EQUATIOn................. ..?
Q. P = 2(l + b) make b the subject of the equation
Asked by andrew - Sun Jun 22 06:47:35 2008 - - 8 Answers - 0 Comments
A. if you mean solving for b then... P = 2(l + b) P= 2l + 2b P - 2l= 2b 1/2p - l= b
Answered by brian - Sun Jun 22 06:52:15 2008
Q. P = 2(l + b) make b the subject of the equation
Asked by andrew - Sun Jun 22 06:47:35 2008 - - 8 Answers - 0 Comments
A. if you mean solving for b then... P = 2(l + b) P= 2l + 2b P - 2l= 2b 1/2p - l= b
Answered by brian - Sun Jun 22 06:52:15 2008
What is the balanced equation and the word equation of the following?
Q. What is the balanced equation and the word equation of the following? The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:18:47 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O + heat >> CuSO4 + 5H2O CuSO4 + 5H2O - heat >> CuSO4.5H2O
Answered by Dr.A - Sun Dec 16 12:31:42 2007
Q. What is the balanced equation and the word equation of the following? The Reaction is when Copper (II) Sulfate Hydrate crystals (CuSO4.5H2O) is HEATED until it is turned into Copper (II) Sulfate+Water. The other reaction is the REVERSE of this reaction. When water is added to Copper (II) Sulfate (the anhydrous salt) to turn into CuSO4.5H2O. Any help on the following would be GREATLY appreciated!
Asked by This Sentence Has 32 Characters! - Sun Dec 16 12:18:47 2007 - - 1 Answers - 0 Comments
A. CuSO4.5H2O + heat >> CuSO4 + 5H2O CuSO4 + 5H2O - heat >> CuSO4.5H2O
Answered by Dr.A - Sun Dec 16 12:31:42 2007
How can the equation for kinetic energy be used to explain how matter is created?
Q. The equation for kinetic energy is KE = 1/2m*v^2. In English, "Kinetic energy is equal to half the mass multiplied by the velocity squared." So how do you change energy into matter with this equation?
Asked by CrO4^2- - Mon Sep 15 01:56:37 2008 - - 1 Answers - 0 Comments
A. Think about this. Matter can't travel faster than light. Thar mean you have only one variable once object reaches speed of light since velocity is fixed. Now, if energy increase then only variable left is mass. Thus, energy goes up by increase in mass. Hey read a article on particle accelerator. It might help you.
Answered by 2cent - Mon Sep 15 02:25:31 2008
Q. The equation for kinetic energy is KE = 1/2m*v^2. In English, "Kinetic energy is equal to half the mass multiplied by the velocity squared." So how do you change energy into matter with this equation?
Asked by CrO4^2- - Mon Sep 15 01:56:37 2008 - - 1 Answers - 0 Comments
A. Think about this. Matter can't travel faster than light. Thar mean you have only one variable once object reaches speed of light since velocity is fixed. Now, if energy increase then only variable left is mass. Thus, energy goes up by increase in mass. Hey read a article on particle accelerator. It might help you.
Answered by 2cent - Mon Sep 15 02:25:31 2008
What is an equation relating heat to thermal energy?
Q. What is an equation relating heat to thermal energy? And what is an equation to solve for heat?
Asked by lala - Sat Feb 6 20:16:42 2010 - - 1 Answers - 0 Comments
A. So, it sounds like your asking how is heat energy related to temperature? There are a lot of ways - but for a stationary object increasing or decreasing in temperature you could say: Q = m*Cp*(T2-T1) where Q is heat m is mass Cp is heat capacity T2 is final temperature T1 is initial temperature Heat and temperature are also related for conduction and convection, which have different equations.
Answered by asdfasdfman - Sat Feb 6 20:31:54 2010
Q. What is an equation relating heat to thermal energy? And what is an equation to solve for heat?
Asked by lala - Sat Feb 6 20:16:42 2010 - - 1 Answers - 0 Comments
A. So, it sounds like your asking how is heat energy related to temperature? There are a lot of ways - but for a stationary object increasing or decreasing in temperature you could say: Q = m*Cp*(T2-T1) where Q is heat m is mass Cp is heat capacity T2 is final temperature T1 is initial temperature Heat and temperature are also related for conduction and convection, which have different equations.
Answered by asdfasdfman - Sat Feb 6 20:31:54 2010
What equation allows conversion to the partial pressure of that gas?
