How do I Balance this equation? : "Cu(s) + HNO3(aq) -> H2O(l) + NO2(g) + Cu(NO3)2(aq)"?
Q. When I try to balance it, the oxygens always are unbalanced. But it said that I allowed to use coefficients "1" and "0" (0 meaning none of that substance is present in the equation.)
Asked by Kotomi - Sat Sep 27 16:26:47 2008 - - 4 Answers - 0 Comments
A. That problem should not be given to any human to solve Cu(s) + 4HNO3(aq) > Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) That is one of the harder reactions
Answered by syntroniks - Sat Sep 27 16:34:47 2008
Q. When I try to balance it, the oxygens always are unbalanced. But it said that I allowed to use coefficients "1" and "0" (0 meaning none of that substance is present in the equation.)
Asked by Kotomi - Sat Sep 27 16:26:47 2008 - - 4 Answers - 0 Comments
A. That problem should not be given to any human to solve Cu(s) + 4HNO3(aq) > Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) That is one of the harder reactions
Answered by syntroniks - Sat Sep 27 16:34:47 2008
Write balanced net ionic equation for the reactions, if any, that occur between a. K2CO3 (aq) and Cu(NO3)2 ..?
Q. Write balanced net ionic equation for the reactions, if any, that occur between a. K2CO3 (aq) and Cu(NO3)2 (aq), b. Fe(NO3)2 (aq) and HCl(aq), c. Bi(OH)3S and HNO3 (aq).
Asked by Sana A - Thu Jan 29 01:55:03 2009 - - 2 Answers - 0 Comments
A. All you can do is switch cations and anions in thesese types. K2CO3 + Cu(NO3)2 = 2KNO3 + CuCO3 Now look up your solubility tables. CuCO3 is only slightl soluble so the reaction would be K2CO3(aq) + Cu(NO3)2(aq) = 2KNO3(aq) + CuCO3(s)
Answered by Otts Shoals - Thu Jan 29 02:33:36 2009
Q. Write balanced net ionic equation for the reactions, if any, that occur between a. K2CO3 (aq) and Cu(NO3)2 (aq), b. Fe(NO3)2 (aq) and HCl(aq), c. Bi(OH)3S and HNO3 (aq).
Asked by Sana A - Thu Jan 29 01:55:03 2009 - - 2 Answers - 0 Comments
A. All you can do is switch cations and anions in thesese types. K2CO3 + Cu(NO3)2 = 2KNO3 + CuCO3 Now look up your solubility tables. CuCO3 is only slightl soluble so the reaction would be K2CO3(aq) + Cu(NO3)2(aq) = 2KNO3(aq) + CuCO3(s)
Answered by Otts Shoals - Thu Jan 29 02:33:36 2009
Balance this reaction by half-reactions: Cu(s) + NO3-1 (aq) ------ACID----Cu+2 (aq) + NO2 (g)?
Q. Please help! This is my call out to those who understand these equations. i have failed to make this equation clear. The dotted lines with acid is an arrow with Acid written above the arrow.
Asked by Gibby - Sat Dec 6 20:32:24 2008 - - 1 Answers - 0 Comments
A. Cu + NO3- + H+ = Cu+2 + NO2 + H2O + NO3- the copper change is -2 electrons, the nitrogen +1 so Cu + 3NO3- + 4H+ = Cu+2 + 2NO2 + 2H2O + NO3-
Answered by Otts Shoals - Sat Dec 6 20:57:58 2008
Q. Please help! This is my call out to those who understand these equations. i have failed to make this equation clear. The dotted lines with acid is an arrow with Acid written above the arrow.
Asked by Gibby - Sat Dec 6 20:32:24 2008 - - 1 Answers - 0 Comments
A. Cu + NO3- + H+ = Cu+2 + NO2 + H2O + NO3- the copper change is -2 electrons, the nitrogen +1 so Cu + 3NO3- + 4H+ = Cu+2 + 2NO2 + 2H2O + NO3-
Answered by Otts Shoals - Sat Dec 6 20:57:58 2008
(NH4)2S(aq)+Cu(NO3)2(aq)- ->CuS9s)+NH4NO3(aq)?
