How can Electromagnetic Radiation travel without a medium?
Q. If Electromagnetic Radiation can travel through the vacuum of space then it can travel without a medium, but shouldn't this be imposable? Or is it true that Electromagnetic Radiation uses the medium of existing magnetic fields, such as earths, distorting these fields much like sound waves do to air? And if so how can this have a direction of travel?
Asked by Resist - Mon Dec 1 18:14:32 2008 - - 4 Answers - 1 Comments
A. Electromagnetic waves travel through a vacuum and any other physical medium slows or stops their progression. They do not use existing magnetic fields as a medium, though they do interact with them. An electromagnetic wave is nothing more than an a propagation of a changing electric and magnetic field. these fields are always perpendicular to each other and travel in the direction of E x B, where E and B are vectors indicating the direction of these fields. Its because these are electric and magnetic fields. These fields are just regions where forces are exerted on charged particles, they are not made of particles themselves in the same way that sound waves are made from air molecules.
Answered by tbencreighton - Mon Dec 1 18:32:32 2008
Q. If Electromagnetic Radiation can travel through the vacuum of space then it can travel without a medium, but shouldn't this be imposable? Or is it true that Electromagnetic Radiation uses the medium of existing magnetic fields, such as earths, distorting these fields much like sound waves do to air? And if so how can this have a direction of travel?
Asked by Resist - Mon Dec 1 18:14:32 2008 - - 4 Answers - 1 Comments
A. Electromagnetic waves travel through a vacuum and any other physical medium slows or stops their progression. They do not use existing magnetic fields as a medium, though they do interact with them. An electromagnetic wave is nothing more than an a propagation of a changing electric and magnetic field. these fields are always perpendicular to each other and travel in the direction of E x B, where E and B are vectors indicating the direction of these fields. Its because these are electric and magnetic fields. These fields are just regions where forces are exerted on charged particles, they are not made of particles themselves in the same way that sound waves are made from air molecules.
Answered by tbencreighton - Mon Dec 1 18:32:32 2008
What characteristic of electromagnetic radiation determines how it is reflected by a particular substance?
Q. Full question: What characteristic of electromagnetic radiation determines how it is reflected, transmitted or absorbed by a particular substance? Muchas Gracias/ Thanks!
Asked by Lauren [Delays] - Tue Sep 8 12:55:42 2009 - - 3 Answers - 1 Comments
A. it is actually not the characteristics of the radiation. It the the property of the substance only. like black object absorbs every radiations
Answered by sainis - Tue Sep 8 13:03:14 2009
Q. Full question: What characteristic of electromagnetic radiation determines how it is reflected, transmitted or absorbed by a particular substance? Muchas Gracias/ Thanks!
Asked by Lauren [Delays] - Tue Sep 8 12:55:42 2009 - - 3 Answers - 1 Comments
A. it is actually not the characteristics of the radiation. It the the property of the substance only. like black object absorbs every radiations
Answered by sainis - Tue Sep 8 13:03:14 2009
What type of electromagnetic radiation does the atmosphere NOT screen for us?
Q. Our atmosphere shields us from many harmful forms of radiation from space. Which of the following forms of electromagnetic radiation is NOT screened from us by the atmosphere? A. 20 cm radio waves B. mm-microwaves C. ultraviolet radiation D. gamma rays E. x-rays I thought it was gamma rays but I do remember hearing somewhere that the atmosphere does protect us from them
Asked by Blue R - Sun Nov 15 21:41:15 2009 - - 2 Answers - 0 Comments
Q. Our atmosphere shields us from many harmful forms of radiation from space. Which of the following forms of electromagnetic radiation is NOT screened from us by the atmosphere? A. 20 cm radio waves B. mm-microwaves C. ultraviolet radiation D. gamma rays E. x-rays I thought it was gamma rays but I do remember hearing somewhere that the atmosphere does protect us from them
Asked by Blue R - Sun Nov 15 21:41:15 2009 - - 2 Answers - 0 Comments
When electromagnetic radiation is absorbed why does its energy heat up the substance which absorbs it?
