EVALUATE this expression MATHEMATICS!!!?
Q. -4.75 < -11.59 thanks!!! ok so it would be x= -4.75 > -11.59?? how do you evaluate this expression?
Asked by hkittylover - Tue Jan 27 18:55:39 2009 - - 2 Answers - 0 Comments
A. Its not true or false it is "greater than" or >.
Answered by E=MO^2 - Tue Jan 27 19:04:33 2009
Q. -4.75 < -11.59 thanks!!! ok so it would be x= -4.75 > -11.59?? how do you evaluate this expression?
Asked by hkittylover - Tue Jan 27 18:55:39 2009 - - 2 Answers - 0 Comments
A. Its not true or false it is "greater than" or >.
Answered by E=MO^2 - Tue Jan 27 19:04:33 2009
factor this expression in mathematics?
Q. Factor the expression given below. Write each factor as a polynomial in descending order. Enter exponents using the caret ( ^ ). For example, you would enter x2 as x^2. 27x3 + 343y3
Asked by Carl W - Wed Feb 18 10:31:20 2009 - - 5 Answers - 0 Comments
A. 27x^3 + 343y^3 =(3x+7y)(9x^2-21xy+49y^2) answer//
Answered by Engr. Ronald - Wed Feb 18 10:48:15 2009
Q. Factor the expression given below. Write each factor as a polynomial in descending order. Enter exponents using the caret ( ^ ). For example, you would enter x2 as x^2. 27x3 + 343y3
Asked by Carl W - Wed Feb 18 10:31:20 2009 - - 5 Answers - 0 Comments
A. 27x^3 + 343y^3 =(3x+7y)(9x^2-21xy+49y^2) answer//
Answered by Engr. Ronald - Wed Feb 18 10:48:15 2009
Can someone please factorise this expression (its in mathematics)?
Q. Note: If the number is after the variable it is an exponent if it is before the variable it is a coefficient The expression is a3 - 1/a3 -2a + 2/a Thank You
Asked by Not this time - Sun Jan 14 05:05:57 2007 - - 5 Answers - 0 Comments
A. The standard formula for factorising difference of two cubes x^3 - y^3 = (x-y)(x^2+xy+y^2) gives us factors of the first pair of terms (a - 1/a)(a^2 + 1 + 1/(a^2)) The second pair is -2(a - 1/a) Now these two expressions have a common factor, a - 1/a, so taking out this common factor gives us (a - 1/a)(a^2 + 1 + 1/(a^2) -2) = (a - 1/a)(a^2 - 1 + 1/(a^2)) This is a much later PS (40 minutes later, in fact). I'm pleased to see avunger agrees with my solution. The reason I've come back is that it occurs to me that we can go further with the second factor. If we write it as a^2 + 2 + 1/(a^2) - 3, then it becomes (a + 1/a)^2 -3 = (a + 1/a + 3)(a + 1/a - 3), using the standard "difference of squares" formula, but we don't usually use… [cont.]
Answered by Hy - Sun Jan 14 05:23:56 2007
Q. Note: If the number is after the variable it is an exponent if it is before the variable it is a coefficient The expression is a3 - 1/a3 -2a + 2/a Thank You
Asked by Not this time - Sun Jan 14 05:05:57 2007 - - 5 Answers - 0 Comments
A. The standard formula for factorising difference of two cubes x^3 - y^3 = (x-y)(x^2+xy+y^2) gives us factors of the first pair of terms (a - 1/a)(a^2 + 1 + 1/(a^2)) The second pair is -2(a - 1/a) Now these two expressions have a common factor, a - 1/a, so taking out this common factor gives us (a - 1/a)(a^2 + 1 + 1/(a^2) -2) = (a - 1/a)(a^2 - 1 + 1/(a^2)) This is a much later PS (40 minutes later, in fact). I'm pleased to see avunger agrees with my solution. The reason I've come back is that it occurs to me that we can go further with the second factor. If we write it as a^2 + 2 + 1/(a^2) - 3, then it becomes (a + 1/a)^2 -3 = (a + 1/a + 3)(a + 1/a - 3), using the standard "difference of squares" formula, but we don't usually use… [cont.]