Q. What is this in the balanced equation, ionic equation, and the net ionic equation?
Asked by sweetserenity - Sat Apr 4 19:27:35 2009 - - 1 Answers - 0 Comments
A. (NH4)2S(aq)+ Cu(NO3)2(aq)---> CuS(s)+2 NH4NO3(aq) NH4 +1 NO3+1 S-2 Cu+2
Answered by science teacher - Sat Apr 4 19:34:24 2009
Q. What is this in the balanced equation, ionic equation, and the net ionic equation?
Asked by sweetserenity - Sat Apr 4 19:27:35 2009 - - 1 Answers - 0 Comments
A. (NH4)2S(aq)+ Cu(NO3)2(aq)---> CuS(s)+2 NH4NO3(aq) NH4 +1 NO3+1 S-2 Cu+2
Answered by science teacher - Sat Apr 4 19:34:24 2009
Chemistry help please. Net-ionic equation.?
Q. This one is correct but I can't figure out the net-ionic equation... Balance the following reaction equations. 1 Cu(s) + 4 HNO3(aq) 2 NO2(g) + 2 H2O(l) + 1 Cu(NO3)2(aq) Balance the Net Ionic equation for this reaction. ___ NO3-(aq) +___H+(aq) + ___Cu(s) ___NO2(g) + ___H2O(l) + ___NO3-(aq) + ___Cu2+(aq) Fill in the blanks. And on net-ionic equations the spectator ions have a 0 Coefficient. Sorry Here are the arrows. 1 Cu(s) + 4 HNO3(aq) -> 2 NO2(g) + 2 H2O(l) + 1 Cu(NO3)2(aq) Balance the Net Ionic equation for this reaction. ___ NO3-(aq) +___H+(aq) + ___Cu(s) -> ___NO2(g) + ___H2O(l) + ___NO3-(aq) + ___Cu2+(aq)
Asked by Hinata - Sun Mar 1 15:00:51 2009 - - 1 Answers - 0 Comments
Q. This one is correct but I can't figure out the net-ionic equation... Balance the following reaction equations. 1 Cu(s) + 4 HNO3(aq) 2 NO2(g) + 2 H2O(l) + 1 Cu(NO3)2(aq) Balance the Net Ionic equation for this reaction. ___ NO3-(aq) +___H+(aq) + ___Cu(s) ___NO2(g) + ___H2O(l) + ___NO3-(aq) + ___Cu2+(aq) Fill in the blanks. And on net-ionic equations the spectator ions have a 0 Coefficient. Sorry Here are the arrows. 1 Cu(s) + 4 HNO3(aq) -> 2 NO2(g) + 2 H2O(l) + 1 Cu(NO3)2(aq) Balance the Net Ionic equation for this reaction. ___ NO3-(aq) +___H+(aq) + ___Cu(s) -> ___NO2(g) + ___H2O(l) + ___NO3-(aq) + ___Cu2+(aq)
Asked by Hinata - Sun Mar 1 15:00:51 2009 - - 1 Answers - 0 Comments
need help balancing this equation???
Q. Cu(s) + AgNO3 (aq) --> Cu(NO3) (aq) + [ ]
Asked by Margaret T - Thu Nov 15 15:40:42 2007 - - 1 Answers - 0 Comments
A. Cu(s) + 2AgNO3(aq) ===> Cu(NO3)2(aq) + 2Ag(s)
Answered by steve_geo1 - Thu Nov 15 15:44:22 2007
Q. Cu(s) + AgNO3 (aq) --> Cu(NO3) (aq) + [ ]
Asked by Margaret T - Thu Nov 15 15:40:42 2007 - - 1 Answers - 0 Comments
A. Cu(s) + 2AgNO3(aq) ===> Cu(NO3)2(aq) + 2Ag(s)
Answered by steve_geo1 - Thu Nov 15 15:44:22 2007
Why is this equation not balanced?
Q. Started with: Cu(NO3)2(aq) + KOH(aq) Cu(OH)2(s) + KNO3(aq) And to balance it I added a 2 in front of the KOH molecule and the KNO3. Cu(NO3)2(aq) + 2KOH(aq) Cu(OH)2(s) + 2KNO3(aq) Why is this wrong? Did I miss something? The online homework system said it was wrong.
