What are the names of the products of these reactions?
Q. -hydrochloric acid+silver nitrate -magnesium+copper(II) sulfate -copper+silver nitrate -lead(II) nitrate+sodium hydroxide -potassium iodide+silver nitrate -barium chloride+sodium carbonate -lead+silver nitrate -lead (II) nitrate+barium chloride -copper(II) sulfate+magnesium -sodium chloride+lead(II) nitrate Thank you :D
Asked by Anolay S - Mon Nov 10 18:45:37 2008 - - 2 Answers - 0 Comments
A. hydrochloric acid+silver nitrate --> sliver chloride + nitric acid(HNO3) -magnesium+copper(II) sulfate --> magnesium sulphate + copper -copper+silver nitrate --> copper(II) nitrate + silver -lead(II) nitrate+sodium hydroxide --> lead(II) hydroxide + sodium nitrate -potassium iodide+silver nitrate --> potassium nitrate + silver iodide -barium chloride+sodium carbonate --> barium carbonate + sodium chloride -lead+silver nitrate --> lead(II) nitrate + silver -lead (II) nitrate+barium chloride --> barium nitrate + lead(II) chlordie -copper(II) sulfate+magnesium --> magnesium sulphate + copper -sodium chloride+lead(II) nitrate --> sodium nitrate + lead(II) chloride
Answered by NJ-NJ=NJ+NJ - Mon Nov 10 18:57:40 2008
Q. -hydrochloric acid+silver nitrate -magnesium+copper(II) sulfate -copper+silver nitrate -lead(II) nitrate+sodium hydroxide -potassium iodide+silver nitrate -barium chloride+sodium carbonate -lead+silver nitrate -lead (II) nitrate+barium chloride -copper(II) sulfate+magnesium -sodium chloride+lead(II) nitrate Thank you :D
Asked by Anolay S - Mon Nov 10 18:45:37 2008 - - 2 Answers - 0 Comments
A. hydrochloric acid+silver nitrate --> sliver chloride + nitric acid(HNO3) -magnesium+copper(II) sulfate --> magnesium sulphate + copper -copper+silver nitrate --> copper(II) nitrate + silver -lead(II) nitrate+sodium hydroxide --> lead(II) hydroxide + sodium nitrate -potassium iodide+silver nitrate --> potassium nitrate + silver iodide -barium chloride+sodium carbonate --> barium carbonate + sodium chloride -lead+silver nitrate --> lead(II) nitrate + silver -lead (II) nitrate+barium chloride --> barium nitrate + lead(II) chlordie -copper(II) sulfate+magnesium --> magnesium sulphate + copper -sodium chloride+lead(II) nitrate --> sodium nitrate + lead(II) chloride
Answered by NJ-NJ=NJ+NJ - Mon Nov 10 18:57:40 2008
Word equations for chemical reactions?
Q. Lead (II) Nitrate + Potassium Iodide Sodium Hydroxide + Copper (II) Sulfate Iron (III) Nitrate + Potassium Thiocyanate thank you so much !!!
Asked by Hero/Heroine - Fri Apr 24 00:38:08 2009 - - 4 Answers - 0 Comments
A. 1)Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3 2)copper (II) sulfate and sodium hydroxide --> copper (II) hydroxide + sodium sulfate CuSO4 + NaOH --> CuOH2 + Na2SO4 3)Iron (III) thiocyanate The nitrate ions will separate and form potassium nitrate as well. BE: Fe(NO3)3(aq) + 3KSCN -> Fe(SCN)3 + 3KNO3 hope this helps
Answered by luna - Fri Apr 24 00:49:23 2009
Q. Lead (II) Nitrate + Potassium Iodide Sodium Hydroxide + Copper (II) Sulfate Iron (III) Nitrate + Potassium Thiocyanate thank you so much !!!
Asked by Hero/Heroine - Fri Apr 24 00:38:08 2009 - - 4 Answers - 0 Comments
A. 1)Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3 2)copper (II) sulfate and sodium hydroxide --> copper (II) hydroxide + sodium sulfate CuSO4 + NaOH --> CuOH2 + Na2SO4 3)Iron (III) thiocyanate The nitrate ions will separate and form potassium nitrate as well. BE: Fe(NO3)3(aq) + 3KSCN -> Fe(SCN)3 + 3KNO3 hope this helps
Answered by luna - Fri Apr 24 00:49:23 2009
chemistry help plz! writing and balancing equations?
Q. ok so i got this paper do tmw and if i dont pass it i will recieve an incomplete for the course and have to retake it next year. (which believe me is a waste of tax payers money) if u help me i will be forever greatful. god bless. I need the balanced equation for the following reactions: synthesis reaction of zinc and sulfur- copper and oxygen- copper and sulfur - calcium oxide and water- decomposition of mercuric oxide- sodium bicarbonate- cupric sulfate pentahydrate- single replacement zinc and hydrobolic acid- zinc and cupric sulfate- copper and silver nitrate - sodium bromide and chlorine- calcium and hydrogen hydroxide- double replacement silver nitrate+ sodium chloride- sodium sulfite+ hydrochloric acid- … [cont.]
Asked by eric - Sun May 10 21:48:25 2009 - - 1 Answers - 0 Comments
A. You've got to be kidding. I and others will be glad to try to explain some sticky point of chemistry, but I don't do your homework for you. If there is something you don't understand, like what a synthesis reaction is, then I'll be glad to explain that it is where two or more reactants combine to form a single product. But we won't do all of these for you. Check out page 6 on the North Carolina references tables. It contains some guidelines on equation writing. If this is standing in the way of you passing chemistry, then maybe you don't need to pass. Re-taking the course, might be your best option.
Answered by pisgahchemist - Sun May 10 21:58:59 2009
Q. ok so i got this paper do tmw and if i dont pass it i will recieve an incomplete for the course and have to retake it next year. (which believe me is a waste of tax payers money) if u help me i will be forever greatful. god bless. I need the balanced equation for the following reactions: synthesis reaction of zinc and sulfur- copper and oxygen- copper and sulfur - calcium oxide and water- decomposition of mercuric oxide- sodium bicarbonate- cupric sulfate pentahydrate- single replacement zinc and hydrobolic acid- zinc and cupric sulfate- copper and silver nitrate - sodium bromide and chlorine- calcium and hydrogen hydroxide- double replacement silver nitrate+ sodium chloride- sodium sulfite+ hydrochloric acid- … [cont.]
Asked by eric - Sun May 10 21:48:25 2009 - - 1 Answers - 0 Comments
A. You've got to be kidding. I and others will be glad to try to explain some sticky point of chemistry, but I don't do your homework for you. If there is something you don't understand, like what a synthesis reaction is, then I'll be glad to explain that it is where two or more reactants combine to form a single product. But we won't do all of these for you. Check out page 6 on the North Carolina references tables. It contains some guidelines on equation writing. If this is standing in the way of you passing chemistry, then maybe you don't need to pass. Re-taking the course, might be your best option.
