Correct way to draw a lewis structures for N2O without it being an isomer?
Q. I am trying to draw the lewis structure for N2O. I am wondering if the correct way to draw it would be: N-N-O or N-O-N (not including the actual number of bonds and e-) I'm thinking that it should be the first one and that the second one is a structural isomer. Is this correct? Thank you for your help!
Asked by MissBrittney - Tue Nov 25 02:07:37 2008 - - 2 Answers - 0 Comments
A. Miss Brittney, You are correct: N-N-O, 100%. See link down below (nice work!). There are resonance structures, but while the N-O-N structure seems plausible, it does not go down that way. The link shows the resonance structures. Hope that helped!
Answered by Dr. Buzz - Tue Nov 25 02:19:23 2008
Q. I am trying to draw the lewis structure for N2O. I am wondering if the correct way to draw it would be: N-N-O or N-O-N (not including the actual number of bonds and e-) I'm thinking that it should be the first one and that the second one is a structural isomer. Is this correct? Thank you for your help!
Asked by MissBrittney - Tue Nov 25 02:07:37 2008 - - 2 Answers - 0 Comments
A. Miss Brittney, You are correct: N-N-O, 100%. See link down below (nice work!). There are resonance structures, but while the N-O-N structure seems plausible, it does not go down that way. The link shows the resonance structures. Hope that helped!
Answered by Dr. Buzz - Tue Nov 25 02:19:23 2008
How to find Volume of N2O in a chemical question?
Q. In the formula 4NH3 +3O2 => 2N2O + 6H2O I need to know how to solve the volume for N2O. The only given is NH3 - 45.6L. The only idea I have so far on this equation is the usage of Avogadro's Law, but that's as far as I got. Can anyone help me out?
Asked by JonDo - Tue Apr 15 00:57:27 2008 - - 2 Answers - 1 Comments
A. Well let's take a look at this Jon and see what we have. 4NH3 +3O2 => 2N2O + 6H2O I agree with Gladys, you have a slight balancing problem, but a 4 in front of O2 will fix that. 4NH3 +4O2 => 2N2O + 6H2O But that means that all of the coefficients can now be reduced 2NH3 +2O2 => N2O + 3H2O Now. How's that? You're on the right track with Avogadro's law. The coefficients in the balanced equation not only give the ratio of moles but also the ratio of volumes of gases. The equation tells us that for every 2 liters of NH3 that react, 1 liter of N2O will be produced. So set up a conversion factor: 45.6 L NH3 x 1 L N2O / 2 L NH3 = 22.8 L N2O
Answered by pisgahchemist - Tue Apr 15 01:24:32 2008
Q. In the formula 4NH3 +3O2 => 2N2O + 6H2O I need to know how to solve the volume for N2O. The only given is NH3 - 45.6L. The only idea I have so far on this equation is the usage of Avogadro's Law, but that's as far as I got. Can anyone help me out?
Asked by JonDo - Tue Apr 15 00:57:27 2008 - - 2 Answers - 1 Comments
A. Well let's take a look at this Jon and see what we have. 4NH3 +3O2 => 2N2O + 6H2O I agree with Gladys, you have a slight balancing problem, but a 4 in front of O2 will fix that. 4NH3 +4O2 => 2N2O + 6H2O But that means that all of the coefficients can now be reduced 2NH3 +2O2 => N2O + 3H2O Now. How's that? You're on the right track with Avogadro's law. The coefficients in the balanced equation not only give the ratio of moles but also the ratio of volumes of gases. The equation tells us that for every 2 liters of NH3 that react, 1 liter of N2O will be produced. So set up a conversion factor: 45.6 L NH3 x 1 L N2O / 2 L NH3 = 22.8 L N2O
Answered by pisgahchemist - Tue Apr 15 01:24:32 2008
How many standard N2O chargers can I put in my .5 liter whipped cream dispenser?
Q. How many standard N2O chargers can I put in my .5 liter whipped cream dispenser? Before it explodes? lol
Asked by D - Thu Nov 15 22:57:54 2007 - - 1 Answers - 0 Comments
A. It should never explode. You should be able to put one, at which point the pressure inside is balanced by the charger and no more pressure increase occurs.
