How can I ensure the complete combustion of an alcohol using a spirit burner?
Q. I'm desiging a lab which involves burning different alcohols and measuring their different enthalpies of combustion. using a spirit burner, is there any way to ensure that the alcohol undergoes complete combustion? this lab is to be conducted in a high school lab so i have limited equipment.
Asked by AB - Wed Feb 11 21:11:36 2009 - - 1 Answers - 0 Comments

A. okay i did that not in practice but kinda in theory...well my teacher explained to that you could measure the initial mass of alcohol used... now there are two cases; CASE I light the spirit after some time(note the time) is takes to heat, lets say water...note temperature rise...extinguish the spirit lamp..note the mass of alcohol help..from there you could proceed to your answer...you can do that to all your alcohol...time can be varied CASE 2 time remains the same..after certain time interval, the spirit lamp is extinguished, weighed and you could find your answer again.. am sure both are correct... hope this helps=)
Answered by Arnaq - Wed Feb 11 22:05:17 2009

A.What mass of carbon dioxide is produced from the complete combustion of 2.20 10 3 g of methane?
Q. B. What mass of water is produced from the complete combustion of 2.20 10 3 of methane? C. What mass of oxygen is needed for the complete combustion of 2.20 10 3 g of methane?
Asked by daniel b - Mon Feb 23 17:09:17 2009 - - 1 Answers - 0 Comments

A. CH4+2O2=>CO2+2H2O moles of ch4 BURNED=2.2*10^-3/16=1.375 *10^-4 A. one mole of ch4 PRODUCE 1 mole of co2 SO, moles of co2 FORMED=1.375*10-4 =1.375*10-4*44=6.05*10^-3 g B. one mole of ch4 PRODUCE 2 mole of h2O SO, moles of h2O FORMED=2*1.375*10-4 =2*18*1.375*10-4=3.614*10 ^-3g C.One mole of ch4 REQUIRE 2 mole of o2 for combustion so, moles of o2 NEED=2*1.375*10-4 =32*2*1.375*10-4=8.8*10^- 3g
Answered by chem - Mon Feb 23 17:25:24 2009

what is the general equation for the complete combustion of an alkene?
Q. i really need help on this science question because i have my GCSE test in 2 days and i'm still a bit uncertain in this area: The formula of hexane is C6H14 How many molecules of oxygen are needed to burn one molecule of hexane? and what is the general formula for the complete combustion of an alkane it would really help if you added an explanation so i could comprehend it as well! thanks.
Asked by elz1582 - Mon Mar 2 14:54:56 2009 - - 3 Answers - 1 Comments

A. The general combustion will mean the alkene will burn with oxygen to make carbon dioxide and water: C6H14 + 02 C02 + H20 Now, let's balance the equation. It's not balanced - there aren't enough products made from the reactants (for example, there are 14 hydrogens on the left side of the equation, but the right side only has 1) So: 2 C6H14 + 19 O2 12 CO2 + 14 H2O So, 19 molecules of oxygen combusts 2 molecules of hexane. Thus, 9.5 molecules of oxygen burn 1 mole of hexane.
Answered by Felt Monkey - Mon Mar 2 15:08:44 2009

Write an equation for complete and incomplete combustion?
Q. I've got complete combustion covered: CH4 + 2O2 CO2 + 2H2O + heat but I don't know how to write an equation for incomplete combustion. It needs to start with CH4 + oxygen and end with carbon monoxide and whatever else is left. It is amongst questions about carbon monoxide air pollution from cars. Please answer (even if you're a bit uncertain!)
Asked by drspa44 - Mon May 25 13:20:38 2009 - - 1 Answers - 0 Comments

A. CH4 + 2(1/2)O2 ---> CO + 4H2O
Answered by Jimmy - Tue May 26 10:12:41 2009

what mass of carbon dioxide would be produced by the complete combustion of 50kg of octane?
Q. what mass of carbon dioxide would be produced by the complete combustion of 50kg of octane i understand the answer, a bit but not the working, please show me?
Asked by thegrimreaper - Tue Sep 16 18:07:38 2008 - - 1 Answers - 0 Comments

A. Let UNITs guide you; always use them in your calculation to prevent errors eqn: C8H18 + 25/2O2 ---> 8CO2 + 9H2O kg CO2 = (8kmoles CO2/kmole C8H18)* (50kg of C8H18 / MW of C8H18 in kg/kmole) * (MW of CO2 in kg/kmole) Plug and SOLVE Basic mathematics is a prerequisite to chemistry I just try to help you with the methodology of solving the problem - SciMann
Answered by SciMann - Tue Sep 16 19:22:42 2008