Answered by pisgahchemist - Sun May 10 21:58:59 2009
Can someone PLEASE write the formulars for these compounds?
Q. like carbon dioxide would be CO2 I have no idea how to do these and I really need help. Please!!! -Silver Nitrate -Barium Chloride -Copper(II) Nitrate -Copper(II) Sulfate -Lead(II) Nitrate -Potassium Iodide -Sodium Thiosulfate I don't know if they are even called formulas but you get what I mean. I got : AgNO3 BaCl2 Cu(NO3)2 CuSO3 Pb(NO3)2 KI Na2S2O3 is that right?
Asked by SchoolSucks - Thu Sep 10 22:14:53 2009 - - 1 Answers - 0 Comments
A. Only one wrong The sulfate ion is (SO4)2- giving CuSO4 for copper (II) sulfate ((SO3)2- is sulfite) Alll others are correct
Answered by Lexi R - Fri Sep 11 01:02:38 2009
Q. like carbon dioxide would be CO2 I have no idea how to do these and I really need help. Please!!! -Silver Nitrate -Barium Chloride -Copper(II) Nitrate -Copper(II) Sulfate -Lead(II) Nitrate -Potassium Iodide -Sodium Thiosulfate I don't know if they are even called formulas but you get what I mean. I got : AgNO3 BaCl2 Cu(NO3)2 CuSO3 Pb(NO3)2 KI Na2S2O3 is that right?
Asked by SchoolSucks - Thu Sep 10 22:14:53 2009 - - 1 Answers - 0 Comments
A. Only one wrong The sulfate ion is (SO4)2- giving CuSO4 for copper (II) sulfate ((SO3)2- is sulfite) Alll others are correct
Answered by Lexi R - Fri Sep 11 01:02:38 2009
Chemical Equation Help?
Q. Write correct formulas for the reactants, identify the reaction type, write correct formulas for the products, and balance the equation. Use the appropriate symbols/subscripts to indicate conditions and states of matter. Zinc + Hydrochloric acid (aq) Copper (II) nitrate (aq) + Sodium sulfate (aq) Magnesium + Oxygen (heated) Ammonium hydroxide (aq) + Sulfuric acid (aq) Silver oxide (solid) (heated) Copper (II) nitrate (aq) + Magnesium Aluminum nitrate (aq) + Sodium hydroxide (aq) Silver + Sulfer (both solid) (heated) Barium nitrate (aq) + Potassium phosphate (aq) Sodium iodide (aq) + Chlorine (aq)
Asked by spaceace_50212 - Wed Apr 22 14:00:33 2009 - - 1 Answers - 0 Comments
A. Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (g) Single Displacement Cu(NO3)2 (aq) + Na2SO4 (aq) --> CuSO4 (s) + 2NaNO3 (aq) Double Displacement 2Mg (s) + O2 (g) --> 2MgO (s) Synthesis/Combination NH4OH (aq) + H2SO4 (aq) --> (NH4)2SO4 + HNO3 (aq) Acid-Base Neutralization (Double Displacement) 2Ag2O (S) --> 4Ag (s) + O2 (g) Decomposition Cu(NO3)2 (aq) + Mg (s) --> Mg(NO3)2 (aq) + Cu (s) Single Displacement Al(NO3)3 (aq) + 3NaOH (aq) --> 3NaNO3 (aq) + Al(OH)3 (s) Double Displacement Ag (s) + S (s) --> Ag2S (s) Synthesis/Combination 3Ba(NO3)2 (aq) + 2K3PO4 (aq) --> Ba3(PO4)2 (s)+ 6KNO3 (aq) Double Displacement NaI (aq) + Cl2 (g) --> NaCl (aq) + I2 (s) Double Displacement
Answered by Zafer - Wed Apr 22 14:15:34 2009
Q. Write correct formulas for the reactants, identify the reaction type, write correct formulas for the products, and balance the equation. Use the appropriate symbols/subscripts to indicate conditions and states of matter. Zinc + Hydrochloric acid (aq) Copper (II) nitrate (aq) + Sodium sulfate (aq) Magnesium + Oxygen (heated) Ammonium hydroxide (aq) + Sulfuric acid (aq) Silver oxide (solid) (heated) Copper (II) nitrate (aq) + Magnesium Aluminum nitrate (aq) + Sodium hydroxide (aq) Silver + Sulfer (both solid) (heated) Barium nitrate (aq) + Potassium phosphate (aq) Sodium iodide (aq) + Chlorine (aq)
Asked by spaceace_50212 - Wed Apr 22 14:00:33 2009 - - 1 Answers - 0 Comments
A. Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (g) Single Displacement Cu(NO3)2 (aq) + Na2SO4 (aq) --> CuSO4 (s) + 2NaNO3 (aq) Double Displacement 2Mg (s) + O2 (g) --> 2MgO (s) Synthesis/Combination NH4OH (aq) + H2SO4 (aq) --> (NH4)2SO4 + HNO3 (aq) Acid-Base Neutralization (Double Displacement) 2Ag2O (S) --> 4Ag (s) + O2 (g) Decomposition Cu(NO3)2 (aq) + Mg (s) --> Mg(NO3)2 (aq) + Cu (s) Single Displacement Al(NO3)3 (aq) + 3NaOH (aq) --> 3NaNO3 (aq) + Al(OH)3 (s) Double Displacement Ag (s) + S (s) --> Ag2S (s) Synthesis/Combination 3Ba(NO3)2 (aq) + 2K3PO4 (aq) --> Ba3(PO4)2 (s)+ 6KNO3 (aq) Double Displacement NaI (aq) + Cl2 (g) --> NaCl (aq) + I2 (s) Double Displacement
Answered by Zafer - Wed Apr 22 14:15:34 2009
After acidification with dilute nitric acid, a colourless solution of X reacts with aqueous silver nitrate to?
Q. After acidification with dilute nitric acid, a colourless solution of X reacts with aqueous silver nitrate to give a white precipitate. What could X be? Choose one answer. a. calcium iodide b. copper(II) chloride c. iron(ll) iodide d. sodium chloride
Asked by the3_littlepigs - Thu Mar 29 08:19:16 2007 - - 2 Answers - 0 Comments
A. The acidified silver nitrate test is used to identify chlorides, and as the solution is colorless we can identify that X is sodium chloride (d), as copper (II) chloride is a deep blue colour.
Answered by The exclamation mark - Thu Mar 29 08:32:26 2007
Q. After acidification with dilute nitric acid, a colourless solution of X reacts with aqueous silver nitrate to give a white precipitate. What could X be? Choose one answer. a. calcium iodide b. copper(II) chloride c. iron(ll) iodide d. sodium chloride
Asked by the3_littlepigs - Thu Mar 29 08:19:16 2007 - - 2 Answers - 0 Comments
A. The acidified silver nitrate test is used to identify chlorides, and as the solution is colorless we can identify that X is sodium chloride (d), as copper (II) chloride is a deep blue colour.
Answered by The exclamation mark - Thu Mar 29 08:32:26 2007
Homeschooling Homework Help Science Gr 10 Chemistry?
