Where can I find challenging Geometry problems?
Q. Dear readers, I need to find some very challenging geometry problems based on the point-line distance formula, stewart's theorem, ptolemy's theorem, mass points, or the inradius/circumradius formulas. The problems can also include whatever other theorems students in high school taking honors geometry should have learned. Can anyone please give me a website that gives problems like this and with detailed explanations (worked out solutions)? Thanks.
Asked by ERL - Wed May 23 19:38:25 2007 - - 3 Answers - 0 Comments
A. try typing in challenging geometry problems on google
Answered by jimbothe_smartguy - Wed May 23 19:43:12 2007
Q. Dear readers, I need to find some very challenging geometry problems based on the point-line distance formula, stewart's theorem, ptolemy's theorem, mass points, or the inradius/circumradius formulas. The problems can also include whatever other theorems students in high school taking honors geometry should have learned. Can anyone please give me a website that gives problems like this and with detailed explanations (worked out solutions)? Thanks.
Asked by ERL - Wed May 23 19:38:25 2007 - - 3 Answers - 0 Comments
A. try typing in challenging geometry problems on google
Answered by jimbothe_smartguy - Wed May 23 19:43:12 2007
Are there any websites where I could practice geometry problems?
Q. OK, summer is basically over. I'm going back to school in a few weeks, & I'll be taking honors geometry. I'm nervous, mostly because everybody I know says it's really hard, but I think I'll do well because I've gotten A's in nearly every math course I've ever taken. However, I still want to prepare myself mentally; get a head start so it's not as hard when the class actually starts. Are there any websites that have geometry lessons & problems?
Asked by Lemongoat Jones - Sat Aug 23 19:58:43 2008 - - 2 Answers - 0 Comments
A. Geometry is not that bad if you practice. Here is a good Yahoo site with geometry problems:
Answered by Wonder - Sat Aug 23 20:09:11 2008
Q. OK, summer is basically over. I'm going back to school in a few weeks, & I'll be taking honors geometry. I'm nervous, mostly because everybody I know says it's really hard, but I think I'll do well because I've gotten A's in nearly every math course I've ever taken. However, I still want to prepare myself mentally; get a head start so it's not as hard when the class actually starts. Are there any websites that have geometry lessons & problems?
Asked by Lemongoat Jones - Sat Aug 23 19:58:43 2008 - - 2 Answers - 0 Comments
A. Geometry is not that bad if you practice. Here is a good Yahoo site with geometry problems:
Answered by Wonder - Sat Aug 23 20:09:11 2008
If the service menu is of no help, how does a technician fix geometry problems on a television?
Q. I have a crt hdtv with noticeable geometry distortions. I have tried everything in the service menu to fix them, but nothing has worked. Assuming the problems are fixable and the service menu is of no help, what would a technician do to correct them? And is it practical to consider having this work done? Thanks. The tv is a Samsung TX-p2675wh. The geomwtry problems are basically vertical lines are not straight from the bottom to the top of the screen. When they get to the top, they sort of bend off to the right. It's noticeable when a person is in front of a doorway, and the frame looks all crooked.
Asked by Danny27 - Fri Apr 20 19:06:12 2007 - - 2 Answers - 0 Comments
A. They can always replace the video board and see if that helps.
Answered by TV guy - Fri Apr 20 19:31:42 2007
Q. I have a crt hdtv with noticeable geometry distortions. I have tried everything in the service menu to fix them, but nothing has worked. Assuming the problems are fixable and the service menu is of no help, what would a technician do to correct them? And is it practical to consider having this work done? Thanks. The tv is a Samsung TX-p2675wh. The geomwtry problems are basically vertical lines are not straight from the bottom to the top of the screen. When they get to the top, they sort of bend off to the right. It's noticeable when a person is in front of a doorway, and the frame looks all crooked.
Asked by Danny27 - Fri Apr 20 19:06:12 2007 - - 2 Answers - 0 Comments
A. They can always replace the video board and see if that helps.
Answered by TV guy - Fri Apr 20 19:31:42 2007
Can any of you teach me how to do these geometry problems?
Q. Ok here is what i need to learn for geometry was there for a week and missed the lessons. Finding the length of a line on a coordinate plane Finding the distance between two points Finding coordinates of the mid point. Any help would be awesome.
