How do I Balance this equation? : "Cu(s) + HNO3(aq) -> H2O(l) + NO2(g) + Cu(NO3)2(aq)"?
Q. When I try to balance it, the oxygens always are unbalanced. But it said that I allowed to use coefficients "1" and "0" (0 meaning none of that substance is present in the equation.)
Asked by Kotomi - Sat Sep 27 16:26:47 2008 - - 4 Answers - 0 Comments
A. That problem should not be given to any human to solve Cu(s) + 4HNO3(aq) > Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) That is one of the harder reactions
Answered by syntroniks - Sat Sep 27 16:34:47 2008
Q. When I try to balance it, the oxygens always are unbalanced. But it said that I allowed to use coefficients "1" and "0" (0 meaning none of that substance is present in the equation.)
Asked by Kotomi - Sat Sep 27 16:26:47 2008 - - 4 Answers - 0 Comments
A. That problem should not be given to any human to solve Cu(s) + 4HNO3(aq) > Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l) That is one of the harder reactions
Answered by syntroniks - Sat Sep 27 16:34:47 2008
What is the balanced galvanic cell equation for Cu | Cu(NO3)2 || KSCN | Ag, AgSCN?
Q. Hi, From an experiment we have the galvanic cell: Cu | Cu(NO3)2 || KSCN | Ag, AgSCN I need to find the solubility constant using Nernst and Ksp. However, I need to know how to write the balanced cell equation. I know that copper is oxidation, and the other side is cathode so it's reduction. But I don't know what to do with the KSCN. please help me find the balanced cell equation!! Please answer ASAP! thanks.
Asked by mazin - Wed Aug 6 18:57:30 2008 - - 2 Answers - 0 Comments
A. The silver complex is [Ag(SCN)2]+. Cu + 2[Ag(SCN)2]+.---> Cu2+ + 2Ag + 2SCN-
Answered by Gervald F - Thu Aug 7 14:00:25 2008
Q. Hi, From an experiment we have the galvanic cell: Cu | Cu(NO3)2 || KSCN | Ag, AgSCN I need to find the solubility constant using Nernst and Ksp. However, I need to know how to write the balanced cell equation. I know that copper is oxidation, and the other side is cathode so it's reduction. But I don't know what to do with the KSCN. please help me find the balanced cell equation!! Please answer ASAP! thanks.
Asked by mazin - Wed Aug 6 18:57:30 2008 - - 2 Answers - 0 Comments
A. The silver complex is [Ag(SCN)2]+. Cu + 2[Ag(SCN)2]+.---> Cu2+ + 2Ag + 2SCN-
Answered by Gervald F - Thu Aug 7 14:00:25 2008
How do I balance this equation: Cu(OH)2 + NaOH?
Q. How do I balance this equation: Cu(OH)2 + NaOH?
Asked by Miawzi - Sun Aug 2 01:49:58 2009 - - 3 Answers - 0 Comments
A. No reaction
Answered by joeyeehung - Sun Aug 2 01:58:02 2009
Q. How do I balance this equation: Cu(OH)2 + NaOH?
Asked by Miawzi - Sun Aug 2 01:49:58 2009 - - 3 Answers - 0 Comments
A. No reaction
Answered by joeyeehung - Sun Aug 2 01:58:02 2009
How do you write a balanced chemical equation for copper (II) nitrate - Cu(NO3)2 and socium iodide - Nal?
Q. Suddenly I'm having problems balancing this equation. I am doing an experiment with ionic reactions and found that this combination had a precipitate that turned dark yellow. I need to write a balanced chem equation and drew a blank! Any help would be appreciated! Thanks! I meant sodium iodide!
Asked by Kenny S. - Wed Mar 5 10:40:46 2008 - - 1 Answers - 0 Comments
A. Good observation. This is an interesting oxidation-reduction reaction. 2Cu2+ + 4 I- = 2 CuI + I2 And, if you have excess NaI, the iodine stays in the solution as dark brown I3-: I- + I2 = I3 - Cu(I) compounds are not usually stable in the presence of water, but CuI is an exception because it is so very insoluble. If you have the chance, decant off the solution, and make separate notes of the colour of the solution and of the solid.