Q. - Ca(AIO2)2 + HCI -> AICI3 + CaCI2 + H2O - C7H5N306 + O2 -> CO2 + N2 + H2O Balanced equations for the following: a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper (II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a postssium bromide solution e) lead (IV) nitrate and sodium iodide undergo a double displacement reaction I have been going crazy and my dad won't let me go the the youth dance unless this is done. Please can someone help...Thank you so much
Asked by margarittanosalt - Wed Nov 29 15:56:32 2006 - - 3 Answers - 0 Comments
A. a) 3SiO2 +2 Al --->3 Si + 2Al2O3 b)AgNO3 +HCl---> AgCl +HNO3 c) Mg + CuSO4 ---> MgSO4 + Cu d) Pb(NO3)4 +4 NaI --->4 NaNO3 + PbI4 (s)
Answered by science teacher - Wed Nov 29 17:19:00 2006
Q. - Ca(AIO2)2 + HCI -> AICI3 + CaCI2 + H2O - C7H5N306 + O2 -> CO2 + N2 + H2O Balanced equations for the following: a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper (II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a postssium bromide solution e) lead (IV) nitrate and sodium iodide undergo a double displacement reaction I have been going crazy and my dad won't let me go the the youth dance unless this is done. Please can someone help...Thank you so much
Asked by margarittanosalt - Wed Nov 29 15:56:32 2006 - - 3 Answers - 0 Comments
A. a) 3SiO2 +2 Al --->3 Si + 2Al2O3 b)AgNO3 +HCl---> AgCl +HNO3 c) Mg + CuSO4 ---> MgSO4 + Cu d) Pb(NO3)4 +4 NaI --->4 NaNO3 + PbI4 (s)
Answered by science teacher - Wed Nov 29 17:19:00 2006
easy ten points! balancing equations. chemistry help!?
Q. balanced equations to represent each reaction below?: a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper(II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a potassium bromide solution e) lead(IV) nitrate and sodium iodide undergo a double displacement reaction
Asked by bob - Wed Nov 5 19:41:38 2008 - - 1 Answers - 0 Comments
A. 3SiO2 +4 Al >>2 Al2O3 +3 Si AgNO3 + HCl >> AgCl + HNO3 Mg + CuSO4 >> MgSO4 + Cu Cl2 + 2 KBr >> 2 KCl + Br2 Pb(NO3)4 + 4 NaI >> PbI4 + 4 NaNO3
Answered by Dr.A - Thu Nov 6 08:50:50 2008
Q. balanced equations to represent each reaction below?: a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper(II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a potassium bromide solution e) lead(IV) nitrate and sodium iodide undergo a double displacement reaction
Asked by bob - Wed Nov 5 19:41:38 2008 - - 1 Answers - 0 Comments
A. 3SiO2 +4 Al >>2 Al2O3 +3 Si AgNO3 + HCl >> AgCl + HNO3 Mg + CuSO4 >> MgSO4 + Cu Cl2 + 2 KBr >> 2 KCl + Br2 Pb(NO3)4 + 4 NaI >> PbI4 + 4 NaNO3
Answered by Dr.A - Thu Nov 6 08:50:50 2008
easy ten points!! chemistry help!!?
Q. balanced equations to represent each reaction? a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper(II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a potassium bromide solution e) lead(IV) nitrate and sodium iodide undergo a double displacement reaction thanks alot
Asked by ASHA Y - Wed Nov 5 20:30:05 2008 - - 2 Answers - 0 Comments
A. a) 3SiO2 + 2Al -> 3Si + 2AlO3 b) AgNO3 + HCl -> AgCl + HNO3 c) Mg + CuSO4 -> MgSO4 + Cu d) Cl + KBr -> KCl + Br e) Pb(NO3)4 + 4NaI -> PbI4 + 4NaNO3
Answered by monkey31492 - Wed Nov 5 20:41:34 2008
Q. balanced equations to represent each reaction? a) silicon dioxide gas reacts with solid aluminum to produce solid silicon and solid aluminum oxide b) silver nitrate reacts with hydrogen chloride to produce silver chloride and hydrogen nitrate c) magnesium and copper(II) sulphate undergo a single displacement reaction d) to produce a single displacement reaction, chlorine gas is bubbled into a potassium bromide solution e) lead(IV) nitrate and sodium iodide undergo a double displacement reaction thanks alot
Asked by ASHA Y - Wed Nov 5 20:30:05 2008 - - 2 Answers - 0 Comments
A. a) 3SiO2 + 2Al -> 3Si + 2AlO3 b) AgNO3 + HCl -> AgCl + HNO3 c) Mg + CuSO4 -> MgSO4 + Cu d) Cl + KBr -> KCl + Br e) Pb(NO3)4 + 4NaI -> PbI4 + 4NaNO3
Answered by monkey31492 - Wed Nov 5 20:41:34 2008
Chemistry help, please?
Q. 1.) iron + sulfur ---> iron (II) sulfide 2.) zinc + copper(II) sulfate ---> zinc sulfate + copper 3.) silver nitrate + sodium bromide ---> sodium nitrate + silver bromide 4.) potassium chlorate (heated) ---> potassium chloride + oxygen 5.) water (electricity) ---> hydrogen + oxygen 6.) mercury(II) oxide (heated) ---> mercury + oxygen 7.) potassium iodide + lead(II) nitrate ---> lead(II) iodide + potassium nitrate 8.) aluminum + oxygen ---> aluminum oxide 9.) magnesium chloride + ammonium nitrate ---> magnesium nitrate + ammonium chloride 10.) iron(III) cloride + ammonium hydroxide ---> iron(III) hydroxide + ammonium chloride 11.) sodium peroxide + water ---> sodium hydroxide + oxygen 12.) iron(III) oxide + carbon --> iron + carbon… [cont.]
Asked by Elise - Wed Jan 30 19:32:00 2008 - - 1 Answers - 0 Comments
A. OK - I'll write out the chemcial formulas. 1.Fe S FeS 2. Zn CuSO4 ZnSO4 Cu 3. AgNO3 NaBr NaNO3 AgBr 4.KClO4 KCl O2 5. H2O H2 O2 6. HgO Hg O2 7. KI Pb(NO3)2 PbI2 KNO3 8. Al O2 Al2O3 9. MgCl2 NH4NO3 Mg(NO3)2 NH4Cl 10. FeCl3 NH4OH Fe(OH)3 NH4Cl 11. Na2O2 H2O NaOH O2 12. Fe2O3 C Fe CO 13. Fe H2O H2 FeO 14. FeCl3 KOH KCl Fe(OH)3 15. Al H2SO4 Al2(SO4)3 H2 Good luck
Answered by KennyB - Wed Jan 30 19:50:32 2008
Q. 1.) iron + sulfur ---> iron (II) sulfide 2.) zinc + copper(II) sulfate ---> zinc sulfate + copper 3.) silver nitrate + sodium bromide ---> sodium nitrate + silver bromide 4.) potassium chlorate (heated) ---> potassium chloride + oxygen 5.) water (electricity) ---> hydrogen + oxygen 6.) mercury(II) oxide (heated) ---> mercury + oxygen 7.) potassium iodide + lead(II) nitrate ---> lead(II) iodide + potassium nitrate 8.) aluminum + oxygen ---> aluminum oxide 9.) magnesium chloride + ammonium nitrate ---> magnesium nitrate + ammonium chloride 10.) iron(III) cloride + ammonium hydroxide ---> iron(III) hydroxide + ammonium chloride 11.) sodium peroxide + water ---> sodium hydroxide + oxygen 12.) iron(III) oxide + carbon --> iron + carbon… [cont.]