Answered by mike1942f - Mon Nov 19 00:30:45 2007
Q. How many standard N2O chargers can I put in my .5 liter whipped cream dispenser? Before it explodes? lol
Asked by D - Thu Nov 15 22:57:54 2007 - - 1 Answers - 0 Comments
A. It should never explode. You should be able to put one, at which point the pressure inside is balanced by the charger and no more pressure increase occurs.
Answered by mike1942f - Mon Nov 19 00:30:45 2007
What is the best way to amp up the power of my Honda Shadow Aero 750 without N2O?
Q. Do not want to spend a fortune.
Asked by Casey - Sat Feb 21 18:20:57 2009 - - 3 Answers - 0 Comments
Q. Do not want to spend a fortune.
Asked by Casey - Sat Feb 21 18:20:57 2009 - - 3 Answers - 0 Comments
Where can i find N2O Cartridges locally?
Q. i was wondering one could find whippets, nitrous cartridges, locally? Pleese give actual names of stores and do head shops sell them?
Asked by Will L - Thu Jul 10 23:07:39 2008 - - 1 Answers - 0 Comments
A. Where is locally? Here is some additional info:
Answered by J. P. - Fri Jul 11 19:55:50 2008
Q. i was wondering one could find whippets, nitrous cartridges, locally? Pleese give actual names of stores and do head shops sell them?
Asked by Will L - Thu Jul 10 23:07:39 2008 - - 1 Answers - 0 Comments
A. Where is locally? Here is some additional info:
Answered by J. P. - Fri Jul 11 19:55:50 2008
In the first-order decomposition of dinitrogen pentoxide at 335 K, assume we start with a 2.50 g sample of N2O
Q. In the first-order decomposition of dinitrogen pentoxide at 335 K, assume we start with a 2.50 g sample of N2O5 at 335 K and have 1.50 g remaining after 109 s. (a) What is the value of the rate constant k? (b) What is the half-life of the reaction? (c) What mass of N2O5 will remain after 4.9 min?
Asked by jska87 - Tue Feb 19 22:05:18 2008 - - 1 Answers - 0 Comments
A. C) so A) ln(1.5g/2.5g=-k 109s -.511=-k109s k= 4.69*10^-3 B) t(1/2)=.693/k=(.693/4.69* 10^-3)=148s this is an example of how to do c) it the only thing that is different is the time just plug in your time where 5.0min are and you will be able to solve it I would do the calcultions for you but I don't have my calculator. C) ln(m/2.50g)=(4.69* 10^-3/s)*(5.0min)*(60s/mi n)=-1.41 Raise both sides of the equation to a power of e. eln(m/2.50g)=(m/2.50g)=e- 1.41=0.244 m=0.61g
Answered by Codiee - Wed Feb 20 12:19:47 2008
Q. In the first-order decomposition of dinitrogen pentoxide at 335 K, assume we start with a 2.50 g sample of N2O5 at 335 K and have 1.50 g remaining after 109 s. (a) What is the value of the rate constant k? (b) What is the half-life of the reaction? (c) What mass of N2O5 will remain after 4.9 min?
Asked by jska87 - Tue Feb 19 22:05:18 2008 - - 1 Answers - 0 Comments
A. C) so A) ln(1.5g/2.5g=-k 109s -.511=-k109s k= 4.69*10^-3 B) t(1/2)=.693/k=(.693/4.69* 10^-3)=148s this is an example of how to do c) it the only thing that is different is the time just plug in your time where 5.0min are and you will be able to solve it I would do the calcultions for you but I don't have my calculator. C) ln(m/2.50g)=(4.69* 10^-3/s)*(5.0min)*(60s/mi n)=-1.41 Raise both sides of the equation to a power of e. eln(m/2.50g)=(m/2.50g)=e- 1.41=0.244 m=0.61g
Answered by Codiee - Wed Feb 20 12:19:47 2008
Describe how the molecule whose formula is NO is different from the molecule whose formula is N2O?