Answered by Hy - Sun Jan 14 05:23:56 2007
Mathematics Log Law expression?
Q. This is simple a log Law question but, what do u do with the 2 in front of the log. do u expand then simplify? loga(2x) + 2loga(x-1) loga(x+1) Please show me the working on how to move the 2 and solve the expression
Asked by Allen - Tue Mar 31 07:39:33 2009 - - 2 Answers - 0 Comments
A. If we leave out the (a), which I assume is the base, the expression can be simplified as follows. log(2x) + 2log(x-1) - log(x+1) *[2log(x-1) can be re-written as log(x-1) ]:- log(2x) + log(x-1) - log(x+1) *[log(2x) + log(x-1) can be re-written as log (2x(x-1) )]:- log (2x(x-1) ) - log(x+1) *Finally, two logs subtracted of the same base can be written as a quotient:- log [(2x(x-1) )/(x + 1)] Simplified as required.
Answered by Oms at the Proms [Deletion] - Tue Mar 31 08:11:51 2009
Q. This is simple a log Law question but, what do u do with the 2 in front of the log. do u expand then simplify? loga(2x) + 2loga(x-1) loga(x+1) Please show me the working on how to move the 2 and solve the expression
Asked by Allen - Tue Mar 31 07:39:33 2009 - - 2 Answers - 0 Comments
A. If we leave out the (a), which I assume is the base, the expression can be simplified as follows. log(2x) + 2log(x-1) - log(x+1) *[2log(x-1) can be re-written as log(x-1) ]:- log(2x) + log(x-1) - log(x+1) *[log(2x) + log(x-1) can be re-written as log (2x(x-1) )]:- log (2x(x-1) ) - log(x+1) *Finally, two logs subtracted of the same base can be written as a quotient:- log [(2x(x-1) )/(x + 1)] Simplified as required.
Answered by Oms at the Proms [Deletion] - Tue Mar 31 08:11:51 2009
what are the uses of expressions in mathematics?
Q. what are the uses of expressions in mathematics?
Asked by chatterbug115 - Thu Jun 14 06:24:24 2007 - - 3 Answers - 0 Comments
A. Why so you can have homework of course.
Answered by TECHX69 - Thu Jun 14 06:26:19 2007
Q. what are the uses of expressions in mathematics?
Asked by chatterbug115 - Thu Jun 14 06:24:24 2007 - - 3 Answers - 0 Comments
A. Why so you can have homework of course.
Answered by TECHX69 - Thu Jun 14 06:26:19 2007
Please help me about my mathematics problem it is about subtracting algebraic expressions?
Q. What is the answer if my equation is: -4 (a+b) - 8 (a+b) 2. 2xy - 3xy 3. 0 - 4(xty) 4. 7bc - - 2 bc 5. x-y= 6. 2xy-(-2xy) Thank you youll have 100 points if ever you help me..
Asked by Mae De Vera - Thu Oct 2 06:47:00 2008 - - 1 Answers - 0 Comments
A. im gonna assume theyre all subtraction questions so, -4(a+b)-8(a+b) =-4a-4b-8a-8b =-12a-12b second one, 2xy-3xy =-xy third one 0-4(xty) =-4(xty) fourth one 7bc-(-2bc) =7bc+2bc =9bc fifth one x-y=x-y (cannot be simplified) last one 2xy-(-2xy) =2xy+2xy =4xy hope i helped
Answered by brian - Thu Oct 2 06:56:27 2008
Q. What is the answer if my equation is: -4 (a+b) - 8 (a+b) 2. 2xy - 3xy 3. 0 - 4(xty) 4. 7bc - - 2 bc 5. x-y= 6. 2xy-(-2xy) Thank you youll have 100 points if ever you help me..