Answered by Paul B - Wed Mar 5 10:47:43 2008
Q. Suddenly I'm having problems balancing this equation. I am doing an experiment with ionic reactions and found that this combination had a precipitate that turned dark yellow. I need to write a balanced chem equation and drew a blank! Any help would be appreciated! Thanks! I meant sodium iodide!
Asked by Kenny S. - Wed Mar 5 10:40:46 2008 - - 1 Answers - 0 Comments
A. Good observation. This is an interesting oxidation-reduction reaction. 2Cu2+ + 4 I- = 2 CuI + I2 And, if you have excess NaI, the iodine stays in the solution as dark brown I3-: I- + I2 = I3 - Cu(I) compounds are not usually stable in the presence of water, but CuI is an exception because it is so very insoluble. If you have the chance, decant off the solution, and make separate notes of the colour of the solution and of the solid.
Answered by Paul B - Wed Mar 5 10:47:43 2008
Balancing equation?
Q. This is one of the sample chemistry questions from college board for the SAT subject test, and I don't get it at all. It's difficulty is only 2/5, so I feel really stupid :( ...Cu 2+ (aq)+ ...I- (aq) ---> ...CuI(s) + ...I2(s) When the equation above is balanced and all coefficients are reduced to lowest whole number terms, the coefficient for I- (aq) is and the answer is 4, but how!!? Why can't the answer just be: Cu2+ + 3I- ---> CuI + I2
Asked by Daniel - Sun Apr 13 00:28:54 2008 - - 2 Answers - 0 Comments
A. ooo i have a test on this monday thnx for reminding me about it.
Answered by LaxPlay - Sun Apr 13 00:32:42 2008
Q. This is one of the sample chemistry questions from college board for the SAT subject test, and I don't get it at all. It's difficulty is only 2/5, so I feel really stupid :( ...Cu 2+ (aq)+ ...I- (aq) ---> ...CuI(s) + ...I2(s) When the equation above is balanced and all coefficients are reduced to lowest whole number terms, the coefficient for I- (aq) is and the answer is 4, but how!!? Why can't the answer just be: Cu2+ + 3I- ---> CuI + I2
Asked by Daniel - Sun Apr 13 00:28:54 2008 - - 2 Answers - 0 Comments
A. ooo i have a test on this monday thnx for reminding me about it.
Answered by LaxPlay - Sun Apr 13 00:32:42 2008
Can you help me balance this equation? __Cu + __HNO3 __Cu(NO3)2 + __NO + __H2O?
Q. Can you help me balance this equation? __Cu + __HNO3 __Cu(NO3)2 + __NO + __H2O?
Asked by Brittany L - Tue Oct 23 22:45:50 2007 - - 1 Answers - 1 Comments
A. 1 4 1 2 2 nitric acid acting upon copper movie emistry.com/KentsDemos.ht m
Answered by kentchemistry.com - Tue Oct 23 22:48:27 2007
Q. Can you help me balance this equation? __Cu + __HNO3 __Cu(NO3)2 + __NO + __H2O?
Asked by Brittany L - Tue Oct 23 22:45:50 2007 - - 1 Answers - 1 Comments
A. 1 4 1 2 2 nitric acid acting upon copper movie emistry.com/KentsDemos.ht m
Answered by kentchemistry.com - Tue Oct 23 22:48:27 2007
So the balanced equation of Cu + (Fe2+) ---> (Cu+) + Fe is 2Cu + (Fe2+) ----> (2Cu+) + Fe how was this found?
Q. So the balanced equation of Cu + (Fe2+) ---> (Cu+) + Fe is 2Cu + (Fe2+) ---> (2Cu+) + Fe how was this found?
Asked by surflov3 - Wed Jun 10 19:50:27 2009 - - 1 Answers - 0 Comments
A. This is a redox reaction. Since Fe2+ is reduced to Fe, two electrons are transferred in the reaction, but since Cu is only oxidized to Cu+, two Cu atoms need to be oxidized in order to transfer two electrons to Fe2+. Since the number of atoms needs to balance out, write 2 as the coefficient for copper on both sides.
