What are the coordinates of the point in Cartesian coordinates?
Q. The coordinates of a point in plane-polar coordinates are (r, ) = (6.50, 33 ). What are the coordinates of the point in Cartesian coordinates?
Asked by nag554 - Wed Nov 11 20:21:35 2009 - - 2 Answers - 0 Comments
A. x = (6.5)cos(33) = 5.45136 y = (6.5)sin(33) = 3.54015 Coordinate (5.45136, 3.54015)
Answered by Faz - Wed Nov 11 20:30:53 2009
Q. The coordinates of a point in plane-polar coordinates are (r, ) = (6.50, 33 ). What are the coordinates of the point in Cartesian coordinates?
Asked by nag554 - Wed Nov 11 20:21:35 2009 - - 2 Answers - 0 Comments
A. x = (6.5)cos(33) = 5.45136 y = (6.5)sin(33) = 3.54015 Coordinate (5.45136, 3.54015)
Answered by Faz - Wed Nov 11 20:30:53 2009
How do you get the coordinates to call an airstrike on the Front Lines?
Q. I was wondering how people get the coordinates for an artillery or air strike. Because I've seen movies where people say numbers for teh coordinates and I don't know if they just make it up. PLZ HELP!
Asked by Wilson V - Sat May 31 13:26:27 2008 - - 6 Answers - 0 Comments
A. An AF team of air-strike coordinators deploys with the front line unit (not necessarily at the squad level) and coordinates with aircraft using a map with a classified grid system that was set up specifically for that operation. If they don't have an AF team with them, someone (the leader or guy with the communications equipment, or both) will have a map with the same coordinates, they can paint the target with a laser, or call in their position and giver directions from there (west of our position in the big blue house).
Answered by sonnydays15 - Sat May 31 14:43:39 2008
Q. I was wondering how people get the coordinates for an artillery or air strike. Because I've seen movies where people say numbers for teh coordinates and I don't know if they just make it up. PLZ HELP!
Asked by Wilson V - Sat May 31 13:26:27 2008 - - 6 Answers - 0 Comments
A. An AF team of air-strike coordinators deploys with the front line unit (not necessarily at the squad level) and coordinates with aircraft using a map with a classified grid system that was set up specifically for that operation. If they don't have an AF team with them, someone (the leader or guy with the communications equipment, or both) will have a map with the same coordinates, they can paint the target with a laser, or call in their position and giver directions from there (west of our position in the big blue house).
Answered by sonnydays15 - Sat May 31 14:43:39 2008
How do i translate spherical coordinates such that the center is a different point?
Q. I have spherical coordinates r, theta, phi centered at x_1 and spherical coordinates r' ,theta' ,phi' centered at x_2. How do I put r' in terms of r , theta' in terms of theta and phi' in terms of phi?
Asked by Jon H - Sat Dec 8 23:04:02 2007 - - 1 Answers - 0 Comments
A. but why... spherical coordinate system is most advantageous when the conditions are: the solid has spherical/ conical shape... and the center/ vertex is at the origin... note: x = sin cos y = sin sin z = cos these are the equations relating cartesian and spherical... maybe consider the cartesian equation first... again... note: when you do the conversions... algebraic/ calculus manipulations become meticulous... if the center/vertex translate... especially if it will be outside the z-axis...
Answered by Alam Ko Iyan - Sat Dec 8 23:18:07 2007
Q. I have spherical coordinates r, theta, phi centered at x_1 and spherical coordinates r' ,theta' ,phi' centered at x_2. How do I put r' in terms of r , theta' in terms of theta and phi' in terms of phi?
Asked by Jon H - Sat Dec 8 23:04:02 2007 - - 1 Answers - 0 Comments
A. but why... spherical coordinate system is most advantageous when the conditions are: the solid has spherical/ conical shape... and the center/ vertex is at the origin... note: x = sin cos y = sin sin z = cos these are the equations relating cartesian and spherical... maybe consider the cartesian equation first... again... note: when you do the conversions... algebraic/ calculus manipulations become meticulous... if the center/vertex translate... especially if it will be outside the z-axis...
Answered by Alam Ko Iyan - Sat Dec 8 23:18:07 2007
Where can I find the latitude and longitude coordinates to draw counties?
Q. I am trying to draw counties on a google map for a mashup. I'd like to find a database of latitude and longitude coordinates to make this easier.