Asked by Mae De Vera - Thu Oct 2 06:47:00 2008 - - 1 Answers - 0 Comments
A. im gonna assume theyre all subtraction questions so, -4(a+b)-8(a+b) =-4a-4b-8a-8b =-12a-12b second one, 2xy-3xy =-xy third one 0-4(xty) =-4(xty) fourth one 7bc-(-2bc) =7bc+2bc =9bc fifth one x-y=x-y (cannot be simplified) last one 2xy-(-2xy) =2xy+2xy =4xy hope i helped
Answered by brian - Thu Oct 2 06:56:27 2008
Help with mathematics area and perimeter of inscribed rectangle?
Q. Consider a rectangle ABCD inscribed in a circle of radius r and let CA^B (the angle made by side AB and diagonal AC) = (zeta). What would be the expressions for the perimeter and the area of the rectangle?
Asked by blob - Sun Apr 5 12:31:00 2009 - - 1 Answers - 0 Comments
A. Since this is a rectangle, angle ABC is a right-angle, therefore it is an angle in a semi-circle, i.e. 90 . So ABC is a right-angled triangle, AC is a diameter of the circle, hence of length 2r. So side AB = 2r cos , and side BC = 2r sin And area of rectangle = AB x BC = (2r cos ) x (2r sin ) = 4r sin cos Half the perimeter = 2r cos + 2r sin = 2r (cos + sin ) So full perimeter = 4r (cos + sin )
Answered by ignoramus - Sun Apr 5 13:53:43 2009
Q. Consider a rectangle ABCD inscribed in a circle of radius r and let CA^B (the angle made by side AB and diagonal AC) = (zeta). What would be the expressions for the perimeter and the area of the rectangle?
Asked by blob - Sun Apr 5 12:31:00 2009 - - 1 Answers - 0 Comments
A. Since this is a rectangle, angle ABC is a right-angle, therefore it is an angle in a semi-circle, i.e. 90 . So ABC is a right-angled triangle, AC is a diameter of the circle, hence of length 2r. So side AB = 2r cos , and side BC = 2r sin And area of rectangle = AB x BC = (2r cos ) x (2r sin ) = 4r sin cos Half the perimeter = 2r cos + 2r sin = 2r (cos + sin ) So full perimeter = 4r (cos + sin )
Answered by ignoramus - Sun Apr 5 13:53:43 2009
Expressions in mathematics?
Q. Which of the following expressions represents "no more than 5"? 1. x < 5 2. x 5 3. x > 5 4. x 5
Asked by Jumpin Joe in Florida - Mon Sep 8 13:14:23 2008 - - 1 Answers - 0 Comments
A. 2 says all numbers less than or equal to 5, meaning it can be 5 but nothing higher.
Answered by Brian S - Mon Sep 8 13:18:24 2008
Q. Which of the following expressions represents "no more than 5"? 1. x < 5 2. x 5 3. x > 5 4. x 5
Asked by Jumpin Joe in Florida - Mon Sep 8 13:14:23 2008 - - 1 Answers - 0 Comments
A. 2 says all numbers less than or equal to 5, meaning it can be 5 but nothing higher.
Answered by Brian S - Mon Sep 8 13:18:24 2008
In your experience thus far, does the word "factoring" mean in mathematics?
Q. How can you tell if a number or an expression has been "factored"? What is a "greatest common factor" in Algebra.
Asked by Amanda - Wed Aug 5 16:47:53 2009 - - 2 Answers - 0 Comments
Q. How can you tell if a number or an expression has been "factored"? What is a "greatest common factor" in Algebra.
Asked by Amanda - Wed Aug 5 16:47:53 2009 - - 2 Answers - 0 Comments
Who is smart to answer these mathematics questions?
Q. Write the words that can be represented by each expression. 5. y+4 6.6 over an x 7. 8z 8. 7 y
Asked by Lo L - Sat May 10 03:37:24 2008 - - 6 Answers - 0 Comments
A. 5. y + 4 y plus four 6. 6/x six divided by x or six over x 7. 8z eight times z or eight multiplied by z 8. 7 y seven less y or seven minus y
Answered by Jun Agruda - Sat May 10 06:18:34 2008
Q. Write the words that can be represented by each expression. 5. y+4 6.6 over an x 7. 8z 8. 7 y
Asked by Lo L - Sat May 10 03:37:24 2008 - - 6 Answers - 0 Comments
A. 5. y + 4 y plus four 6. 6/x six divided by x or six over x 7. 8z eight times z or eight multiplied by z 8. 7 y seven less y or seven minus y
Answered by Jun Agruda - Sat May 10 06:18:34 2008
Math challenge. Who can make the longest, most difficult, most complex, advanced math equation/expression?