Answered by Emmeline - Wed Jun 10 19:56:55 2009
Q. So the balanced equation of Cu + (Fe2+) ---> (Cu+) + Fe is 2Cu + (Fe2+) ---> (2Cu+) + Fe how was this found?
Asked by surflov3 - Wed Jun 10 19:50:27 2009 - - 1 Answers - 0 Comments
A. This is a redox reaction. Since Fe2+ is reduced to Fe, two electrons are transferred in the reaction, but since Cu is only oxidized to Cu+, two Cu atoms need to be oxidized in order to transfer two electrons to Fe2+. Since the number of atoms needs to balance out, write 2 as the coefficient for copper on both sides.
Answered by Emmeline - Wed Jun 10 19:56:55 2009
Balance Equations...__Cu + __HNO3 -> __Cu(NO3)2 + __H20 + __NO2?
Q. Balance Equations...Please Help...Thanks :)? Balancing Equations...HELP!?!? 1) __Cu + __HNO3 -> __Cu(NO3)2 + __H20 + __NO2 2) __Na2SiO3 + __HF -> __H2SiF + __NF + __H2O 3) __Cu + __AgNO3 -> __Ag + __Cu(NO3)2 4) Octane is burned in an engine, but rarel is combusted. Write an incomplete combustion of octane. 5) Sulfuric acid is neutralized by (reacts with) lithium hydroxide. Write the balanced equation. 6) Reaction between lead(II) nitrate and potassium iodide. Write the balanced equation.
Asked by kickitup21 - Tue Mar 20 19:44:46 2007 - - 2 Answers - 0 Comments
A. I think that in problem 2 some how you miss typed with Na2SiO3 of NF because other wise it is impossible. 1) Cu+4HNO3->Cu(NO3)2+2H2O+2 NO2 3)Cu+2AgNo3->2Ag+Cu(NO3)2
Answered by cally - Tue Mar 20 20:22:37 2007
Q. Balance Equations...Please Help...Thanks :)? Balancing Equations...HELP!?!? 1) __Cu + __HNO3 -> __Cu(NO3)2 + __H20 + __NO2 2) __Na2SiO3 + __HF -> __H2SiF + __NF + __H2O 3) __Cu + __AgNO3 -> __Ag + __Cu(NO3)2 4) Octane is burned in an engine, but rarel is combusted. Write an incomplete combustion of octane. 5) Sulfuric acid is neutralized by (reacts with) lithium hydroxide. Write the balanced equation. 6) Reaction between lead(II) nitrate and potassium iodide. Write the balanced equation.
Asked by kickitup21 - Tue Mar 20 19:44:46 2007 - - 2 Answers - 0 Comments
A. I think that in problem 2 some how you miss typed with Na2SiO3 of NF because other wise it is impossible. 1) Cu+4HNO3->Cu(NO3)2+2H2O+2 NO2 3)Cu+2AgNo3->2Ag+Cu(NO3)2
Answered by cally - Tue Mar 20 20:22:37 2007
Using the smallest possible integer coefficients to balance the redox equation Cu (+) NO3- --> Cu+2 (+) NO2.?
Q. (acidic solution), the coefficient for NO2 is? PLeaseee help me answer this question and how did u derive to ur answer? 1) 4 2) 1 3) 3 4) 2 5) The correct coefficient is not given
Asked by alexa - Wed Mar 11 14:02:51 2009 - - 2 Answers - 0 Comments
Q. (acidic solution), the coefficient for NO2 is? PLeaseee help me answer this question and how did u derive to ur answer? 1) 4 2) 1 3) 3 4) 2 5) The correct coefficient is not given
Asked by alexa - Wed Mar 11 14:02:51 2009 - - 2 Answers - 0 Comments
balance the chemical equation Cu^2+ + NH4OH [Cu(NH3)4]^2+?
Q. I can't figure out how to balance this reaction. I'm not sure if you can put a coefficient between the Cu and the NH3 for the product.
Asked by allieappstate - Mon Oct 20 16:30:59 2008 - - 2 Answers - 0 Comments
A. lol i see. no you cant put a coefficient btwn cu and nh3 lols. okay i see your problem. im not sure if you guys learned this yet but the reason you cant balance this is because your products are wrong. where did the extra H go from the NH4? why is there no Oxygens on the product side? the real answer would be: Cu + NH4OH --> Cu(NH4)2 + H2O to balance it, it would be Cu + 2NH4OH --> Cu(NH4)2 + 2H2O hope ive helped!