Q. Given the concentration in molarity of a gas (in the gas phase) and your knowledge of gas laws, what equation allows conversion to the partial pressure of that gas? How does this differ from the concept of Henry's Law?
Asked by Kimberly L - Sun Sep 23 11:56:29 2007 - - 1 Answers - 0 Comments
A. From PV = nRT P = nRT / V = MRT since n/V =M Henry's law partial pressure(p) = kc where c = concentration and k =constant If the concentration in Henry' law is molar concentration, then k is equal to RT.
Answered by ADITYA V - Sun Sep 23 13:07:08 2007
Q. Given the concentration in molarity of a gas (in the gas phase) and your knowledge of gas laws, what equation allows conversion to the partial pressure of that gas? How does this differ from the concept of Henry's Law?
Asked by Kimberly L - Sun Sep 23 11:56:29 2007 - - 1 Answers - 0 Comments
A. From PV = nRT P = nRT / V = MRT since n/V =M Henry's law partial pressure(p) = kc where c = concentration and k =constant If the concentration in Henry' law is molar concentration, then k is equal to RT.
Answered by ADITYA V - Sun Sep 23 13:07:08 2007
How do i algebraically determine if an equation is a function?
Q. I've been trying for a couple hours and can't figure this thing out on my own. How do I take an equation and determine if an equation is a function: x=y^2 y=sqrt(x) y=1/x if i put these in a graph they both pass the vertical line test but the first equation is not a function while the 2nd one is. Why?
Asked by David T - Tue Aug 22 18:50:15 2006 - - 4 Answers - 0 Comments
A. it's not one-to-one. Every x value must have only one corresponding y value. In the first equation, if x=4, y can be either 2 or -2. Maybe you graphed y=sqrt(x) or accidently y=x^2 instead of x=y^2. If you want to graph it on a TI, you'd have to graph both y=sqrt(x) and y=-sqrt(x), b/c whenever you take the square root of x=y^2 you get y=+/-sqrt(x)
Answered by godmike - Tue Aug 22 18:53:30 2006
Q. I've been trying for a couple hours and can't figure this thing out on my own. How do I take an equation and determine if an equation is a function: x=y^2 y=sqrt(x) y=1/x if i put these in a graph they both pass the vertical line test but the first equation is not a function while the 2nd one is. Why?
Asked by David T - Tue Aug 22 18:50:15 2006 - - 4 Answers - 0 Comments
A. it's not one-to-one. Every x value must have only one corresponding y value. In the first equation, if x=4, y can be either 2 or -2. Maybe you graphed y=sqrt(x) or accidently y=x^2 instead of x=y^2. If you want to graph it on a TI, you'd have to graph both y=sqrt(x) and y=-sqrt(x), b/c whenever you take the square root of x=y^2 you get y=+/-sqrt(x)
Answered by godmike - Tue Aug 22 18:53:30 2006
What is the differential equation for steady state molecular diffusion of fluid in a laminar flow?
Q. I need the equation in differential form for steady state molecular diffusion of a fluid in a laminar flow. I am looking for an equation that will work for Reynold's Number 35. Also is it possible to derive it from Ficks law of mass transfer?
Asked by Fluorine - Mon Nov 26 19:23:53 2007 - - 2 Answers - 0 Comments
A. Of course you can use Fick's law! Since it is dependent upon the molecular average velocity anyway, so your variable will be included, anyway; your equation is: JA= -DAB(dCA/dCB); where JA is the diffusion flux for component A, which is proportional to the concentration gradient dCA/dCB, DAB is the diffusivity of component A in its mixture with B. Now how we come up with that and in regard to velocities; the molal flux of a mixture is NM=rMuo, where rM is the average MOLAR denisty of the mixture and uo is the average velocity, then, by substituting rM with more measurable variable which is the molar concentration, we obtain -for a molecule of A crossing a stationary plane with a linear velocity the following: NA=cAuA; so JA=cAuA-cAuo… [cont.]
Answered by Dean B - Mon Nov 26 20:12:20 2007
Q. I need the equation in differential form for steady state molecular diffusion of a fluid in a laminar flow. I am looking for an equation that will work for Reynold's Number 35. Also is it possible to derive it from Ficks law of mass transfer?