Asked by Jim C - Tue Dec 11 23:20:31 2007 - - 3 Answers - 0 Comments
A. Atlas or map or google earth :)
Answered by Cactus Jack - Wed Dec 12 00:21:46 2007
Q. I am trying to draw counties on a google map for a mashup. I'd like to find a database of latitude and longitude coordinates to make this easier.
Asked by Jim C - Tue Dec 11 23:20:31 2007 - - 3 Answers - 0 Comments
A. Atlas or map or google earth :)
Answered by Cactus Jack - Wed Dec 12 00:21:46 2007
How do you identify a color using CIELab coordinates?
Q. For example, what is the L*a*b* coordinates for the color blue? Is there a standard governing the definition of colors?
Asked by Yuri - Tue Feb 6 23:53:14 2007 - - 2 Answers - 0 Comments
A. The chromaticity diagram is reproduced in many places, including in some filter catalogs, and it is considered a standard. Part of it is points representing standard definitions of "white" light, Illuminant A and Illuminant C, which represent tungsten filament lamps, and daylight. Blue is represented by a portion on the left side of the diagram, in the approximate range of x = 0.1 and y = 0.2 to 0.5, more or less, depending on the exact wavelength.
Answered by rhsaunders - Wed Feb 7 00:13:01 2007
Q. For example, what is the L*a*b* coordinates for the color blue? Is there a standard governing the definition of colors?
Asked by Yuri - Tue Feb 6 23:53:14 2007 - - 2 Answers - 0 Comments
A. The chromaticity diagram is reproduced in many places, including in some filter catalogs, and it is considered a standard. Part of it is points representing standard definitions of "white" light, Illuminant A and Illuminant C, which represent tungsten filament lamps, and daylight. Blue is represented by a portion on the left side of the diagram, in the approximate range of x = 0.1 and y = 0.2 to 0.5, more or less, depending on the exact wavelength.
Answered by rhsaunders - Wed Feb 7 00:13:01 2007
How do I find the coordinates of these points?
Q. I need help with this homework problem: A compact disc is 120 mm across with a center hole of 15 mm in diameter. The center of the disc is at the origin. 1) What are the coordinates of the points at which the inner and outer edge intersect the positive x-axis? 2) What are the coordinates of the points at which the inner and outer edges cut a line making an angle z with the positive x-axis? Note: the z is standing in for the greek symbol phi. Best answer gets 10 points!
Asked by Alchemist89 - Wed Jun 24 17:58:23 2009 - - 1 Answers - 1 Comments
A. 1) So you basically have two circles with center at (0,0). The smaller circle (which is the hole in the CD) has a radius of 7.5 mm. The larger circle (the CD itself) has a radius of 60 mm. So in the positive direction, there will be points of intersection of (7.5, 0) and (60,0), and in the negative direction, the points will be (-7.5, 0) and (-60,0). 2) I don't know if you are working in polar coordinates yet, but if so, it will be (7.5,z) and (60,z) in polar form. The equivalent in x-y form is (7.5cosz, 7.5sinz) and (60cosz, 60sinz).
Answered by Kathleen K - Wed Jun 24 18:26:47 2009
Q. I need help with this homework problem: A compact disc is 120 mm across with a center hole of 15 mm in diameter. The center of the disc is at the origin. 1) What are the coordinates of the points at which the inner and outer edge intersect the positive x-axis? 2) What are the coordinates of the points at which the inner and outer edges cut a line making an angle z with the positive x-axis? Note: the z is standing in for the greek symbol phi. Best answer gets 10 points!
Asked by Alchemist89 - Wed Jun 24 17:58:23 2009 - - 1 Answers - 1 Comments
A. 1) So you basically have two circles with center at (0,0). The smaller circle (which is the hole in the CD) has a radius of 7.5 mm. The larger circle (the CD itself) has a radius of 60 mm. So in the positive direction, there will be points of intersection of (7.5, 0) and (60,0), and in the negative direction, the points will be (-7.5, 0) and (-60,0). 2) I don't know if you are working in polar coordinates yet, but if so, it will be (7.5,z) and (60,z) in polar form. The equivalent in x-y form is (7.5cosz, 7.5sinz) and (60cosz, 60sinz).
Answered by Kathleen K - Wed Jun 24 18:26:47 2009
What is the displacement in rectangular and polar coordinates?