Asked by Who - Sat Oct 17 15:31:30 2009 - - 1 Answers - 0 Comments
A. who said this was wrong. could it be because you end up with a precipitate in the end? but i dont see how that would make this unbalanced. you should ask your teacher or professor because i dont see anything wrong. I just found a website that balances equations. and this is giving me the same answer.
Answered by dr. wii - Sat Oct 17 15:39:54 2009
Q. Started with: Cu(NO3)2(aq) + KOH(aq) Cu(OH)2(s) + KNO3(aq) And to balance it I added a 2 in front of the KOH molecule and the KNO3. Cu(NO3)2(aq) + 2KOH(aq) Cu(OH)2(s) + 2KNO3(aq) Why is this wrong? Did I miss something? The online homework system said it was wrong.
Asked by Who - Sat Oct 17 15:31:30 2009 - - 1 Answers - 0 Comments
A. who said this was wrong. could it be because you end up with a precipitate in the end? but i dont see how that would make this unbalanced. you should ask your teacher or professor because i dont see anything wrong. I just found a website that balances equations. and this is giving me the same answer.
Answered by dr. wii - Sat Oct 17 15:39:54 2009
How do you balance this oxidation reduction equation?
Q. CuS(c) + NO3-(aq) ---> Cu+2(aq) + NO2(g) + S(c)
Asked by sv student - Mon May 12 19:50:37 2008 - - 2 Answers - 0 Comments
A. CuS+ 2NO3 -> Cu + 3NO2 + S
Answered by booster seat - Mon May 12 19:56:01 2008
Q. CuS(c) + NO3-(aq) ---> Cu+2(aq) + NO2(g) + S(c)
Asked by sv student - Mon May 12 19:50:37 2008 - - 2 Answers - 0 Comments
A. CuS+ 2NO3 -> Cu + 3NO2 + S
Answered by booster seat - Mon May 12 19:56:01 2008
Why does copper added to silver nitrate turn blue?
Q. Here is the balanced chemical equation: Cu(s)+2AgNO3(aq) Cu(NO3)2(aq) + 2Ag(s). But I don't understand how I am supposed to know WHY the aqueous solution turned blue. I guess what I'm asking is, what specifically caused the blue color? And why wasn't the original solution blue?
Asked by canadienne - Tue Sep 30 06:49:33 2008 - - 2 Answers - 0 Comments
A. Copper Nitrate forms blue crystals which dissolve in water. Transition metal salts often form colored crystals. Since the other reaction product is metallic silver precipitate, and everyone knows what silver looks like, the blue is from the copper nitrate by process of elimination. The original solution was not blue because silver nitrate is colorless/slight gray when in solution and Cu(s) is just copper metal.
Answered by virgo47tp - Tue Sep 30 06:56:31 2008
Q. Here is the balanced chemical equation: Cu(s)+2AgNO3(aq) Cu(NO3)2(aq) + 2Ag(s). But I don't understand how I am supposed to know WHY the aqueous solution turned blue. I guess what I'm asking is, what specifically caused the blue color? And why wasn't the original solution blue?
Asked by canadienne - Tue Sep 30 06:49:33 2008 - - 2 Answers - 0 Comments
A. Copper Nitrate forms blue crystals which dissolve in water. Transition metal salts often form colored crystals. Since the other reaction product is metallic silver precipitate, and everyone knows what silver looks like, the blue is from the copper nitrate by process of elimination. The original solution was not blue because silver nitrate is colorless/slight gray when in solution and Cu(s) is just copper metal.
Answered by virgo47tp - Tue Sep 30 06:56:31 2008
Writing and balancing equations?
Q. Write a balanced chemical equation for each of the following. Express your answer as a chemical equation. Identify all of the phases in your answer. 1) Solid copper reacts with solid sulfur to form solid copper(I) sulfide. 2) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. 3) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. 4) Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water. ___ Balance each of the following chemical equations.Express your answer as a chemical equation. Identify all of the phases in your answer. 1) Na2S (aq) + Cu (NO3)2 ( aq) ---> NaNO3 (aq) + CuS (s) 2) HCl (a [cont.]