Q. I'm doing my physics GCSE and this is one of the things that came up in a past paper. Could you please explain this to me? It also has something about the ebsorbtion of the electromagnetic radiation creating an alternate current in a wire?? Thank you
Asked by Katie W - Sun Mar 1 11:56:32 2009 - - 2 Answers - 0 Comments
A. electromagnetic radiation is converted to heat energy when it's absorbed because electromagnetic radiation causes the atoms to vibrate. it's similar to how wind makes a tree vibrate, only electromagnetic waves vibrate much much much faster. oo, i'm just now reading the second part of your question. yeh, an alternating current is the reason. alternating current constantly switches it's polarity billions of times per second. therefore, when a polar object is subjected to AC, it's going to try to make itself aligned with the radiation. however, since the radiation is constantly switching polarity, the object will be spinning.
Answered by anoman5000 - Sun Mar 1 12:05:34 2009
Q. I'm doing my physics GCSE and this is one of the things that came up in a past paper. Could you please explain this to me? It also has something about the ebsorbtion of the electromagnetic radiation creating an alternate current in a wire?? Thank you
Asked by Katie W - Sun Mar 1 11:56:32 2009 - - 2 Answers - 0 Comments
A. electromagnetic radiation is converted to heat energy when it's absorbed because electromagnetic radiation causes the atoms to vibrate. it's similar to how wind makes a tree vibrate, only electromagnetic waves vibrate much much much faster. oo, i'm just now reading the second part of your question. yeh, an alternating current is the reason. alternating current constantly switches it's polarity billions of times per second. therefore, when a polar object is subjected to AC, it's going to try to make itself aligned with the radiation. however, since the radiation is constantly switching polarity, the object will be spinning.
Answered by anoman5000 - Sun Mar 1 12:05:34 2009
Wavelength of electromagnetic radiation required to excite an electron?
Q. Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with n = 5 in a one-dimensional box 49.0 pm in length. I'm not sure how to start this one, any help?
Asked by Evnot - Fri Nov 14 22:37:25 2008 - - 1 Answers - 0 Comments
A. E = (h^2)*(n^2)/8mL^2 E5 = [(6.62618*10^-34 j-s)^2]*(5^2) / 8*(9.109*10^-31 kg)*[(49*10^-12)^2) this would be correct if the ground state is n=0, if it is n=1 subtract this by E1 calculated the same way. then E = E5 -E1 then just plug E into this equation: wavelength = hc/E h = 6.62618*10^-34 j-s c = 3*10^8 m/s wavelength in meters not 100% sure
Answered by Martin M - Fri Nov 14 23:00:52 2008
Q. Calculate the wavelength of the electromagnetic radiation required to excite an electron from the ground state to the level with n = 5 in a one-dimensional box 49.0 pm in length. I'm not sure how to start this one, any help?
Asked by Evnot - Fri Nov 14 22:37:25 2008 - - 1 Answers - 0 Comments
A. E = (h^2)*(n^2)/8mL^2 E5 = [(6.62618*10^-34 j-s)^2]*(5^2) / 8*(9.109*10^-31 kg)*[(49*10^-12)^2) this would be correct if the ground state is n=0, if it is n=1 subtract this by E1 calculated the same way. then E = E5 -E1 then just plug E into this equation: wavelength = hc/E h = 6.62618*10^-34 j-s c = 3*10^8 m/s wavelength in meters not 100% sure
Answered by Martin M - Fri Nov 14 23:00:52 2008
Is visible light considered a type of electromagnetic radiation?
Q. Is visible light considered a type of electromagnetic radiation like gamma rays, and infrared, and ultraviolet, or is it just certain wavelengths of these types of radiation that can be seen as visible light? Thanks.
Asked by mc_swirl_girl - Thu Nov 20 00:17:06 2008 - - 5 Answers - 1 Comments
A. Gamma is particulate, from uranium and not electromagnetic. Visible light is 'white' light, in that it is all the electromagnetic spectrum combined together. check it out
Answered by baghmom - Thu Nov 20 00:33:12 2008
Q. Is visible light considered a type of electromagnetic radiation like gamma rays, and infrared, and ultraviolet, or is it just certain wavelengths of these types of radiation that can be seen as visible light? Thanks.