Q. What is the displacement in rectangular and polar coordinates of a line that goes north 10cm and east 15cm? Please explain how you do this...
Asked by Keith - Wed Oct 21 14:32:57 2009 - - 1 Answers - 0 Comments
Q. What is the displacement in rectangular and polar coordinates of a line that goes north 10cm and east 15cm? Please explain how you do this...
Asked by Keith - Wed Oct 21 14:32:57 2009 - - 1 Answers - 0 Comments
How do you do a cross product in spherical coordinates?
Q. I am doing E&M and need to do a cross product in spherical. I am pretty sure I can't just use a straight determinant like in rectangular coordinates, but I can't remember what changes in a spherical determinant. I can't find the definition of it in my books or online. Appreciate the help.
Asked by Dre - Mon Jan 25 17:04:30 2010 - - 1 Answers - 0 Comments
A. It is a bit different, though the same basic concept. Let's say you have two coordinates, (A, B, C) and (X, Y, Z). Your cross product will be (BZ - CY, XC - ZA, AY - BX). Give me a second to type how to remember it: First, position the coordinates above each other visually, with the first one on top (yes, order does matter): (A, B, C) (X, Y, Z) For the first term, cover up the first values: ( , B, C) ( , Y, Z) and then multiply the B times Z, subtracting from that C times Y (BZ - CY). For the second term, cover the middle values: (A, , C) (X, , Z) And multiply and subtract again, but this time switch directions. Start with the first value in the second coordinate (XC - ZA) For the third term, cover the last values: (A, B, ) ( [cont.]
Answered by Mr. Smith - Mon Jan 25 17:10:16 2010
Q. I am doing E&M and need to do a cross product in spherical. I am pretty sure I can't just use a straight determinant like in rectangular coordinates, but I can't remember what changes in a spherical determinant. I can't find the definition of it in my books or online. Appreciate the help.
Asked by Dre - Mon Jan 25 17:04:30 2010 - - 1 Answers - 0 Comments
A. It is a bit different, though the same basic concept. Let's say you have two coordinates, (A, B, C) and (X, Y, Z). Your cross product will be (BZ - CY, XC - ZA, AY - BX). Give me a second to type how to remember it: First, position the coordinates above each other visually, with the first one on top (yes, order does matter): (A, B, C) (X, Y, Z) For the first term, cover up the first values: ( , B, C) ( , Y, Z) and then multiply the B times Z, subtracting from that C times Y (BZ - CY). For the second term, cover the middle values: (A, , C) (X, , Z) And multiply and subtract again, but this time switch directions. Start with the first value in the second coordinate (XC - ZA) For the third term, cover the last values: (A, B, ) ( [cont.]
Answered by Mr. Smith - Mon Jan 25 17:10:16 2010
How do AutoCAD coordinates relate to units of measurment?
Q. Disclaimer: I don't have AutoCAD so don't please write this off as a stupid question. Can someone explain how units of measurement are represented in AutoCAD? Is there a scale setting where a user can setup a relationship between coordinates and meters? For example, 100 units = 1 meter. If so, is there a default setting? Thanks!
Asked by Scott B - Tue Dec 11 15:54:03 2007 - - 5 Answers - 1 Comments
A. There is no units in auotcad, you draw to true demsion, for display purposes you can use the units command, so if you want to draw let say in architecture you can type 6' and it converts it to inches for you. The best way to draw is to draw it in full scale, go to paper space, set up the size tittle block you want and scale your drawing down inside of viewports.
Answered by Zenkai - Wed Dec 12 12:17:08 2007
Q. Disclaimer: I don't have AutoCAD so don't please write this off as a stupid question. Can someone explain how units of measurement are represented in AutoCAD? Is there a scale setting where a user can setup a relationship between coordinates and meters? For example, 100 units = 1 meter. If so, is there a default setting? Thanks!
Asked by Scott B - Tue Dec 11 15:54:03 2007 - - 5 Answers - 1 Comments
A. There is no units in auotcad, you draw to true demsion, for display purposes you can use the units command, so if you want to draw let say in architecture you can type 6' and it converts it to inches for you. The best way to draw is to draw it in full scale, go to paper space, set up the size tittle block you want and scale your drawing down inside of viewports.
Answered by Zenkai - Wed Dec 12 12:17:08 2007
Will my satellite dish have the same coordinates as my neighbours?