Asked by Fluorine - Mon Nov 26 19:23:53 2007 - - 2 Answers - 0 Comments
A. Of course you can use Fick's law! Since it is dependent upon the molecular average velocity anyway, so your variable will be included, anyway; your equation is: JA= -DAB(dCA/dCB); where JA is the diffusion flux for component A, which is proportional to the concentration gradient dCA/dCB, DAB is the diffusivity of component A in its mixture with B. Now how we come up with that and in regard to velocities; the molal flux of a mixture is NM=rMuo, where rM is the average MOLAR denisty of the mixture and uo is the average velocity, then, by substituting rM with more measurable variable which is the molar concentration, we obtain -for a molecule of A crossing a stationary plane with a linear velocity the following: NA=cAuA; so JA=cAuA-cAuo… [cont.]
Answered by Dean B - Mon Nov 26 20:12:20 2007
What is the balanced equation for the reaction between vinegar and baking soda?
Q. I need to know the balanced equation for the reaction between vinegar and baking soda. Full equation please.
Asked by joeblake15 - Tue Jan 8 16:26:18 2008 - - 2 Answers - 0 Comments
A. Sodium bicarbonate and Acetic acid make Sodium acetate and Carbonic acid: NaHCO3 + CH3CO2H -> CH3CO2Na + H2CO3 The carbonic acid then decomposes into water and CO2: H2CO3 -> H2O + CO2 This is what makes all the froth.
Answered by Roger S - Tue Jan 8 16:33:26 2008
Q. I need to know the balanced equation for the reaction between vinegar and baking soda. Full equation please.
Asked by joeblake15 - Tue Jan 8 16:26:18 2008 - - 2 Answers - 0 Comments
A. Sodium bicarbonate and Acetic acid make Sodium acetate and Carbonic acid: NaHCO3 + CH3CO2H -> CH3CO2Na + H2CO3 The carbonic acid then decomposes into water and CO2: H2CO3 -> H2O + CO2 This is what makes all the froth.
Answered by Roger S - Tue Jan 8 16:33:26 2008
What is the balanced equation for the reaction between iron and oxygen?
Q. I need to know the balnced equation in the reaction between iron and oxygen. Full equation please.
Asked by joeblake15 - Tue Jan 8 16:10:26 2008 - - 5 Answers - 0 Comments
A. 3Fe(s) + 2O2(g) --> Fe3O4(s)
Answered by Dr Dave P - Tue Jan 8 16:13:53 2008
Q. I need to know the balnced equation in the reaction between iron and oxygen. Full equation please.
Asked by joeblake15 - Tue Jan 8 16:10:26 2008 - - 5 Answers - 0 Comments
A. 3Fe(s) + 2O2(g) --> Fe3O4(s)
Answered by Dr Dave P - Tue Jan 8 16:13:53 2008
How do i find the equation of a secant line between 2 points on a graph?
Q. I have to find the equation of the secant line between 2 certian times. I am not given the equation of the graph, only a table of points and their y values. How would i go about doing this?
Asked by burtonboards332 - Mon Dec 8 19:24:03 2008 - - 2 Answers - 0 Comments
A. Find the absolute maxes and then do mean value theorem.
Answered by abracadabra holmes! - Mon Dec 8 19:43:34 2008
Q. I have to find the equation of the secant line between 2 certian times. I am not given the equation of the graph, only a table of points and their y values. How would i go about doing this?
Asked by burtonboards332 - Mon Dec 8 19:24:03 2008 - - 2 Answers - 0 Comments
A. Find the absolute maxes and then do mean value theorem.
Answered by abracadabra holmes! - Mon Dec 8 19:43:34 2008
What equation can I use for this convection problem?
Q. Okay the problem was, in simple terms, an external flow problem with air flowing over a steel plate. I know all properties of the steel and the fluid such as thermal conductivity, viscosity, density, etc. Part a of the problem asked to find the rate of heat transfer which i did correctly. Now part b is to find the "corresponding" rate of temperature change of the plate temperature. What equation do I use to compute this? I just want the equation and am not going to spend all day typing in my numbers. Just please give me the equation to use.
Asked by The CLB - Tue Mar 3 12:41:00 2009 - - 1 Answers - 0 Comments
A. For the steel, Q = Cp * m * T So, if Cp (specific heat of steel) is in J/g C, and mass in g, and the Temperature is in C , then Q is in J.
