Would Arithmetica Unversalis by Newton or Diophantus's Aritmetica teach me Algebra?
Q. I really do not like the traditional algebra books and while I know I must practice algebra problems to get faster and other issues, would these books teach me algebra?
Asked by aadnub4jesus - Fri Jan 23 18:22:26 2009 - - 1 Answers - 0 Comments

how are we using Diophantus of Alexandria's accomplishments today??
Q. list three examples. (please help!)
Asked by meagan - Tue Oct 16 23:41:43 2007 - - 1 Answers - 0 Comments

A. they teach it in school use it in business also in manufacturing look it up
Answered by SPCPerz - Sun Oct 21 07:38:34 2007

how long did diophantus live? (math problem)?
Q. let x be the number of years he lived. find how long he lived by using the facts below: 1/6 of his life was spent in boyhood 1/12 of his life was spent in youth after 1/7 more of his life past, he got married five years after getting married, he had a son his son lived 1/2 as long as diophantus lived the son died 4 years before diophantus died
Asked by jon n - Wed Oct 28 18:57:05 2009 - - 1 Answers - 0 Comments

How do you solve the difference between two known squares with a known solution?
Q. How do you solve x^2-y^2=60 Thanks! (It has to do with Diophantus II 10)
Asked by thebassgirl - Mon Apr 20 14:55:32 2009 - - 1 Answers - 0 Comments

A. Remember how to factor a difference of squares: (x - y)(x + y) = 60 Assuming that x and y have to be positive integers, you have the following ways to factor 60: 1 x 60 2 x 30 3 x 20 4 x 15 5 x 12 6 x 10 If you add the two equations: x - y = a x + y = b 2x = a + b So only the ones that add to even numbers will work: 2 x 30 6 x 10 Try solving each one in turn: x + y = 30 x - y = 2 2x = 32 x = 16 y = 14 x + y = 10 x - y = 6 2x = 16 x = 8 y = 2 Answers: (16,14) and (8,2) Double-check: 16 - 14 = 256 - 196 = 60 8 - 2 = 64 - 4 = 60
Answered by Puzzling - Mon Apr 20 15:04:10 2009

Hey can you help me???? This puzzle is about the Greek mathematician Diophantus, who lived around A.D. 250 ?
Q. his childhood lasted one sixth of his life; he grew a beard after one twelfth more; one seventh. The son lived exactly half as long as his father. Four years later, Diophantus died. How old was he??? (I need the answer from A through D...So can u help me???) A... Guess how old Diophantus was when he died. Check your guess. B...Make another guess. Write the steps you use to find whether your guess is correct... C...Suppose your guess is a number N. How can you check whether N is the correct result??? D...Find the correct result without guessing...
Asked by -----M----- - Thu Oct 9 23:22:12 2008 - - 2 Answers - 0 Comments

A. childhood = 1/6 life. beard after 1/12 more = 1/6 + 1/12 = 3/12 = 1/4 life --> 1/7 DOESN'T make sense. info must be missing. However, I'm going to assume that it says something like 1/7 more, he had a kid. So 1/4 + 1/7 = 11/28 life kid was born. son = 1/2 life. So son died at 11/28 + 1/2 = 11/28 + 14/28 = 25/28 life. Four years late, life complete (died), so 25/28 life + 4 = life. subtract 25/28 life from both sides and get 4 = 3/28 life life = 4*28/3 = 37.3 doesn't seem right so needed corrected question.
Answered by Chuck S - Fri Oct 10 00:35:23 2008

diophantus math problem?
Q. God granted him to be a boy for a sixth part of his life, and adding a twelfth part to this, He clothed his cheeks with down; He lit him the light of wedlock after a seventh part, and five years after his marriage He granted him a son. Alas! late-borne wretched child; after attaining the measure of half his father's life, chill Fate took him. After consoling his grief by this science of numbers for four years he ended his life. how do you solve this??
Asked by Osamu M - Sat Mar 8 12:35:27 2008 - - 2 Answers - 0 Comments

A. 12(6)=72 died 12+6=18 clothed his cheeks 18+10=28 married at 33 born child 28 =born child
Answered by Tony - Sat Mar 8 13:04:32 2008

How do I get this one right?
Q. Father of Algebra. The age of Diophantus, the father of algebra may be calculated from what is carved on his tombstone. It goes: "Diophantus' youth lasted one-sixth of his life. He grew a beard after one-twelve more. After one-seventh more of his life, Diophantus married. Five years later, he had a son. The son lived exactly one-half as long as his father, and Diophnatus died just after fours years after his son. All these add up to the years Diophantus lived" How old was Diophantus when he died? How to solve? Thanks.
Asked by Anonymous. - Sat Feb 14 03:25:01 2009 - - 4 Answers - 0 Comments