Asked by Elise - Wed Jan 30 19:32:00 2008 - - 1 Answers - 0 Comments
A. OK - I'll write out the chemcial formulas. 1.Fe S FeS 2. Zn CuSO4 ZnSO4 Cu 3. AgNO3 NaBr NaNO3 AgBr 4.KClO4 KCl O2 5. H2O H2 O2 6. HgO Hg O2 7. KI Pb(NO3)2 PbI2 KNO3 8. Al O2 Al2O3 9. MgCl2 NH4NO3 Mg(NO3)2 NH4Cl 10. FeCl3 NH4OH Fe(OH)3 NH4Cl 11. Na2O2 H2O NaOH O2 12. Fe2O3 C Fe CO 13. Fe H2O H2 FeO 14. FeCl3 KOH KCl Fe(OH)3 15. Al H2SO4 Al2(SO4)3 H2 Good luck
Answered by KennyB - Wed Jan 30 19:50:32 2008
Anything interesting I can do with these chemicals?
Q. -Cobalt (II) chloride hexahydrate -Copper (II) Sulphate -Sodium Metasilicate -Calcium Hydroxide -Calcium Nitrate -Citric Acid -Iron (II) Sulphate -Methylene Blue - Potassium Iodide - Sodium Tetraborate -Sodium Carbonate powder - Sodium sulphate -ammonium aluminium sulphate -ammonium chloride -magnesium suplhate -phenolphthalein -sodium carbonate -zinc powder - Potassium Nitrate - Sodium Hydroxide anything worth doing? Recommend any others that would give me a good reaction :D
Asked by You Make Me Smile - Tue Jul 8 13:26:22 2008 - - 4 Answers - 0 Comments
A. 1) Add a few drops of phenolphthalein to some distilled water (1 cup). Now test each of the compounds above by putting a few grains of each solid into 10 ml of the aqueous Phenolphthalein. The basic materials will turn the solution red. 2) Put copper (II) sulfate into distilled water and Note the color. (pale blue) now add ammonium chloride and make it dissolve in the solution. There should be no color change . Now add a few drops of NaOH to the mixture ( a little att a time . The Ammonium ion will turn into the ammonia and the ammonia will form a deep blue complex with the copper (II) ion. 3) Make a dilute solution of calcium Hydoxide and filter it through a coffe filter. Now take a straw and blow into the clear calcium hydoxide… [cont.]
Answered by George F - Tue Jul 8 13:57:41 2008
Q. -Cobalt (II) chloride hexahydrate -Copper (II) Sulphate -Sodium Metasilicate -Calcium Hydroxide -Calcium Nitrate -Citric Acid -Iron (II) Sulphate -Methylene Blue - Potassium Iodide - Sodium Tetraborate -Sodium Carbonate powder - Sodium sulphate -ammonium aluminium sulphate -ammonium chloride -magnesium suplhate -phenolphthalein -sodium carbonate -zinc powder - Potassium Nitrate - Sodium Hydroxide anything worth doing? Recommend any others that would give me a good reaction :D
Asked by You Make Me Smile - Tue Jul 8 13:26:22 2008 - - 4 Answers - 0 Comments
A. 1) Add a few drops of phenolphthalein to some distilled water (1 cup). Now test each of the compounds above by putting a few grains of each solid into 10 ml of the aqueous Phenolphthalein. The basic materials will turn the solution red. 2) Put copper (II) sulfate into distilled water and Note the color. (pale blue) now add ammonium chloride and make it dissolve in the solution. There should be no color change . Now add a few drops of NaOH to the mixture ( a little att a time . The Ammonium ion will turn into the ammonia and the ammonia will form a deep blue complex with the copper (II) ion. 3) Make a dilute solution of calcium Hydoxide and filter it through a coffe filter. Now take a straw and blow into the clear calcium hydoxide… [cont.]
Answered by George F - Tue Jul 8 13:57:41 2008
Chemistry: Balanced Equations...HELP!!?
Q. Barium Hydroxide + Carbonic Acid Silver Nitrate + Sodium Chloride Copper II Sulfate + Sodium Hydroxide Cobalt II Chloride + Sodium Carbonate Magnesium + Zinc Sulfate Magnesium + Hydrochloric Acid Magnesium + Acetic Acid Hydrochloric Acid + Sodium Hydroxide Sulfuric Acid + Potassium Hydroxide Sulfur + Oxygen Sulfer Dioxide + Water Sulfer Dioxide + Oxygen Sulfer Trioxide + Water Sulfuric Acid + Calcium Carbonate Hydrochloric Acid + Sodium Carbonate Iron (III) Nitrate + Sodium Thiocynate Copper (II) Sulfate + Ammonia Hydrogen Peroxide + Potassium Iodide + Acid Iodide + Starch Silver Chloride + Ammonia Copper Sulfide + Hot Nitric Acid Bismith Ion + Ammonia Nickel Sulfide + Nitric Acid Calcium Ion Oxalate
Asked by what!!! - Tue Jul 22 20:04:21 2008 - - 1 Answers - 0 Comments
A. Ba(OH)2 + H2CO3 >> BaCO3 + 2 H2O AgNO3 + NaCl >> AgCl + NaNO3 CuSO4 + 2 NaOH >> Cu(OH)2 + Na2SO4 CoCl2 + Na2CO3 >> CoCO3 + 2 NaCl Mg + ZnSO4 >> MgSO4 + Zn Mg + 2 HCl >> MgCl2 + H2 Mg + 2 CH3COOH >> Mg(CH3COO)2 + H2 HCl + NaOH >> NaCl + H2O H2SO4 + 2 KOH >> K2SO4 + 2 H2O S + O2 >> SO2 2 SO2 + O2 >> 2 SO3 SO3 + H2O >> H2SO4 H2SO4 + CaCO3 >> CaSO4 + H2CO3 2 HCl + Na2CO3 >> H2CO3 + 2 NaCl Fe(NO3)3 +3 KSCN >> Fe(SCN)3 + 3 KNO3 CuSO4 + 2 NH4OH >>Cu(OH)2 + (NH4)2SO4
Answered by Dr.A - Wed Jul 23 04:14:49 2008
Q. Barium Hydroxide + Carbonic Acid Silver Nitrate + Sodium Chloride Copper II Sulfate + Sodium Hydroxide Cobalt II Chloride + Sodium Carbonate Magnesium + Zinc Sulfate Magnesium + Hydrochloric Acid Magnesium + Acetic Acid Hydrochloric Acid + Sodium Hydroxide Sulfuric Acid + Potassium Hydroxide Sulfur + Oxygen Sulfer Dioxide + Water Sulfer Dioxide + Oxygen Sulfer Trioxide + Water Sulfuric Acid + Calcium Carbonate Hydrochloric Acid + Sodium Carbonate Iron (III) Nitrate + Sodium Thiocynate Copper (II) Sulfate + Ammonia Hydrogen Peroxide + Potassium Iodide + Acid Iodide + Starch Silver Chloride + Ammonia Copper Sulfide + Hot Nitric Acid Bismith Ion + Ammonia Nickel Sulfide + Nitric Acid Calcium Ion Oxalate
Asked by what!!! - Tue Jul 22 20:04:21 2008 - - 1 Answers - 0 Comments
A. Ba(OH)2 + H2CO3 >> BaCO3 + 2 H2O AgNO3 + NaCl >> AgCl + NaNO3 CuSO4 + 2 NaOH >> Cu(OH)2 + Na2SO4 CoCl2 + Na2CO3 >> CoCO3 + 2 NaCl Mg + ZnSO4 >> MgSO4 + Zn Mg + 2 HCl >> MgCl2 + H2 Mg + 2 CH3COOH >> Mg(CH3COO)2 + H2 HCl + NaOH >> NaCl + H2O H2SO4 + 2 KOH >> K2SO4 + 2 H2O S + O2 >> SO2 2 SO2 + O2 >> 2 SO3 SO3 + H2O >> H2SO4 H2SO4 + CaCO3 >> CaSO4 + H2CO3 2 HCl + Na2CO3 >> H2CO3 + 2 NaCl Fe(NO3)3 +3 KSCN >> Fe(SCN)3 + 3 KNO3 CuSO4 + 2 NH4OH >>Cu(OH)2 + (NH4)2SO4
Answered by Dr.A - Wed Jul 23 04:14:49 2008
Chemistry Equation help?