Asked by mc_swirl_girl - Thu Nov 20 00:17:06 2008 - - 5 Answers - 1 Comments
A. Gamma is particulate, from uranium and not electromagnetic. Visible light is 'white' light, in that it is all the electromagnetic spectrum combined together. check it out
Answered by baghmom - Thu Nov 20 00:33:12 2008
What is the behaviour that supports the dual nature of electromagnetic radiation?
Q. Electromagnetic radiation (i.e. infra red and so on) have a wave-particle duality meaning it can behave as a wave or as a photon (that exhibits particle-like behaviour), I want to know the behaviour that they exhibit that supports this theory...can anyone help?
Asked by KaffyJay - Tue Mar 25 12:59:55 2008 - - 3 Answers - 0 Comments
A. Young's slit experiment: Photoelectric effect, slightly more complex. The principle behind the Photoelectric effect basically is that if light is a wave then the only factor which should affect the amount of electrons escaping the electrostatic attraction of the metal should be the amplitude (i.e. the amount of energy in the wave) but not the frequency of the wave- doesn t matter how many times you hit a lorry with a hammer, its never going to move. Also, if the light waves amplitude is too low, then you get no electrons escaping from the electrostatic force, because the waves won t transfer enough energy to liberate them themselves. But Planck s constant, which is referred to as h, and apparently h=6.626x10^(-34)Joules, showed… [cont.]
Answered by Owen G - Tue Mar 25 13:13:32 2008
Q. Electromagnetic radiation (i.e. infra red and so on) have a wave-particle duality meaning it can behave as a wave or as a photon (that exhibits particle-like behaviour), I want to know the behaviour that they exhibit that supports this theory...can anyone help?
Asked by KaffyJay - Tue Mar 25 12:59:55 2008 - - 3 Answers - 0 Comments
A. Young's slit experiment: Photoelectric effect, slightly more complex. The principle behind the Photoelectric effect basically is that if light is a wave then the only factor which should affect the amount of electrons escaping the electrostatic attraction of the metal should be the amplitude (i.e. the amount of energy in the wave) but not the frequency of the wave- doesn t matter how many times you hit a lorry with a hammer, its never going to move. Also, if the light waves amplitude is too low, then you get no electrons escaping from the electrostatic force, because the waves won t transfer enough energy to liberate them themselves. But Planck s constant, which is referred to as h, and apparently h=6.626x10^(-34)Joules, showed… [cont.]
Answered by Owen G - Tue Mar 25 13:13:32 2008
Does solar radiation contain a complete spectrum of all forms of electromagnetic radiation?
Q. Hey Everyone. I was just confused about this question in science: true or false: 1) Does solar radiation contain a complete spectrum of all forms of electromagnetic radiation?
Asked by MitchellDavis1393 - Wed May 27 19:48:07 2009 - - 2 Answers - 0 Comments
A. If by "complete" spectrum you mean continuous over some finite range, then the answer is false. The reason for this is that the materials of the star itself will absorb some of it's emission spectrum, essentially casting a "shadow" of a certain wavelength (or small portion of wavelengths) cf "line spectra". You may have done (or might yet do) an experiment with a sodium, hydrogen and/or mercury lamp to analyse the wavelengths emitted. Interestingly, a sodium lamp near a burning candle will cause a usually visible shadow of the candle, because some of the chemicals in the flame absorbs some of the emission from the sodium lamp - thus you have a flame casting a shadow (albeit a partial one). edit: "And how could it be possible the radio… [cont.]
Answered by Villhelm - Wed May 27 20:01:16 2009
Q. Hey Everyone. I was just confused about this question in science: true or false: 1) Does solar radiation contain a complete spectrum of all forms of electromagnetic radiation?