Asked by The angry Matt - Thu Sep 24 13:48:43 2009 - - 2 Answers - 0 Comments
A. So let's say you have a line (segment) in the coordinate plane. It goes from (a,b) to (c,d). Let's say, as an example, (0,3) to (3,7). The midpoint of the line is easy: you just average the X coordinates and the Y coordinates. So, the midpoint is ((a+c)/2, (b+d)/2), in this case, (1.5,5). For the length of the line, the easiest thing is to use the Pythagorean theorem. You can make a triangle with the line as the hypotenuse, where one leg is horizontal and the other is vertical. The lengths of the two legs are the differences between the coordinates: |a-c| and |b-d|, in this case, 3 and 4. So the length is SQRT(|a-c|^2 + |b-d|^2), in this case, SQRT(3^2 + 4^2) = SQRT(25) = 5. The distance between two points is the same as the… [cont.]
Answered by unknown - Thu Sep 24 13:59:14 2009
Q. Ok here is what i need to learn for geometry was there for a week and missed the lessons. Finding the length of a line on a coordinate plane Finding the distance between two points Finding coordinates of the mid point. Any help would be awesome.
Asked by The angry Matt - Thu Sep 24 13:48:43 2009 - - 2 Answers - 0 Comments
A. So let's say you have a line (segment) in the coordinate plane. It goes from (a,b) to (c,d). Let's say, as an example, (0,3) to (3,7). The midpoint of the line is easy: you just average the X coordinates and the Y coordinates. So, the midpoint is ((a+c)/2, (b+d)/2), in this case, (1.5,5). For the length of the line, the easiest thing is to use the Pythagorean theorem. You can make a triangle with the line as the hypotenuse, where one leg is horizontal and the other is vertical. The lengths of the two legs are the differences between the coordinates: |a-c| and |b-d|, in this case, 3 and 4. So the length is SQRT(|a-c|^2 + |b-d|^2), in this case, SQRT(3^2 + 4^2) = SQRT(25) = 5. The distance between two points is the same as the… [cont.]
Answered by unknown - Thu Sep 24 13:59:14 2009
Who can help me out with geometry problems?
Q. 1. In triangle ABC, BD and AE are medians. If ED is drawn, what is the ratio of ED:AB? #2.The ratio of the areas of two similar triangles is 4:25.What is the ratio of the length of a side of the smaller triangle to the length of the corresponding side of the larger triangle? #3.What is the positive root of the equation x^2+7x-8=0 Thanks a lot in advance i really need help in those problems!
Asked by sweety_marishka - Wed Jan 28 20:59:14 2009 - - 1 Answers - 0 Comments
Q. 1. In triangle ABC, BD and AE are medians. If ED is drawn, what is the ratio of ED:AB? #2.The ratio of the areas of two similar triangles is 4:25.What is the ratio of the length of a side of the smaller triangle to the length of the corresponding side of the larger triangle? #3.What is the positive root of the equation x^2+7x-8=0 Thanks a lot in advance i really need help in those problems!
Asked by sweety_marishka - Wed Jan 28 20:59:14 2009 - - 1 Answers - 0 Comments
Can you please give me 8th,9th and 10th grade geometry problems?
Q. I need to create a test containing 8th-10th grade geometry problems for school
Asked by keke - Sat May 23 14:10:57 2009 - - 2 Answers - 0 Comments
A. im in 8th grade y=3x+5 for instance and we had to find the slope and y intercept which is b ans slope is m the anwser would be b=5 m=3
Answered by kelli n - Sat May 23 14:19:09 2009
Q. I need to create a test containing 8th-10th grade geometry problems for school
Asked by keke - Sat May 23 14:10:57 2009 - - 2 Answers - 0 Comments
A. im in 8th grade y=3x+5 for instance and we had to find the slope and y intercept which is b ans slope is m the anwser would be b=5 m=3
Answered by kelli n - Sat May 23 14:19:09 2009
Could anyone please help me with these 2 simple geometry problems?
Q. I understand these might be simple but I'm having difficulties understanding them as I don't have a book handy yet and just started with the course. For problem A I need to find the value of angle A. For problem B I need to find the x,y and polar coordinates for both points A and B. Please help me out here. If you don't wish to tell me the answer then at least name the theorem or postulate that I need to solve this. Thank you.