Q. for 10 pointss??? pls help with the equation and the observation for the following.. -lead II nitrate solution and potassium iodide solution -barium chloride solution and copper II sulfate solution -solid zinc hydroxide and sodium hydroxide solution -potassium permanganate solution and ethanol -zinc metal and copper II sulfate solution -hydrogen sulfide gas bubbled through chlorine water -1 mole HCL solution and 1 mole Na[Al(OH)4] solution -chlorine water and sodium sulfide solution -ammonium phosphate solution and magnesium chloride solution -copper II nitrate solution and sodium sulfide solution -ethanoic acid and acidified ethanol is heated -ammonia gas is added to water containing methyl orange -acidified sodium dichromate… [cont.]
Asked by hello =] - Tue Apr 29 09:00:54 2008 - - 3 Answers - 0 Comments
A. I can help only with the equations... -lead II nitrate solution and potassium iodide solution : Pb (NO3)2 + 2 K I ===> Pb (I)2 + 2 K NO3 -barium chloride solution and copper II sulfate solution Ba (Cl)2 + Cu SO4 ===> Ba SO4 + Cu (Cl)2 -zinc metal and copper II sulfate solution Zn + Cu SO4 ===> Zn SO4 + Cu -ammonium phosphate solution and magnesium chloride solution 4(NH4)3 PO4 + 6Mg (Cl)2 ===> 12NH4 Cl + 2Mg3 (PO4)2 -copper II nitrate solution and sodium sulfide solution Cu (NO3)2 + Na2 S ===> 2Na NO3 + CuS -ethanoic acid and acidified ethanol is heated CH3 COOH + C2 H5 OH (acidified and heated) ===> CH3-COO-C2 H5 + H2O -hydrochloric acid and silver nitrate… [cont.]
Answered by Addy - The Boy Genius!!! - Tue Apr 29 09:19:01 2008
Q. for 10 pointss??? pls help with the equation and the observation for the following.. -lead II nitrate solution and potassium iodide solution -barium chloride solution and copper II sulfate solution -solid zinc hydroxide and sodium hydroxide solution -potassium permanganate solution and ethanol -zinc metal and copper II sulfate solution -hydrogen sulfide gas bubbled through chlorine water -1 mole HCL solution and 1 mole Na[Al(OH)4] solution -chlorine water and sodium sulfide solution -ammonium phosphate solution and magnesium chloride solution -copper II nitrate solution and sodium sulfide solution -ethanoic acid and acidified ethanol is heated -ammonia gas is added to water containing methyl orange -acidified sodium dichromate… [cont.]
Asked by hello =] - Tue Apr 29 09:00:54 2008 - - 3 Answers - 0 Comments
A. I can help only with the equations... -lead II nitrate solution and potassium iodide solution : Pb (NO3)2 + 2 K I ===> Pb (I)2 + 2 K NO3 -barium chloride solution and copper II sulfate solution Ba (Cl)2 + Cu SO4 ===> Ba SO4 + Cu (Cl)2 -zinc metal and copper II sulfate solution Zn + Cu SO4 ===> Zn SO4 + Cu -ammonium phosphate solution and magnesium chloride solution 4(NH4)3 PO4 + 6Mg (Cl)2 ===> 12NH4 Cl + 2Mg3 (PO4)2 -copper II nitrate solution and sodium sulfide solution Cu (NO3)2 + Na2 S ===> 2Na NO3 + CuS -ethanoic acid and acidified ethanol is heated CH3 COOH + C2 H5 OH (acidified and heated) ===> CH3-COO-C2 H5 + H2O -hydrochloric acid and silver nitrate… [cont.]
Answered by Addy - The Boy Genius!!! - Tue Apr 29 09:19:01 2008
balancing equations help?
Q. Can you help me balance these equations and state whether its s/l/g/aq. 1. Copper (II) sulfate pentahydrate and water 2. Potassium iodide and lead (II) nitrate 3. Copper and silver nitrate 4. Sodium carbonate and lime water
Asked by XyZ12 - Wed Dec 5 21:04:31 2007 - - 1 Answers - 0 Comments
A. 1. CuSO_4 * 5 H_2O(s) + H_2O (l)--> CuSO_4(aq) + 6 H_2O(l) (Double Replacement Reaction) 2. KI(ag) + Pb(NO_3)_2(aq) --> 2 KNO_3(s) + PbI_2(aq) (Double Replacement Reaction) 3. Cu(s) + 2 AgNO_3(aq) --> Cu(NO_3)_2(aq) + 2 Ag(s) (Single Replacemnet Reaction) 4. NaCO_3 (s) + Ca(OH)_2(aq) --> 2 NaOH (aq) + 2 Ca(CO_3) (s) (double Replacement) The underscores refer to the subscripts
Answered by americandog02 - Wed Dec 5 21:22:51 2007
Q. Can you help me balance these equations and state whether its s/l/g/aq. 1. Copper (II) sulfate pentahydrate and water 2. Potassium iodide and lead (II) nitrate 3. Copper and silver nitrate 4. Sodium carbonate and lime water
Asked by XyZ12 - Wed Dec 5 21:04:31 2007 - - 1 Answers - 0 Comments
A. 1. CuSO_4 * 5 H_2O(s) + H_2O (l)--> CuSO_4(aq) + 6 H_2O(l) (Double Replacement Reaction) 2. KI(ag) + Pb(NO_3)_2(aq) --> 2 KNO_3(s) + PbI_2(aq) (Double Replacement Reaction) 3. Cu(s) + 2 AgNO_3(aq) --> Cu(NO_3)_2(aq) + 2 Ag(s) (Single Replacemnet Reaction) 4. NaCO_3 (s) + Ca(OH)_2(aq) --> 2 NaOH (aq) + 2 Ca(CO_3) (s) (double Replacement) The underscores refer to the subscripts
Answered by americandog02 - Wed Dec 5 21:22:51 2007
I need help with chemical equations for this reaction? They are Precipitate reactions?
