the first one is wrong... It should be HCL + Na2S and not 5 2HCl + Na2S --> H2S + 2NaCl 2Al + 3CuSO4 --> Al2(SO4)3 +3Cu 4Fe + 3O2 --> 2Fe2O3 It's been a while, so I'm not so sure if these are right...
Answered by ytmaya - Wed Dec 13 10:33:43 2006
Q. 1. HCL+Na25 yeilds H2S+ NaCl? 2. Al + CuSO4 yeilds Al2(SO4)3 + Cu? 3. Fe + 02 yeilds Fe203?
Asked by pinkpanther014 - Tue Dec 12 23:38:23 2006 - - 2 Answers - 0 Comments
A. the first one is wrong... It should be HCL + Na2S and not 5 2HCl + Na2S --> H2S + 2NaCl 2Al + 3CuSO4 --> Al2(SO4)3 +3Cu 4Fe + 3O2 --> 2Fe2O3 It's been a while, so I'm not so sure if these are right...
Answered by ytmaya - Wed Dec 13 10:33:43 2006
help balancing chemical equations?
Q. i need help balancing these: (thank you to anyone!!! ) HCl + Mg --> H2 + MgCl2 FeS + HCl --> H2S + FeCl2 BaCl2 + Na2CrO4 --> BaCrO4 + NaCl BaCl2 + Na2SO4 --> BaSO4 + NaCl CuSO4 + NH4OH --> {[Cu(NH3)4] SO4} and, also, in each equation, did an oxidation-reduction occur? which was oxidized and which was reduced?? i'm having hard troubles with that
Asked by kay - Mon Mar 3 18:32:11 2008 - - 2 Answers - 0 Comments
A. (1) 2HCl+Mg = H2+MgCl2 (2)Fes+2HCl=H2S+FeCl2 3. BaCl2+Na2CrO4=BaCrO4+2NaC l 4. The same as three I'm not sure what all the () in 5 are, or about the oxidation reductions, sorry.
Answered by Maggie - Mon Mar 3 18:54:54 2008
Q. i need help balancing these: (thank you to anyone!!! ) HCl + Mg --> H2 + MgCl2 FeS + HCl --> H2S + FeCl2 BaCl2 + Na2CrO4 --> BaCrO4 + NaCl BaCl2 + Na2SO4 --> BaSO4 + NaCl CuSO4 + NH4OH --> {[Cu(NH3)4] SO4} and, also, in each equation, did an oxidation-reduction occur? which was oxidized and which was reduced?? i'm having hard troubles with that
Asked by kay - Mon Mar 3 18:32:11 2008 - - 2 Answers - 0 Comments
A. (1) 2HCl+Mg = H2+MgCl2 (2)Fes+2HCl=H2S+FeCl2 3. BaCl2+Na2CrO4=BaCrO4+2NaC l 4. The same as three I'm not sure what all the () in 5 are, or about the oxidation reductions, sorry.
Answered by Maggie - Mon Mar 3 18:54:54 2008
is there any site for flame colors on molecules?
Q. such as glucose, water, NaCl, KOH, ect... if not, can someone help me how to determine their color?? --- For those who knows these color, can you answer? H2SO4 (sulfuric acid) KOH (potassium hydroxide) AgNO3 (silver (1) nitrate) Sr(NO3)2 (strontium nitrate) CH3 COOH (acetate) NaOH (sodium hydroxide) HCl (hydrochloric acid) H2O (water) NaCl (sodium chloride) CuSO4 (copper (||) sulfate) C6H12O6 (glucose)
Asked by gogogo - Mon Oct 30 19:05:49 2006 - - 1 Answers - 0 Comments
A. It is mainly metals that produce colors in flame tests. So, compounds like glucose, and water aren't going to produce any color if the test is done right. I Googled "flame test" and found this site which has the colors and the spectra of the flame tests on a whole lot of different metal and metal ion containing things:
Answered by hcbiochem - Mon Oct 30 19:17:07 2006
Q. such as glucose, water, NaCl, KOH, ect... if not, can someone help me how to determine their color?? --- For those who knows these color, can you answer? H2SO4 (sulfuric acid) KOH (potassium hydroxide) AgNO3 (silver (1) nitrate) Sr(NO3)2 (strontium nitrate) CH3 COOH (acetate) NaOH (sodium hydroxide) HCl (hydrochloric acid) H2O (water) NaCl (sodium chloride) CuSO4 (copper (||) sulfate) C6H12O6 (glucose)
Asked by gogogo - Mon Oct 30 19:05:49 2006 - - 1 Answers - 0 Comments
A. It is mainly metals that produce colors in flame tests. So, compounds like glucose, and water aren't going to produce any color if the test is done right. I Googled "flame test" and found this site which has the colors and the spectra of the flame tests on a whole lot of different metal and metal ion containing things:
Answered by hcbiochem - Mon Oct 30 19:17:07 2006
Qualitative Analysis question?
Q. Is there a machine that could determine the chemicals in a substance so that you could forego qualitative tests? ie putting in a sample of chemical and the machine tells you that it contains NaCl and CuSO4...
Asked by Blitzed & Bombed - Thu May 28 18:30:41 2009 - - 1 Answers - 0 Comments
A. Yes, that would be spectroscopy. see
Answered by Exiled - Thu May 28 18:39:20 2009
Q. Is there a machine that could determine the chemicals in a substance so that you could forego qualitative tests? ie putting in a sample of chemical and the machine tells you that it contains NaCl and CuSO4...