Q. I live in a very small town (350 People) and I am trying to get the correct location for my satellite. My brother lives about 5 minutes away and has tried to use his coordinates (used satellite finder) but it still does not work. Should I find my own coordinates? Thanks!
Asked by speck79 - Thu Jul 23 15:43:10 2009 - - 3 Answers - 0 Comments
A. If you mean right next door, that would be a good start. You will still have to tweak the dish using an alignment meter or the signal screen on the receiver.
Answered by classicsat - Thu Jul 23 16:51:31 2009
Q. I live in a very small town (350 People) and I am trying to get the correct location for my satellite. My brother lives about 5 minutes away and has tried to use his coordinates (used satellite finder) but it still does not work. Should I find my own coordinates? Thanks!
Asked by speck79 - Thu Jul 23 15:43:10 2009 - - 3 Answers - 0 Comments
A. If you mean right next door, that would be a good start. You will still have to tweak the dish using an alignment meter or the signal screen on the receiver.
Answered by classicsat - Thu Jul 23 16:51:31 2009
What website would show me the city of some map coordinates?
Q. I don't have an atlas at home and I need to finish some geography homework. The question in my textbook gives me the map coordinates, but I have to find the city.
Asked by pink tortoise - Mon Feb 9 16:35:02 2009 - - 2 Answers - 0 Comments
A. Try this:
Answered by stephhh - Mon Feb 9 16:44:46 2009
Q. I don't have an atlas at home and I need to finish some geography homework. The question in my textbook gives me the map coordinates, but I have to find the city.
Asked by pink tortoise - Mon Feb 9 16:35:02 2009 - - 2 Answers - 0 Comments
A. Try this:
Answered by stephhh - Mon Feb 9 16:44:46 2009
How do you calculate coordinates by adding footage?
Q. I have latitude and longitude of a point and want to determine the coordinates 3 feet south and 2 feet west of that point. What formula would I use?
Asked by Sam M - Tue Dec 30 12:27:57 2008 - - 1 Answers - 0 Comments
A. I wont give you the formula but I can tell you how to come up with one yourself. The distance around the earth is greater east and west than it is north and south. You might want to take this into consideration if you want to be more accurate. Wikipedia has this information. For the degrees east and west find out what the circumference is. Then divide this by the number of degrees it takes to go around the earth. I think it is 360 but I am not completely sure. Now you will know how much a degree east and west is in feet. Do the same north and south and you will know how much a degree is north and south. Take 2 feet west and divide it by the first number you got, then do the same with 3 feet but divide it by the second number. … [cont.]
Answered by Jimmy - Tue Dec 30 12:45:20 2008
Q. I have latitude and longitude of a point and want to determine the coordinates 3 feet south and 2 feet west of that point. What formula would I use?
Asked by Sam M - Tue Dec 30 12:27:57 2008 - - 1 Answers - 0 Comments
A. I wont give you the formula but I can tell you how to come up with one yourself. The distance around the earth is greater east and west than it is north and south. You might want to take this into consideration if you want to be more accurate. Wikipedia has this information. For the degrees east and west find out what the circumference is. Then divide this by the number of degrees it takes to go around the earth. I think it is 360 but I am not completely sure. Now you will know how much a degree east and west is in feet. Do the same north and south and you will know how much a degree is north and south. Take 2 feet west and divide it by the first number you got, then do the same with 3 feet but divide it by the second number. … [cont.]
Answered by Jimmy - Tue Dec 30 12:45:20 2008
What are the approximate coordinates of the source of the sound?
Q. Listening posts are at points A, B, and C. Point A is 2000 feet north of B, and C is 2000 feet east of B. A sound reaches A and B simultaneously one second after it reaches C. If B and C are placed on the x-axis such that the origin is the midpoint of BC what are the approximate coordinates of the source of the sound? (Assume that the speed of sound is 1100 feet per second)
Asked by rmp21990 - Wed Dec 19 13:29:33 2007 - - 1 Answers - 0 Comments
A. It's best to draw a diagram to help you. Draw the x axis and put B and C one unit to the left and right of the origin. Draw A two units above B. If the sound reaches A and B simultaneously, then the sound source is the same distance from those two points. That means its locus is a straight line, the perpendicular bisector of AB. That would be a horizontal line one and a half units above the origin. If the sound takes half the time to reach C, then the source is the point on the line that's twice as far from B as it is from C. That places it up one unit (1000 feet) and a little to the right of the origin.