Q. okay, 1. write out the chemical equation in words for each of the reaction which gave you precipitate: ( in the lab, I got this equations that gave me ppt) - HgCl2{Mercury II Chloride} w/ No2(Co3) {Sodium Carbonate} - No2(Co3) {Sodium Carbonate} w/ Pb(No3)2 {Lead II nitrate) - No2(Co3) {Sodium Carbonate} w/ KI {Potassium iodide} - Pb(No3)2 {Lead II nitrate) w/ Na2(SO4){Sodium Sulfate) -BaCl2 {Barium Cloride} w/ Na2(SO4){Sodium Sulfate) -CuCl2 {Copper II chloride} w/ No2(Co3) {Sodium Carbonate} - CuCl2 {Copper II chloride} w/ KI {Potassium iodide} there are a lot more, but those are that I dont understand also what are chemical "word" and how do I write the corresponding chemical equations using the correct chemical for each below… [cont.]
Asked by MadNet - Sun Dec 17 15:20:17 2006 - - 1 Answers - 0 Comments
A. The names of your reactants have two words. Switch the first word in each name to get the name of the two new products. If you have to identify which of the new substances formed the precipitate, look for a compound that does not contain sodium or potassium (I don't see anything in your third equation that would form a precipitate). When a new substance forms that is "insoluble" in water, that means it "falls" out of solution as a precipitate and the solution looks cloudy. That's how you recognize the formation of a precipitate - the solution turns cloudy. I'll do the first reaction for you: Mercury(II)chloride plus sodium carbonate form sodium chloride and mercury(II) carbonate (the precipitate). If you need the equation using… [cont.]
Answered by The Old Professor - Sun Dec 17 15:33:18 2006
Q. okay, 1. write out the chemical equation in words for each of the reaction which gave you precipitate: ( in the lab, I got this equations that gave me ppt) - HgCl2{Mercury II Chloride} w/ No2(Co3) {Sodium Carbonate} - No2(Co3) {Sodium Carbonate} w/ Pb(No3)2 {Lead II nitrate) - No2(Co3) {Sodium Carbonate} w/ KI {Potassium iodide} - Pb(No3)2 {Lead II nitrate) w/ Na2(SO4){Sodium Sulfate) -BaCl2 {Barium Cloride} w/ Na2(SO4){Sodium Sulfate) -CuCl2 {Copper II chloride} w/ No2(Co3) {Sodium Carbonate} - CuCl2 {Copper II chloride} w/ KI {Potassium iodide} there are a lot more, but those are that I dont understand also what are chemical "word" and how do I write the corresponding chemical equations using the correct chemical for each below… [cont.]
Asked by MadNet - Sun Dec 17 15:20:17 2006 - - 1 Answers - 0 Comments
A. The names of your reactants have two words. Switch the first word in each name to get the name of the two new products. If you have to identify which of the new substances formed the precipitate, look for a compound that does not contain sodium or potassium (I don't see anything in your third equation that would form a precipitate). When a new substance forms that is "insoluble" in water, that means it "falls" out of solution as a precipitate and the solution looks cloudy. That's how you recognize the formation of a precipitate - the solution turns cloudy. I'll do the first reaction for you: Mercury(II)chloride plus sodium carbonate form sodium chloride and mercury(II) carbonate (the precipitate). If you need the equation using… [cont.]
Answered by The Old Professor - Sun Dec 17 15:33:18 2006
Chemistry Net Ionic Equation Help!?!?
Q. Hi, I'm having a bit of trouble understanding how to do these net ionic equations, so I thought I'd try and get some help! 1.Aqueous solutions of copper(II) Cu2+ nitrate NO-3 and sodium Na+ hydroxide OH- are mixed. 2.Aqueous solutions of nickel(II) Ni2+ chloride Cl- and sodium Na+ carbonate CO2-3 are mixed. 3.A solution of sodium Na+ hydroxide OH- is added by drops to a solution of aluminium Al3+ nitrate NO-3 a.Initially b.With excess NaOH 4.Solution of ammonia NH3 is added by drops to a solution of zinc Zn2+ Nitrate NO-3 a.Initially b.With excess NH3 5.Aqueous solutions of potassium K+ chromate CrO2-4 and sulfuric acid are mixed. 6.Aqueous solutions of lead Pb2+ nitrate NO-3 and sodium Na+ iodide I- are mixed. Any guidance would… [cont.]
Asked by montana_to_rice8 - Mon Mar 30 04:48:21 2009 - - 1 Answers - 0 Comments
A. Thats alot of problems, I'll show you some, and hopefuly you'll be able to do the rest. 5) K4CrO2+H2S-->KS+H4CrO2 (unbalanced) first off, it's a good idea to balance these things out after getting them set up K4CrO2+2H2S-->2K2S+H4CrO2 Now we break apart what we can, 4K^(+1)+2CrO^(-1)+4H^(+1) +2S^(-2) -->4K^(+1)+2S^(-2)+H4CrO2 Note that the H4CrO2 is insoluable because it is a weak acid. now we cancle out what we can --- and are left with 2CrO^(-1)+4H^(+1)-->H4CrO 2 also notice that the nonsoluable things don't show their ionic charges, because they don't break apart. ~~~ once again, the steps are as follows balance the equation make sure there are the same amount of elements/compounds on each side write out there ionic forms… [cont.]
Answered by unknown - Mon Mar 30 05:41:02 2009
Q. Hi, I'm having a bit of trouble understanding how to do these net ionic equations, so I thought I'd try and get some help! 1.Aqueous solutions of copper(II) Cu2+ nitrate NO-3 and sodium Na+ hydroxide OH- are mixed. 2.Aqueous solutions of nickel(II) Ni2+ chloride Cl- and sodium Na+ carbonate CO2-3 are mixed. 3.A solution of sodium Na+ hydroxide OH- is added by drops to a solution of aluminium Al3+ nitrate NO-3 a.Initially b.With excess NaOH 4.Solution of ammonia NH3 is added by drops to a solution of zinc Zn2+ Nitrate NO-3 a.Initially b.With excess NH3 5.Aqueous solutions of potassium K+ chromate CrO2-4 and sulfuric acid are mixed. 6.Aqueous solutions of lead Pb2+ nitrate NO-3 and sodium Na+ iodide I- are mixed. Any guidance would… [cont.]