Q. I absolutely do NOT want an unsolved math problem. People say, go to Wikipedia's Unsolved problems in mathematics, dont want that al all. I want something very long and advanced. I want it to completely fill a page, or at least half of one. Have it contain a lot of Trig, Calc, and Albegra terms. Here's an example of Vector Calculus: 2*x*`#mover(mi("e"),mo("& lowbar;"))`[x]-`#mover(mi ("e"),mo("_"))`[y] /y^(3/2)-4*(exp(z))^2*`#m over(mi("e"),mo("_ "))`[z] I want it to be much, much more complex. Make it much less of a word problem, and much more of an equation or expression. Longest and most complex one gets best answer. I have Maple 11, so you can put it in text form. Giving more than one hard problem will add to the… [cont.]
Asked by College guy - Sat Jun 30 08:51:51 2007 - - 3 Answers - 0 Comments
A. I pity you. You do not even know vector calculus. Not all math questions can be answered through/ by maple. longest? most complex? I have a retort for you, two words: Russell's paradox.
Answered by Alam Ko Iyan - Sat Jun 30 08:58:57 2007
Q. I absolutely do NOT want an unsolved math problem. People say, go to Wikipedia's Unsolved problems in mathematics, dont want that al all. I want something very long and advanced. I want it to completely fill a page, or at least half of one. Have it contain a lot of Trig, Calc, and Albegra terms. Here's an example of Vector Calculus: 2*x*`#mover(mi("e"),mo("& lowbar;"))`[x]-`#mover(mi ("e"),mo("_"))`[y] /y^(3/2)-4*(exp(z))^2*`#m over(mi("e"),mo("_ "))`[z] I want it to be much, much more complex. Make it much less of a word problem, and much more of an equation or expression. Longest and most complex one gets best answer. I have Maple 11, so you can put it in text form. Giving more than one hard problem will add to the… [cont.]
Asked by College guy - Sat Jun 30 08:51:51 2007 - - 3 Answers - 0 Comments
A. I pity you. You do not even know vector calculus. Not all math questions can be answered through/ by maple. longest? most complex? I have a retort for you, two words: Russell's paradox.
Answered by Alam Ko Iyan - Sat Jun 30 08:58:57 2007
Conceptual problems with the mathematics of physics.?
Q. What are some good resources to try to learn how to take a list of values and come up with an equation or expression that describes them? I've seen the square root of 1-(v^2*c^2) in a lot of relativistic equations. My question is a general one (not specific to the relativity example) Why are there a lot of relationships that have the numerical values that they have. As to the example above why 1 instead of 2 or 68.543?
Asked by Lynus - Fri Mar 2 23:37:03 2007 - - 5 Answers - 1 Comments
A. Part of it is that you are trying to find fractions of a whole, or numbers to multiply by another number to get the answer. So you subtract some fraction from 1 to get the new fraction. The fraction cannot be more than 1. In the relativistic equations, you are trying to find out the increase in mass or time as the speed becomes significant relative to light speed. So maybe the formula will result in a multiplier that would be multiplied by the mass in question to get the result. So for instance if one is traveling at .5 the speed of light, the multiplier would be 1-.5^2 = 3/4. So you would multiply your mass by square root of (3/4). This is not exactly right, but it is something like this.
Answered by David S - Fri Mar 2 23:59:35 2007
Q. What are some good resources to try to learn how to take a list of values and come up with an equation or expression that describes them? I've seen the square root of 1-(v^2*c^2) in a lot of relativistic equations. My question is a general one (not specific to the relativity example) Why are there a lot of relationships that have the numerical values that they have. As to the example above why 1 instead of 2 or 68.543?
