JAVA array/for loop?
Q. i know how to determine if a number is odd or even using java program w/ prompt box.. but i don't know how to execute this kind of program. i know the syntax but not the logic enter number of inputs: ___ (consider we will input 5 nums) INPUT 1: ___ INPUT 2: ___ INPUT 3: ___ INPUT 4: ___ INPUT 5: ___ there are ___ even numbers [ _,_,_,_,_ ] (number of even numbers inputted) there are ___ odd numbers [ _,_,_,_,_ ] (number of ODD numbers inputted) ***please help me guys... i don't know how to add array in my program!***
Asked by pink16 - Sun Jul 20 21:29:06 2008 - - 1 Answers - 0 Comments

A. import java.util.ArrayList; import java.util.List; import java.util.Scanner; public class EvenOdd { public static void main ( String argv[]) { System.out.print("Enter number of inputs: "); Scanner input = new Scanner(System.in); int numValues = input.nextInt(); // Obtain the number of values // Create a list to hold the values List vals = new ArrayList(numVal ues); // Read in all the values for (int i = 0; i < numValues; i++) { System.out.print("INPUT " + i + " : "); vals.add(input.nextInt()) ; } // Now count the number of evens and odds int numEvens = 0; int numOdds = 0; for (int eachValue : vals) { if (eachValue % 2 == 0 ) numEvens++; else … [cont.]
Answered by Truly W - Wed Jul 23 23:23:12 2008