Q. Help please
Asked by Monica - Fri Aug 7 15:15:18 2009 - - 2 Answers - 0 Comments
A. NO is nitric oxide, where there is a double bond between the nitrogen and the oxygen molecules, In addition to the double bond there is a single electron that each molecule shares that forms a weak third bond. N2O is nitrous oxide. Where the arrangement of molecules is in a linear fashion where N-N-O. There can be a triple or double bond from N to N where as there can be a single to double bond from N to O. Partial positive and negative charges apply depending on bond upon electronegativity values.
Answered by Eric K - Fri Aug 7 15:26:18 2009
Q. Help please
Asked by Monica - Fri Aug 7 15:15:18 2009 - - 2 Answers - 0 Comments
A. NO is nitric oxide, where there is a double bond between the nitrogen and the oxygen molecules, In addition to the double bond there is a single electron that each molecule shares that forms a weak third bond. N2O is nitrous oxide. Where the arrangement of molecules is in a linear fashion where N-N-O. There can be a triple or double bond from N to N where as there can be a single to double bond from N to O. Partial positive and negative charges apply depending on bond upon electronegativity values.
Answered by Eric K - Fri Aug 7 15:26:18 2009
Calculate the ratio of the effusion rates of N2 and N2O?
Q. Calculate the ratio of the effusion rates of N2 and N2O please show work so i can learn
Asked by peste - Wed Oct 28 12:00:12 2009 - - 2 Answers - 0 Comments
A. rate N2 / rate N2O = sq.rt ( 44 / 28)= 1.25 Graham's law
Answered by tanialo - Wed Oct 28 12:11:03 2009
Q. Calculate the ratio of the effusion rates of N2 and N2O please show work so i can learn
Asked by peste - Wed Oct 28 12:00:12 2009 - - 2 Answers - 0 Comments
A. rate N2 / rate N2O = sq.rt ( 44 / 28)= 1.25 Graham's law
Answered by tanialo - Wed Oct 28 12:11:03 2009
Why does N2O support combustion and H2O not support combustion?
Q. Why does N2O support combustion and H2O not support combustion?
Asked by nikkindeet - Wed Aug 26 14:42:44 2009 - - 3 Answers - 0 Comments
A. The reason is the strength of the bonds between the atoms. N2O is more volatile because of the weaker bond between the atoms in the molecule. When those atoms break apart, energy is released and thus, burns. H20 if exposed to the correct energy would burn, but it would take a lot. While oxygen is necessary for any kind of combustible reaction, it doesn't burn when connected to hydrogen as in the way it is connected in water because the bonds are extremely strong. The hydrogen keeps the oxygen from being able to bond to anything else.
Answered by Ken Whelan - Wed Aug 26 14:49:43 2009
Q. Why does N2O support combustion and H2O not support combustion?
Asked by nikkindeet - Wed Aug 26 14:42:44 2009 - - 3 Answers - 0 Comments
A. The reason is the strength of the bonds between the atoms. N2O is more volatile because of the weaker bond between the atoms in the molecule. When those atoms break apart, energy is released and thus, burns. H20 if exposed to the correct energy would burn, but it would take a lot. While oxygen is necessary for any kind of combustible reaction, it doesn't burn when connected to hydrogen as in the way it is connected in water because the bonds are extremely strong. The hydrogen keeps the oxygen from being able to bond to anything else.
Answered by Ken Whelan - Wed Aug 26 14:49:43 2009
What are the different N2O ligands?
Q. Our teacher asked us to look for N2O ligands. I can't understand what ligands are, can someone tell me some of N2O lignads?