Asked by MitchellDavis1393 - Wed May 27 19:48:07 2009 - - 2 Answers - 0 Comments
A. If by "complete" spectrum you mean continuous over some finite range, then the answer is false. The reason for this is that the materials of the star itself will absorb some of it's emission spectrum, essentially casting a "shadow" of a certain wavelength (or small portion of wavelengths) cf "line spectra". You may have done (or might yet do) an experiment with a sodium, hydrogen and/or mercury lamp to analyse the wavelengths emitted. Interestingly, a sodium lamp near a burning candle will cause a usually visible shadow of the candle, because some of the chemicals in the flame absorbs some of the emission from the sodium lamp - thus you have a flame casting a shadow (albeit a partial one). edit: "And how could it be possible the radio… [cont.]
Answered by Villhelm - Wed May 27 20:01:16 2009
Can anyone help me solve this problem. What is the wavelength and teh type of electromagnetic radiation?
Q. A photon has an energy of 1.10 x 10 . What is the wavelength and the type of electromagnetic radiation ?
Asked by Jasmine Brown - Sun Oct 25 17:15:43 2009 - - 1 Answers - 0 Comments
A. E = h*c/(wavelength) wavelength = h*c/E = 6.63E-34 (J-s)* 3E8 (m/s) / 1.1E-13J wavelength(lambda) = 1.81E-12 m or 1.81 pm That falls on the upper range of X-rays. Xrays are 1nm-1pm and Gamma rays are less than 1 pm
Answered by unknown - Wed Oct 28 05:54:44 2009
Q. A photon has an energy of 1.10 x 10 . What is the wavelength and the type of electromagnetic radiation ?
Asked by Jasmine Brown - Sun Oct 25 17:15:43 2009 - - 1 Answers - 0 Comments
A. E = h*c/(wavelength) wavelength = h*c/E = 6.63E-34 (J-s)* 3E8 (m/s) / 1.1E-13J wavelength(lambda) = 1.81E-12 m or 1.81 pm That falls on the upper range of X-rays. Xrays are 1nm-1pm and Gamma rays are less than 1 pm
Answered by unknown - Wed Oct 28 05:54:44 2009
Wavelength of electromagnetic radiation from a hydrogen atom when electron undergoes transition n=5 to n=3?
Q. What is the wavelength of the electromagnetic radiation emitted from a hydrogen atom when the electron undergoes the transition n = 5 to n = 3? In what region of the spectrum does the line occur?
Asked by Punk Elvis - Sun Nov 23 22:17:03 2008 - - 2 Answers - 0 Comments
A. Use the Rydberg Equation: Answer: wavelength = 1283 nm, so it falls into the infrared range.
Answered by Smark - Sun Nov 23 22:25:36 2008
Q. What is the wavelength of the electromagnetic radiation emitted from a hydrogen atom when the electron undergoes the transition n = 5 to n = 3? In what region of the spectrum does the line occur?
Asked by Punk Elvis - Sun Nov 23 22:17:03 2008 - - 2 Answers - 0 Comments
A. Use the Rydberg Equation: Answer: wavelength = 1283 nm, so it falls into the infrared range.
Answered by Smark - Sun Nov 23 22:25:36 2008
Somebody help me calculate the wave length of the electromagnetic radiation produced?
Q. 0-1e + 0+1e 2 00 Assuming that both rays have the same energy, calculate the wavelength of the electromagnetic radiation produced.
Asked by =P - Fri Oct 24 22:24:08 2008 - - 1 Answers - 0 Comments
A. It's a little difficult to understand your question. Are you looking for the two photons produced when an electron and an anti-electron annihilate? Just off the top of my head, it's 511 keV each. But let's work it out anyway. The mass of the electron / anti-electron is 9.11 x 10^-31 kg. Using E = mc , the corresponding energy per electron is 8.2 x 10^-14 J = 511 keV. My PhD was in nuclear physics; all of our gamma-ray spectra had that annoying antimatter annihilation peak at 511 keV, and it almost always obscured something interesting.