Answered by Talia S - Mon Oct 20 16:44:34 2008
Q. I can't figure out how to balance this reaction. I'm not sure if you can put a coefficient between the Cu and the NH3 for the product.
Asked by allieappstate - Mon Oct 20 16:30:59 2008 - - 2 Answers - 0 Comments
A. lol i see. no you cant put a coefficient btwn cu and nh3 lols. okay i see your problem. im not sure if you guys learned this yet but the reason you cant balance this is because your products are wrong. where did the extra H go from the NH4? why is there no Oxygens on the product side? the real answer would be: Cu + NH4OH --> Cu(NH4)2 + H2O to balance it, it would be Cu + 2NH4OH --> Cu(NH4)2 + 2H2O hope ive helped!
Answered by Talia S - Mon Oct 20 16:44:34 2008
Balancing Molecular Equation: give most points i can give for best answer?
Q. a reaction between aqueous solutions of Cu(NO3)2 and KI to form CuI and I2. The CuI precipitates from the reaction as a solid, and the other products (KNO3 and I2) remain in aqueous solution. Write a balanced molecular equation for the overall reaction, using the smallest whole number coefficients, including the states of matter for each reactant and product.
Asked by sti_momo - Wed Oct 3 21:48:16 2007 - - 1 Answers - 0 Comments
A. 2Cu(NO3)2(aq) +4 KI (aq)>>2 CuI (s)+ I2 +4 KNO3 (aq)
Answered by Dr.A - Thu Oct 4 11:40:08 2007
Q. a reaction between aqueous solutions of Cu(NO3)2 and KI to form CuI and I2. The CuI precipitates from the reaction as a solid, and the other products (KNO3 and I2) remain in aqueous solution. Write a balanced molecular equation for the overall reaction, using the smallest whole number coefficients, including the states of matter for each reactant and product.
Asked by sti_momo - Wed Oct 3 21:48:16 2007 - - 1 Answers - 0 Comments
A. 2Cu(NO3)2(aq) +4 KI (aq)>>2 CuI (s)+ I2 +4 KNO3 (aq)
Answered by Dr.A - Thu Oct 4 11:40:08 2007
how do u balance Cu + HNO3 = Cu(NO3)2 + NO2 + H2O?
Q. How do you balance this redox equation. My chemistry text book gave a method to solve this equation and its not working. The root of the approach given by the book is oxidation numbers. it involves you writing out all the oxidation numbers, then identifying which elements are oxidized and reduced. Then you connect the atoms that change oxidation numbers by using a bracket, and write the change in oxidation number at the midpoint of each bracket. THen you choose coefficients that make the total increase in oxidation number equal the total decrease in oxidation number. Finally you balance the remaining elements. i know the balanced equation is Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O. I just don't know how to use the formula i gave to find… [cont.]
Asked by chris_clarke_mail - Sun Apr 15 21:49:45 2007 - - 4 Answers - 0 Comments
A. When you balance a chemical equation, you must have the same number of atoms of each element on each side of the equation. Usually all you have to do is find a common multiple of the coefficients for each atom or molecule involved in the equation to balance the equation. Let us first look at oxygen. There are three on the left side and nine on the right. Thus we need at least three HNO3. Unfortunately, three HNO3 doesn't work with the H2O thus we must have six HNO3 and three H2O. Unfortunately this doesn;t work either due to the odd number of Oxygen on the right. Thus we try 12 HNO3 and 6 H2O. After we subtract out the O in the water we have 30 O to divide up between (NO3)2 and NO2. Trial and error gives the following: 3 Cu + 12… [cont.]
Answered by MICHAEL R - Sun Apr 15 22:21:16 2007
Q. How do you balance this redox equation. My chemistry text book gave a method to solve this equation and its not working. The root of the approach given by the book is oxidation numbers. it involves you writing out all the oxidation numbers, then identifying which elements are oxidized and reduced. Then you connect the atoms that change oxidation numbers by using a bracket, and write the change in oxidation number at the midpoint of each bracket. THen you choose coefficients that make the total increase in oxidation number equal the total decrease in oxidation number. Finally you balance the remaining elements. i know the balanced equation is Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O. I just don't know how to use the formula i gave to find… [cont.]