Answered by Raichu - Wed Dec 19 13:49:46 2007
Q. Listening posts are at points A, B, and C. Point A is 2000 feet north of B, and C is 2000 feet east of B. A sound reaches A and B simultaneously one second after it reaches C. If B and C are placed on the x-axis such that the origin is the midpoint of BC what are the approximate coordinates of the source of the sound? (Assume that the speed of sound is 1100 feet per second)
Asked by rmp21990 - Wed Dec 19 13:29:33 2007 - - 1 Answers - 0 Comments
A. It's best to draw a diagram to help you. Draw the x axis and put B and C one unit to the left and right of the origin. Draw A two units above B. If the sound reaches A and B simultaneously, then the sound source is the same distance from those two points. That means its locus is a straight line, the perpendicular bisector of AB. That would be a horizontal line one and a half units above the origin. If the sound takes half the time to reach C, then the source is the point on the line that's twice as far from B as it is from C. That places it up one unit (1000 feet) and a little to the right of the origin.
Answered by Raichu - Wed Dec 19 13:49:46 2007
How to calculate distance in miles between two given geographical coordinates?
Q. Between two different geographical coordinates in degree(s), minute(s) and second(s) is it possible to determine by computer software the distance between such two locations in miles? Please mention the weblink.
Asked by triximetric - Fri Mar 14 12:08:17 2008 - - 3 Answers - 0 Comments
A. The easiest way to get the answer is to use the Ruler in Google Earth, but the formula is easy for smaller distances (larger ones require spherical geometry) distance = sqrt ((latitude diff in miles)^2 + (longitude diff in miles)^2) distance = sqrt ( (Lat1-Lat2)*69.2)^2 + (69.2*cos((lat1+lat2)/2)* (long1-long2))^2 ) 69.2 is the miles per degree at the equator the cos() is used because long degrees get smaller as you go north and ((lat1+lat2)/2) chooses the average long of the pair to set the cos() You will probably have to change degrees, minutes, seconds to decimal degrees to work in spreadsheet or computer. degree.decimal = degree+min/60 + sec/3600
Answered by mike1942f - Fri Mar 14 12:30:31 2008
Q. Between two different geographical coordinates in degree(s), minute(s) and second(s) is it possible to determine by computer software the distance between such two locations in miles? Please mention the weblink.
Asked by triximetric - Fri Mar 14 12:08:17 2008 - - 3 Answers - 0 Comments
A. The easiest way to get the answer is to use the Ruler in Google Earth, but the formula is easy for smaller distances (larger ones require spherical geometry) distance = sqrt ((latitude diff in miles)^2 + (longitude diff in miles)^2) distance = sqrt ( (Lat1-Lat2)*69.2)^2 + (69.2*cos((lat1+lat2)/2)* (long1-long2))^2 ) 69.2 is the miles per degree at the equator the cos() is used because long degrees get smaller as you go north and ((lat1+lat2)/2) chooses the average long of the pair to set the cos() You will probably have to change degrees, minutes, seconds to decimal degrees to work in spreadsheet or computer. degree.decimal = degree+min/60 + sec/3600
Answered by mike1942f - Fri Mar 14 12:30:31 2008
How do you put coordinates into a TI-83 calculator to get a graph?
Q. If you are given a list of coordinates, what do you do to put them into a TI-83 calculator to get a graph or scatter plot?
Asked by djm - Mon Jan 12 15:23:58 2009 - - 1 Answers - 0 Comments
A. Please give me 10 points 1. Press STAT 2. Select 1: Edit 3. Create two lists, one for the x values, and one for the y 4. Press 2ND-Stat plot 5. Select the plot you want to use 6. Enter the information 7. Press WINDOW 8. Set appropriate values 9. Press graph
Answered by || @rn ue - Wed Jan 14 17:10:56 2009
Q. If you are given a list of coordinates, what do you do to put them into a TI-83 calculator to get a graph or scatter plot?
Asked by djm - Mon Jan 12 15:23:58 2009 - - 1 Answers - 0 Comments
A. Please give me 10 points 1. Press STAT 2. Select 1: Edit 3. Create two lists, one for the x values, and one for the y 4. Press 2ND-Stat plot 5. Select the plot you want to use 6. Enter the information 7. Press WINDOW 8. Set appropriate values 9. Press graph
Answered by || @rn ue - Wed Jan 14 17:10:56 2009
How do I find out the coordinates of an object in an image?