Answered by wingstwo - Tue Mar 3 14:37:38 2009
Q. Okay the problem was, in simple terms, an external flow problem with air flowing over a steel plate. I know all properties of the steel and the fluid such as thermal conductivity, viscosity, density, etc. Part a of the problem asked to find the rate of heat transfer which i did correctly. Now part b is to find the "corresponding" rate of temperature change of the plate temperature. What equation do I use to compute this? I just want the equation and am not going to spend all day typing in my numbers. Just please give me the equation to use.
Asked by The CLB - Tue Mar 3 12:41:00 2009 - - 1 Answers - 0 Comments
A. For the steel, Q = Cp * m * T So, if Cp (specific heat of steel) is in J/g C, and mass in g, and the Temperature is in C , then Q is in J.
Answered by wingstwo - Tue Mar 3 14:37:38 2009
How do you draw an equation on a computer?
Q. I need to draw a graph of an equation and it is too tedious to use paint, and excel spreadsheet equations don't really look right. How do you draw a graph using a computer? Plus, how are you able to post pictures on Y!Answers without using photobucket?
Asked by Kenny McCormick - Tue Sep 23 17:37:47 2008 - - 2 Answers - 0 Comments
A. Your welcome.
Answered by dylan m - Tue Sep 23 17:41:38 2008
Q. I need to draw a graph of an equation and it is too tedious to use paint, and excel spreadsheet equations don't really look right. How do you draw a graph using a computer? Plus, how are you able to post pictures on Y!Answers without using photobucket?
Asked by Kenny McCormick - Tue Sep 23 17:37:47 2008 - - 2 Answers - 0 Comments
A. Your welcome.
Answered by dylan m - Tue Sep 23 17:41:38 2008
How do you change an equation from polar coordinate to cartesian?
Q. I am in Calc 2 and we are working on polar coodinate graphs and I can't seem to handle them. The question that I need help with is how to change the equation, r=4sec(theta)(1+ tan(theta)), into the cartesian equation. Thank you so much for your help!
Asked by kjwilson - Tue Apr 10 14:42:46 2007 - - 4 Answers - 2 Comments
A. x = r cos (theta) y = r sin (theta) x = 4 sec (theta)(1+tan(theta)) cos (theta) y = 4 sec(theta)(1+tan(theta)) sin(theta) I'm going to use T instead fo "theta" x = 4 sec(T)(1+tan(T)) cos (T) x = 4 (1+tan(T)) since sec = 1/cos, and cos/cos = 1 y = 4 sec(T)(1+tan(T)) sin(T) y = 4 (1+tan(T)) tan(T) since sin/cos = tan y = 4 (tan(T) + tan^2(T)) you might be able to simplify it a bit more since tan^2(T) + 1 = sec^2(T), but I think that just makes it messier. I hope this helps (but double check its accuracy!).
Answered by Stuey - Tue Apr 10 14:47:57 2007
Q. I am in Calc 2 and we are working on polar coodinate graphs and I can't seem to handle them. The question that I need help with is how to change the equation, r=4sec(theta)(1+ tan(theta)), into the cartesian equation. Thank you so much for your help!
Asked by kjwilson - Tue Apr 10 14:42:46 2007 - - 4 Answers - 2 Comments
A. x = r cos (theta) y = r sin (theta) x = 4 sec (theta)(1+tan(theta)) cos (theta) y = 4 sec(theta)(1+tan(theta)) sin(theta) I'm going to use T instead fo "theta" x = 4 sec(T)(1+tan(T)) cos (T) x = 4 (1+tan(T)) since sec = 1/cos, and cos/cos = 1 y = 4 sec(T)(1+tan(T)) sin(T) y = 4 (1+tan(T)) tan(T) since sin/cos = tan y = 4 (tan(T) + tan^2(T)) you might be able to simplify it a bit more since tan^2(T) + 1 = sec^2(T), but I think that just makes it messier. I hope this helps (but double check its accuracy!).
Answered by Stuey - Tue Apr 10 14:47:57 2007
What is a really complicated equation i can ask somebody?
Q. My friend thinks hes really good at maths and can solve any equations. What is a really hard and complicated equation i can ask him?
Asked by usa_fox1234 - Wed Dec 20 14:05:14 2006 - - 8 Answers - 0 Comments
A. well i asked this question a while ago--- a+b+c=4 a^2+b^2+c^2=10 a^3+b^3+c^3=22 find the values of a, b ,and c It is REALLY hard clue: cubic polynominals...??!!