What happened when the complete engine combustion not occured?
Q. What really happened when the complete engine combustion didn't occur?What happened when the air and petrol in engine not mix in proper ratio?
Asked by akabane0 - Sun Feb 1 01:38:28 2009 - - 1 Answers - 0 Comments

A. You will get predetination which is where you get pinging from and it will scar and pit the piston and cylinder walls.
Answered by unknown - Sun Feb 1 01:56:02 2009

How many moles of CO2(g) are produced by the complete combustion of 58 g of butane?
Q. Here is what the question asks: Consider the following equation: 2C4H10(g)+13O2(g)-->8CO2( g)+10H2O(I) How many moles of CO2 (g) are produced by the complete combustion of 58 g of butane, C4H10(g)
Asked by IB chem - Sun Nov 15 16:39:55 2009 - - 1 Answers - 0 Comments

What is the total number of liters of carbon dioxide formed by the complete combustion of 28.0 liters of C2H6?
Q. Given the reaction: 2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g) What is the total number of liters of carbon dioxide formed by the complete combustion of 28.0 liters of C2H6(g)? 1. 14.0 L 2. 28.0 L 3. 56.0 L 4. 112 L
Asked by Tsunami - Fri May 29 20:11:41 2009 - - 1 Answers - 0 Comments

What are the energies produced in the complete combustion of ethyne?
Q. And in incomplete combustion of ethyne.
Asked by Tally - Thu Oct 2 16:26:30 2008 - - 2 Answers - 0 Comments

A. Heat of complete combustion under air atmosphere is 57.120 kJ/m Density is 1,18 kg/m (0 C, 1013 hPa) Without air (oxygen) it can react to hydrogen and carbon under liberation of 8733 kJ/kg (incomplete) C2H2 ---> 2 C + H2 Other incomplete reaction: C2H2 + O2 ---> 2 CO + 2 H2 Completing: 2 CO + O2 ---> 2 CO2 and 2 H2 + O2 ---> 2 H2O
Answered by picus48 - Thu Oct 2 17:31:07 2008

How many liters of CO2 at STP are produced from the complete combustion of 2. M of heptane?
Q. I don't want the answer, I just want some help setting this up. The reaction for the combustion of heptane is C7H16 + 11O2=>7CO2 + 8 H2O
Asked by LindseyJo - Sat Nov 8 16:13:41 2008 - - 1 Answers - 0 Comments

A. 2.0 M C7H16 produces 2(7mol)(22.4 L/mol) CO2
Answered by Helmut - Sat Nov 8 16:42:37 2008

The balanced equation for the complete combustion of propane is?
Q. The balanced equation for the complete combustion of propane is C3H8(g) + 5 O2(g) ---> 3 CO2(g) + 4 H2O(l) What is the mol ratio of oxygen to carbon dioxide? A) 3 mol CO2 / 5 mol O2 B) 1 mol C3H8/ 3 mol CO2 C) 5 mol O2 / 3 mol CO2 D) 5 mol O2 / 4 mol H2O
Asked by DanielleH - Tue May 5 19:27:42 2009 - - 1 Answers - 0 Comments

A. C)
Answered by Dr.A - Wed May 6 13:19:14 2009

What are the two products of the complete combustion of starch?
Q. What two products do you get when you burn starch? What are their formulae?
Asked by civilprotectionunitone - Mon Mar 10 15:11:34 2008 - - 2 Answers - 0 Comments

A. The two products of combustion of starch are: carbondioxide and water CO2 and H2O The balanced chemical equation is: 2 C6H12O6 + 12 O2 = 12 CO2 +12 H2O
Answered by Geochemist - Mon Mar 10 15:23:07 2008

Before firing liq. fuel, atomising steam is used to atomised fuel for complete combustion in boiler?
Q. Before firing liq. fuel, atomising steam is used to atomised fuel for complete combustion in boilers, why atomising steam temprature reduced with water before it introduced in burner with liq. fuel ? please explain me.
Asked by amshaikh748 - Wed Oct 3 20:11:09 2007 - - 2 Answers - 0 Comments

A. YNOT is spot on. To further answer why water is added to steam. When high temperature steam is reduced in pressure it becomes super heated steam. The temperature of super heated steam is higher than its saturation temperature and the steam is dry. In other words superheated steam is hotter than the temperature it takes to boil water at that pressure and is 100% dry all the moisture has been converted into steam. To reduce the superheated steam temperature to that of saturated steam water is sprayed into the steam line just after it has been reduced in pressure. The sprayer is called an atemperator which uses water to cool dry superheated steam and convert it into moist saturated steam. Atomizing steam is passed through the burner… [cont.]
Answered by Mark G - Wed Oct 3 22:34:32 2007