Asked by sachiko s - Fri Jan 2 12:20:07 2009 - - 1 Answers - 0 Comments
A. Ligands are electron rich particles (atoms or ions or molecular ions) that have at least one pair of non bonding electrons which they use to form co- ordinate or dative bonds with an electron deficient atom or ion (usually with transition metal atoms or their ions). The product formed after ligands have formed co-ordinate bonds with metal atoms or ions are then called complex molecules (or ions). Nitrogen atom has a pair of non bonding electrons which it can use to form co-ordinate bond with a metal atom. Ligands involving nitrogen atom include NH3 (ammonia), NH2CH2CH2NH2 (ethylenediamine), N-O2 (nitrite), CN (cyanide), C5H5N (pyridine)
Answered by A_R - Fri Jan 2 14:21:40 2009
Q. Our teacher asked us to look for N2O ligands. I can't understand what ligands are, can someone tell me some of N2O lignads?
Asked by sachiko s - Fri Jan 2 12:20:07 2009 - - 1 Answers - 0 Comments
A. Ligands are electron rich particles (atoms or ions or molecular ions) that have at least one pair of non bonding electrons which they use to form co- ordinate or dative bonds with an electron deficient atom or ion (usually with transition metal atoms or their ions). The product formed after ligands have formed co-ordinate bonds with metal atoms or ions are then called complex molecules (or ions). Nitrogen atom has a pair of non bonding electrons which it can use to form co-ordinate bond with a metal atom. Ligands involving nitrogen atom include NH3 (ammonia), NH2CH2CH2NH2 (ethylenediamine), N-O2 (nitrite), CN (cyanide), C5H5N (pyridine)
Answered by A_R - Fri Jan 2 14:21:40 2009
A sample of N2O effuses from a container in 46 seconds?
Q. How long would it take the same amount of gaseous I2 to effuse from the same container under identical conditions?
Asked by Leondra - Sun Jun 28 02:22:11 2009 - - 1 Answers - 1 Comments
A. 46 / rate I2 = square root( 253.8 g/mol/ 44.01 g/mol) = 2.40 rate I2 = 19 s ( Graham's law)
Answered by Dr.A - Sun Jun 28 02:49:02 2009
Q. How long would it take the same amount of gaseous I2 to effuse from the same container under identical conditions?
Asked by Leondra - Sun Jun 28 02:22:11 2009 - - 1 Answers - 1 Comments
A. 46 / rate I2 = square root( 253.8 g/mol/ 44.01 g/mol) = 2.40 rate I2 = 19 s ( Graham's law)
Answered by Dr.A - Sun Jun 28 02:49:02 2009
how can i do my N2O molecule?
Q. please can somebody explain me! how can i make it!? i dont know if the oxige is the central atom, and covalent bonds between the nitrogen and oxygen?
Asked by M.A. - Thu Mar 5 14:37:01 2009 - - 2 Answers - 0 Comments
Q. please can somebody explain me! how can i make it!? i dont know if the oxige is the central atom, and covalent bonds between the nitrogen and oxygen?
Asked by M.A. - Thu Mar 5 14:37:01 2009 - - 2 Answers - 0 Comments
How do I balance the equation NH3 + NO2 --> N2O + H2O?
Q. How do I balance this chemical equation? It is a bonus question in one of my classes that will earn me much needed points! But, every time i think I have it balanced, something is still off! I can't get it to work! HELP!
Asked by lil frenchie - Wed Jan 30 19:56:58 2008 - - 2 Answers - 0 Comments
A. In this case, you must also account for the oxidation-reduction of the N's. 2NO2 + 6H+ + 6e- --> N2O + 3H2O 2NH3 + 8OH- --> N2O + 7H2O + 8e- Multiply the first equation by 8 and the second equation by 6 (to balance the electrons) 16NO2 + 12NH3 +48H2O --> 14N2O + 66H2O Subtract 48 waters 16NO2 + 12NH3 --> 14N2O + 18H2O Divide by 2 8NO2 + 6NH3 --> 7N2O + 9H2O That looks balanced to me.
Answered by KennyB - Wed Jan 30 20:16:13 2008
Q. How do I balance this chemical equation? It is a bonus question in one of my classes that will earn me much needed points! But, every time i think I have it balanced, something is still off! I can't get it to work! HELP!