Asked by vanillax33 - Fri Oct 2 22:50:29 2009 - - 1 Answers - 0 Comments
A. 1) 8Cu(s) + S8(s) ---> 8CuS(s) 2) 2SO2(g) + O2(g) ---> 2SO3(g) 3) 4HCl(aq) + MnO2(s) ---> MnCl2(aq) + 2H2O(l) + Cl2(g) ___ 1) Na2S (aq) + Cu (NO3)2 ( aq) ---> 2NaNO3 (aq) + CuS (s) 2) 4HCl (aq) + O2 ( g) ---> 2H2O ( l) + 2Cl2 ( g) 3) 2H2 (g) + O2 (g) ---> 2H2O (l) 4) FeS (s) + 2HCl (aq) ---> FeCl2 (aq) + H2S (g)
Answered by sailor astra - Sat Oct 3 01:01:55 2009
Q. Write a balanced chemical equation for each of the following. Express your answer as a chemical equation. Identify all of the phases in your answer. 1) Solid copper reacts with solid sulfur to form solid copper(I) sulfide. 2) Sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas. 3) Aqueous hydrochloric acid reacts with solid manganese(IV) oxide to form aqueous manganese(II) chloride, liquid water, and chlorine gas. 4) Liquid benzene (C6H6) reacts with gaseous oxygen to form carbon dioxide and liquid water. ___ Balance each of the following chemical equations.Express your answer as a chemical equation. Identify all of the phases in your answer. 1) Na2S (aq) + Cu (NO3)2 ( aq) ---> NaNO3 (aq) + CuS (s) 2) HCl (a [cont.]
Asked by vanillax33 - Fri Oct 2 22:50:29 2009 - - 1 Answers - 0 Comments
A. 1) 8Cu(s) + S8(s) ---> 8CuS(s) 2) 2SO2(g) + O2(g) ---> 2SO3(g) 3) 4HCl(aq) + MnO2(s) ---> MnCl2(aq) + 2H2O(l) + Cl2(g) ___ 1) Na2S (aq) + Cu (NO3)2 ( aq) ---> 2NaNO3 (aq) + CuS (s) 2) 4HCl (aq) + O2 ( g) ---> 2H2O ( l) + 2Cl2 ( g) 3) 2H2 (g) + O2 (g) ---> 2H2O (l) 4) FeS (s) + 2HCl (aq) ---> FeCl2 (aq) + H2S (g)
Answered by sailor astra - Sat Oct 3 01:01:55 2009
Balancing Equations.?
Q. Please balance the following. Thank you. 1) ---Mg (cr) + --- HCl (aq) --- ---MgCl2 (aq) + --- H2 (g) 2) --- NaI (aq) + --- Cl2 (g) --- --- NaCl (aq) + ---I2 (cr) 3) --- KClO3 --- --- KCl (cr) + --- O2 (g) 4) --- Cu (cr) + --- AgNO3 (aq) --- --- Cu(NO3)2 (aq) + --- Ag (cr) 5) --- NaCl(aq) --- H2SO4(aq) --- --- HCl(g) + --- Na2SO4(aq) 6) --- NaOH(aq) + --- H2SO4(aq) --- --- Na2SO4(cr) + --- H2O (g)
Asked by LYYY - Mon Mar 2 22:24:39 2009 - - 12 Answers - 0 Comments
A. Do u not understand it or r u just too lazy ??? Want a tip? Listen in class and actually ask if u have questions xoxo Lollie
Answered by Lollie - Mon Mar 2 22:29:04 2009
Q. Please balance the following. Thank you. 1) ---Mg (cr) + --- HCl (aq) --- ---MgCl2 (aq) + --- H2 (g) 2) --- NaI (aq) + --- Cl2 (g) --- --- NaCl (aq) + ---I2 (cr) 3) --- KClO3 --- --- KCl (cr) + --- O2 (g) 4) --- Cu (cr) + --- AgNO3 (aq) --- --- Cu(NO3)2 (aq) + --- Ag (cr) 5) --- NaCl(aq) --- H2SO4(aq) --- --- HCl(g) + --- Na2SO4(aq) 6) --- NaOH(aq) + --- H2SO4(aq) --- --- Na2SO4(cr) + --- H2O (g)
Asked by LYYY - Mon Mar 2 22:24:39 2009 - - 12 Answers - 0 Comments
A. Do u not understand it or r u just too lazy ??? Want a tip? Listen in class and actually ask if u have questions xoxo Lollie
Answered by Lollie - Mon Mar 2 22:29:04 2009
BALANCING EQUATIONS? a.s.a.p?!!?