Asked by montana_to_rice8 - Mon Mar 30 04:48:21 2009 - - 1 Answers - 0 Comments
A. Thats alot of problems, I'll show you some, and hopefuly you'll be able to do the rest. 5) K4CrO2+H2S-->KS+H4CrO2 (unbalanced) first off, it's a good idea to balance these things out after getting them set up K4CrO2+2H2S-->2K2S+H4CrO2 Now we break apart what we can, 4K^(+1)+2CrO^(-1)+4H^(+1) +2S^(-2) -->4K^(+1)+2S^(-2)+H4CrO2 Note that the H4CrO2 is insoluable because it is a weak acid. now we cancle out what we can --- and are left with 2CrO^(-1)+4H^(+1)-->H4CrO 2 also notice that the nonsoluable things don't show their ionic charges, because they don't break apart. ~~~ once again, the steps are as follows balance the equation make sure there are the same amount of elements/compounds on each side write out there ionic forms… [cont.]
Answered by unknown - Mon Mar 30 05:41:02 2009
I need help im chemistry class. Please Correct the formula of each of the compounds?
Q. Potassium Iodide, Barium chloride, lithium Bromide, Iron(III) sulfate, Chrominum(III) sulfide, Calcium Carbonate, sodium acetate, cobalt(II) fluoride, sodium phosphide, tin(IV) oxide, gold(III) bromide, copper(II) iodide, stromium chloride, lithium acetate, magnbesium hydroxide, nickel(II) nitrate, silver oxide, zinc chloride, magnesium phospate. Thanks you for taking the time doing these.
Asked by truckin_90 - Wed Oct 4 13:32:41 2006 - - 3 Answers - 0 Comments
A. potassium iodide: KI barium chloride: BaCl2 lithium bromide: LiBr iron III sulfate: Fe2(SO4)3 chromium sulfide: Cr2S3 Calcium carbonate: CaCO3 Sodium acetate: NaCH3COO Cobalt II fluoride: CoF2 Sodium phosphide: Na3P tin IV oxide: SnO2 gold III bromide: AuBr3 copper II oxide: CuO Strontium chloride: SrCl2 Lithium acetate: LeCH3COO Magnesium hydroxide: Mg(OH)2 nickel II nitrate: Ni(NO3)2 Silver oxide: Ag2O is most likely, AgO is possible zink chloride: ZnCl2 Magnesium phosphate: Mg3(PO4)2
Answered by yupchagee - Wed Oct 4 13:46:44 2006
Q. Potassium Iodide, Barium chloride, lithium Bromide, Iron(III) sulfate, Chrominum(III) sulfide, Calcium Carbonate, sodium acetate, cobalt(II) fluoride, sodium phosphide, tin(IV) oxide, gold(III) bromide, copper(II) iodide, stromium chloride, lithium acetate, magnbesium hydroxide, nickel(II) nitrate, silver oxide, zinc chloride, magnesium phospate. Thanks you for taking the time doing these.
Asked by truckin_90 - Wed Oct 4 13:32:41 2006 - - 3 Answers - 0 Comments
A. potassium iodide: KI barium chloride: BaCl2 lithium bromide: LiBr iron III sulfate: Fe2(SO4)3 chromium sulfide: Cr2S3 Calcium carbonate: CaCO3 Sodium acetate: NaCH3COO Cobalt II fluoride: CoF2 Sodium phosphide: Na3P tin IV oxide: SnO2 gold III bromide: AuBr3 copper II oxide: CuO Strontium chloride: SrCl2 Lithium acetate: LeCH3COO Magnesium hydroxide: Mg(OH)2 nickel II nitrate: Ni(NO3)2 Silver oxide: Ag2O is most likely, AgO is possible zink chloride: ZnCl2 Magnesium phosphate: Mg3(PO4)2
Answered by yupchagee - Wed Oct 4 13:46:44 2006
I need help with these Chemical equations....?
Q. Complete the word equation Then write the balanced equation. 27. calcium + oxygen >>> 28. copper(II) carbonate>>> 29. aluminum + hydrochloric acid >>> 30. potassium iodide + chlorine >>> 31. barium chloride + sodium sulfate >>> 32. copper + silver nitrate >>> copper(II) nitrate + 33. barium hydroxide + sulfuric acid>>> 34. zinc sulfate + ammonium sulfide>>> 35. sodium + water >>> 36. magnesium + sulfuric acid >>> 37. Mercury(II) oxide >>>
Asked by truckin_90 - Thu Dec 28 22:53:08 2006 - - 1 Answers - 0 Comments
A. Your chemistry book should explain to you the different types of chemical reactions. For example, the 5 types of reactions are: (1)Combination / Synthesis (2)Decomposition (3)Combustion (4)Single Replacement (5)Double Replacement It is hard to show you how to balance equations on the computer, but you book should explain it to you too.
Answered by theOffice - Thu Dec 28 23:42:09 2006
Q. Complete the word equation Then write the balanced equation. 27. calcium + oxygen >>> 28. copper(II) carbonate>>> 29. aluminum + hydrochloric acid >>> 30. potassium iodide + chlorine >>> 31. barium chloride + sodium sulfate >>> 32. copper + silver nitrate >>> copper(II) nitrate + 33. barium hydroxide + sulfuric acid>>> 34. zinc sulfate + ammonium sulfide>>> 35. sodium + water >>> 36. magnesium + sulfuric acid >>> 37. Mercury(II) oxide >>>
Asked by truckin_90 - Thu Dec 28 22:53:08 2006 - - 1 Answers - 0 Comments
A. Your chemistry book should explain to you the different types of chemical reactions. For example, the 5 types of reactions are: (1)Combination / Synthesis (2)Decomposition (3)Combustion (4)Single Replacement (5)Double Replacement It is hard to show you how to balance equations on the computer, but you book should explain it to you too.
Answered by theOffice - Thu Dec 28 23:42:09 2006
Can someone check my answer for balancing equations / help me? :D (its pretty easy!!) THANKS!?
Q. Hi! I'm working on my chemistry H homework right now, but I'm having trouble because I'm not sure how to balance equations with compounds that have roman numerals :( !! Here are the ones I'm confused on (help w/ at least one would be great! :D thank you!) : #1 Zinc reacts with copper(II) nitrate to form zinc nitrate and copper. My Answer: Zn + CuNo3 = ZnNo3 + Cu #2 Manganese (II) iodide decomposes when exposed to light to form manganese and iodine. My Answer: MgI = Mg + I #3 Magnesium reacts with titanium (IV) chloride to produce magnesium chloride and titanium. #4 Bromine reacts with sodium iodide to form sodium bromide and iodide. My Answer: Br + NaI = NaBr + I #5 Sulfuric acid, H2SO4, reacts with potassium hydroxide to produce… [cont.]