Asked by Blitzed & Bombed - Thu May 28 18:30:41 2009 - - 1 Answers - 0 Comments
A. Yes, that would be spectroscopy. see
Answered by Exiled - Thu May 28 18:39:20 2009
In which case would the least number of faradays of electricity be required for the liberation of 1.0 g?
Q. 1.0 g of free metal? K 39.1 g per mol, Na 23.0 Cu 63.5 Ag 107.9 a) k from molten KOH b) Na from molten NaCl c) Cu from aqueous CuSO4 d) Ag from aqueous AgNO3 I need detailed explannation as well. Thank you
Asked by song.park69 - Wed Jul 30 01:29:44 2008 - - 1 Answers - 0 Comments
A. d) Ag because it is monovalent (+1) and has a high atomic weight (grams per mole and therefore grams per faraday.
Answered by Leo H - Wed Jul 30 02:27:11 2008
Q. 1.0 g of free metal? K 39.1 g per mol, Na 23.0 Cu 63.5 Ag 107.9 a) k from molten KOH b) Na from molten NaCl c) Cu from aqueous CuSO4 d) Ag from aqueous AgNO3 I need detailed explannation as well. Thank you
Asked by song.park69 - Wed Jul 30 01:29:44 2008 - - 1 Answers - 0 Comments
A. d) Ag because it is monovalent (+1) and has a high atomic weight (grams per mole and therefore grams per faraday.
Answered by Leo H - Wed Jul 30 02:27:11 2008
i need to know the Reaction Types and why those are the types.?
Q. Reaction choice 2Fe + O2 ---> 2FeO Ca (OH)2 + 2HCl --> CaCl2 + 2HOH Fe + CuSO4 --> FeSO4 + Cu 2 H2O2 --> 2H2O + O2 4Cr + 3SnCl4 --> 4CrCl3 + 3Sn C4H8 + 6O2 ---> 4CO2 + 4H2O HCl + NaOH ---> H2O + NaCl 2KNO3(s) ---> 2KNO2(s) + O2(g) AgNO3 + NaCl ---> NaNO3 + AgCl 2Mg + O2 ---> 2MgO 2Ag + S ---> Ag2S MgCO3(s) ---> MgO(s) + CO2(g) Cl2 + 2KBr ---> 2KCl + Br2 i need to know the Reaction Types and why those are the types.
Asked by kumquat - Thu Feb 1 13:38:36 2007 - - 0 Answers - 0 Comments
A. 1) 2Fe + O2 --> 2FeO 2) C4H4 + O4 --> 4CO2 + 4H2O 3) 2Mg + O2 --> 2MgO 4) 2Ag + S --> Ag2S These are all oxidation reactions (adding oygen ( or sulfur in the same period of the periodic table as oxygen it's properties are similar to oxygen). Reaction 4 is tanishing of silver. Reaction 2 is a special oxidation called combustion. 5) Ca(OH)2 + 2HCl --> CaCl2 + 2 H2O 6) HCl + NaOH --> H2O + NaCl 7) AgNO3 + NaCl --> NaNO3 + AgCl These are simple ion exchage reactions. Reaction 6 is a special case of an acid base reaction - but the pricnciple is the same. 8) Fe + CuSO4 --> FeSO4 + Cu 9) 4Cr + 3SnCl4 --> 4CrCl3 + 3Sn These are oxidation reduction reactions. You will find reagenton one side of the reaction are reduced while the correcpding… [cont.]
Answered by Dr Dave P - Thu Feb 1 14:10:07 2007
Q. Reaction choice 2Fe + O2 ---> 2FeO Ca (OH)2 + 2HCl --> CaCl2 + 2HOH Fe + CuSO4 --> FeSO4 + Cu 2 H2O2 --> 2H2O + O2 4Cr + 3SnCl4 --> 4CrCl3 + 3Sn C4H8 + 6O2 ---> 4CO2 + 4H2O HCl + NaOH ---> H2O + NaCl 2KNO3(s) ---> 2KNO2(s) + O2(g) AgNO3 + NaCl ---> NaNO3 + AgCl 2Mg + O2 ---> 2MgO 2Ag + S ---> Ag2S MgCO3(s) ---> MgO(s) + CO2(g) Cl2 + 2KBr ---> 2KCl + Br2 i need to know the Reaction Types and why those are the types.
Asked by kumquat - Thu Feb 1 13:38:36 2007 - - 0 Answers - 0 Comments
A. 1) 2Fe + O2 --> 2FeO 2) C4H4 + O4 --> 4CO2 + 4H2O 3) 2Mg + O2 --> 2MgO 4) 2Ag + S --> Ag2S These are all oxidation reactions (adding oygen ( or sulfur in the same period of the periodic table as oxygen it's properties are similar to oxygen). Reaction 4 is tanishing of silver. Reaction 2 is a special oxidation called combustion. 5) Ca(OH)2 + 2HCl --> CaCl2 + 2 H2O 6) HCl + NaOH --> H2O + NaCl 7) AgNO3 + NaCl --> NaNO3 + AgCl These are simple ion exchage reactions. Reaction 6 is a special case of an acid base reaction - but the pricnciple is the same. 8) Fe + CuSO4 --> FeSO4 + Cu 9) 4Cr + 3SnCl4 --> 4CrCl3 + 3Sn These are oxidation reduction reactions. You will find reagenton one side of the reaction are reduced while the correcpding… [cont.]
Answered by Dr Dave P - Thu Feb 1 14:10:07 2007
From Yahoo Answer Search: 'CuSO4 with NaCl'
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