The time translation

Business Standard, India

In a similar time frame Vilfred Pareto with his Pareto distribution started the work on fractional Brownian motion. One can easily generate a random sample from Pareto distribution. Bachelier and Pareto were on two sides of the Brownian randomness. ...

Can anyone help me with my Pre-Calculus?
Q. Can anyone help me with my pre-calculus homework? I am stuck trying to understand how to simplify a fractional expression. Like for example one of my problems is 3t over t + 2 (+) 4t over t-2 (-) 18 over t to the second power - 4. I made t to the second power minus 4 (t-2)(t+4) then I multiplied it across the top, but once I get my polynomial I can't figure out how to break it up. I think I get 5t to the second power + 9t -18 Can anyone help me? Thanks you all!
Asked by jer_n_me - Sun Sep 14 00:28:28 2008 - - 4 Answers - 0 Comments

A. first off, (t-2)(t+4) is not the proper factoring. it is (t+2)(t-2) just like adding and subtracting normal fractions, you need a common denominator. lucky for you, the common denominator is (t+2)(t-2)! Now what you want to do is look at each fraction separately. -Multiply the first one by (t-2) over (t-2) *you can do this because it is the same as multiplying by 1 over 1* -Multiply the second one by (t+2) over (t+2). -The third fraction does not need to be multiplied by anything: it already has the proper denominator. *** From here, you should have... 3t(t-2) over t^2-4 PLUS 4t(t+2) overt^2+4 MINUS 18 over t^2+4*** what you do now is preform the operations being asked, multiply out everything, then simplify. the answer i got was… [cont.]
Answered by Melissa - Sun Sep 14 00:41:53 2008

Calculus Challenges!?
Q. It would be so helpful if you could answer even a few... Find f(x+ x) for f(x) = x^2-2x-3 Find (f(x+ x)-f(x))/( x) if f(x) = 8x^2 + 1 what do i have to do with the change of x? rewrite with fractional exponents 1/ sqrt of ((1 + z^2)^3) Solve xy^1 + y = 1 + y^1 for y^1 Find the solution of the equations for 0 less than or equal to x less than or equal to 2pi 2sin^2 = 1- sin 2tan -sec^2 =0 sin2 + sin = 0 what does arcsin/arctan/arccos mean / why are they different from sin/tan/cos?
Asked by crazicarly989 - Sun Sep 2 16:36:05 2007 - - 2 Answers - 0 Comments

A. 1. (x+ x)^2 - 2(x+ x) - 3 2. {8 [x^2 + 2x x + ( x)^2] +1 - 8x^2 - 1} / x = (8x^2 + 16x x + 8( x)^2 - 8x^2) / x = (16x x + 8( x)^2) = x = 16x + 8 x You'll learn what do do with x when you get to limits and derivatives. 3. (1 + z^2)^(-3/2) 4. x y^1 - y^1 = 1 - y y^1 (x - 1) = 1 - y y^1 = (1 - y) / (x - 1) 5. 2sin^2( ) + sin + 1 = 0 Use the quadratic formula with sin = x sin = [-1 +/- sqrt (-7)] / 4 This is imaginary, so there are no solutions between 0 and 2pi, inclusive. 6. Use the pythagorean theorem to convert sec^2 into tan^2. tan^2 - 2tan + 1 = 0 Quadratic formula gives: tan = (2 +/- sqrt (0)) / 2 tan = 1 = pi/4 7. Factor: sin (sin + 1) = 0 sin = 0, -1 = 0, pi, 3pi/2, 2pi arcsin, arccos, arctan, and sin^-1,… [cont.]
Answered by mediaptera - Sun Sep 2 17:08:03 2007

Pre-Calculus Problem?
Q. Hey guys, need help on the following problem: Solve the following equations given that 0 x < 2pi. Give exact, fractional answers. a. 2cos^2(x) + 3sin(x) - 3 = 0 b. sin^4(x) + cos^4(x) = 1/2 Thanks for any and all help!!!
Asked by The Great Bamboozle - Sun Apr 27 11:37:23 2008 - - 1 Answers - 0 Comments

A. You might want to try the Mathway website This is your first problem done with steps:
Answered by Yvonne and Scott S - Sun Apr 27 11:43:37 2008