Q. Balance the following equations after putting them in net ionic form i don'T think its saying to do half-Reaction method... I DON'T get it dang :[ 1) Cu(cr)+HNO3(aq)-->Cu(NO3) 2(aq)+NO(g)+H2O(l) 2) Fe(NO3)2(aq)+HNO3(aq)-->F e(NO3)3(aq)+NO(g)+H2O(l) 3) Zn(cr)+HNO3(aq)-->Zn(NO3) 2(aq)+NO2(g)+H2O(l) 4) CO(g)+I2O5(g)-->CO2(g)+I2 (g) thank you sooo much !
Asked by DUHH :D - Sun May 18 05:32:13 2008 - - 2 Answers - 0 Comments
A. These are all redox reactions. Why not use the half-reaction method since the reaction must be charge balanced as well as mass balanced? 3 (Cu --> Cu2+ + 2e-) 2( 4H+ + NO3-+ 3e- --> NO + 2H2O ) --- 8 H+ + 3 Cu + 2 NO3- --> 3 Cu2+ + 2 NO + 4 H2O === 2(Fe2+ --> Fe3+ + e-) 2H+ + 2e- --> H2 --- 2 Fe2+ + 2H+ --> 2 Fe3+ + H2 === Zn + 2H+ --> Zn2+ + H2 === 5 ( CO + H2O --> CO2 + 2 H+ + 2 e- ) 10 H+ + I2O5 + 10 e- --> I2 + 5 H2O --- 10 H+ + 5 CO + I2O5 + 5 H2O --> 5 CO2 + I2 + 10 H+ + 5 H2O simplify H+ and H2O both cancel out 5 CO + I2O5 --> 5 CO2 + I2 === With all due respect, Dr A's #1 is wrong. Copper doesn't liberate hydrogen from acid. Copper reacts with the nitrate ion in nitric acid to produce NO (or NO2).
Answered by pisgahchemist - Sun May 18 06:44:28 2008
Q. Balance the following equations after putting them in net ionic form i don'T think its saying to do half-Reaction method... I DON'T get it dang :[ 1) Cu(cr)+HNO3(aq)-->Cu(NO3) 2(aq)+NO(g)+H2O(l) 2) Fe(NO3)2(aq)+HNO3(aq)-->F e(NO3)3(aq)+NO(g)+H2O(l) 3) Zn(cr)+HNO3(aq)-->Zn(NO3) 2(aq)+NO2(g)+H2O(l) 4) CO(g)+I2O5(g)-->CO2(g)+I2 (g) thank you sooo much !
Asked by DUHH :D - Sun May 18 05:32:13 2008 - - 2 Answers - 0 Comments
A. These are all redox reactions. Why not use the half-reaction method since the reaction must be charge balanced as well as mass balanced? 3 (Cu --> Cu2+ + 2e-) 2( 4H+ + NO3-+ 3e- --> NO + 2H2O ) --- 8 H+ + 3 Cu + 2 NO3- --> 3 Cu2+ + 2 NO + 4 H2O === 2(Fe2+ --> Fe3+ + e-) 2H+ + 2e- --> H2 --- 2 Fe2+ + 2H+ --> 2 Fe3+ + H2 === Zn + 2H+ --> Zn2+ + H2 === 5 ( CO + H2O --> CO2 + 2 H+ + 2 e- ) 10 H+ + I2O5 + 10 e- --> I2 + 5 H2O --- 10 H+ + 5 CO + I2O5 + 5 H2O --> 5 CO2 + I2 + 10 H+ + 5 H2O simplify H+ and H2O both cancel out 5 CO + I2O5 --> 5 CO2 + I2 === With all due respect, Dr A's #1 is wrong. Copper doesn't liberate hydrogen from acid. Copper reacts with the nitrate ion in nitric acid to produce NO (or NO2).
