What physical method of separation should be used to separate the copper (II) sulfate pentahydrate and sand ?
Q. What physical method of separation should be used to separate the copper (II) sulfate pentahydrate and sand from each other? What is the basic procedure? What equipment should be used? THANKS~ :]
Asked by LOSTONE - Sun Sep 28 13:32:18 2008 - - 1 Answers - 0 Comments
A. Copper(II) sulfate is soluble in water, while sand is not. Add the mixture to distilled water, stir until all CuSO4 dissolves. Filter the solution. Remove the filtrate (liquid) and either boil off the water or let it evaporate to recover the copper sulfate. Rinse the sand with water and let dry to recover it.
Answered by zircalium - Sun Sep 28 15:12:00 2008
Q. What physical method of separation should be used to separate the copper (II) sulfate pentahydrate and sand from each other? What is the basic procedure? What equipment should be used? THANKS~ :]
Asked by LOSTONE - Sun Sep 28 13:32:18 2008 - - 1 Answers - 0 Comments
A. Copper(II) sulfate is soluble in water, while sand is not. Add the mixture to distilled water, stir until all CuSO4 dissolves. Filter the solution. Remove the filtrate (liquid) and either boil off the water or let it evaporate to recover the copper sulfate. Rinse the sand with water and let dry to recover it.
Answered by zircalium - Sun Sep 28 15:12:00 2008
Given copper (II) sulfate, what less expensive metal could you use to precipitate the copper out of solution?
Q. It's for a chemistry test... please help! The full question is: If a mine had a rich copper ore in which the copper was mostly found as copper (II) sulfate, what less expensive metal could be used to precipitate the copper out of solution?
Asked by benjymg92london - Tue Nov 4 14:07:31 2008 - - 1 Answers - 0 Comments
A. for Cu+2 to be reduced to Cu metal, it takes 2 electrons with a force of Eo = +0.337 all of these will work Aluminum --> Al+3 @ Eo = +1.66 volts Magnesium --> Mg+2 @ Eo = +2.37 volts Zinc --> Zn+2 @ Eo = + 0.763 volts Iron --> Fe+2 @ Eo = 0.440 Volts prices as of today: Copper $ 1.7962/pound Aluminum $.8918/ pound Magnesium $ 1.36/pound Zinc $0.4992/pound "Prepared" scrap Iron $0.08/pound your answer ... all of the metals given are cheaper than copper, will do the job, but srap iron is the cheapest/ mole of electrons
Answered by Steve O - Tue Nov 4 14:53:06 2008
Q. It's for a chemistry test... please help! The full question is: If a mine had a rich copper ore in which the copper was mostly found as copper (II) sulfate, what less expensive metal could be used to precipitate the copper out of solution?
Asked by benjymg92london - Tue Nov 4 14:07:31 2008 - - 1 Answers - 0 Comments
A. for Cu+2 to be reduced to Cu metal, it takes 2 electrons with a force of Eo = +0.337 all of these will work Aluminum --> Al+3 @ Eo = +1.66 volts Magnesium --> Mg+2 @ Eo = +2.37 volts Zinc --> Zn+2 @ Eo = + 0.763 volts Iron --> Fe+2 @ Eo = 0.440 Volts prices as of today: Copper $ 1.7962/pound Aluminum $.8918/ pound Magnesium $ 1.36/pound Zinc $0.4992/pound "Prepared" scrap Iron $0.08/pound your answer ... all of the metals given are cheaper than copper, will do the job, but srap iron is the cheapest/ mole of electrons
Answered by Steve O - Tue Nov 4 14:53:06 2008
Can you calculate the mass of solid copper (II) sulfate pentahydrate needed?