A. Diophantus lived 84 years and his son lived 42. I'll show my work in a few minutes. Let x = length of Diopantus' life youth = (1/6)*x grew a beard (1/12)*x later married (1/7)*x after that had a son 5 years after that son died and then Diophantus died 4 years later So! (1/6)*x + (1/12)*x + (1/7)*x + 5years = age of diophantus when son was born Get a common denominator and simplify, this becomes: (33/84)*x +5years = age of D when son born son's age at death = (1/2)*x x - 4 = age of father when son died With all this, how do we solve? Like so: the age of the father when the son died minus the age of the father when the son was born will be equal to the son's age, which is equal to half D's age. Here's the equation: (x - 4) - ( (3 [cont.]
Answered by A R - Sat Feb 14 03:55:01 2009

any historical note about negative numbers?
Q. esp. diophantus.
Asked by Luz - Sat Jul 5 01:42:08 2008 - - 1 Answers - 0 Comments

A. negative numbers wee first mentioned in the early writings (200 b.c.)of the chinese. diophanus, in his work arithmetica(4th century), spoke of the equation 4x+20=4 is absurd since x=-4. the hindu brahmagupta spoke of negative and affirmative quantities. the chinese mathematician chu shi-ku gave the rules of signs in his algebra text. italian mathematician cardano recognized negative roots and rules of negative numbers in his ars magna. He used symbol m(minus) for megative, such as -3 was written m:3.
Answered by Mimi - Sat Jul 5 02:20:46 2008

Here's a little word problem for the budding genius......?
Q. The question is: How long did Diophantus live? His boyhood lasted 1/6th of his life. He grew a beard after another 1/12th. After 1/7th more he got married. And had a son five years later. The son lived to half the father's age And the father died four years later.
Asked by Keira D - Fri Dec 28 10:14:25 2007 - - 6 Answers - 0 Comments

A. here is an equation to reflect the several agez of Diophanntus: 1/6x + 1/12x + 1/7x + 5 + 1/2x + 4 = x So the solution (x) is 84 years.
Answered by bergalain - Fri Dec 28 10:19:46 2007

Why do some Islamic websites still make false claims about Mathematics?
Q. Wikipedia says the following Indian contributions have not been given due acknowledgement in modern history. Many discoveries and inventions by Indian mathematicians are presently culturally attributed to their western counterparts, as a result of Eurocentrism. The historian Florian Cajori, one of the most celebrated historians of mathematics in the early 20th century, suggested that "Diophantus, the father of Greek algebra, got the first algebraic knowledge from India." This theory is supported by evidence of continuous contact between India and the Hellenistic world from the late 4th century BC, and earlier evidence that the eminent Greek mathematician Pythagoras studied in India, which further 'throws open' the Eurocentric ideal. More… [cont.]
Asked by Nick L - Mon Sep 4 17:51:17 2006 - - 17 Answers - 1 Comments

A. The so called Pythagorean therom was proven in India at least 600 years before Pythagoras was born. The Indian texts have an accurate measure of an angstrom, working electrical batteries, etc. Even the American Revolutionary War was fought by Britains Generals that were left over from the campaign in India going on at the same time. The US fought the scrubs because the Indians had rocketry. The So Called Aryan Invasion has no support, was obviously politically and religiously motivated, and is still being taught today. India has offered the highest in thought for millenia, and has had its economic wealth stolen since antiquity. They had metal recurve bows when we Europeans were still crawling around in the muck. Most of history is… [cont.]
Answered by neil s - Mon Sep 4 18:02:57 2006

Hey =] okAY, so for math i have a riddle to solve. however, i cant figure it out so please help!!!?
Q. The riddle & answer is here: However, I had additionAl questions. How old was Diophantus when he was married? How old was Diophantus when his some was born? and How old was Diophantus when his son died. Please help!!!
Asked by Iyana - Thu Aug 21 17:00:32 2008 - - 5 Answers - 0 Comments

A. How old was Diophantus when he was married? ~~ 33 years old! How old was Diophantus when his some was born? ~~ 38 years old! and How old was Diophantus when his son died. ~~ 80 years old!!!.
Answered by Brainz - Thu Aug 21 17:19:41 2008

someone plz tell me the whole equation to this.?
Q. Diophantus's youth lasted 1/6 of his life. He had the first beard in the next 1/12 of his life. At the end of the following 1/7 of his life Diophantus got married. Five years from then his son was born. His son lived exactly 1/2 of Diophantus's life. Diophantus died 4 years after the death of his son. How long did Diophantus live?
Asked by revengeance - Wed Apr 25 23:49:48 2007 - - 3 Answers - 0 Comments