Answered by pisgahchemist - Sun May 18 06:44:28 2008
help balancing equations?
Q. Write (reduced) balanced equations for each of the following by inserting the correct coefficients in the blanks. (Use the lowest possible coefficients.) (a) Cu(NO3)2(aq) + KOH(aq) --->Cu(OH)2(s) + KNO3(aq) (b) BCl3(g) + H2O(l) ---> H3BO3(s) + HCl(g) (c) CaSiO3(s) + HF(g)---> SiF4(g) + CaF2(s) + H2O(l) (d) (CN)2(g) + H2O(l) ---> H2C2O4(aq) + NH3(g)
Asked by Brittany M - Wed Jul 23 16:48:52 2008 - - 1 Answers - 0 Comments
Q. Write (reduced) balanced equations for each of the following by inserting the correct coefficients in the blanks. (Use the lowest possible coefficients.) (a) Cu(NO3)2(aq) + KOH(aq) --->Cu(OH)2(s) + KNO3(aq) (b) BCl3(g) + H2O(l) ---> H3BO3(s) + HCl(g) (c) CaSiO3(s) + HF(g)---> SiF4(g) + CaF2(s) + H2O(l) (d) (CN)2(g) + H2O(l) ---> H2C2O4(aq) + NH3(g)
Asked by Brittany M - Wed Jul 23 16:48:52 2008 - - 1 Answers - 0 Comments
Chemistry Lab DUE TMRW PLEASE HELP- Balancing Equations?
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 22:08:58 2009 - - 2 Answers - 0 Comments
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 22:08:58 2009 - - 2 Answers - 0 Comments
Balancing equations - stuck!!!! Please Help, it would be appreciated!?
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 22:50:06 2009 - - 1 Answers - 0 Comments
A. Sorry, wrong board. That's chem, not math.
Answered by unknown - Thu Mar 5 18:23:02 2009
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 22:50:06 2009 - - 1 Answers - 0 Comments
A. Sorry, wrong board. That's chem, not math.
Answered by unknown - Thu Mar 5 18:23:02 2009
Chemistry - Balancing Equations - Please Help!?
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 21:57:08 2009 - - 1 Answers - 0 Comments
A. Pb(NO3)2(aq) + 2Nal(aq) ---> PbI2 + 2NaNO3
Answered by unknown - Wed Mar 4 09:58:23 2009
Q. Pb(NO3)2(aq)+Nal(aq) Cu(NO3)2(aq)+NaOH(aq) KNO3(aq)+Na2CO3(aq) AgNO3(aq)+Nal(aq) Co(NO3)2(aq)+NaOH(aq) Fe(NO3)3(aq)+Na2CO3(aq) HCl(aq)+NaCO3(aq)
Asked by GlitzGirl - Sun Mar 1 21:57:08 2009 - - 1 Answers - 0 Comments
A. Pb(NO3)2(aq) + 2Nal(aq) ---> PbI2 + 2NaNO3
Answered by unknown - Wed Mar 4 09:58:23 2009
Am I right: I'm balancing some equations. please help!?