What is the complete combustion of carbon?
Q. I was going to guess it's C + O2 --> CO2 but i'm not confident. Is that correct?
Asked by Joe C - Sat Nov 10 20:29:23 2007 - - 2 Answers - 1 Comments

A. Looks correct to me.
Answered by parry43 - Sat Nov 10 20:40:28 2007

what is the balanced equation for the complete combustion of methane?
Q. 10 points best anwser..best answer and best explanation.pleaz thanks dude.. now i gotta wait a couple days so i can give u 10 points.
Asked by life long love - Wed Dec 10 21:21:49 2008 - - 1 Answers - 0 Comments

A. CH4 + 2O2 --> CO2 + 2H2O Hopefully no explanation needed?
Answered by The Frontrunner - Wed Dec 10 21:26:31 2008

What volume of O2 (m3) is needed for the complete combustion of 171 g of C2H6 ,,(see below)?
Q. What volume of O2 (m3) is needed for the complete combustion of 171 g of C2H6 at 17.0oC and 100.0 kPa? Enter a numeric answer only, no units.
Asked by nietzsche - Mon Nov 20 22:36:13 2006 - - 2 Answers - 0 Comments

A. 0.481
Answered by Bill me later - Mon Nov 20 23:13:30 2006

What mass of carbon dioxide is produced from the complete combustion of 6.50 10 3 g of methane?
Q. Can someone anwser this please?
Asked by FINALE - Wed Oct 21 01:46:20 2009 - - 1 Answers - 0 Comments

A. moles CH4 = 6.50 x 10^-3 g/16.043 g/mol=0.000405 CH4 + O2 = CO2 + 2 H2O moles CO2 = 0.000405 mass CO2 = 0.000405 mol x 44 g/mol=0.0178 g
Answered by Dr.A - Wed Oct 21 09:15:12 2009

What volume of O2 (m3) is needed for the complete combustion of 118 g of CH4 at 28.0oC and 1?
Q. What volume of O2 (m3) is needed for the complete combustion of 118 g of CH4 at 28.0oC and 100.0 kPa?
Asked by Jessica Rabbit - Fri Mar 27 12:16:39 2009 - - 1 Answers - 0 Comments

A. First write the balanced equation: CH4 + 2 O2 --> CO2 + 2 H2O Calculate moles of CH4: 118 g CH4 / 16 g/mol = 7.375 mol CH4 Calculate moles O2 needed: 7.375 mol CH4 X 2 mol O2/mol CH4 = 14.75 mol Use ideal gas law to calculate volume: V = nRT/P (I'm old, so I'm converting pressure into atm, and T into Kelvin) V = (14.75)(0.0821)(301)/0.98 69 = 369 L Convert L into m^3 gives 0.369 m3.
Answered by hcbiochem - Fri Mar 27 12:27:09 2009

What is the balanced equation for the complete combustion of kerosene?
Q. What is the balanced equation for the complete combustion of kerosene?
Asked by gadm18 - Thu May 17 15:45:36 2007 - - 2 Answers - 0 Comments

A. 2 C8H18 + 25 O2 >> 16 CO2 + 18 H2O
Answered by Non piu attiva su answers - Thu May 17 15:58:07 2007

b. What mass of water is produced from the complete combustion of 6.50 10 3 g of methane?
Q. c. What mass of oxygen is needed for the complete combustion of 6.50 10 3 g of methane? can someone please answer these questions because i dont know what to do? and can you show your work so next time I try to do this I can on my own...
Asked by FINALE - Wed Oct 21 18:09:36 2009 - - 1 Answers - 0 Comments

A. First you need a proper equation. A complete combustion reaction produces carbon dioxide and water. This is theoretical however, you will hardly see pure burning in a real world setting; usually you will see carbon monoxide, nitrogen oxides and carbon. CH4 = methane CH4 + 302 -> CO2 + 4H20 (sorry it looks bad, don't know how to make subscripts in firefox) The next thing to do is convert 6.50x 10^ -3 grams of methane into moles. (6.50 x 10^ -3 g) / (16.042 g/mol) = 4.05 x 10^ -4 moles CH4 In our reaction we need 3 moles of oxygen for every 1 mole of methane we are burning. Thus we will need 1.22 x 10^ -3 moles of O2. Now we need to convert moles of O2 into grams. (1.22 x 10^ -3 moles) x (32.00 grams/mole) = 3.89 x 10^ -2 grams of 02… [cont.]
Answered by Chris - Wed Oct 21 18:24:20 2009