Asked by Lynus - Fri Mar 2 23:37:03 2007 - - 5 Answers - 1 Comments
A. Part of it is that you are trying to find fractions of a whole, or numbers to multiply by another number to get the answer. So you subtract some fraction from 1 to get the new fraction. The fraction cannot be more than 1. In the relativistic equations, you are trying to find out the increase in mass or time as the speed becomes significant relative to light speed. So maybe the formula will result in a multiplier that would be multiplied by the mass in question to get the result. So for instance if one is traveling at .5 the speed of light, the multiplier would be 1-.5^2 = 3/4. So you would multiply your mass by square root of (3/4). This is not exactly right, but it is something like this.
Answered by David S - Fri Mar 2 23:59:35 2007
first answer 10 points word problem mathematics?
Q. Frank purchased x tickets for a concert.Mark has 1 more ticket than Frank.Karen has twice as many tickets as Mark.Which expression represents how many tickets they have in all? A.4x + 2 B.3x + 3 C.3x + 2 D.4x + 3 i really need help!
Asked by LIL DREAM - Thu Feb 19 19:06:53 2009 - - 8 Answers - 0 Comments
A. im first answer pick me! u never said we have to answer the prob.
Answered by THE BOM!!!! - Thu Feb 19 19:10:11 2009
Q. Frank purchased x tickets for a concert.Mark has 1 more ticket than Frank.Karen has twice as many tickets as Mark.Which expression represents how many tickets they have in all? A.4x + 2 B.3x + 3 C.3x + 2 D.4x + 3 i really need help!
Asked by LIL DREAM - Thu Feb 19 19:06:53 2009 - - 8 Answers - 0 Comments
A. im first answer pick me! u never said we have to answer the prob.
Answered by THE BOM!!!! - Thu Feb 19 19:10:11 2009
Integrate this expression?
Q. Let Q1,Q2 and Q3 be three (3) different quadratic equations in terms of x, I would like to find an expression which is integral of the following Integral { [Q1*log(Q2)] / Q3 } dx. (Note: Q3 is common denominator for Q1*log(Q2), which is in numerator) I have already tried in integrals.com, but it is giving results in terms of special function (poly logarithmic function). Is there an expression with basic functions which we normally use in mathematics at school or undergraduate level?
Asked by Jam - Thu Mar 1 03:55:51 2007 - - 2 Answers - 0 Comments
A. Try to apply the bernolli formulae.., Keep Q1/Q3 as U and log(Q2) as dV... from there you drive the values of V Now apply bernolli formula as Integral {UdV} = UV1 - U'V2 + U''V3 - U'''V4 + ... where V1 is Integral {V}, V2 is is Integral {V1} & ... U' is diff. of U, U'' is diff of ' &... Again U need to break U as Q1/Q3 to simplify...
Answered by Kesavan - Thu Mar 1 04:43:19 2007
Q. Let Q1,Q2 and Q3 be three (3) different quadratic equations in terms of x, I would like to find an expression which is integral of the following Integral { [Q1*log(Q2)] / Q3 } dx. (Note: Q3 is common denominator for Q1*log(Q2), which is in numerator) I have already tried in integrals.com, but it is giving results in terms of special function (poly logarithmic function). Is there an expression with basic functions which we normally use in mathematics at school or undergraduate level?
Asked by Jam - Thu Mar 1 03:55:51 2007 - - 2 Answers - 0 Comments
A. Try to apply the bernolli formulae.., Keep Q1/Q3 as U and log(Q2) as dV... from there you drive the values of V Now apply bernolli formula as Integral {UdV} = UV1 - U'V2 + U''V3 - U'''V4 + ... where V1 is Integral {V}, V2 is is Integral {V1} & ... U' is diff. of U, U'' is diff of ' &... Again U need to break U as Q1/Q3 to simplify...
Answered by Kesavan - Thu Mar 1 04:43:19 2007
fill in the blank and choose an appropriate transitional expression from the list below?