Q. 1. Calculate the mass of solid copper (II) sulfate pentahydrate needed to prepare 100.0 mL of a 0.5000 mol/L solution 2. Calculate the Volume of a 0.5000 mol/L standard solution of CuSO4(aq) required to prepare 250.0 mL of a 0.02000 mol/L solution Please show steps to answer too
Asked by Ron Loves Jessie - Fri Apr 10 17:17:25 2009 - - 3 Answers - 0 Comments
A. 100ml of 0.5M solution: 0.1L * 0.5mol / L = 0.05 mol each mole of Copper (II) Sulfate Pentahydrate = 249.5 g 0.05 mol * 249.5g/mol = 12.475g 2) M1V1 = M2V2 (.250)(.02) = (.5)(v) ---> V = (.25)(.02)/(.5) = .01L = 10ml btw ktrna69's answer was wrong: She calculated mass for monohydrate not pentahydrate
Answered by itzezbeinmoe - Fri Apr 10 17:25:46 2009
Q. 1. Calculate the mass of solid copper (II) sulfate pentahydrate needed to prepare 100.0 mL of a 0.5000 mol/L solution 2. Calculate the Volume of a 0.5000 mol/L standard solution of CuSO4(aq) required to prepare 250.0 mL of a 0.02000 mol/L solution Please show steps to answer too
Asked by Ron Loves Jessie - Fri Apr 10 17:17:25 2009 - - 3 Answers - 0 Comments
A. 100ml of 0.5M solution: 0.1L * 0.5mol / L = 0.05 mol each mole of Copper (II) Sulfate Pentahydrate = 249.5 g 0.05 mol * 249.5g/mol = 12.475g 2) M1V1 = M2V2 (.250)(.02) = (.5)(v) ---> V = (.25)(.02)/(.5) = .01L = 10ml btw ktrna69's answer was wrong: She calculated mass for monohydrate not pentahydrate
Answered by itzezbeinmoe - Fri Apr 10 17:25:46 2009
Does a change in color observed when copper(II)sulfate crystals become dehydrated?
Q. How do you account for the color change when water is added to the heated copper(II)sulfate?
Asked by k0hrin - Fri Aug 10 10:49:17 2007 - - 2 Answers - 0 Comments
A. Copper(II )sulfate pentahydrate is blue. When it is heated, the water present in the pentahydrate evaporates. Copper slufate anhydrous remaines. It is white in color. If water is then added back and mixed with the anhydrous compound, then the color returns to blue as copper(II )sulfate pentahydrate is formed.
Answered by Metallic stuff - Fri Aug 10 15:15:14 2007
Q. How do you account for the color change when water is added to the heated copper(II)sulfate?
Asked by k0hrin - Fri Aug 10 10:49:17 2007 - - 2 Answers - 0 Comments
A. Copper(II )sulfate pentahydrate is blue. When it is heated, the water present in the pentahydrate evaporates. Copper slufate anhydrous remaines. It is white in color. If water is then added back and mixed with the anhydrous compound, then the color returns to blue as copper(II )sulfate pentahydrate is formed.
Answered by Metallic stuff - Fri Aug 10 15:15:14 2007
What's the formula mass for Copper(II) Sulfate Pentahydrate?
Q. I know that copper is Cu2 and that sulfate is So4 but what would Pentahydrate be So far I know that Penta stands for 5 but what would it all be? Thanks to those who take there time to answer my question.
Asked by Bubbagum - Thu Oct 2 00:01:13 2008 - - 2 Answers - 0 Comments
A. Well first you will need to balance this compound. You make the first Ionic, then, for each Ionic compound (CuSO4) you will need 5 waters. So: CuSO4.5H2O Then, find the molar mass of Copper (63.54g/mol) then the molar mass of Sulfur (32) then the molar mass of Oxygen (16) then multiply the Oxygen by Four, because you have 4 of them, then add those. You should get 159.54g, then add 5 times the molar mass of H2O (16 + 1 + 1) to get 90. Then add 90 and 159.54, and you get 249.54g/mole. And that answer is rounded of course, because I'm lazy.
Answered by Taylor D - Thu Oct 2 00:15:45 2008
Q. I know that copper is Cu2 and that sulfate is So4 but what would Pentahydrate be So far I know that Penta stands for 5 but what would it all be? Thanks to those who take there time to answer my question.