Answered by jgoulden - Fri Oct 24 22:29:33 2008
Q. 0-1e + 0+1e 2 00 Assuming that both rays have the same energy, calculate the wavelength of the electromagnetic radiation produced.
Asked by =P - Fri Oct 24 22:24:08 2008 - - 1 Answers - 0 Comments
A. It's a little difficult to understand your question. Are you looking for the two photons produced when an electron and an anti-electron annihilate? Just off the top of my head, it's 511 keV each. But let's work it out anyway. The mass of the electron / anti-electron is 9.11 x 10^-31 kg. Using E = mc , the corresponding energy per electron is 8.2 x 10^-14 J = 511 keV. My PhD was in nuclear physics; all of our gamma-ray spectra had that annoying antimatter annihilation peak at 511 keV, and it almost always obscured something interesting.
Answered by jgoulden - Fri Oct 24 22:29:33 2008
Whats the longest wavelength of the electromagnetic radiation emitted by the H atom in a transition from n=6?
Q. full question: Calculate the longest wavelength of the electromagnetic radiation emitted by the hydrogen atom in undergoing a transition from the n = 6 level.
Asked by DGill28 - Tue Sep 15 23:40:33 2009 - - 2 Answers - 0 Comments
A. (n*n-1)/2 so we get (6 * 5)/2 =30/2 =15. 15 is the answer.
Answered by siddharth m - Wed Sep 16 00:01:36 2009
Q. full question: Calculate the longest wavelength of the electromagnetic radiation emitted by the hydrogen atom in undergoing a transition from the n = 6 level.
Asked by DGill28 - Tue Sep 15 23:40:33 2009 - - 2 Answers - 0 Comments
A. (n*n-1)/2 so we get (6 * 5)/2 =30/2 =15. 15 is the answer.
Answered by siddharth m - Wed Sep 16 00:01:36 2009
Is electromagnetic radiation composed of wave or particle, both, or neither?
Q. Is electromagnetic radiation composed of wave or particle, both, or neither?
Asked by Justin B - Sun Dec 14 14:15:43 2008 - - 5 Answers - 0 Comments
A. Both. This is called wave-particle duality.
Answered by Adam - Sun Dec 14 14:23:14 2008
Q. Is electromagnetic radiation composed of wave or particle, both, or neither?
Asked by Justin B - Sun Dec 14 14:15:43 2008 - - 5 Answers - 0 Comments
A. Both. This is called wave-particle duality.
Answered by Adam - Sun Dec 14 14:23:14 2008
How are the energy and frequency of electromagnetic radiation related. and How are the energy and wavelength..
Q. electromagnetic radiation related?
Asked by Blaine L - Sun Aug 19 12:32:13 2007 - - 2 Answers - 0 Comments
A. E = hv h is the Plank's constant ( = 6.63 x 10^-34 J s) v is the frequency of the wave lambda ( wawelenght ) is inverse proportional with the frequency lambda = propagation velocity of the wave / v v = propagation velocity of the wave / lambda E = h propagation velocity of the wave / lambda
Answered by Dr.A - Sun Aug 19 13:07:19 2007
Q. electromagnetic radiation related?
Asked by Blaine L - Sun Aug 19 12:32:13 2007 - - 2 Answers - 0 Comments
A. E = hv h is the Plank's constant ( = 6.63 x 10^-34 J s) v is the frequency of the wave lambda ( wawelenght ) is inverse proportional with the frequency lambda = propagation velocity of the wave / v v = propagation velocity of the wave / lambda E = h propagation velocity of the wave / lambda
Answered by Dr.A - Sun Aug 19 13:07:19 2007
Among the different forms of electromagnetic radiation emitted by the sun,which form is visible?