Asked by lil frenchie - Wed Jan 30 19:56:58 2008 - - 2 Answers - 0 Comments
A. In this case, you must also account for the oxidation-reduction of the N's. 2NO2 + 6H+ + 6e- --> N2O + 3H2O 2NH3 + 8OH- --> N2O + 7H2O + 8e- Multiply the first equation by 8 and the second equation by 6 (to balance the electrons) 16NO2 + 12NH3 +48H2O --> 14N2O + 66H2O Subtract 48 waters 16NO2 + 12NH3 --> 14N2O + 18H2O Divide by 2 8NO2 + 6NH3 --> 7N2O + 9H2O That looks balanced to me.
Answered by KennyB - Wed Jan 30 20:16:13 2008
One of these would not react with molecular oxygen. NO, N2O, SO2, SO3, P4O6. What is it and why?
Q. I have no idea how to solve this problem. I will be honest, yes, this is homework. Any help anyone can give is appreciated! I have no idea how I begin to solve this problem. I will be honest, yes, this is homework. Any help anyone can give is appreciated! I hate Chemistry and I just don't understand parts of it.
Asked by allienoble20 - Sat Oct 6 23:02:57 2007 - - 1 Answers - 0 Comments
A. SO3 will not react with oxygen because it has reached its maximum positive oxidation state. No electrons left, in short!
Answered by Gervald F - Sun Oct 7 03:47:44 2007
Q. I have no idea how to solve this problem. I will be honest, yes, this is homework. Any help anyone can give is appreciated! I have no idea how I begin to solve this problem. I will be honest, yes, this is homework. Any help anyone can give is appreciated! I hate Chemistry and I just don't understand parts of it.
Asked by allienoble20 - Sat Oct 6 23:02:57 2007 - - 1 Answers - 0 Comments
A. SO3 will not react with oxygen because it has reached its maximum positive oxidation state. No electrons left, in short!
Answered by Gervald F - Sun Oct 7 03:47:44 2007
What is the structural formula (or dot and Cross diagram) of Nitrous oxide (N2O)?
Q. Please need help, quick! Need dot and cross diagram or the structural formula...
Asked by Fefinu - Tue Sep 2 09:04:24 2008 - - 2 Answers - 0 Comments
A. There are several resonance (canonical) forms that you can draw for N2O ... several of which will end up with unpaird electrons. Perhaps N///N-->O is the simplest (where /// is a triple bond; and --> is a dative bond)?
Answered by CB - Tue Sep 2 09:42:05 2008
Q. Please need help, quick! Need dot and cross diagram or the structural formula...
Asked by Fefinu - Tue Sep 2 09:04:24 2008 - - 2 Answers - 0 Comments
A. There are several resonance (canonical) forms that you can draw for N2O ... several of which will end up with unpaird electrons. Perhaps N///N-->O is the simplest (where /// is a triple bond; and --> is a dative bond)?
Answered by CB - Tue Sep 2 09:42:05 2008
Calculate the kinetic energy (in joules) of an N2O molecule traveling at this speed. question below?
Q. Nitrous oxide, N2O, has been used as a dental anesthetic. Suppose that the average speed of an N2O molecule at 25 C is 369 m/s. (It is actually 379 m/s.) Calculate the kinetic energy (in joules) of an N2O molecule traveling at this speed.
Asked by MICHAEL s - Mon Mar 31 20:12:00 2008 - - 1 Answers - 0 Comments
Q. Nitrous oxide, N2O, has been used as a dental anesthetic. Suppose that the average speed of an N2O molecule at 25 C is 369 m/s. (It is actually 379 m/s.) Calculate the kinetic energy (in joules) of an N2O molecule traveling at this speed.
Asked by MICHAEL s - Mon Mar 31 20:12:00 2008 - - 1 Answers - 0 Comments
Nitrous oxide (N2O) is also called "laughing gas'. It can be prepared by the thermal decomposition of ammonium
Q. nitrate (NH4nO3). The other product is water. a. write a balanced equation for the reaction b. how many grams of N2O are formed if 0.46 mole of NH4NO3 is used in the reaction?