Q. a. AgNO3*(aq) + Cu(s) ---> Cu(NO3*)2*(aq) + Ag(s) my answer: 2AgNO3*(aq) + Cu(s) ---> Cu(NO3*)2*(aq) + 2Ag(s) b. BaCl2*(aq) + Na2*SO(aq) ---> BaSO4*(s) + NaCl(aq) my answer: BaCl2*(aq) + Na2*SO4*(aq) ---> BaSO4*(s) +2NaCl(aq) c. Cl2*(g) + NaBr(aq) ---> NaCl(aq) + Br2*(l) my answer: Cl2*(g) + 2NaBr(aq) ---> 2NaCl(aq) + Br2*(l) d. KClO2*(s) ---> KCl(s) + O2*(g) My answer: KClO2*(s) ---> 2KCl(s) + O2* e. AlCl3*(aq) + NH4*OH(aq) ---> NH4*Cl(aq) + Al(OH)3*(s) my answer: AlCl3*+ 3NH4*OH(aq) ---> 3NH4*Cl(aq) + 3Al(OH)3*(s) f. H2*(g) + O2*(g) ---> H2*O(g) my answer: H2* (g) + O2*(g) ---> 2H2*O(g) P.S. This * means that the numbers are not coefficients. =)
Asked by Mystery - Sat Nov 15 09:13:15 2008 - - 2 Answers - 0 Comments
A. a , b , c and e are balanced d . KClO2 >> KCl + O2 f . 2 H2 + O2 >> 2 H2O
Answered by Dr.A - Sat Nov 15 09:21:06 2008
Q. a. AgNO3*(aq) + Cu(s) ---> Cu(NO3*)2*(aq) + Ag(s) my answer: 2AgNO3*(aq) + Cu(s) ---> Cu(NO3*)2*(aq) + 2Ag(s) b. BaCl2*(aq) + Na2*SO(aq) ---> BaSO4*(s) + NaCl(aq) my answer: BaCl2*(aq) + Na2*SO4*(aq) ---> BaSO4*(s) +2NaCl(aq) c. Cl2*(g) + NaBr(aq) ---> NaCl(aq) + Br2*(l) my answer: Cl2*(g) + 2NaBr(aq) ---> 2NaCl(aq) + Br2*(l) d. KClO2*(s) ---> KCl(s) + O2*(g) My answer: KClO2*(s) ---> 2KCl(s) + O2* e. AlCl3*(aq) + NH4*OH(aq) ---> NH4*Cl(aq) + Al(OH)3*(s) my answer: AlCl3*+ 3NH4*OH(aq) ---> 3NH4*Cl(aq) + 3Al(OH)3*(s) f. H2*(g) + O2*(g) ---> H2*O(g) my answer: H2* (g) + O2*(g) ---> 2H2*O(g) P.S. This * means that the numbers are not coefficients. =)
Asked by Mystery - Sat Nov 15 09:13:15 2008 - - 2 Answers - 0 Comments
A. a , b , c and e are balanced d . KClO2 >> KCl + O2 f . 2 H2 + O2 >> 2 H2O
Answered by Dr.A - Sat Nov 15 09:21:06 2008
What are the completely balanced chemical equations for the following reactions?
Q. Hey sorry guys, last time I posted these questions, some you got mad thinking that I just want the answers. But, I ve actually tried. You guys can verify my answers... thanks.. (PS: I don t have rubber book so I don t know the right answers!) Please give balanced equations (include states of reatcants & products. Also, indicate oxidizing agent (OA) where redox reactions are applicable: 1) Burning Mg ribbon in O2. 2 Mg(s) + O2(g) 2MgO(s) (OA oxygen) 2) Combustion of elemental Phosphorus. P4(s) + 5 O2(g) P4O10(s) (OA oxygen) 3) Combustion of S. S(s) + O2(g) SO2(g) (OA oxygen) 4) Dissolving Cu in concentrated nitric acid. Cu(s) + 4 HNO3(aq) Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l) (OA nitric acid) 5) Dissolving MgO in HCl acid.… [cont.]
Asked by Karan S - Sat Sep 30 18:11:53 2006 - - 3 Answers - 0 Comments
A. split the question up into 7 different ones and i promise you'll get your anwers...
Answered by Jacqueline - Sun Oct 1 00:39:35 2006
Q. Hey sorry guys, last time I posted these questions, some you got mad thinking that I just want the answers. But, I ve actually tried. You guys can verify my answers... thanks.. (PS: I don t have rubber book so I don t know the right answers!) Please give balanced equations (include states of reatcants & products. Also, indicate oxidizing agent (OA) where redox reactions are applicable: 1) Burning Mg ribbon in O2. 2 Mg(s) + O2(g) 2MgO(s) (OA oxygen) 2) Combustion of elemental Phosphorus. P4(s) + 5 O2(g) P4O10(s) (OA oxygen) 3) Combustion of S. S(s) + O2(g) SO2(g) (OA oxygen) 4) Dissolving Cu in concentrated nitric acid. Cu(s) + 4 HNO3(aq) Cu(NO3)2(aq) + 2 NO2(g) + 2 H2O(l) (OA nitric acid) 5) Dissolving MgO in HCl acid.… [cont.]