Asked by chris_clarke_mail - Sun Apr 15 21:49:45 2007 - - 4 Answers - 0 Comments
A. When you balance a chemical equation, you must have the same number of atoms of each element on each side of the equation. Usually all you have to do is find a common multiple of the coefficients for each atom or molecule involved in the equation to balance the equation. Let us first look at oxygen. There are three on the left side and nine on the right. Thus we need at least three HNO3. Unfortunately, three HNO3 doesn't work with the H2O thus we must have six HNO3 and three H2O. Unfortunately this doesn;t work either due to the odd number of Oxygen on the right. Thus we try 12 HNO3 and 6 H2O. After we subtract out the O in the water we have 30 O to divide up between (NO3)2 and NO2. Trial and error gives the following: 3 Cu + 12… [cont.]
Answered by MICHAEL R - Sun Apr 15 22:21:16 2007
How do I do figure out the coefficients in this equation? (balancing act)?
Q. (v means down like the opposite of ^ when using exponents.) Cu + AgNOv3 ---> Cu(NOv3)v2 + Ag 10 points goes to the first person that explains how they get their coefficients for the equation.
Asked by mari ^.^ - Sun Dec 7 16:45:57 2008 - - 3 Answers - 0 Comments
A. Cu + 2AgNOv3 ---> Cu(NOv3)v2 + 2Ag The product copper nitrate has two nitrates, so there must be two nitrates in the reactants. The only nitrate present in the reactants is silver nitrate, so a '2' goes in front of silver nitrate. This leaves us with 2 x silver, so a '2' goes in front of silver in the products. NB Metals, unlike gases, are NOT diatomic molecules so the number of metal atoms goes in front of the metal.
Answered by lenpol7 - Sun Dec 7 16:59:35 2008
Q. (v means down like the opposite of ^ when using exponents.) Cu + AgNOv3 ---> Cu(NOv3)v2 + Ag 10 points goes to the first person that explains how they get their coefficients for the equation.
Asked by mari ^.^ - Sun Dec 7 16:45:57 2008 - - 3 Answers - 0 Comments
A. Cu + 2AgNOv3 ---> Cu(NOv3)v2 + 2Ag The product copper nitrate has two nitrates, so there must be two nitrates in the reactants. The only nitrate present in the reactants is silver nitrate, so a '2' goes in front of silver nitrate. This leaves us with 2 x silver, so a '2' goes in front of silver in the products. NB Metals, unlike gases, are NOT diatomic molecules so the number of metal atoms goes in front of the metal.
Answered by lenpol7 - Sun Dec 7 16:59:35 2008
How many g of Cu is required to replace all the Ag in 200mL of a 0.02M AgNO3 solution in this equation?
Q. Cu + AgNO3 > Cu(NO3)2 + Ag After balancing: Cu + 2AgNO3 > Cu(NO3)2 + 2Ag
Asked by Mark M - Mon Jun 8 05:31:16 2009 - - 3 Answers - 0 Comments
Q. Cu + AgNO3 > Cu(NO3)2 + Ag After balancing: Cu + 2AgNO3 > Cu(NO3)2 + 2Ag
Asked by Mark M - Mon Jun 8 05:31:16 2009 - - 3 Answers - 0 Comments
balance equation in acidic environment... Cu + NO3- yields Cu+2 + NO-2?
Q. Cu on the left has charge zero... I have worked the problem but keep getting 3Cu + 8H + 3NO3 yields 3Cu + 2NO + 4H2O and the answer is supposed to be 2NO3 on the left side... i need to see the work to know where i am going wrong, thanks
Asked by sam h - Wed Sep 26 00:42:40 2007 - - 1 Answers - 0 Comments
A. (Cu >> Cu2+ + 2e-) x3 (NO3- + 4H+ + 3e->> NO + 2H2O) x2 3 Cu + 2NO3- + 8H+ >> 3Cu2+ + 2NO + 4H2O
Answered by Dr.A - Thu Sep 27 12:32:56 2007
Q. Cu on the left has charge zero... I have worked the problem but keep getting 3Cu + 8H + 3NO3 yields 3Cu + 2NO + 4H2O and the answer is supposed to be 2NO3 on the left side... i need to see the work to know where i am going wrong, thanks
Asked by sam h - Wed Sep 26 00:42:40 2007 - - 1 Answers - 0 Comments
A. (Cu >> Cu2+ + 2e-) x3 (NO3- + 4H+ + 3e->> NO + 2H2O) x2 3 Cu + 2NO3- + 8H+ >> 3Cu2+ + 2NO + 4H2O
Answered by Dr.A - Thu Sep 27 12:32:56 2007
Copper and nitric acid include nitrogen dioxide and Cu ++. please balance the equation , cofficient for NO2?