Asked by Bubbagum - Thu Oct 2 00:01:13 2008 - - 2 Answers - 0 Comments
A. Well first you will need to balance this compound. You make the first Ionic, then, for each Ionic compound (CuSO4) you will need 5 waters. So: CuSO4.5H2O Then, find the molar mass of Copper (63.54g/mol) then the molar mass of Sulfur (32) then the molar mass of Oxygen (16) then multiply the Oxygen by Four, because you have 4 of them, then add those. You should get 159.54g, then add 5 times the molar mass of H2O (16 + 1 + 1) to get 90. Then add 90 and 159.54, and you get 249.54g/mole. And that answer is rounded of course, because I'm lazy.
Answered by Taylor D - Thu Oct 2 00:15:45 2008
Calculate the percentage of the hydrate's mass due to copper II sulfate and the percentage that was due to H2O?
Q. The formula is CuSO4 xH2O. The original mass of the copper II sulfate hydrate was 1.55g and the mass of the anhydrous crystals was .98g. How do I find the percentage composition of the copper II sulfate and then H20? thanks :D
Asked by Rise, Lord Vader - Sat Feb 21 15:39:22 2009 - - 3 Answers - 0 Comments
A. The hydrate's formula is actually CuSO4 x nH2O, where n is unknown and has to be determined. Molecular masses: CuSO4 160 H2O 18 CuSO4 x nH2O 160+18n The mass of water is the difference between the mass of the hydrate and the mass of anhydrous crystals: 1.55-0.98=0.57 g. 160 g CuSO4...0.98 g CuSO4 18n g H2O...0.57 g H2O From here you get n=5, so the formula is CuSO4 x 5H2O Now for the percentage calculation 160+5*18 g hydrate...160 g CuSO4...5*18g H2O 100 g hydrate ...x...y x=64% CuSO4 y=36% H2O
Answered by Doctor D - Sat Feb 21 16:00:14 2009
Q. The formula is CuSO4 xH2O. The original mass of the copper II sulfate hydrate was 1.55g and the mass of the anhydrous crystals was .98g. How do I find the percentage composition of the copper II sulfate and then H20? thanks :D
Asked by Rise, Lord Vader - Sat Feb 21 15:39:22 2009 - - 3 Answers - 0 Comments
A. The hydrate's formula is actually CuSO4 x nH2O, where n is unknown and has to be determined. Molecular masses: CuSO4 160 H2O 18 CuSO4 x nH2O 160+18n The mass of water is the difference between the mass of the hydrate and the mass of anhydrous crystals: 1.55-0.98=0.57 g. 160 g CuSO4...0.98 g CuSO4 18n g H2O...0.57 g H2O From here you get n=5, so the formula is CuSO4 x 5H2O Now for the percentage calculation 160+5*18 g hydrate...160 g CuSO4...5*18g H2O 100 g hydrate ...x...y x=64% CuSO4 y=36% H2O
Answered by Doctor D - Sat Feb 21 16:00:14 2009
what change happens to an iron nail and copper (II) sulfate?
Q. An iron nail is put into a test tube with copper (II) sulfate. After 15 minutes what change has happened to the iron nail and copper (II) sulfate? CuSO4+Fe=FeSO4+Cu ??
Asked by Coco - Mon Oct 8 16:48:37 2007 - - 2 Answers - 0 Comments
A. Redox! The copper precipitates into a solid and the iron dissolves, becoming aqueous. I think.
Answered by Sean S - Mon Oct 8 16:54:32 2007
Q. An iron nail is put into a test tube with copper (II) sulfate. After 15 minutes what change has happened to the iron nail and copper (II) sulfate? CuSO4+Fe=FeSO4+Cu ??
Asked by Coco - Mon Oct 8 16:48:37 2007 - - 2 Answers - 0 Comments
A. Redox! The copper precipitates into a solid and the iron dissolves, becoming aqueous. I think.
Answered by Sean S - Mon Oct 8 16:54:32 2007
What is the products of calcium chloride and copper (II) sulfate pentahydrate?