Q. Among the difference forms of electromagnetic radiation emitted by sun,which form is visible a) ultraviolet b)gamma rays c)light d)microwaves e)infrared thanks 4 any help
Asked by Emmanuela - Sun Sep 27 19:08:53 2009 - - 4 Answers - 0 Comments
A. C Light, which is technically Visible Light, the only part of the EM spectrum which is visible, hence the name visible light
Answered by King Nothing - Sun Sep 27 19:16:49 2009
Q. Among the difference forms of electromagnetic radiation emitted by sun,which form is visible a) ultraviolet b)gamma rays c)light d)microwaves e)infrared thanks 4 any help
Asked by Emmanuela - Sun Sep 27 19:08:53 2009 - - 4 Answers - 0 Comments
A. C Light, which is technically Visible Light, the only part of the EM spectrum which is visible, hence the name visible light
Answered by King Nothing - Sun Sep 27 19:16:49 2009
How is electromagnetic radiation produced in both nuclear fusion and fission reactions?
Q. I know how heat is produced in nuclear fusion and fission. but how exactly is the EM radiation produced?
Asked by daniel - Fri Dec 12 04:38:16 2008 - - 2 Answers - 0 Comments
A. I cannot hand-wave you into this one. You need to study quantum mechanics for that. Roughly, when protons rearrange in the nucleon after fusion/fission, change in E&M field results in radiation. The field in the nucleon is extremely strong, so the change is really wild and leads to gamma radiation.
Answered by gmyuri - Fri Dec 12 05:25:46 2008
Q. I know how heat is produced in nuclear fusion and fission. but how exactly is the EM radiation produced?
Asked by daniel - Fri Dec 12 04:38:16 2008 - - 2 Answers - 0 Comments
A. I cannot hand-wave you into this one. You need to study quantum mechanics for that. Roughly, when protons rearrange in the nucleon after fusion/fission, change in E&M field results in radiation. The field in the nucleon is extremely strong, so the change is really wild and leads to gamma radiation.
Answered by gmyuri - Fri Dec 12 05:25:46 2008
Can lead stop the penetration of electromagnetic radiation?
Q. The heat on earth is produced by electromagnetic rays striking the earth and the atmosphere, right? Electromagnetic rays are part of the spectrum that also contain X-rays, ultraviolet, etc. We know lead stops the penetration of X-rays, but can the lead also stop the electromagnetic rays? Common sense tells me that the lead will still heat up from regular sunlight.
Asked by KnottedBrain - Mon Jan 14 17:02:55 2008 - - 1 Answers - 0 Comments
A. You've got it backwards, X-rays, ultraviolet, visible light, radio waves, etc. are all electromagnetic. It is the electromagnetic spectrum. The fact that lead stops X-rays says that lead stops at least some electromagnetic radiation. The fact that lead is opaque means that it also stops visible light. Whether there are frequency ranges to which lead is transparent, I can't say, but I wouldn't be surprised. I do know that lead not a particularly good conductor so a thin layer of lead foil would not do a very good job of stopping radio frequencies. As for it heating up, radiation contains energy. When something stops that radiation by absorbing it, as opposed to reflecting it, you should expect that something to heat up. Hit a block… [cont.]
Answered by simplicitus - Wed Jan 16 03:21:47 2008
Q. The heat on earth is produced by electromagnetic rays striking the earth and the atmosphere, right? Electromagnetic rays are part of the spectrum that also contain X-rays, ultraviolet, etc. We know lead stops the penetration of X-rays, but can the lead also stop the electromagnetic rays? Common sense tells me that the lead will still heat up from regular sunlight.
Asked by KnottedBrain - Mon Jan 14 17:02:55 2008 - - 1 Answers - 0 Comments
A. You've got it backwards, X-rays, ultraviolet, visible light, radio waves, etc. are all electromagnetic. It is the electromagnetic spectrum. The fact that lead stops X-rays says that lead stops at least some electromagnetic radiation. The fact that lead is opaque means that it also stops visible light. Whether there are frequency ranges to which lead is transparent, I can't say, but I wouldn't be surprised. I do know that lead not a particularly good conductor so a thin layer of lead foil would not do a very good job of stopping radio frequencies. As for it heating up, radiation contains energy. When something stops that radiation by absorbing it, as opposed to reflecting it, you should expect that something to heat up. Hit a block… [cont.]