Answered by rahbonzy - Wed Dec 20 14:25:32 2006
Q. My friend thinks hes really good at maths and can solve any equations. What is a really hard and complicated equation i can ask him?
Asked by usa_fox1234 - Wed Dec 20 14:05:14 2006 - - 8 Answers - 0 Comments
A. well i asked this question a while ago--- a+b+c=4 a^2+b^2+c^2=10 a^3+b^3+c^3=22 find the values of a, b ,and c It is REALLY hard clue: cubic polynominals...??!!
Answered by rahbonzy - Wed Dec 20 14:25:32 2006
How do I write the equation for the plane perpendicular to the xy plane going through y=x?
Q. Basically, I need the equation in the form ax + by + cz + d = 0. Again, it is the plane perpendicular to the xy plane, and cutting through the xy plane on the line y=x. This is part of a bigger problem to do with stereographic projection, and I am just kind of having a mental block on how I write the equation for planes! Pretty pathetic considering I'm a math major lol Is it just the plane y=x?
Asked by daniel o - Sat Feb 27 16:33:45 2010 - - 1 Answers - 0 Comments
A. If that plane is perpendicular to the xy plane, it is parallel to oz and its equation does not contain z. So you already have it, think a little
Answered by jean-de-la-lune - Sat Feb 27 16:37:22 2010
Q. Basically, I need the equation in the form ax + by + cz + d = 0. Again, it is the plane perpendicular to the xy plane, and cutting through the xy plane on the line y=x. This is part of a bigger problem to do with stereographic projection, and I am just kind of having a mental block on how I write the equation for planes! Pretty pathetic considering I'm a math major lol Is it just the plane y=x?
Asked by daniel o - Sat Feb 27 16:33:45 2010 - - 1 Answers - 0 Comments
A. If that plane is perpendicular to the xy plane, it is parallel to oz and its equation does not contain z. So you already have it, think a little
Answered by jean-de-la-lune - Sat Feb 27 16:37:22 2010
How do you write the molecular equation for dissolving hydrated compounds?
Q. If I dissolve a solid BaCl2.2H2O in water to form a solution of barium chloride, how can I represent this reaction as an equation? I am particularly confused about what to do with the "H2O" in the equation.
Asked by WC - Thu Nov 27 10:35:50 2008 - - 1 Answers - 0 Comments
A. Barium Chloride dihydrate dissolves in water to form Ba+ and 2Cl-. The water is water and dissolves as water and joins the rest of the water, so it just goes away.
Answered by stnicholas6496 - Thu Nov 27 10:50:22 2008
Q. If I dissolve a solid BaCl2.2H2O in water to form a solution of barium chloride, how can I represent this reaction as an equation? I am particularly confused about what to do with the "H2O" in the equation.
Asked by WC - Thu Nov 27 10:35:50 2008 - - 1 Answers - 0 Comments
A. Barium Chloride dihydrate dissolves in water to form Ba+ and 2Cl-. The water is water and dissolves as water and joins the rest of the water, so it just goes away.
Answered by stnicholas6496 - Thu Nov 27 10:50:22 2008
What is the difference between an equation and an expression?
Q. What is the difference between an equation and an expression? Include an example of each. Can you solve for a variable in an expression? Explain. Can you solve for a variable in an equation? Explain. Write a mathematical phrase or sentence.
Asked by Valerie C - Tue Jan 15 15:28:10 2008 - - 6 Answers - 0 Comments
A. An expression is a description of a mathematical object (some class or set). So, 4 is an expression describing the class of all sets of four objects, for example. An equation is an assertion (whether right or wrong) that one expression refers to the same class as another. Therefore, 2+2=4 is a claim that, if we work out what class the expression 2+2 is, it will be the same as the class 4. This equation is true, of course. If an equation includes variables, you can have an equation that is sometimes right or sometimes wrong. For example, the equation x+2=5 is true if x happens to refer to the class 3, and is false otherwise. On the other hand, the equation x+2 = x+2 is true always. Such equations are called identities. The whole… [cont.]
Answered by acafrao341 - Tue Jan 15 15:36:46 2008
Q. What is the difference between an equation and an expression? Include an example of each. Can you solve for a variable in an expression? Explain. Can you solve for a variable in an equation? Explain. Write a mathematical phrase or sentence.
