NounSingular radius radius (plural radii or radiuses)
Related termsFrom Wiktionary under the GNU Free Documentation License. In classical geometry, a radius of a circle or sphere is any line segment from its center to its perimeter. By extension, the radius of a circle or sphere is the length of any such segment, which is half the diameter. More generally — in geometry, science, engineering, and many other contexts — the radius of something (e.g., a cylinder, a polygon, a mechanical part, a hole, or a galaxy) usually refers to the distance from its center or axis of symmetry to a point in the periphery: usually the point farthest from the center or axis (the outermost or maximum radius), or, sometimes, the closest point (the short or minimum radius). If the object does not have an obvious center, the term may refer to its circumradius, the radius of its circumscribed circle or circumscribed sphere. In either case, the radius may be more than half the diameter (which is usually defined as the maximum distance between any two points of the figure). The inradius of a geometric figure is usually the radius of the largest circle or sphere contained in it. The inner radius of a ring, tube or other hollow object is the radius of its cavity. The radius of a regular polygon (or polyhedron) is the distance from its center to any of its vertices; which is also its circumradius. The inradius of a regular polygon is also called apothegm. In graph theory, the radius of a graph is the minimum over all vertices u of the maximum distance from u to any other vertex of the graph. The name comes from Latin radius, meaning "ray" but also the spoke of a chariot wheel. The plural in English is radii (as in Latin), but radiuses can be used, though it rarely is. From Wikipedia under the
GNU Free Documentation License The radius of a solid sphere is twice the radius of a second solid sphere. What is the ratio of? Q. The radius of a solid sphere is twice the radius of a second solid sphere. What is the ratio of a) their volumes, b) their surface areas? Asked by Jennifer T - Mon May 5 22:30:10 2008 - - 2 Answers - 0 Comments A. vb/vx=(rb/rs)^3 vb:vs=9:1 ab/as=(rb/rs)^2 ab:as=4:1 Answered by someone else - Mon May 5 22:33:32 2008 What is the radius of the circle circumscribing the pentagon in a five sided star? Q. Here' s an imperfect picture of what I mean (drawn in Paint) I want to find the radius of the circle circumscribing the pentagon in the star (the length of the red line). The radius of the larger circle is known. Asked by S - Sun Apr 6 18:05:13 2008 - - 1 Answers - 0 Comments A. OK -- draw yourself a nice picture and give it some labels. This is going to be a little wild. (There may be another way that's a little more suave, but we're going to try it this way right now . . .) Orient your star so that there is a point of the star at the top of the diagram. Label this top point "A." Label the other four points of the star in a clockwise fashion -- "B," "C," "D," and "E." Now -- draw a vertical line from "A", through the center of the circle, until it hits the bottom of the circle. Label the point where this line intersects the bottom of the circle "F." Label the point where this line intersects the bottom, concave part of the star "G." Next -- connect points "C" and "F" with another line. Now it's time to… [cont.] Answered by Answer Guy - Sun Apr 6 21:28:30 2008 How do i find gravity given a radius and an altitude?
Q. Using g = m/r^2? What is the acceleration due to gravity at an altitude of 1.00 x 10^6 above the earth's surface, given that the radius of the earth is 6.38 x 10^6 m? How do i go about solving that? Asked by Voldemort - Thu Dec 20 21:07:38 2007 - - 2 Answers - 1 Comments A. Let's try this: First: Fg = GMm/r^2 So, if you are only changing r then write Fg1 = GMm/r1^2. Now write Fg1 / Fg2 = GMm/r1^2 divided by GMm/r2^2 Canceling gives Fg1 / Fg2 = r2^2/r1^2 Um ... you can do the same thing with g, since g = Fg/m .: g1/g2 = r2^2/r1^2 (you can work it out using the same procedure as in the previous paragraph. Maybe I should just have started with this, but I am figuring it out as I type). Since you know g1 = 9.81/m/s/s and r1=6.38E6 and r2=1.00E6 + r1 (you MUST add the earth's radius to the altitude. ALWAYS do this anytime you see the code word ALTITUDE), you know all of the variables in the equation except for g2 --- which is what you are trying to find. Answered by mk_gecko - Thu Dec 20 21:23:21 2007 From Yahoo Answer Search: "radius" EUFA: Authorities Need To Postpone Mondays Radius AGM
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