Q. actually, while, therefore, since, then,nevertheless ,first,after a while,after that, meanwhile. The old time beekeeper had a clever way of locating a cluster of wild bees.Equipped with a small wooden box that has a slider cover,he would go to a meadow___,he would find a bee in a flower and capture it,in his box___he would pull back the cover and release the bee___he knew that the pollen laden insect would make a beeline to the tree where the wild bees were cluster ,he would carefully note the direction of the flight.He would___move to the other side of the meadow,capture another bee,release it,and note the direction in which it flew. he knew that both bees had headed home by the most direct route___he knew that the cluster of bees must… [cont.]
Asked by valit - Sat Dec 6 03:42:24 2008 - - 1 Answers - 0 Comments
A. 1.) then 2.) after that 3.) since 4.) then 5.) nevertheless 6.) therefore 7.) while
Answered by Rita - Sat Dec 6 04:14:37 2008
Q. actually, while, therefore, since, then,nevertheless ,first,after a while,after that, meanwhile. The old time beekeeper had a clever way of locating a cluster of wild bees.Equipped with a small wooden box that has a slider cover,he would go to a meadow___,he would find a bee in a flower and capture it,in his box___he would pull back the cover and release the bee___he knew that the pollen laden insect would make a beeline to the tree where the wild bees were cluster ,he would carefully note the direction of the flight.He would___move to the other side of the meadow,capture another bee,release it,and note the direction in which it flew. he knew that both bees had headed home by the most direct route___he knew that the cluster of bees must… [cont.]
Asked by valit - Sat Dec 6 03:42:24 2008 - - 1 Answers - 0 Comments
A. 1.) then 2.) after that 3.) since 4.) then 5.) nevertheless 6.) therefore 7.) while
Answered by Rita - Sat Dec 6 04:14:37 2008
if N=number o sides on the base, write an expression to determine the number?
Q. mathematics
Asked by cindy a - Wed Oct 3 17:48:24 2007 - - 1 Answers - 0 Comments
A. "if N=number o sides on the base, write an expression to determine the number?" Is there supposed to be another word at the end of the question? Determine the number of what?
Answered by MsMath - Wed Oct 3 19:55:59 2007
Q. mathematics
Asked by cindy a - Wed Oct 3 17:48:24 2007 - - 1 Answers - 0 Comments
A. "if N=number o sides on the base, write an expression to determine the number?" Is there supposed to be another word at the end of the question? Determine the number of what?
Answered by MsMath - Wed Oct 3 19:55:59 2007
The expression 3x^3 + 2x^2 + ax + b leaves a remainder of -5 when divided by (x+1) ....?
Q. and a remainder of 2 when divided by (x-1). Find 'a' and 'b' Now I don't have an A'level in mathematics but I am doing this subject in university and can't find a solution for this one so pls if possible explain answer if you can. Thanks.
Asked by Jonathan24 - Fri Dec 26 12:04:36 2008 - - 5 Answers - 0 Comments
A. f(x) = 3x^3 + 2x^2 + ax + b According to remainder theorem when f(x) is divided by (x - a) f(a) is remainder. so when f(x) is divided by (x+1), f(-1) = -5 f(-1) = -3 + 2 - a + b = -5 -a + b = - 4---(1) f(1) = 3 + 2 + a + b = 2 a + b = -3 ---(2) add (1) and (2) 2b = -7 b = -7/2 substitute in eqn(2) a - 7/2 = -3 a = 7/2 - 3 = 1/2 so a = 0.5 and b = -3.5
Answered by mohanrao d - Fri Dec 26 12:12:35 2008
Q. and a remainder of 2 when divided by (x-1). Find 'a' and 'b' Now I don't have an A'level in mathematics but I am doing this subject in university and can't find a solution for this one so pls if possible explain answer if you can. Thanks.
Asked by Jonathan24 - Fri Dec 26 12:04:36 2008 - - 5 Answers - 0 Comments
A. f(x) = 3x^3 + 2x^2 + ax + b According to remainder theorem when f(x) is divided by (x - a) f(a) is remainder. so when f(x) is divided by (x+1), f(-1) = -5 f(-1) = -3 + 2 - a + b = -5 -a + b = - 4---(1) f(1) = 3 + 2 + a + b = 2 a + b = -3 ---(2) add (1) and (2) 2b = -7 b = -7/2 substitute in eqn(2) a - 7/2 = -3 a = 7/2 - 3 = 1/2 so a = 0.5 and b = -3.5
Answered by mohanrao d - Fri Dec 26 12:12:35 2008
Does anyone know of a really good Math website?