A. Let us assume that Diophantus lived for x years Therefore,his youth was for x/6 years In the next x/12 years he had the first beard. After x/7 years more,he got married His son was born after 5 more years. his son lived for x/2 years,and finally after 4 years of his son's death,he died Therefore according to the problem, x=x/6+x/12+x/7 +5+x/2 +4 => 84x=14x+7x+12x+420+42x+33 6 [multiplying both sides by LCD 84] =>84x-14x-7x-12x-42x=420+ 336 =>9x=756 =>x=756/9=84 Therefore Diphantus lived for 84 years
Answered by alpha - Thu Apr 26 00:41:58 2007

can you solve this puzzle?
Q. After the death (about 290 A.D.) of Diophantus, a famous Greek mathematician, someone described his life as a puzzle. He was a boy for 1/6 of his life. After 1/12 more, he acquired a beard. After another 1/7, he married. In the fifth year after his marriage his son was born. The son lived half as many years as his father. Diophantus died 4 years after his son. How old was Diophantus when he died?
Asked by brEEZYfeen - Sat Apr 11 01:39:50 2009 - - 3 Answers - 0 Comments

A. There is an easy equation to reflect the several ages of Diophantus: 1/6x + 1/12x + 1/7x + 5 + 1/2x + 4 = x So the solution (x) is 84 years. OR another way... Knowing that ancient Greeks did not use floating point operations, (yes they use portioning like 1/2 etc.) we can figure out that all the parts of life are integers or better natural numbers. So from this i make: 1/2, 1/6, 1/7, 1/12 Finding the Lowest Common Multiple: So 7*12 = 84. Diophatius lived 84 years. his life was: Youth 14 years, Beard 14 + 7 = 21 He got married 21 + 12 = 33 Years His son was born on 33+5=38 years old his son died when he was 38+42=80 years old He died 84 years old.
Answered by Sylvia H - Sat Apr 11 01:47:03 2009

can someone help solve this riddle?
Q. Can someone solve this riddle and show me how you do it please I dont get how to set it up and stuff? Thank you very mucho!! <33 Diophantus's youth lasted one sixth of his life. He grew a beard after one twelfth more. After one seventh more of his life, he married. 5 years later, he and his wife had a son. The son lived exactly one half as long as his father, and Diophantus died four years after his son. How long did Diophantus live?
Asked by Nicole H - Mon Sep 17 19:47:53 2007 - - 7 Answers - 0 Comments

A. the riddle, the "facts" of which may or may not be true, results in the following equation: x/6 + x/12 + x/7 + 5 + x/2 + 4 = x where x is Diophantus's age at the time of his death. Therefore, Diophantus lived exactly 84 years.
Answered by Yo yo yo yo oy oyo - Mon Sep 17 20:28:33 2007

Math word problem, Help please?
Q. By working out the riddle, determine the age of the Ancient Greek mathematician, Diophantus. His youth lasted one-sixth of his life. He grew a beard after one-twelfth more. He married after one-seventh more. He had a son 5 years later. His son lived half as long as his father. Diophantus died 4 years after his son died.
Asked by Amanda - Mon May 4 10:06:03 2009 - - 1 Answers - 0 Comments

A. 1/6x+1/12x+1/7x+5+1/2x+4= x 14+7+12+9+42=84
Answered by Mr Fixit - Mon May 4 10:24:05 2009

math problems?
Q. 16. Four years ago, Boyet was two years more than thrice as old as Bong. In another four years, Boyet will be two years more than twice as old as Bong.. How old is Boyet? 17. The cost of sending a telegram is based on a flat rate for the first 10 words and a fixed charge for each additional word. If a telegram of 15 words cost P116.50 and the telegram of 19 words cost P145.70, what is the flat rate, and what is the fixed charge for each additions word? 18. The age Diophantus, the father of algebra may be calculated from what is carved on his tombstone. It goes "Diophantus' youth lasted 1/6 of his life. He grew a beard after 1/12 more. After 1/7 more of his life Diophantus married. Five years later, he had a son. The son lived exactly 1/2 [cont.]
Asked by abyy - Wed Dec 12 10:17:14 2007 - - 5 Answers - 0 Comments