Asked by Elvis - Fri Aug 14 22:55:33 2009 - - 1 Answers - 0 Comments
A. Where are Problem A and B?
Answered by Msean - Sat Aug 15 13:49:41 2009
Q. I understand these might be simple but I'm having difficulties understanding them as I don't have a book handy yet and just started with the course. For problem A I need to find the value of angle A. For problem B I need to find the x,y and polar coordinates for both points A and B. Please help me out here. If you don't wish to tell me the answer then at least name the theorem or postulate that I need to solve this. Thank you.
Asked by Elvis - Fri Aug 14 22:55:33 2009 - - 1 Answers - 0 Comments
A. Where are Problem A and B?
Answered by Msean - Sat Aug 15 13:49:41 2009
Can somebody help me with these 2 geometry problems?
Q. 1. A local pizzeria sells a 10-in cheese pizza for $5.99 while a 12-in cheese pizza sells for $7.99 and a 14-in cheese pizza sells for $8.99. Find the best buy and show your work to support your answer. 2. A baseball has a diameter of about 3 inches. Find the volume of the baseball. Use 3.14 for pie. Round the nearest whole number. Label correctly. Thank you!
Asked by JR. - Sun Mar 29 21:08:40 2009 - - 10 Answers - 0 Comments
A. 1. I guess you'd use area for comparison, since you need to eat the whole thing. I am assuming that the 10, 12, and 14 refer to the diameter of the pizza. So the radii are 5, 6, and 7. The formula for area is (pi)r^2 10 inch pizza has area of 25pi 12 inch pizza has area of 36pi 14 inch pizza has area of 49pi divide the cost by the area to get cost per square inch So the 10 inch pizza costs 7.6 cents per square inch the 12 inch one costs 7.1 cents per square inch the 14 inch one costs 5.8 cents per square inch The 14 inch one is the best buy. 2. Formula for volume of a sphere is 4/3(pi)r^3 so you have (4/3)(3.14)(1.5)^3 = 14 cubic inches
Answered by fsateacher - Sun Mar 29 21:17:10 2009
Q. 1. A local pizzeria sells a 10-in cheese pizza for $5.99 while a 12-in cheese pizza sells for $7.99 and a 14-in cheese pizza sells for $8.99. Find the best buy and show your work to support your answer. 2. A baseball has a diameter of about 3 inches. Find the volume of the baseball. Use 3.14 for pie. Round the nearest whole number. Label correctly. Thank you!
Asked by JR. - Sun Mar 29 21:08:40 2009 - - 10 Answers - 0 Comments
A. 1. I guess you'd use area for comparison, since you need to eat the whole thing. I am assuming that the 10, 12, and 14 refer to the diameter of the pizza. So the radii are 5, 6, and 7. The formula for area is (pi)r^2 10 inch pizza has area of 25pi 12 inch pizza has area of 36pi 14 inch pizza has area of 49pi divide the cost by the area to get cost per square inch So the 10 inch pizza costs 7.6 cents per square inch the 12 inch one costs 7.1 cents per square inch the 14 inch one costs 5.8 cents per square inch The 14 inch one is the best buy. 2. Formula for volume of a sphere is 4/3(pi)r^3 so you have (4/3)(3.14)(1.5)^3 = 14 cubic inches
Answered by fsateacher - Sun Mar 29 21:17:10 2009
Can someone explain these geometry problems?
Q. I've tried to work through them but i don't understand it at all so i would really appreciate it if someone could walk me through it? 1. Find the coordinate of the image of the point (8,12) dilated with center at the origin, scale factor 3/4. 2. FInd the coordinate of the image of the point (5,1) dilated with center at the origin, scale factor 3.
Asked by Court2114 - Fri Aug 29 15:21:55 2008 - - 1 Answers - 0 Comments
A. 1) Just take 3/4 of each coordinate of (8, 12) to get (6, 9) 2) Multiply each coordinate by 3 to get (15, 3)
Answered by Chris - Fri Aug 29 15:27:14 2008
Q. I've tried to work through them but i don't understand it at all so i would really appreciate it if someone could walk me through it? 1. Find the coordinate of the image of the point (8,12) dilated with center at the origin, scale factor 3/4. 2. FInd the coordinate of the image of the point (5,1) dilated with center at the origin, scale factor 3.