Q. The hydrate is the part that in confusing.
Asked by J M - Wed Apr 30 15:53:17 2008 - - 2 Answers - 0 Comments
A. A rare nickel polymorphide conglomorate only found in isolated phitoplankon east of Vladivostok.
Answered by Tuna County - Wed Apr 30 15:59:10 2008
Q. The hydrate is the part that in confusing.
Asked by J M - Wed Apr 30 15:53:17 2008 - - 2 Answers - 0 Comments
A. A rare nickel polymorphide conglomorate only found in isolated phitoplankon east of Vladivostok.
Answered by Tuna County - Wed Apr 30 15:59:10 2008
In chemistry, if I heat copper (II) sulfate in water and then add steel wool to the mixture, what is formed?
Q. In a chemistry lab, I added copper (II) sulfate to water and dissolved it. Then, I added steel wool to the heated solution. I can't figure out the formula or the resulting creation. The resulting creation was a dust-like purple maroon substance.
Asked by azteckathryn - Wed Feb 7 22:57:48 2007 - - 2 Answers - 0 Comments
A. CuSO4 + Fe = FeSO4 + Cu steel wool is basically iron with some carbon so this is what I beleive to be true. look here for a picture of FeSO4
Answered by calpain20002000 - Wed Feb 7 23:07:54 2007
Q. In a chemistry lab, I added copper (II) sulfate to water and dissolved it. Then, I added steel wool to the heated solution. I can't figure out the formula or the resulting creation. The resulting creation was a dust-like purple maroon substance.
Asked by azteckathryn - Wed Feb 7 22:57:48 2007 - - 2 Answers - 0 Comments
A. CuSO4 + Fe = FeSO4 + Cu steel wool is basically iron with some carbon so this is what I beleive to be true. look here for a picture of FeSO4
Answered by calpain20002000 - Wed Feb 7 23:07:54 2007
zinc metal is placed in a solution of copper (II) sulfate?
Q. please solve these single replacement reactions! plz try including steps 1. zinc metal is placed in a solution of copper (II) sulfate 2. a small piece of sodium metal is added to distilled water 3. Chlorine gas is bubbled into a solution of sodium iodide first one to answer n show steps correctly gets 10 PTS!
Asked by Mia - Thu Nov 29 22:49:31 2007 - - 4 Answers - 0 Comments
A. 1. Zn + CuSO4 ===> ZnSO4 + Cu 2. 2Na + 2H2O ===> 2NaOH + H2 3. Cl2 + 2NaI ===> 2NaCl + I2
Answered by steve_geo1 - Thu Nov 29 22:55:18 2007
Q. please solve these single replacement reactions! plz try including steps 1. zinc metal is placed in a solution of copper (II) sulfate 2. a small piece of sodium metal is added to distilled water 3. Chlorine gas is bubbled into a solution of sodium iodide first one to answer n show steps correctly gets 10 PTS!
Asked by Mia - Thu Nov 29 22:49:31 2007 - - 4 Answers - 0 Comments
A. 1. Zn + CuSO4 ===> ZnSO4 + Cu 2. 2Na + 2H2O ===> 2NaOH + H2 3. Cl2 + 2NaI ===> 2NaCl + I2
Answered by steve_geo1 - Thu Nov 29 22:55:18 2007
How to syntesize copper (II) sulfate pentahydrate in a lab, starting from copper?
Q. How to syntesize copper (II) sulfate pentahydrate in a lab, starting from copper?
Asked by Dejan S - Mon Apr 7 07:52:14 2008 - - 3 Answers - 0 Comments
A. With Concentrated acid the reaction of copper Metal with Sulphuric acid will be Cu + 2H2SO4 --> CuSO4 + SO2 + 2H2O Copper + Sulphuric Acid --> Copper Sulphate + Sulphur Dioxide + Water With Dilute acid the reaction of copper Metal with Sulphuric acid will be Cu + H2SO4 --> CuSO4+ H2 Copper + Sulphuric Acid --> Copper Sulphate + Hydrogen using some excess of metal and removing it after reaction by simple filtration, the resulting blue solution can be evaporated to super saturation and allowed CuSO4 to crystal out and separate. These crystals should be filtered and dried in a desiccator (instead of under heat) to ensure that the water of crystallisation is not lost.