A. 16) x: bong's age; y: boyet's age y -4 = (x-4)*3+2 y+4 = (x+4)*2+2 y=30 x=12 17) x=charge for each word over 10; y=flat rate 116.50= y+5x 145.70= y+9x x=7.3 y=80 18) diophantus age when he died=x diophantus age when he died= 1/6x + 1/12x + 1/7x +5+1/2x+4 = (25/28)x + 9 which means 9=(3/28)x => x=84
Answered by Miguel A - Wed Dec 12 10:55:12 2007

ProBlem In ALGEBRA!!age problem?
Q. It is told that the age of Diophantus, a Greek mathematician, may be calculated from his epitaph. His eitaph read as follows: "Diophantus spent one-sixthe of his life in childhood, one-twelfth in youth and one-seventh as a bachelor. Five years after his marraige was born a son who died four years before his father died at half his father's age." How old was Diophantus when he died?
Asked by Jonah K.E. - Wed Dec 10 09:26:39 2008 - - 1 Answers - 0 Comments

algebra problems?
Q. 1)6x+7=8x-13 2)3n/5-2/5=7/10 3)13.7b-6.5=-2.3b+8.3 4)3/2y-y=4+.5y 5)-7(x-3)=-4 6)28-2.2y=11.6y+262.6 7)7-3x=x-4(2+x) 8)6(y+2)-4=-10 9)-8(4+9x)=7(-2-11x) 10)4(2a-8)=1/7(49a+70) 11)diophantus passed one sixth of his life in childhood, one twelth in youth, and one seventh more as a bachelor. five years after his marriage, there was born a son who died four years before his father, at half his father's (final) age. how old was diophantus when he died. any answers are helpful, i'm not sure if i've been doing it right.(some are false)
Asked by giannine s - Wed Oct 10 22:23:55 2007 - - 5 Answers - 0 Comments

A. The first 10 problems simply exercise your algebra mechanics, but the story problem was more interesting. So, let "D" represent the number of years in Diophantus' life. The problem breaks down his life into several segments: D = (1/6)D + (1/12)D + (1/7)D + 5 + X + 4 And it also describes the length of the child's entire life, "C", as being half of "D": X = (1/2) D So, solving: D = (2/12)D + (1/12)D + (1/7)D + 5 + (6/12)D + 4 D = (3/4)D + (1/7)D + 9 D = (21/28)D + (4/28)D + 9 D = (25/28)D + 9 (3/28)D = 9 D = 9(28/3) D = 3*28 D = 84 childhood = (1/6)84 = 14 youth = (1/12)84 = 7 bachelor = (1/7)84 = 12 Child lived to be 42 14+7+12+5+42+4 = 84 Diophantus died at the age of 84
Answered by jj_hillis - Wed Oct 10 22:48:20 2007

MATHS ALGEBRAIC WORDED PROBLEM NEED HELP!!!?
Q. Here's the question, I'm trying to solve it but I get stuck at the end. Please show all working out. The question: Diophantus was a boy for one-sixth of his life and after a further one-twelfth of his life he started to shave. After a further one-seventh of his life he married and had a son five years later. After attaining the measure of half his father's life, the son died. Four years later Diophantus died. 1. At what age did Diophantus die? 2. What age was Diophantus when each of the events mentioned above occurred?
Asked by lckh - Tue Jan 13 18:14:16 2009 - - 1 Answers - 0 Comments

How would you go about finding the answer?
Q. I'm lacking LOTS of sleep and this question is becoming harder every time i look at it, I am just making it difficult but i need some help, please? : Diophantus passed one sixth of his life in childhood, one twelfth in youth and one seventh more as a bachelor. Five years later after his marriage, there was born a son who died for years before his father, at half his fathers final age, How old was Diophantus when he died? The way its worded confuses me, can someone help? Yes, I did man four, my keyboard is jamming buttons lately. Thank you, it makes much more sense now! Yes, I did men four, my keyboard is jamming buttons lately. Thank you, it makes much more sense now! Mean* As you can tell. :-)
Asked by Felecity - Wed Feb 20 18:30:07 2008 - - 3 Answers - 0 Comments

A. Let x = life span of father Then x/6 = childhood x/12 = youth x/7 = bachelor days son born when dad was x/6 + x/12 + x/7 + 5yrs or 14x/84 + 7x/84 + 12x/84 + 5 33x/84 +5 yrs = age when son born x/2 = life span of son x (final age of father) = 33x/84 + 5 (age when son born) + x/2 (son's age) + 4 yrs (since son died four years before dad). I think this is set up correctly but haven't worked it out.
Answered by duffy - Wed Feb 20 18:47:31 2008