Asked by Court2114 - Fri Aug 29 15:21:55 2008 - - 1 Answers - 0 Comments
A. 1) Just take 3/4 of each coordinate of (8, 12) to get (6, 9) 2) Multiply each coordinate by 3 to get (15, 3)
Answered by Chris - Fri Aug 29 15:27:14 2008
i need answers that are correct to these Geometry problems?
Q. 1. What's the perimeter of a regular hexagon whose sides are 12.7 yards long? 2. If RX= 2y+2x , TX=3y-1 , and SV=28 what's the values of x+y?
Asked by bettyboopboop - Mon May 11 12:15:12 2009 - - 1 Answers - 0 Comments
Q. 1. What's the perimeter of a regular hexagon whose sides are 12.7 yards long? 2. If RX= 2y+2x , TX=3y-1 , and SV=28 what's the values of x+y?
Asked by bettyboopboop - Mon May 11 12:15:12 2009 - - 1 Answers - 0 Comments
Will you help me with these Geometry billiards problems?
Q. I'm in Honors Geography 8th grade and I'm very confused by these two questions. It shows you a picture of the pool table all set up, and the guy about to shoot the ball. It asks you if the 4 ball or whatever will make it into the corner pocket, but I have no idea how I'm supposed to solve this. It says to use a protractor. Please help me! Also is it pathetic that I'm already having trouble with Geometry on the 3rd day?
Asked by Griffin Henderson - Thu Aug 28 19:08:05 2008 - - 2 Answers - 0 Comments
A. You need to calculate the angle of the ball that will go into the corner pocket. Hence, use the protractor
Answered by BJ - Thu Aug 28 19:12:23 2008
Q. I'm in Honors Geography 8th grade and I'm very confused by these two questions. It shows you a picture of the pool table all set up, and the guy about to shoot the ball. It asks you if the 4 ball or whatever will make it into the corner pocket, but I have no idea how I'm supposed to solve this. It says to use a protractor. Please help me! Also is it pathetic that I'm already having trouble with Geometry on the 3rd day?
Asked by Griffin Henderson - Thu Aug 28 19:08:05 2008 - - 2 Answers - 0 Comments
A. You need to calculate the angle of the ball that will go into the corner pocket. Hence, use the protractor
Answered by BJ - Thu Aug 28 19:12:23 2008
What problems do you have understanding geometry?
Q. I am doing a project on the problems students have understanding geometry. So please share.
Asked by Jyoti M - Wed Sep 5 12:13:30 2007 - - 1 Answers - 0 Comments
A. Problems knowing the value of angles especially the ones in a polygon... Problems applying the angle concepts...(alternate angels, corresponding angles etc.)
Answered by beaniebeans - Wed Sep 5 12:47:42 2007
Q. I am doing a project on the problems students have understanding geometry. So please share.
Asked by Jyoti M - Wed Sep 5 12:13:30 2007 - - 1 Answers - 0 Comments
A. Problems knowing the value of angles especially the ones in a polygon... Problems applying the angle concepts...(alternate angels, corresponding angles etc.)
Answered by beaniebeans - Wed Sep 5 12:47:42 2007
How would i do this geometry problems?
Q. Find the distance from G(-3, -1) to the line whose equation is y = 4. Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectivel
Asked by *wearing my heart on my sleeve* - Thu Jun 4 11:44:18 2009 - - 1 Answers - 0 Comments
A. for second, choose point on one of the lines and do the same. Not sure your math level so dont want to use vectors unless you know them.
Answered by mackler - Thu Jun 4 11:51:19 2009
Q. Find the distance from G(-3, -1) to the line whose equation is y = 4. Find the distance between the parallel lines m and n whose equations are y = x + 4 and y = x - 6, respectivel
Asked by *wearing my heart on my sleeve* - Thu Jun 4 11:44:18 2009 - - 1 Answers - 0 Comments
A. for second, choose point on one of the lines and do the same. Not sure your math level so dont want to use vectors unless you know them.