Q. I need a really good website that can be used to assist with learning and using mathematics. Operation Order Evaluating an Expression with One Variable Evaluating an Expression with Two Variables Algebra Vocabulary Hard Word Problems Really Hard Word Problems
Asked by Chris - Thu Sep 7 00:27:02 2006 - - 7 Answers - 0 Comments
A. Tons of them. Just fire up a search engine and go for it Doug
Answered by doug_donaghue - Thu Sep 7 00:30:02 2006
Q. I need a really good website that can be used to assist with learning and using mathematics. Operation Order Evaluating an Expression with One Variable Evaluating an Expression with Two Variables Algebra Vocabulary Hard Word Problems Really Hard Word Problems
Asked by Chris - Thu Sep 7 00:27:02 2006 - - 7 Answers - 0 Comments
A. Tons of them. Just fire up a search engine and go for it Doug
Answered by doug_donaghue - Thu Sep 7 00:30:02 2006
GCSE Mathematics higher tier nth term question I need help!!!?
Q. The nth even number is 2n. The next even number after 2n is 2n + 2 (a) Explain why. (b) Write down an expression, in terms of n, for the next even number after 2n +2. (c) Show algebraically that the sum of any 3 consecutive even numbers is always a multiple of 6.
Asked by Ree Ree - Tue Nov 3 15:06:21 2009 - - 1 Answers - 0 Comments
A. If the nth even number is 2n, the kth even number is 2k, the (3+7)th even number is 2(3+7), and in particular the (n+1)st even number - the one which is next after the nth - is 2(n+1) = 2n+2. If the even number next after 2n is 2n+2, the even number next after 12 is 12+2, the even number after x is x+2, and in particular the even number after 2n+2 is (2n+2)+2 = 2n+4. Then three consecutive even numbers will be of the form 2n, 2n+2, 2n+4: the sum of these is then (2n)+(2n+2)+(2n+4) = 2n+2n+2n+2+4 = 6n+6 = 6(n+1), the n+1st multiple of 6.
Answered by Anna O. - Wed Nov 4 01:13:38 2009
Q. The nth even number is 2n. The next even number after 2n is 2n + 2 (a) Explain why. (b) Write down an expression, in terms of n, for the next even number after 2n +2. (c) Show algebraically that the sum of any 3 consecutive even numbers is always a multiple of 6.
Asked by Ree Ree - Tue Nov 3 15:06:21 2009 - - 1 Answers - 0 Comments
A. If the nth even number is 2n, the kth even number is 2k, the (3+7)th even number is 2(3+7), and in particular the (n+1)st even number - the one which is next after the nth - is 2(n+1) = 2n+2. If the even number next after 2n is 2n+2, the even number next after 12 is 12+2, the even number after x is x+2, and in particular the even number after 2n+2 is (2n+2)+2 = 2n+4. Then three consecutive even numbers will be of the form 2n, 2n+2, 2n+4: the sum of these is then (2n)+(2n+2)+(2n+4) = 2n+2n+2n+2+4 = 6n+6 = 6(n+1), the n+1st multiple of 6.
Answered by Anna O. - Wed Nov 4 01:13:38 2009
Help me with these mathematics problems -- please!?
Q. A. If T varies directly as S, and S=15 when T=12, find S when T=4. B. For what value of X is the expression 7/(X + 8) undefined? (The expression is written as a fraction. C. How do I write an equation to represent a line witha slope of -3 adn a Y-intercept of 1. (Please explain why -- I know the equation is Y=3X+1) D. What is an irrational number? EWhatis a trinomial, and how can I find an equivalent to (3x-1)(x+4)? F. The factor of 2n(squared)-6 are? (How do I find the factors of a equation like this?)