Asked by Karan S - Sat Sep 30 18:11:53 2006 - - 3 Answers - 0 Comments
A. split the question up into 7 different ones and i promise you'll get your anwers...
Answered by Jacqueline - Sun Oct 1 00:39:35 2006
BALANCING EQUATIONS HELP!!?
Q. balance this single replacement equation: Cu(s) + 2AgNO3(aq) ---> 2Ag(s) + Cu(NO3)2
Asked by flapjack - Sat Oct 4 22:54:15 2008 - - 1 Answers - 0 Comments
Q. balance this single replacement equation: Cu(s) + 2AgNO3(aq) ---> 2Ag(s) + Cu(NO3)2
Asked by flapjack - Sat Oct 4 22:54:15 2008 - - 1 Answers - 0 Comments
How would you write a balanced net ionic equation for each of the following two reactions? PLEASE HELP!!!!?
Q. H3PO4 (aq) + NaOH (aq) = Na3Po4 (aq) + 3 H2O Cu(NO3)2 (aq) + 2 KOH (aq) = Cu(OH)2 + KNO3 H3PO4 + 3 NaOH = Na3PO4 + 3 H20 Cu(NO3)2 + 2 KOH = Cu(OH)2 + 2 KNO3 I know that there balanced but whats the net ionic equation for them. Net ionic equation being the one were you eliminate the compounds that stay in the same state on either side of the reaction or something like that...?
Asked by shanna z - Mon Oct 20 04:11:17 2008 - - 3 Answers - 0 Comments
A. H3PO4 + 3NaOH = Na3Po4 + 3H20 Cu(NO3)2 + 2 KOH = Cu(OH)2 + 2 KNO3 you just need to make sure there is the same number of each ion on each side of the equation. i.e. there is two nitrates on the left so you need a two in front of the potassium nitrate, which means you need a 2 in front of the potassium hydroxide (to balance the number of potassiums) then you will notice that it works out because then you have two hydroxides on the left and two on the right.
Answered by AbyP - Mon Oct 20 04:19:51 2008
Q. H3PO4 (aq) + NaOH (aq) = Na3Po4 (aq) + 3 H2O Cu(NO3)2 (aq) + 2 KOH (aq) = Cu(OH)2 + KNO3 H3PO4 + 3 NaOH = Na3PO4 + 3 H20 Cu(NO3)2 + 2 KOH = Cu(OH)2 + 2 KNO3 I know that there balanced but whats the net ionic equation for them. Net ionic equation being the one were you eliminate the compounds that stay in the same state on either side of the reaction or something like that...?
Asked by shanna z - Mon Oct 20 04:11:17 2008 - - 3 Answers - 0 Comments
A. H3PO4 + 3NaOH = Na3Po4 + 3H20 Cu(NO3)2 + 2 KOH = Cu(OH)2 + 2 KNO3 you just need to make sure there is the same number of each ion on each side of the equation. i.e. there is two nitrates on the left so you need a two in front of the potassium nitrate, which means you need a 2 in front of the potassium hydroxide (to balance the number of potassiums) then you will notice that it works out because then you have two hydroxides on the left and two on the right.
Answered by AbyP - Mon Oct 20 04:19:51 2008
From Yahoo Answer Search: 'balancing equation Cu(No3) (aq)'
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MISSISSIPPI STATE UNIV MISSISSIPPI STATE : Bricka, RM, Marwaha, Anirudha, Fabian, Gene L.
Wed, 18 Jun 2008 07:00:01 GM
A Tinius. Olson Super-L compressive apparatus was used to supply the necessary force required to fracture the sample. The maximum strength required to fracture the sample was obtained. The UCS was calculated by using . equation. 4.3. UCS = F/A . ... Fraction . No. 3. - Bound to Iron and Manganese Oxides. The extraction fluid for step . No. 3. was a 0.04 M hydroxylamine hydrochloride solution with 25 percent by volume of acetic acid. The extraction fluid was added to the centrifuge ...
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