Answered by mackler - Thu Jun 4 11:51:19 2009
Need help with some coordinate geometry problems?
Q. I am a little stuck on how to work out the following problems so if anyone could help me with all or any of these problems that would be great. The questions are: 1. The gradient of the line perpendicular to 3x - 4y + 7 = 0 is: A. 3/4 B. 4/3 C. -4/3 D. 3 E. -4 2. Find the equation of the straight line passing through the point (6, -2) and parallel to the line x+2y-1=0
Asked by Will P - Sun Aug 2 08:17:44 2009 - - 4 Answers - 0 Comments
A. Problem 1: Convert the given equation to y = mx + b, where m is the slope. 3x - 4y + 7 = 0 - 4y = - 3x - 7 (Divide all terms by -4) y = (3/4)x + 7/4 Slope is 3/4. In order for a slope to be perpendicular to 3/4, it must be the negative reciprocal of the said slope, so they result to -1 when multiplied together. Thus, it's -4/3. C is the answer. ~~~ Let's determine first the slope of the given equation. Convert it to y = mx + b. x + 2y - 1 = 0 2y = - x + 1 (Divide all terms by 2) y = (-1/2)x + 1/2 Slope is -1/2. Now, in order for our equation to be parallel with that, our slope must also be -1/2. In forming the equation of a line, use this formula: y - y1 = m (x - x1) Substitute our gathered data in the formula. P (6, -2) m = -1/ [cont.]
Answered by Dr. Lucafont - Sun Aug 2 08:26:19 2009
Q. I am a little stuck on how to work out the following problems so if anyone could help me with all or any of these problems that would be great. The questions are: 1. The gradient of the line perpendicular to 3x - 4y + 7 = 0 is: A. 3/4 B. 4/3 C. -4/3 D. 3 E. -4 2. Find the equation of the straight line passing through the point (6, -2) and parallel to the line x+2y-1=0
Asked by Will P - Sun Aug 2 08:17:44 2009 - - 4 Answers - 0 Comments
A. Problem 1: Convert the given equation to y = mx + b, where m is the slope. 3x - 4y + 7 = 0 - 4y = - 3x - 7 (Divide all terms by -4) y = (3/4)x + 7/4 Slope is 3/4. In order for a slope to be perpendicular to 3/4, it must be the negative reciprocal of the said slope, so they result to -1 when multiplied together. Thus, it's -4/3. C is the answer. ~~~ Let's determine first the slope of the given equation. Convert it to y = mx + b. x + 2y - 1 = 0 2y = - x + 1 (Divide all terms by 2) y = (-1/2)x + 1/2 Slope is -1/2. Now, in order for our equation to be parallel with that, our slope must also be -1/2. In forming the equation of a line, use this formula: y - y1 = m (x - x1) Substitute our gathered data in the formula. P (6, -2) m = -1/ [cont.]
Answered by Dr. Lucafont - Sun Aug 2 08:26:19 2009
Can you help me with two of my geometry homework problems?
Q. the first I don't know if i can explain it but ill try its two intersecting lines that you have to find the angles it makes its says 2y+28 and 4x+10 on the top then on the bottom it says 4y+26 and 3x-5 the second one says angle c and angle d are supplementary.The measure of angle d is eight times the measure of angle c.Find angel c and angle d.
Asked by alecstraza475 - Tue Aug 26 17:20:52 2008 - - 2 Answers - 0 Comments
A. For the first question, I imagine the question gives you two intersecting lines with the value of each angle as one of the four values. Vertical Angles are congruent, so you can set them equal and solve for the variables. Make sure after you find the value of the variable you plug it back in to find the measurement of the angle. For the second question the equation can be set up as 8x+ x = 180. x is the value of c, so just solve for x. Again make sure you plug the value of x in to find the value of angles c and d.
Answered by Ssobo - Tue Aug 26 17:38:29 2008
Q. the first I don't know if i can explain it but ill try its two intersecting lines that you have to find the angles it makes its says 2y+28 and 4x+10 on the top then on the bottom it says 4y+26 and 3x-5 the second one says angle c and angle d are supplementary.The measure of angle d is eight times the measure of angle c.Find angel c and angle d.