Asked by charmaine w - Tue Dec 11 23:21:50 2007 - - 1 Answers - 0 Comments
A. a) NH4NO3 ---> N2O + 2H20 b) .46 mol NH4NO3 X (1 mol N20/1 mol NH4NO3) = .46 mol N20 .46 mol N20 X (44g/mol) = 20.24g
Answered by Josh B - Tue Dec 11 23:27:49 2007
Q. nitrate (NH4nO3). The other product is water. a. write a balanced equation for the reaction b. how many grams of N2O are formed if 0.46 mole of NH4NO3 is used in the reaction?
Asked by charmaine w - Tue Dec 11 23:21:50 2007 - - 1 Answers - 0 Comments
A. a) NH4NO3 ---> N2O + 2H20 b) .46 mol NH4NO3 X (1 mol N20/1 mol NH4NO3) = .46 mol N20 .46 mol N20 X (44g/mol) = 20.24g
Answered by Josh B - Tue Dec 11 23:27:49 2007
A sample of N2O gas has a density of 2.95 g/L at 298K. whar must be the pressure of the gas in mmHg?
Q. if you could even explain how to approach the problem that would be great. thanks!
Asked by kinky - Sun Oct 28 20:31:27 2007 - - 1 Answers - 0 Comments
A. Use the fact that any gas occupies 22.4 liters per mole at STP to compute your answer.
Answered by rscanner - Sun Oct 28 20:35:03 2007
Q. if you could even explain how to approach the problem that would be great. thanks!
Asked by kinky - Sun Oct 28 20:31:27 2007 - - 1 Answers - 0 Comments
A. Use the fact that any gas occupies 22.4 liters per mole at STP to compute your answer.
Answered by rscanner - Sun Oct 28 20:35:03 2007
What is the formula weight for Nitrous oxide N2O?
Q. What is the formula weight for Nitrous oxide N2O?
Asked by Susan - Wed Sep 23 17:13:13 2009 - - 2 Answers - 0 Comments
A. O= 16 N 14 14+14+16= 44
Answered by JoseEnrique - Wed Sep 23 17:16:39 2009
Q. What is the formula weight for Nitrous oxide N2O?
Asked by Susan - Wed Sep 23 17:13:13 2009 - - 2 Answers - 0 Comments
A. O= 16 N 14 14+14+16= 44
Answered by JoseEnrique - Wed Sep 23 17:16:39 2009
how many grams of NH4NO3 are required to produce 33.0 g N2O?
Q. Laughing gas (nitrous oxide, N2O) is sometimes used as an anesthetic in dentistry. It is produced when ammonium nitrate is decomposed according to the following reaction. NH4NO3(s)-->N2O(g)+2H2O(l ) also, how many grams of water are produced in this reaction?
Asked by hellllerrrr - Tue Jan 27 20:30:31 2009 - - 1 Answers - 0 Comments
A. You've got three elements involved here: H: 1 g/mol, N: 14 g/mol, O: 16 g/mol N2O is 44 g/mol (2*14+16), NH4NO3 is 80g/mol (4*1+2*14+3*16) If you want 33g of N2O this equals 3/4 mol, so you also need 3/4 mol NH4NO3 which is 60g The water produced is the weight difference so it's 27g
Answered by Starfury - Tue Jan 27 20:42:01 2009
Q. Laughing gas (nitrous oxide, N2O) is sometimes used as an anesthetic in dentistry. It is produced when ammonium nitrate is decomposed according to the following reaction. NH4NO3(s)-->N2O(g)+2H2O(l ) also, how many grams of water are produced in this reaction?
Asked by hellllerrrr - Tue Jan 27 20:30:31 2009 - - 1 Answers - 0 Comments
A. You've got three elements involved here: H: 1 g/mol, N: 14 g/mol, O: 16 g/mol N2O is 44 g/mol (2*14+16), NH4NO3 is 80g/mol (4*1+2*14+3*16) If you want 33g of N2O this equals 3/4 mol, so you also need 3/4 mol NH4NO3 which is 60g The water produced is the weight difference so it's 27g
Answered by Starfury - Tue Jan 27 20:42:01 2009
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