Answered by Abhijit Purohit - Tue Apr 8 09:48:42 2008
Q. How to syntesize copper (II) sulfate pentahydrate in a lab, starting from copper?
Asked by Dejan S - Mon Apr 7 07:52:14 2008 - - 3 Answers - 0 Comments
A. With Concentrated acid the reaction of copper Metal with Sulphuric acid will be Cu + 2H2SO4 --> CuSO4 + SO2 + 2H2O Copper + Sulphuric Acid --> Copper Sulphate + Sulphur Dioxide + Water With Dilute acid the reaction of copper Metal with Sulphuric acid will be Cu + H2SO4 --> CuSO4+ H2 Copper + Sulphuric Acid --> Copper Sulphate + Hydrogen using some excess of metal and removing it after reaction by simple filtration, the resulting blue solution can be evaporated to super saturation and allowed CuSO4 to crystal out and separate. These crystals should be filtered and dried in a desiccator (instead of under heat) to ensure that the water of crystallisation is not lost.
Answered by Abhijit Purohit - Tue Apr 8 09:48:42 2008
can u explain what happen when iron is added to dissolved copper(II) sulfate pentahydrate ?
Q. when i add steel wool into the copper(II) sulfate pentahydrate solution, it turns into pinkish red and then break down into tiny particles (greyish colour) as i stir it. when the solution is pour down into a filter paper, the residue is believed to be copper and the solution that is filtered is iron sulfate. can anyone explain why the metal displacement take place?? why the residue is copper and why iron sulfate is formed? when i add steel wool (which is iron metal with NO chage) into the copper(II) sulfate pentahydrate solution, it turns into pinkish red for a few secondsand (oxidisong) then break down into tiny particles (greyish colour) as i stir it. when the solution is pour down into a filter paper, the residue is believed to be… [cont.]
Asked by Labuuu* - Sun May 20 22:55:04 2007 - - 2 Answers - 0 Comments
A. This process is called Copper Cementation. It was used to recover copper from leached ores until the mid 1950 s when solvent extraction technology was developed. Cementation is Spanish for precipitation and named for the use of the process, carried out on an industrial scale, in the copper mines in the Rio Tinto region of Spain in the mid 18th century. Cementation is the process of spontaneous reduction of the ions of a metal by another metal above it in the electromotive series. For example, a piece of iron immersed in copper sulfate solution will be immediately covered by a thin film of copper. The iron is being anodically dissolved while copper is electroplated on its surface cathodically. This process is also called "metal… [cont.]
Answered by Metallic stuff - Mon May 21 16:46:30 2007
Q. when i add steel wool into the copper(II) sulfate pentahydrate solution, it turns into pinkish red and then break down into tiny particles (greyish colour) as i stir it. when the solution is pour down into a filter paper, the residue is believed to be copper and the solution that is filtered is iron sulfate. can anyone explain why the metal displacement take place?? why the residue is copper and why iron sulfate is formed? when i add steel wool (which is iron metal with NO chage) into the copper(II) sulfate pentahydrate solution, it turns into pinkish red for a few secondsand (oxidisong) then break down into tiny particles (greyish colour) as i stir it. when the solution is pour down into a filter paper, the residue is believed to be… [cont.]
Asked by Labuuu* - Sun May 20 22:55:04 2007 - - 2 Answers - 0 Comments
A. This process is called Copper Cementation. It was used to recover copper from leached ores until the mid 1950 s when solvent extraction technology was developed. Cementation is Spanish for precipitation and named for the use of the process, carried out on an industrial scale, in the copper mines in the Rio Tinto region of Spain in the mid 18th century. Cementation is the process of spontaneous reduction of the ions of a metal by another metal above it in the electromotive series. For example, a piece of iron immersed in copper sulfate solution will be immediately covered by a thin film of copper. The iron is being anodically dissolved while copper is electroplated on its surface cathodically. This process is also called "metal… [cont.]
Answered by Metallic stuff - Mon May 21 16:46:30 2007
What does copper (II) sulfate pentahydrate yield when heated?
Q. CuSO^4 * 5H^2O i think it forms an acid and i only need one thing it forms.
Asked by unctrack11 - Wed Dec 17 18:57:42 2008 - - 1 Answers - 0 Comments
Q. CuSO^4 * 5H^2O i think it forms an acid and i only need one thing it forms.
Asked by unctrack11 - Wed Dec 17 18:57:42 2008 - - 1 Answers - 0 Comments
What is the balanced chemical equation for the conversion of copper (II) sulfate to JUST copper metal?