Asked by alecstraza475 - Tue Aug 26 17:20:52 2008 - - 2 Answers - 0 Comments
A. For the first question, I imagine the question gives you two intersecting lines with the value of each angle as one of the four values. Vertical Angles are congruent, so you can set them equal and solve for the variables. Make sure after you find the value of the variable you plug it back in to find the measurement of the angle. For the second question the equation can be set up as 8x+ x = 180. x is the value of c, so just solve for x. Again make sure you plug the value of x in to find the value of angles c and d.
Answered by Ssobo - Tue Aug 26 17:38:29 2008
Help me with my analytic geometry problems. Can you please show the solution. the answer should be in fraction?
Q. 1. Find the point that extends the line from (-2,-7) to (2,-3) in the ratio -7/3. Please show the solution, and the answer should be in fraction not in mixed number. thank you very much.
Asked by john edgar - Fri Apr 24 06:07:32 2009 - - 2 Answers - 0 Comments
A. m=-3+7/2+2=4/4=1 y=x+b,use your definition of RATIO to find b.
Answered by nozar nazari - Fri Apr 24 06:14:23 2009
Q. 1. Find the point that extends the line from (-2,-7) to (2,-3) in the ratio -7/3. Please show the solution, and the answer should be in fraction not in mixed number. thank you very much.
Asked by john edgar - Fri Apr 24 06:07:32 2009 - - 2 Answers - 0 Comments
A. m=-3+7/2+2=4/4=1 y=x+b,use your definition of RATIO to find b.
Answered by nozar nazari - Fri Apr 24 06:14:23 2009
How do i solve Logic Problems in Geometry?
Q. I have a test tomorrow and i have no clue how to solve these things, and my teacher is unavailable to help. Anyone have any site i could go to, to possibly learn this?
Asked by Don - Thu Oct 1 13:04:27 2009 - - 1 Answers - 0 Comments
A. Hi Could you give me some examples of the types of problem you'll need to solve? If you email me some practice questions, I'll make sure I help. Good luck :-)
Answered by Melanie - Mon Oct 5 04:27:29 2009
Q. I have a test tomorrow and i have no clue how to solve these things, and my teacher is unavailable to help. Anyone have any site i could go to, to possibly learn this?
Asked by Don - Thu Oct 1 13:04:27 2009 - - 1 Answers - 0 Comments
A. Hi Could you give me some examples of the types of problem you'll need to solve? If you email me some practice questions, I'll make sure I help. Good luck :-)
Answered by Melanie - Mon Oct 5 04:27:29 2009
How can I Solve these Trig / Geometry Problems?
Q. I have no idea about this subject, but I really need to know how to solve it and not just the answers. Problem 1: cos (x)+sin (s)=1 Problem 2: ax +bx+c=0 ; a,b,c are constants 1. 3x +2x-5=0 2. x -5x+4=0 3. 2x +7x-3=0
Asked by 43 - Wed Jun 11 18:40:06 2008 - - 3 Answers - 0 Comments
A. In problem 1, x=s I'm not entirely sure what the question is there. In 1. 2. & 3., you need to factor the equations. 1. (3x+5)(x-1)=0, so 3x+5=0 or x-1=0, and x=-(5/3) or 1 2. (x-4)(x-1)=0, so x-4=0 or x-1=0, and x=4 or 1 3. Is this supposed to be +3?
Answered by Jen D - Wed Jun 11 18:56:31 2008
Q. I have no idea about this subject, but I really need to know how to solve it and not just the answers. Problem 1: cos (x)+sin (s)=1 Problem 2: ax +bx+c=0 ; a,b,c are constants 1. 3x +2x-5=0 2. x -5x+4=0 3. 2x +7x-3=0
Asked by 43 - Wed Jun 11 18:40:06 2008 - - 3 Answers - 0 Comments
A. In problem 1, x=s I'm not entirely sure what the question is there. In 1. 2. & 3., you need to factor the equations. 1. (3x+5)(x-1)=0, so 3x+5=0 or x-1=0, and x=-(5/3) or 1 2. (x-4)(x-1)=0, so x-4=0 or x-1=0, and x=4 or 1 3. Is this supposed to be +3?
Answered by Jen D - Wed Jun 11 18:56:31 2008
I need the correct answers for these Geometry problems?