Asked by Blah Blah Blah - Sat Jun 17 09:31:11 2006 - - 8 Answers - 0 Comments
A. First are the answers, and their individual in-depth explanations are below. Hope this helps! A. S=5 B. X=-8 C. Y=-3X+1 D. It is a number that cannot be expressed as the ratio of two integers. E. A trinomial is a polynomial expression with three terms (after simplification). The trinomial you are looking for is 3x^2+11x-4. F. 2 and (N^2 - 3). Factor out all common factors. A. Let K be the constant of variation. T=KS. 12 =15K. K=4/5. Now T=(4/5)S. Substitue the values you've been given. 4=(4/5)S. S=5 B. X = -8. An undefined expression includes division by zero, since this is impossible. To make the denominator zero, X+8=0. C. Actually, it's Y=-3x+1. This is just slope-intercept form, y=mx+b, where m=slope and b=y-intercept. … [cont.]
Answered by I eat apples - Thu Jun 29 18:59:27 2006
Q. A. If T varies directly as S, and S=15 when T=12, find S when T=4. B. For what value of X is the expression 7/(X + 8) undefined? (The expression is written as a fraction. C. How do I write an equation to represent a line witha slope of -3 adn a Y-intercept of 1. (Please explain why -- I know the equation is Y=3X+1) D. What is an irrational number? EWhatis a trinomial, and how can I find an equivalent to (3x-1)(x+4)? F. The factor of 2n(squared)-6 are? (How do I find the factors of a equation like this?)
Asked by Blah Blah Blah - Sat Jun 17 09:31:11 2006 - - 8 Answers - 0 Comments
A. First are the answers, and their individual in-depth explanations are below. Hope this helps! A. S=5 B. X=-8 C. Y=-3X+1 D. It is a number that cannot be expressed as the ratio of two integers. E. A trinomial is a polynomial expression with three terms (after simplification). The trinomial you are looking for is 3x^2+11x-4. F. 2 and (N^2 - 3). Factor out all common factors. A. Let K be the constant of variation. T=KS. 12 =15K. K=4/5. Now T=(4/5)S. Substitue the values you've been given. 4=(4/5)S. S=5 B. X = -8. An undefined expression includes division by zero, since this is impossible. To make the denominator zero, X+8=0. C. Actually, it's Y=-3x+1. This is just slope-intercept form, y=mx+b, where m=slope and b=y-intercept. … [cont.]
Answered by I eat apples - Thu Jun 29 18:59:27 2006
From Yahoo Answer Search: 'Expression (mathematics)'
Thu Nov 5 18:48:15 2009 [ refresh local cache ]
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Blood -- Expression profiling of a hemopoietic cell survival ...
Powell, JA, Thomas, D., Barry, EF, Kok, CH, McClure, BJ, Tsykin, A., To, LB, Brown, A., Lewis, ID, Herbert, K., Goodall, GJ, Speed, TP, Asou, N., Jacob, B., Osato, M., Haylock, DN, Nilsson, SK, D'Andrea, RJ, Lopez, AF, Guthridge, MA
Mon, 05 Oct 2009 18:39:03 GM
Department of . Mathematics. , University of Adelaide, Adelaide, SA, Australia Department of Haematology and Medical Oncology, Peter MacCallum Cancer Centre, East Melbourne, VIC, Australia Cytokine Signaling Laboratory, Centre for Cancer ...
Powell, JA, Thomas, D., Barry, EF, Kok, CH, McClure, BJ, Tsykin, A., To, LB, Brown, A., Lewis, ID, Herbert, K., Goodall, GJ, Speed, TP, Asou, N., Jacob, B., Osato, M., Haylock, DN, Nilsson, SK, D'Andrea, RJ, Lopez, AF, Guthridge, MA
Mon, 05 Oct 2009 18:39:03 GM
Department of . Mathematics. , University of Adelaide, Adelaide, SA, Australia Department of Haematology and Medical Oncology, Peter MacCallum Cancer Centre, East Melbourne, VIC, Australia Cytokine Signaling Laboratory, Centre for Cancer ...
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