Answered by simplicitus - Wed Jan 16 03:21:47 2008
Calculate the frequency of electromagnetic radiation emitted by the hydrogen atom?
Q. Calculate the frequency of electromagnetic radiation emitted by the hydrogen atom in electron transition n=4 to n=3
Asked by some - Mon Apr 13 16:14:05 2009 - - 1 Answers - 0 Comments
A. Transition energy = hf = Rydberg Energy (1/n2^2 - 1/n1^2) f = (1/n2^2 - 1/n1^2) Eryd / h They give you the energy levels, n1 and n2. The Rydberg energy is 13.6 eV. Look up planck's constant, h. plugnchug.
Answered by ( )Mistress Bekki - Mon Apr 13 16:23:12 2009
Q. Calculate the frequency of electromagnetic radiation emitted by the hydrogen atom in electron transition n=4 to n=3
Asked by some - Mon Apr 13 16:14:05 2009 - - 1 Answers - 0 Comments
A. Transition energy = hf = Rydberg Energy (1/n2^2 - 1/n1^2) f = (1/n2^2 - 1/n1^2) Eryd / h They give you the energy levels, n1 and n2. The Rydberg energy is 13.6 eV. Look up planck's constant, h. plugnchug.
Answered by ( )Mistress Bekki - Mon Apr 13 16:23:12 2009
I need help with an electromagnetic radiation question which doesn't fit into this number of characters Please
Q. What relationship exists between the energy transferred by a quantum of electromagnetic radiation and the penetrating ability of the wave. Would you expect microwaves to have a high or low penetrating ability relative to other electormagnetic waves.
Asked by kittykat_017 - Fri Apr 18 10:29:18 2008 - - 1 Answers - 0 Comments
A. dont try to make me belive people know why that stuff really works when they cant even solve their own world problems dealing with money or anything lese like that
Answered by knetwurk@yahoo.com - Fri Apr 18 10:33:07 2008
Q. What relationship exists between the energy transferred by a quantum of electromagnetic radiation and the penetrating ability of the wave. Would you expect microwaves to have a high or low penetrating ability relative to other electormagnetic waves.
Asked by kittykat_017 - Fri Apr 18 10:29:18 2008 - - 1 Answers - 0 Comments
A. dont try to make me belive people know why that stuff really works when they cant even solve their own world problems dealing with money or anything lese like that
Answered by knetwurk@yahoo.com - Fri Apr 18 10:33:07 2008
Do all charged particles give off electromagnetic radiation?
Q. If electrons emit EM radiation, then do all charged particles exchange photons or EM radiation to make the EM force, like the quarks, the proton, and any charged particle? Is this how an electric field works, and how does a magnetic field work? If you could answer this question, I wouild appreciate it.
Asked by w_kneberg - Sat Nov 7 15:10:06 2009 - - 1 Answers - 0 Comments
Q. If electrons emit EM radiation, then do all charged particles exchange photons or EM radiation to make the EM force, like the quarks, the proton, and any charged particle? Is this how an electric field works, and how does a magnetic field work? If you could answer this question, I wouild appreciate it.
Asked by w_kneberg - Sat Nov 7 15:10:06 2009 - - 1 Answers - 0 Comments
From Yahoo Answer Search: 'Electromagnetic radiation'
Thu Nov 19 01:28:46 2009 [ refresh local cache ]
[Hide]▼
news.google.com
Hugo Citizen
... genetically modifi ed crops, pesticides, pre-planting chemical seed coatings, bee nutrition, electromagnetic radiation , beekeeping methods, etc. ...
emc.net.au
321px x 426px | 21.70kB
[source page]
and Safety OH S regulations places the responsibility for the safe operation of telecommunications facilities and RF machines ISM apparatus on the licence holders and employers Measurement results obtained from rf emr eme surveys are used to develop safe working practices and to protect the public from over exposure to emr eme the measurement survey is
blogycopedy.blogspot.com
Catalin
Sat, 29 Aug 2009 15:04:01 GM
science, technology, history, ancient mystery, physics, astronomy.
[Hide]▲