Q. I reallyy am confused with this one...
Asked by Alex - Thu Apr 9 13:07:38 2009 - - 2 Answers - 0 Comments
A. Zn + CuSO4 ZnSO4 + Cu
Answered by gile - Thu Apr 9 13:19:08 2009
Q. I reallyy am confused with this one...
Asked by Alex - Thu Apr 9 13:07:38 2009 - - 2 Answers - 0 Comments
A. Zn + CuSO4 ZnSO4 + Cu
Answered by gile - Thu Apr 9 13:19:08 2009
how much precipitate formed with 2g of strontium chloride and 2g copper(II) sulfate pentahydrate in 75ml h20?
Q. What is the mass of precipitate produced by the reaction of 2.00 g of strontium chloride with 2.00g of copper(II) sulfate pentahydrate in 75 mL of water?
Asked by RIOT! - Sat Jan 31 04:14:26 2009 - - 1 Answers - 0 Comments
A. Moles SrCl2 = 2.00 g / 158.526 g/mol=0.0126 Moles CuSO4 * 5H2O = 2.00 g /249.712 g/mol= 0.00801 ( limiting reactant) we get 0.00801 moles SrSO4 mass SrSO4 = 0.00801 mol x 183.686 g/mol= 1.47 g
Answered by Dr.A - Sat Jan 31 04:32:04 2009
Q. What is the mass of precipitate produced by the reaction of 2.00 g of strontium chloride with 2.00g of copper(II) sulfate pentahydrate in 75 mL of water?
Asked by RIOT! - Sat Jan 31 04:14:26 2009 - - 1 Answers - 0 Comments
A. Moles SrCl2 = 2.00 g / 158.526 g/mol=0.0126 Moles CuSO4 * 5H2O = 2.00 g /249.712 g/mol= 0.00801 ( limiting reactant) we get 0.00801 moles SrSO4 mass SrSO4 = 0.00801 mol x 183.686 g/mol= 1.47 g
Answered by Dr.A - Sat Jan 31 04:32:04 2009
What reaction does Copper (II) Sulfate and Iron make?
Q. Please be specific and provide explanations. Thanks so much!
Asked by Nicole - Tue Nov 27 04:18:28 2007 - - 2 Answers - 0 Comments
A. under the combination of heat, the two chemicals create a burning reaction. . like the sparks of fireworks. I think that's how it works.
Answered by sarabrooke27 - Tue Nov 27 04:24:23 2007
Q. Please be specific and provide explanations. Thanks so much!
Asked by Nicole - Tue Nov 27 04:18:28 2007 - - 2 Answers - 0 Comments
A. under the combination of heat, the two chemicals create a burning reaction. . like the sparks of fireworks. I think that's how it works.
Answered by sarabrooke27 - Tue Nov 27 04:24:23 2007
What are the reduction and oxidation halves of the reaction between Aluminum and Copper II Sulfate?
Q. What are the reduction and oxidation halves of the reaction between Aluminum and Copper II Sulfate?
Asked by lovelyrita64 - Sun Mar 22 20:55:27 2009 - - 1 Answers - 0 Comments
A. Chemical Reactions? The oxidation half of Aluminum and Copper II Sulfate is:___ The reduction half of Aluminum and Copper II Sulfate is:___ hope this helps, try your book index under Reduction, and also Oxidation
Answered by dilbertina - Sun Mar 22 22:28:39 2009
Q. What are the reduction and oxidation halves of the reaction between Aluminum and Copper II Sulfate?
Asked by lovelyrita64 - Sun Mar 22 20:55:27 2009 - - 1 Answers - 0 Comments
A. Chemical Reactions? The oxidation half of Aluminum and Copper II Sulfate is:___ The reduction half of Aluminum and Copper II Sulfate is:___ hope this helps, try your book index under Reduction, and also Oxidation
Answered by dilbertina - Sun Mar 22 22:28:39 2009
how do you balance - asolution fo copper II sulfate is added to a solution of sodium phosphate.?