Q. Copper and nitric acid include nitrogen dioxide and Cu ++. please balance the equation , cofficient for NO2?
Asked by margoretewhitfield - Fri Jun 15 00:45:50 2007 - - 1 Answers - 0 Comments
A. Cu = Cu2+ + 2e 2NO3(-) + 2e +4 H+ = 2NO2 + 2H2O Cu + 4HNO3 = Cu(NO3)2 + 2NO2 + 2H2O
Answered by Chris - Fri Jun 15 12:48:58 2007
Q. Copper and nitric acid include nitrogen dioxide and Cu ++. please balance the equation , cofficient for NO2?
Asked by margoretewhitfield - Fri Jun 15 00:45:50 2007 - - 1 Answers - 0 Comments
A. Cu = Cu2+ + 2e 2NO3(-) + 2e +4 H+ = 2NO2 + 2H2O Cu + 4HNO3 = Cu(NO3)2 + 2NO2 + 2H2O
Answered by Chris - Fri Jun 15 12:48:58 2007
I need help with completing and balancing each equation by predicting the products formed.?
Q. 1.) Fe(solid)+CuCl2(aqeaous)- - 2.) C2H6(gas)+O2(gas)-- 3.) NaCl(aqeous)+NH4OH(aqueou s)-- 4.) H2O-- 5.) Cu(solid)+O2(gas)-- 6.) Al2O3-- 7.) Mg(solid)+HCl(aqeuous)-- 8.) LiNO3(aqeous)+MgCl2(aqeou s)-- && then I need 2 balance them [Dont have 2 if u dont want.] but the MAJOR issue is the 8 problems.. can anyone do aNd explain? THANKS. SO MUCH. chemistry.. whoa.
Asked by BahamaBabi - Tue Oct 9 20:35:21 2007 - - 1 Answers - 0 Comments
A. I will do number eight. 2LiNO3 + MgCl2 >2 LiCl + Mg(NO3)2 See, keep your atoms and charges balanced.
Answered by jonmcn49 - Tue Oct 9 20:47:19 2007
Q. 1.) Fe(solid)+CuCl2(aqeaous)- - 2.) C2H6(gas)+O2(gas)-- 3.) NaCl(aqeous)+NH4OH(aqueou s)-- 4.) H2O-- 5.) Cu(solid)+O2(gas)-- 6.) Al2O3-- 7.) Mg(solid)+HCl(aqeuous)-- 8.) LiNO3(aqeous)+MgCl2(aqeou s)-- && then I need 2 balance them [Dont have 2 if u dont want.] but the MAJOR issue is the 8 problems.. can anyone do aNd explain? THANKS. SO MUCH. chemistry.. whoa.
Asked by BahamaBabi - Tue Oct 9 20:35:21 2007 - - 1 Answers - 0 Comments
A. I will do number eight. 2LiNO3 + MgCl2 >2 LiCl + Mg(NO3)2 See, keep your atoms and charges balanced.
Answered by jonmcn49 - Tue Oct 9 20:47:19 2007
Which is the balanced equation for the redox reaction shown below-Cu + NO3- Cu2+ + NO2?