Q. 1. What's the area of a triangle with a base of 21 inches and an altitude of 13 inches? 2. What's the area of a trapezoid with an altitude of 6ft and bases 2.7 ft. and 1.7 ft. long? 3. What's the system of equations by graphing y= 4x , y= 4x+3 ?
Asked by bettyboopboop - Mon May 11 12:10:27 2009 - - 3 Answers - 0 Comments
Q. 1. What's the area of a triangle with a base of 21 inches and an altitude of 13 inches? 2. What's the area of a trapezoid with an altitude of 6ft and bases 2.7 ft. and 1.7 ft. long? 3. What's the system of equations by graphing y= 4x , y= 4x+3 ?
Asked by bettyboopboop - Mon May 11 12:10:27 2009 - - 3 Answers - 0 Comments
Can anybody help me with two problems on my Geometry homework?
Q. Please explain the problems step by step because I want to learn. Thank you :) 1) The sides of a right triangle are x, x+3, and x+6 units long. Find the side lengths of the triangle by solving for x. 2) Find the radius of the largest circle that can be cut from a square piece of paper with a diagonal length of 20 centimeters. (Round to the nearest decimal place.)
Asked by Bubble Cheeks - Tue May 19 19:20:02 2009 - - 2 Answers - 0 Comments
A. 1) a: if it is a right triangle so you can use the Pythagorean theorem. x^2 + (x+3)^2 = (x+6)^2 x^2 + x^2 + 6x + 9 = x^2 + 12x + 36 2 x^2 + 6x = x^2 +12x +27 x^2 = 6x + 27 x^2 -6x -27 = 0 (x^2 -9x) + (3x -27) = 0 x ( x-9) +3 (x-9) = 0 x + 3 = 3 (x = -3) x - 9 = 0 (x = 9) x= -3 and x = 9 (a length can not be negative so... x = 9) x = 9. sides are 9, 12, and 15 2) since it is a square, all sides are congruent. a^2 + b^2 = c^2 x^2 + x^2 = 20^2 2x^2=400 x^2 = 200 x = 14. 14213562... That means the largest circle would have a diameter of 14.1413562... That means the largest circle would have a radius of 7.071067812 rounded would be 7.07 Hope It Helps. Email me at: african.chef@yahoo.com [cont.]
Answered by african.chef - Tue May 19 23:02:19 2009
Q. Please explain the problems step by step because I want to learn. Thank you :) 1) The sides of a right triangle are x, x+3, and x+6 units long. Find the side lengths of the triangle by solving for x. 2) Find the radius of the largest circle that can be cut from a square piece of paper with a diagonal length of 20 centimeters. (Round to the nearest decimal place.)
Asked by Bubble Cheeks - Tue May 19 19:20:02 2009 - - 2 Answers - 0 Comments
A. 1) a: if it is a right triangle so you can use the Pythagorean theorem. x^2 + (x+3)^2 = (x+6)^2 x^2 + x^2 + 6x + 9 = x^2 + 12x + 36 2 x^2 + 6x = x^2 +12x +27 x^2 = 6x + 27 x^2 -6x -27 = 0 (x^2 -9x) + (3x -27) = 0 x ( x-9) +3 (x-9) = 0 x + 3 = 3 (x = -3) x - 9 = 0 (x = 9) x= -3 and x = 9 (a length can not be negative so... x = 9) x = 9. sides are 9, 12, and 15 2) since it is a square, all sides are congruent. a^2 + b^2 = c^2 x^2 + x^2 = 20^2 2x^2=400 x^2 = 200 x = 14. 14213562... That means the largest circle would have a diameter of 14.1413562... That means the largest circle would have a radius of 7.071067812 rounded would be 7.07 Hope It Helps. Email me at: african.chef@yahoo.com [cont.]
Answered by african.chef - Tue May 19 23:02:19 2009
From Yahoo Answer Search: 'geometry problems'
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by A and B Furthermore the triangle formed by A B and the red line in the diagram has half of the area of the parallelogram so we can calculate its area from the cross product also Line Point Distance Finding the distance from a point to a line is something that comes up often in geometry problems Lets say that you are given 3 points A B and C and you want to
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