Q. For example, I draw a rectangle on the object and I want to know the rectangle's coordinates.
Asked by Depecheara - Fri Nov 14 15:41:31 2008 - - 1 Answers - 1 Comments
A. I use Firefox and the add-on ColorZilla which gives the color where the target is, but also the x,y cooridinates as you move the mouse. Ron
Answered by Oo,oo, Pick Me! - Fri Nov 14 23:35:47 2008
Q. For example, I draw a rectangle on the object and I want to know the rectangle's coordinates.
Asked by Depecheara - Fri Nov 14 15:41:31 2008 - - 1 Answers - 1 Comments
A. I use Firefox and the add-on ColorZilla which gives the color where the target is, but also the x,y cooridinates as you move the mouse. Ron
Answered by Oo,oo, Pick Me! - Fri Nov 14 23:35:47 2008
How do I figure out the coordinates for this midpoint problem?
Q. P is the midpoint of the line segment AB. The coordinates of P are (5,-6). The coordinates of A are (-1,10). Find the coordinates of B.
Asked by Toni - Wed May 9 20:41:13 2007 - - 10 Answers - 0 Comments
A. If you have two points (x1, y1) and (x2, y2), then the midpoint of those two points is ([x1+x2]/2, [y1+y2]/2). Point A is (x1, y1), and it's coordinates are (-1,10) Point P is (5,-6), and this is the midpoint. We need to find point B, which is (x2, y2): Plug everything into the midpoint formula: Midpoint = ([x1+x2]/2, [y1+y2]/2) (5, -6) = ([-1 + x2]/2, [10 + y2]/2) Now, just solve for x2 and y2 to find point B: (-1 + x2)/2 = 5 ---> x2 = 11 (10 + y2)/2 = -6 ---> y2 = -22 *** Therefore, the coordinates of point B are (11, -22)
Answered by ( ) - Wed May 9 20:43:56 2007
Q. P is the midpoint of the line segment AB. The coordinates of P are (5,-6). The coordinates of A are (-1,10). Find the coordinates of B.
Asked by Toni - Wed May 9 20:41:13 2007 - - 10 Answers - 0 Comments
A. If you have two points (x1, y1) and (x2, y2), then the midpoint of those two points is ([x1+x2]/2, [y1+y2]/2). Point A is (x1, y1), and it's coordinates are (-1,10) Point P is (5,-6), and this is the midpoint. We need to find point B, which is (x2, y2): Plug everything into the midpoint formula: Midpoint = ([x1+x2]/2, [y1+y2]/2) (5, -6) = ([-1 + x2]/2, [10 + y2]/2) Now, just solve for x2 and y2 to find point B: (-1 + x2)/2 = 5 ---> x2 = 11 (10 + y2)/2 = -6 ---> y2 = -22 *** Therefore, the coordinates of point B are (11, -22)
Answered by ( ) - Wed May 9 20:43:56 2007
How do you convert State plane coordinates into other formats?
Q. I have this (and other) state plane coordinates I need to mark on a map! Its in Rensselaer county , NY State. N 303,026.220 E 205,684.182 Datum = NAD27 Any idea how I can do this? It only has to be within 10m square!
Asked by James W - Wed Dec 12 11:45:25 2007 - - 1 Answers - 0 Comments
A. If you are using a mapping software like ArcView, you can calulate the coordinates. If you do not have a mapping software then download the free program Corpscon and it will do it for you.
Answered by Corey D. - Wed Dec 12 11:50:51 2007
Q. I have this (and other) state plane coordinates I need to mark on a map! Its in Rensselaer county , NY State. N 303,026.220 E 205,684.182 Datum = NAD27 Any idea how I can do this? It only has to be within 10m square!
Asked by James W - Wed Dec 12 11:45:25 2007 - - 1 Answers - 0 Comments
A. If you are using a mapping software like ArcView, you can calulate the coordinates. If you do not have a mapping software then download the free program Corpscon and it will do it for you.
Answered by Corey D. - Wed Dec 12 11:50:51 2007
How to define the x,y,z coordinates of x points so that they are equally spaced out on a sphere of radius r?