Q. Which is the balanced equation for the redox reaction shown below, which takes place in acidic solution? Cu + NO3- Cu2+ + NO2 A. Cu + 2NO3- + 2H2O Cu2+ + 2NO2 + 4OH- B. Cu + NO3- Cu2+ + NO2 C. Cu + 2NO3- + 4H+ Cu2+ + 2NO2 + 2H2O D. Cu + 2NO3- + 2H+ Cu2+ + 2NO2 + 2H2O E. Cu + NO3- + 4H+ Cu2+ + NO2 + 2H2O
Asked by geez - Fri Aug 21 15:54:26 2009 - - 1 Answers - 0 Comments
A. 2N03- + 4H+ +CU ---> 2NO2 + 2H20 + Cu2+ C. is the correct answer
Answered by unknown - Fri Aug 21 16:08:58 2009
Q. Which is the balanced equation for the redox reaction shown below, which takes place in acidic solution? Cu + NO3- Cu2+ + NO2 A. Cu + 2NO3- + 2H2O Cu2+ + 2NO2 + 4OH- B. Cu + NO3- Cu2+ + NO2 C. Cu + 2NO3- + 4H+ Cu2+ + 2NO2 + 2H2O D. Cu + 2NO3- + 2H+ Cu2+ + 2NO2 + 2H2O E. Cu + NO3- + 4H+ Cu2+ + NO2 + 2H2O
Asked by geez - Fri Aug 21 15:54:26 2009 - - 1 Answers - 0 Comments
A. 2N03- + 4H+ +CU ---> 2NO2 + 2H20 + Cu2+ C. is the correct answer
Answered by unknown - Fri Aug 21 16:08:58 2009
How do I balance and find net ionic equation for Cu(NO3)2*3H2O+Na3PO4*12H2 O and Fe(NO3)3*9H2O+Na3PO4*12H2 O?
Q. How do I balance and find net ionic equation for Cu(NO3)2*3H2O+Na3PO4*12H2 O and Fe(NO3)3*9H2O+Na3PO4*12H2 O?
Asked by samo - Sat Jun 30 12:17:29 2007 - - 1 Answers - 0 Comments
A. 3 Cu2+ + 2 PO4 3- -> Cu3(PO4)2 Fe3+ + PO43- -> FePO4
Answered by ag_iitkgp - Sun Jul 1 03:18:31 2007
Q. How do I balance and find net ionic equation for Cu(NO3)2*3H2O+Na3PO4*12H2 O and Fe(NO3)3*9H2O+Na3PO4*12H2 O?
Asked by samo - Sat Jun 30 12:17:29 2007 - - 1 Answers - 0 Comments
A. 3 Cu2+ + 2 PO4 3- -> Cu3(PO4)2 Fe3+ + PO43- -> FePO4
Answered by ag_iitkgp - Sun Jul 1 03:18:31 2007
what is the balanced form of this equation... Cu + S8 ---> Cu2S?
Q. what is the balanced form of this equation... Cu + S8 ---> Cu2S?
Asked by snowpoon - Wed Oct 31 00:48:16 2007 - - 8 Answers - 0 Comments
A. The balanced form of this equation is: On the reactant side, copper is one and sulphur is eight. But the product turns out to be Cu2S. To balance the equation, add 16 to Cu on the reactant side and add 8 in front of Cu on the product side to complete the equation. 16Cu + 8S >>> 8Cu2S cu>> 16 + S>>8>>>.Cu(8x2) S>>8 Always remember that whatever you do on the reactant side , also do it on the product side. Both must be equal.
Answered by Angel - Wed Oct 31 01:15:50 2007
Q. what is the balanced form of this equation... Cu + S8 ---> Cu2S?
Asked by snowpoon - Wed Oct 31 00:48:16 2007 - - 8 Answers - 0 Comments
A. The balanced form of this equation is: On the reactant side, copper is one and sulphur is eight. But the product turns out to be Cu2S. To balance the equation, add 16 to Cu on the reactant side and add 8 in front of Cu on the product side to complete the equation. 16Cu + 8S >>> 8Cu2S cu>> 16 + S>>8>>>.Cu(8x2) S>>8 Always remember that whatever you do on the reactant side , also do it on the product side. Both must be equal.
Answered by Angel - Wed Oct 31 01:15:50 2007
From Yahoo Answer Search: 'balancing equation Cu'
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AIR FORCE RESEARCH LAB HANSCOM AFB MA SPACE VEHICLES DIRECTORATE : Lai, Shu T., Tautz, Maurice
Wed, 11 Feb 2009 08:00:01 GM
Cu. -Bc (Activated). 0.40. 5.00. 0.3136. 0.0692. 0.6207. E. 0.010. Mgr": 0.85. 6.38. 0.1238. 0.0172. 0.3435. . 0.019. "Anticritical temperature 7"., given in kcV. bHerc means that there is no TA, and indicates that TA is below 1 eV. ... Current . balance equation. (6 + r/) = l for the anticritical temperature TA with and without enhanced backscatter for the surface material gold. We have used. Ea = 0.05 keV for the enhancement fall-off parameter. ...
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