Asked by Erica - Thu Oct 22 23:06:56 2009 - - 1 Answers - 0 Comments
A. 1 Zinc reacts with copper(II) nitrate to form zinc nitrate and copper. My Answer: Zn + CuNo3 = ZnNo3 + Cu should be Zn + Cu(NO3)2 = Zn(NO3)2 + Cu #2 Manganese (II) iodide decomposes when exposed to light to form manganese and iodine. My Answer: MgI = Mg + I should be MnI2 = Mn + I2 #3 Magnesium reacts with titanium (IV) chloride to produce magnesium chloride and titanium. should be 2Mg + TiCl4 = 2MgCl2 + Ti #4 Bromine reacts with sodium iodide to form sodium bromide and iodide. My Answer: Br + NaI = NaBr + I #5 Sulfuric acid, H2SO4, reacts with potassium hydroxide to produce potassium sulfate and water. My Answer: H2SO4 + K(OH) = KSO4 + H2O it should be H2SO4 + 2K(OH) = K2SO4 + 2H2O
Answered by R W - Sat Oct 24 23:36:39 2009
Q. Hi! I'm working on my chemistry H homework right now, but I'm having trouble because I'm not sure how to balance equations with compounds that have roman numerals :( !! Here are the ones I'm confused on (help w/ at least one would be great! :D thank you!) : #1 Zinc reacts with copper(II) nitrate to form zinc nitrate and copper. My Answer: Zn + CuNo3 = ZnNo3 + Cu #2 Manganese (II) iodide decomposes when exposed to light to form manganese and iodine. My Answer: MgI = Mg + I #3 Magnesium reacts with titanium (IV) chloride to produce magnesium chloride and titanium. #4 Bromine reacts with sodium iodide to form sodium bromide and iodide. My Answer: Br + NaI = NaBr + I #5 Sulfuric acid, H2SO4, reacts with potassium hydroxide to produce… [cont.]
Asked by Erica - Thu Oct 22 23:06:56 2009 - - 1 Answers - 0 Comments
A. 1 Zinc reacts with copper(II) nitrate to form zinc nitrate and copper. My Answer: Zn + CuNo3 = ZnNo3 + Cu should be Zn + Cu(NO3)2 = Zn(NO3)2 + Cu #2 Manganese (II) iodide decomposes when exposed to light to form manganese and iodine. My Answer: MgI = Mg + I should be MnI2 = Mn + I2 #3 Magnesium reacts with titanium (IV) chloride to produce magnesium chloride and titanium. should be 2Mg + TiCl4 = 2MgCl2 + Ti #4 Bromine reacts with sodium iodide to form sodium bromide and iodide. My Answer: Br + NaI = NaBr + I #5 Sulfuric acid, H2SO4, reacts with potassium hydroxide to produce potassium sulfate and water. My Answer: H2SO4 + K(OH) = KSO4 + H2O it should be H2SO4 + 2K(OH) = K2SO4 + 2H2O
Answered by R W - Sat Oct 24 23:36:39 2009
What are the formulas for these ionic compounds?
Q. Ammonium hydroxide magnesium nitrate aluminum chlorate lead(IV) sulfide sodium oxalate sodium chromate lead(II) chloride copper (II) carbonate potassium phosphate iron (II) chloride mercury (I) iodide barium sulfate calcium acetate magnesium sulfate tin (IV) oxide ammonium phosphate tin (IV) sulfide can you also explain to me how you get these answers.
Asked by nothinbutnet2009 - Wed Jan 9 17:45:38 2008 - - 3 Answers - 0 Comments
A. Ammonium hydroxide-NH4OH magnesium nitrate-Mg(NO3)2 aluminum chlorate- Al(ClO3)3 lead(IV) sulfide-PbS2 sodium oxalate-Na2C2O4 sodium chromate-CrNa2O4 lead(II) chloride-PbCl2 copper (II) carbonate-CuCO3 potassium phosphate- product contains a mixture of both potassium phosphate monobasic (KH2PO4) and potassium phosphate dibasic (K2HPO4) iron (II) chloride-FeCl3 mercury (I) iodide-HgI2 barium sulfate-BaSO4 calcium acetate-Ca(C2H3O2)2 magnesium sulfate-MgSO4 tin (IV) oxide-SnO2 ammonium phosphate-(NH4)3PO4 tin (IV) sulfide-SnS2
Answered by Melissa - Wed Jan 9 18:07:17 2008
Q. Ammonium hydroxide magnesium nitrate aluminum chlorate lead(IV) sulfide sodium oxalate sodium chromate lead(II) chloride copper (II) carbonate potassium phosphate iron (II) chloride mercury (I) iodide barium sulfate calcium acetate magnesium sulfate tin (IV) oxide ammonium phosphate tin (IV) sulfide can you also explain to me how you get these answers.
Asked by nothinbutnet2009 - Wed Jan 9 17:45:38 2008 - - 3 Answers - 0 Comments
A. Ammonium hydroxide-NH4OH magnesium nitrate-Mg(NO3)2 aluminum chlorate- Al(ClO3)3 lead(IV) sulfide-PbS2 sodium oxalate-Na2C2O4 sodium chromate-CrNa2O4 lead(II) chloride-PbCl2 copper (II) carbonate-CuCO3 potassium phosphate- product contains a mixture of both potassium phosphate monobasic (KH2PO4) and potassium phosphate dibasic (K2HPO4) iron (II) chloride-FeCl3 mercury (I) iodide-HgI2 barium sulfate-BaSO4 calcium acetate-Ca(C2H3O2)2 magnesium sulfate-MgSO4 tin (IV) oxide-SnO2 ammonium phosphate-(NH4)3PO4 tin (IV) sulfide-SnS2
Answered by Melissa - Wed Jan 9 18:07:17 2008
From Yahoo Answer Search: 'copper (II) nitrate and sodium iodide'
Thu Nov 19 04:17:23 2009 [ refresh local cache ]
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chemistry notes / igcse-gcse- Olevel: reactivity series - IGCSE /GCSE
ida stanly
Wed, 05 Nov 2008 14:13:01 GM
Iron displaces . copper. from a solution of . copper II. sulphate. . Copper. displaces silver from a solution of silver . nitrate. . Given this information we can deduce that the most reactive of the three metals is iron, followed by . copper. , followed by silver. This allows us to arrange the . ... Similarly, we can predict that . iodide. ions (left hand side) will NOT react with zinc ions (left hand side) as the zinc ions are poor oxidising agents and the . iodide. ions poor reducing agents. ...
ida stanly
Wed, 05 Nov 2008 14:13:01 GM
Iron displaces . copper. from a solution of . copper II. sulphate. . Copper. displaces silver from a solution of silver . nitrate. . Given this information we can deduce that the most reactive of the three metals is iron, followed by . copper. , followed by silver. This allows us to arrange the . ... Similarly, we can predict that . iodide. ions (left hand side) will NOT react with zinc ions (left hand side) as the zinc ions are poor oxidising agents and the . iodide. ions poor reducing agents. ...
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