Asked by Valerie C - Tue Jan 15 15:28:10 2008 - - 6 Answers - 0 Comments
A. An expression is a description of a mathematical object (some class or set). So, 4 is an expression describing the class of all sets of four objects, for example. An equation is an assertion (whether right or wrong) that one expression refers to the same class as another. Therefore, 2+2=4 is a claim that, if we work out what class the expression 2+2 is, it will be the same as the class 4. This equation is true, of course. If an equation includes variables, you can have an equation that is sometimes right or sometimes wrong. For example, the equation x+2=5 is true if x happens to refer to the class 3, and is false otherwise. On the other hand, the equation x+2 = x+2 is true always. Such equations are called identities. The whole… [cont.]
Answered by acafrao341 - Tue Jan 15 15:36:46 2008
What is the equation for a Sodium hydrogen carbonate reaction?
Q. And how can we tell from this equation that it removes acid?
Asked by Siren Productions - Tue Feb 5 16:52:01 2008 - - 1 Answers - 0 Comments
A. NaHCO3 + HCl --> NaCl + H2O + CO2 where did the acid go?
Answered by skipper - Tue Feb 5 16:56:07 2008
Q. And how can we tell from this equation that it removes acid?
Asked by Siren Productions - Tue Feb 5 16:52:01 2008 - - 1 Answers - 0 Comments
A. NaHCO3 + HCl --> NaCl + H2O + CO2 where did the acid go?
Answered by skipper - Tue Feb 5 16:56:07 2008
Is there an equation to calculate the amount of heat produced by a wire?
Q. I am not sure what the size of the wire would be, but I know the battery is 6 volts. But wait, not an equation for specific conditions, but just one in general where you plug in the wire diameter, the amount of energy running through it, the amount of resistance, and whatever else. Oh, this is under the assumption that the wire is pure, or close to pure, copper. Maybe there isn't even one.
Asked by jeremy_the_cow - Sun Sep 27 23:42:09 2009 - - 1 Answers - 0 Comments
A. Ugggh thermodynamics :S
Answered by Buddy12345 - Sun Sep 27 23:45:45 2009
Q. I am not sure what the size of the wire would be, but I know the battery is 6 volts. But wait, not an equation for specific conditions, but just one in general where you plug in the wire diameter, the amount of energy running through it, the amount of resistance, and whatever else. Oh, this is under the assumption that the wire is pure, or close to pure, copper. Maybe there isn't even one.
Asked by jeremy_the_cow - Sun Sep 27 23:42:09 2009 - - 1 Answers - 0 Comments
A. Ugggh thermodynamics :S
Answered by Buddy12345 - Sun Sep 27 23:45:45 2009
What is the equation for get the volume of a liquid in liters?
Q. Is there an equation for it or do you have to go through a series of them? Please help! I keep seeing ones for oval or cone shaped what about a rectangular shape? If there's a general one that'd be nice too. Help please!
Asked by .* teee - Fri Sep 26 08:23:30 2008 - - 2 Answers - 0 Comments
A. If.. you fill a rectangular tank (um say it's 50cm long, 20cm wide and 60cm tall) up to the brim with liquid, then the volume of the liquid in centimeters cube will be 50 x 20 x 60 = 6000cm3. 6000cm3 is equivalent to 6000millilitres, so I guess you can convert that 6000millilitres to litres from here. (1 litre=1000millilitres) Is this what you're looking for? Really sorry if I'm not answering your question!
Answered by Jaylynn - Fri Sep 26 08:37:36 2008
Q. Is there an equation for it or do you have to go through a series of them? Please help! I keep seeing ones for oval or cone shaped what about a rectangular shape? If there's a general one that'd be nice too. Help please!
Asked by .* teee - Fri Sep 26 08:23:30 2008 - - 2 Answers - 0 Comments
A. If.. you fill a rectangular tank (um say it's 50cm long, 20cm wide and 60cm tall) up to the brim with liquid, then the volume of the liquid in centimeters cube will be 50 x 20 x 60 = 6000cm3. 6000cm3 is equivalent to 6000millilitres, so I guess you can convert that 6000millilitres to litres from here. (1 litre=1000millilitres) Is this what you're looking for? Really sorry if I'm not answering your question!
Answered by Jaylynn - Fri Sep 26 08:37:36 2008
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