Q. also, what is the driving force of lthis equation?
Asked by lisa d - Wed Oct 8 16:59:56 2008 - - 1 Answers - 0 Comments
A. Driving force is the insolubility of Cu3(PO4)2 (Ksp Cu3(PO4)2 = 1.40 10-37. www.ktf-split.hr/periodni /en/abc/kpt.html 3CuSO4 + 2Na3PO4 ---> Cu3(PO4)2 + 3Na2SO4
Answered by SciMann - Wed Oct 8 19:48:21 2008
Q. also, what is the driving force of lthis equation?
Asked by lisa d - Wed Oct 8 16:59:56 2008 - - 1 Answers - 0 Comments
A. Driving force is the insolubility of Cu3(PO4)2 (Ksp Cu3(PO4)2 = 1.40 10-37. www.ktf-split.hr/periodni /en/abc/kpt.html 3CuSO4 + 2Na3PO4 ---> Cu3(PO4)2 + 3Na2SO4
Answered by SciMann - Wed Oct 8 19:48:21 2008
is there a reaction between copper (II) sulfate and potassium iodide?
Q. when i did out the equation, i did not find a precipitate. obviously there is no acid base reaction or gas evolution. thanks for any helf.
Asked by Che Bella Vita - Sun Feb 22 15:45:32 2009 - - 1 Answers - 0 Comments
A. When copper sulfate and potassium iodide are mixed, copper (II) will be reduced by iodide ion to copper (I) and the iodide ion will be oxidized to iodine, I2. The copper (I) cation then reacts with excess iodide ions to form the insoluble copper iodide. 2CuSO4+4NaI=>2CuI+I2+2Na2 SO4 You can clearly observe the violet color or I2 and precipitated CuI
Answered by chem - Sun Feb 22 16:11:59 2009
Q. when i did out the equation, i did not find a precipitate. obviously there is no acid base reaction or gas evolution. thanks for any helf.
Asked by Che Bella Vita - Sun Feb 22 15:45:32 2009 - - 1 Answers - 0 Comments
A. When copper sulfate and potassium iodide are mixed, copper (II) will be reduced by iodide ion to copper (I) and the iodide ion will be oxidized to iodine, I2. The copper (I) cation then reacts with excess iodide ions to form the insoluble copper iodide. 2CuSO4+4NaI=>2CuI+I2+2Na2 SO4 You can clearly observe the violet color or I2 and precipitated CuI
Answered by chem - Sun Feb 22 16:11:59 2009
What happens when you heat copper (II) sulfate pentahydrate?
Q. This was done during a high school lab and I need some help writing it up :S Thank You.
Asked by Mel_mar@mel - Mon Mar 9 14:36:49 2009 - - 1 Answers - 0 Comments
A. The blue rocks (crystal looking things) turn a powdery white when heated and water is given off: CuSO4*5H20 --- Cu SO4 + 5H2O Then, if a few drops of water is added back to the white powder, it turns back into the blue crystals (copper (II) sulphate pentahydrate): CuSO4 + 5H2O --- CuSO4*5H20 The reaction is reversed (reversible reaction)
Answered by XsmilesX - Mon Mar 9 18:54:05 2009
Q. This was done during a high school lab and I need some help writing it up :S Thank You.
Asked by Mel_mar@mel - Mon Mar 9 14:36:49 2009 - - 1 Answers - 0 Comments
A. The blue rocks (crystal looking things) turn a powdery white when heated and water is given off: CuSO4*5H20 --- Cu SO4 + 5H2O Then, if a few drops of water is added back to the white powder, it turns back into the blue crystals (copper (II) sulphate pentahydrate): CuSO4 + 5H2O --- CuSO4*5H20 The reaction is reversed (reversible reaction)
Answered by XsmilesX - Mon Mar 9 18:54:05 2009
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Fri, 13 Apr 2007 01:30:13 GM
About 4g of hydrated . Copper. (. II. ) . Sulfate. was added to the beaker and the weight was recorded. The beaker was placed on a hot plate, heated until the blue crystals lost there blue color. Stirring the compound was essential to making sure ...
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