Q. I want to define the x,y,z coordinates of a given number of points on a sphere of radius r so that they are equally spaced out.
Asked by James B - Thu Aug 14 09:24:00 2008 - - 1 Answers - 0 Comments
A. 3 points can uniquely define a circle. But for defining a sphere 4 points are needed. 3 points can only be spaced equidistant (120d apart) on a great circle of a sphere. If center of sphere is (0, 0), the points lie at r times of (x, y, z)= (1, 0, 0) (-1/2, sqrt3 /2, 0) (-1/2, -sqrt3 /2, 0). You can interchange x, y & z. Even if randomly, but equidistantly placed on sphere, they together define a circle and with maximum distance a great circle.
Answered by poornakumar b - Thu Aug 14 09:51:49 2008
Q. I want to define the x,y,z coordinates of a given number of points on a sphere of radius r so that they are equally spaced out.
Asked by James B - Thu Aug 14 09:24:00 2008 - - 1 Answers - 0 Comments
A. 3 points can uniquely define a circle. But for defining a sphere 4 points are needed. 3 points can only be spaced equidistant (120d apart) on a great circle of a sphere. If center of sphere is (0, 0), the points lie at r times of (x, y, z)= (1, 0, 0) (-1/2, sqrt3 /2, 0) (-1/2, -sqrt3 /2, 0). You can interchange x, y & z. Even if randomly, but equidistantly placed on sphere, they together define a circle and with maximum distance a great circle.
Answered by poornakumar b - Thu Aug 14 09:51:49 2008
Can you explain how celestial motions and coordinates work?
Q. On September 21, from Miami (long = 80 deg west, lat = +25 deg), can you observe a star with the following coordinates: RA = 19 h ; dec = -60 deg? I'm in an astronomy class and I don't understand how the date and a specific location can determine what part of the sky you can see. Does it have to do with vernal equinox? Can you please explain this to me?! HELP!
Asked by Baller28 - Tue Sep 8 16:25:14 2009 - - 3 Answers - 0 Comments
A. The longitude of Miami doesn't really come into it. Declination on the celestial sphere is the equivalent of latitude on the Earth. Thus at latitude 25 N, declination +25 will be directly overhead. To view the southern horizon, you would have to look downwards by an angle of 90 . The declination of a star on the southern horizon would therefore be +25 - 90 = -65 . The star at declination -60 would therefore just be visible for a short time each day providing it isn't daylight. To try and work out whether it's daylight on September 21st, you need to know that this is approximately the date of the autumnal equinox (not vernal), when the Sun is at RA 12h. The star at RA 19h would therefore be on the meridian in the south (at it's highest) [cont.]
Answered by bikenbeer2000 - Tue Sep 8 17:00:22 2009
Q. On September 21, from Miami (long = 80 deg west, lat = +25 deg), can you observe a star with the following coordinates: RA = 19 h ; dec = -60 deg? I'm in an astronomy class and I don't understand how the date and a specific location can determine what part of the sky you can see. Does it have to do with vernal equinox? Can you please explain this to me?! HELP!
Asked by Baller28 - Tue Sep 8 16:25:14 2009 - - 3 Answers - 0 Comments
A. The longitude of Miami doesn't really come into it. Declination on the celestial sphere is the equivalent of latitude on the Earth. Thus at latitude 25 N, declination +25 will be directly overhead. To view the southern horizon, you would have to look downwards by an angle of 90 . The declination of a star on the southern horizon would therefore be +25 - 90 = -65 . The star at declination -60 would therefore just be visible for a short time each day providing it isn't daylight. To try and work out whether it's daylight on September 21st, you need to know that this is approximately the date of the autumnal equinox (not vernal), when the Sun is at RA 12h. The star at RA 19h would therefore be on the meridian in the south (at it's highest) [cont.]
Answered by bikenbeer2000 - Tue Sep 8 17:00:22 2009
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The government wants to map the GPS coordinates directly to you front door! In fact this very thing is probably happening as we speak. 14000 workers intend to map coordinates to some 140 million addresses nationwide. The Census Bureau has commented ...
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TABLE: . coordinates. . type: range. possible_keys: x_floor_y_floor_col_a. KEY: x_floor_y_floor_col_a. key_len: 40. ref: NULL. rows: 121. Extra: using where. 1 row IN SET (0.00 sec). Fantastic! The only remaining problem with this query is ...
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