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Integration is an important concept in mathematics which, together with differentiation, forms one of the main operations in calculus. Given a function ƒ of a real variable x and an interval [a, b] of the real line, the definite integral is defined informally to be the net signed area of the region in the xy-plane bounded by the graph of ƒ, the x-axis, and the vertical lines x = a and x = b. The term integral may also refer to the notion of antiderivative, a function F whose derivative is the given function ƒ. In this case it is called an indefinite integral, while the integrals discussed in this article are termed definite integrals. Some authors maintain a distinction between antiderivatives and indefinite integrals. The principles of integration were formulated independently by Isaac Newton and Gottfried Leibniz in the late 17th century. Through the fundamental theorem of calculus, which they independently developed, integration is connected with differentiation: if ƒ is a continuous real-valued function defined on a closed interval [a, b], then, once an antiderivative F of ƒ is known, the definite integral of ƒ over that interval is given by Integrals and derivatives became the basic tools of calculus, with numerous applications in science and engineering. A rigorous mathematical definition of the integral was given by Bernhard Riemann. It is based on a limiting procedure which approximates the area of a curvilinear region by breaking the region into thin vertical slabs. Beginning in the nineteenth century, more sophisticated notions of integral began to appear, where the type of the function as well as the domain over which the integration is performed has been generalised. A line integral is defined for functions of two or three variables, and the interval of integration [a, b] is replaced by a certain curve connecting two points on the plane or in the space. In a surface integral, the curve is replaced by a piece of a surface in the three-dimensional space. Integrals of differential forms play a fundamental role in modern differential geometry. These generalizations of integral first arose from the needs of physics, and they play an important role in the formulation of many physical laws, notably those of electrodynamics. There are many modern concepts of integration. The most common notion of integration is based on the abstract mathematical theory known as Lebesgue integration, developed by Henri Lebesgue. From Wikipedia under the
GNU Free Documentation License What's the difference between differential and integral calculus??? Q. What's the difference between differential and integral calculus??? Asked by Chichiri - Sat Dec 8 14:18:49 2007 - - 2 Answers - 0 Comments A. Differential calculus is concerned about relations and facts related to the derivatives of functions of one or more variables. Integral calculus, on the other hand, is concerned about facts and relationships related to the integral of a function of one or more variables. Answered by mulla sadra - Sat Dec 8 14:25:17 2007 Can anybody help me with integral calculus? Q. I need to find the equation of a curve that passes through the point (2, 5) and has the gradient 3x^2 + 2x - 4. Can somebody try and talk me through it please? :) Asked by Lloyd - Tue Jun 16 14:05:00 2009 - - 1 Answers - 0 Comments Can somebody help me with these calculus integral problems?
Q. Evaluate the following integrals: a) integral from 0 to sqrt(3)/3 of: 10/(t^2+1) dt b) integral from -3 to 3 of: e^(u+1) du c) integral from 3 to 4 of: (2+u^2)/(u^3) du Asked by jeremy s - Thu Jan 24 00:47:21 2008 - - 1 Answers - 0 Comments A. for a) you have to use a trig identity: integral of 1/(x^2+a^2)dt= (1/a) inverse tan(x/a) in this case a=1, x=t and 10 is a constant so it can be pulled to the front. answer = 10(inverse tan(sqrt(3)/3) - inverse tan((0) = 10(30 - o) = 300 b) integral of e^(u+1)du = e^(3+1) - e^(-3+1) =e^4 - e^(-2) =54.4628 c) you can break this question up. integral from 3 to 4 of (2/u^3)du + integral from 3 to 4 of (u^2/u^3) du = -1/u^2 + lnu (from 3 to 4) = [-1/4^2 + ln4] - [-1/3^2 + ln3] then simplify Answered by J J - Thu Jan 24 01:11:47 2008 From Yahoo Answer Search: "Integral calculus" Power of Maroon: Leadership Spotlight
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