integers................. .....?
Q. what are two integers whose sum is 12 and the difference is -60? (think about what integers are.)
Asked by food101 - Thu Oct 29 06:54:44 2009 - - 2 Answers - 0 Comments
A. x + y = 12 x - y = -60 Then Solve it. 2x= -48 x = -24 y= 24+12 = 36
Answered by up - Thu Oct 29 06:59:59 2009
Q. what are two integers whose sum is 12 and the difference is -60? (think about what integers are.)
Asked by food101 - Thu Oct 29 06:54:44 2009 - - 2 Answers - 0 Comments
A. x + y = 12 x - y = -60 Then Solve it. 2x= -48 x = -24 y= 24+12 = 36
Answered by up - Thu Oct 29 06:59:59 2009
InTeGeRs. ?
Q. -12 - 15 lol. please explain. i think its -3 but then it would be wrong because i thought the rule was if there different signs then the one with the higher value [15] which is positive. NAWW MAN. its negative 12 minute positive 15
Asked by Unceee - Wed Nov 21 18:04:47 2007 - - 4 Answers - 0 Comments
A. -12 - 15 turns to: -12 + -15 (then you add these together for your answer) its a larger (-) number! -12 - -15 would be -12 + + 15 (learn the rules and integers are easy)
Answered by 80's kid - Wed Nov 21 18:10:38 2007
Q. -12 - 15 lol. please explain. i think its -3 but then it would be wrong because i thought the rule was if there different signs then the one with the higher value [15] which is positive. NAWW MAN. its negative 12 minute positive 15
Asked by Unceee - Wed Nov 21 18:04:47 2007 - - 4 Answers - 0 Comments
A. -12 - 15 turns to: -12 + -15 (then you add these together for your answer) its a larger (-) number! -12 - -15 would be -12 + + 15 (learn the rules and integers are easy)
Answered by 80's kid - Wed Nov 21 18:10:38 2007
How do I read integers in from a file in Java and put them in an integer array?
Q. I have a text file with integers that are separated by spaces. The integers are all on one line. How would I get these integers from this file and save them into an array?
Asked by BGRIF - Wed Oct 28 15:10:23 2009 - - 2 Answers - 0 Comments
A. char[] anArray; anArray = new char[20]; String txt = "C:/text.txt"; BufferedReader in = new BufferedReader(new FileReader(txt)); String instr = in.readLine(); StringTokenizer st = new StringTokenizer(instr," ",false); String newstr=""; while (st.hasMoreElements()) newstr += st.nextElement(); anArray = newstr.toCharArray(); int[] newArray = new int[20]; for(int i=0;i
Q. I have a text file with integers that are separated by spaces. The integers are all on one line. How would I get these integers from this file and save them into an array?
Asked by BGRIF - Wed Oct 28 15:10:23 2009 - - 2 Answers - 0 Comments
A. char[] anArray; anArray = new char[20]; String txt = "C:/text.txt"; BufferedReader in = new BufferedReader(new FileReader(txt)); String instr = in.readLine(); StringTokenizer st = new StringTokenizer(instr," ",false); String newstr=""; while (st.hasMoreElements()) newstr += st.nextElement(); anArray = newstr.toCharArray(); int[] newArray = new int[20]; for(int i=0;i
How do I show that the set of nonnegative integers is not a subgroup of integers under addition?
Q. How do I show that the set of nonnegative integers is not a subgroup of integers under addition?
Asked by Abigail - Tue Mar 9 02:45:49 2010 - - 1 Answers - 0 Comments
A. A group is a set over a particular relation that has the following properties: 1) It is closed under that relation 2) It has an identity element in that relation 3) It is associated with respect to that relation 4) Each element in the set has an inverse w.r.t. the relation For the set of nonnegative integers (i.e. the natural numbers = {0, 1, 2, ... }, a subset of the set of integers, the first three conditions are met. 1) N (natural numbers = nonnegative integers) is closed over addition. That is, a non-negative number + a nonnegative number = a nonnegative number. Simple enough. 2) The identity element in N is 0 (over addition). That is, any nonnegative number x, plus 0, equals that same number x. 3) For a, b, c in N, (a + b) + c = a… [cont.]
Answered by ladaghini - Tue Mar 9 03:05:46 2010
Q. How do I show that the set of nonnegative integers is not a subgroup of integers under addition?
Asked by Abigail - Tue Mar 9 02:45:49 2010 - - 1 Answers - 0 Comments
A. A group is a set over a particular relation that has the following properties: 1) It is closed under that relation 2) It has an identity element in that relation 3) It is associated with respect to that relation 4) Each element in the set has an inverse w.r.t. the relation For the set of nonnegative integers (i.e. the natural numbers = {0, 1, 2, ... }, a subset of the set of integers, the first three conditions are met. 1) N (natural numbers = nonnegative integers) is closed over addition. That is, a non-negative number + a nonnegative number = a nonnegative number. Simple enough. 2) The identity element in N is 0 (over addition). That is, any nonnegative number x, plus 0, equals that same number x. 3) For a, b, c in N, (a + b) + c = a… [cont.]
Answered by ladaghini - Tue Mar 9 03:05:46 2010
3digit postive integers.What is the probability that any thee-digit palindrome is also a multiple of eleven?
Q. You are given a special set of numbers that contains all three-digit positive integers that are palindromes. What is the probability that any thee-digit palindrome is also a multiple of eleven?
Asked by hARMaNOoo - Mon Mar 2 11:06:47 2009 - - 6 Answers - 0 Comments
A. Since the numbers are in a form xyx, There are nine possible digits for x (1-9) and ten for y (0-9). So off the bat, there are only 90 numbers in this set. 101x + 10y = 11z For any given x, only one value of y at most is going to produce a multiple of 11. That's because whichever value it is, the next one up will be y+11, and y only goes from 0 to 9. At x=1, the value of y has to be 2, for the number 121. At x=2, y=4, for 242. x=3, y=6: 363 x=4, y=8: 484 As you can see there's a pattern where y=2x. If you add or subtract 11 to y you can still have a multiple of 11. At x=5, y=10, and since y=10 is not an acceptable value, there is no multiple of 11 where x=5. At x=6, y=12. y=12 is not valid but you can subtract 11 to get it back into… [cont.]
Answered by Lummox JR - Mon Mar 2 11:19:51 2009
Q. You are given a special set of numbers that contains all three-digit positive integers that are palindromes. What is the probability that any thee-digit palindrome is also a multiple of eleven?
Asked by hARMaNOoo - Mon Mar 2 11:06:47 2009 - - 6 Answers - 0 Comments
A. Since the numbers are in a form xyx, There are nine possible digits for x (1-9) and ten for y (0-9). So off the bat, there are only 90 numbers in this set. 101x + 10y = 11z For any given x, only one value of y at most is going to produce a multiple of 11. That's because whichever value it is, the next one up will be y+11, and y only goes from 0 to 9. At x=1, the value of y has to be 2, for the number 121. At x=2, y=4, for 242. x=3, y=6: 363 x=4, y=8: 484 As you can see there's a pattern where y=2x. If you add or subtract 11 to y you can still have a multiple of 11. At x=5, y=10, and since y=10 is not an acceptable value, there is no multiple of 11 where x=5. At x=6, y=12. y=12 is not valid but you can subtract 11 to get it back into… [cont.]
Answered by Lummox JR - Mon Mar 2 11:19:51 2009
How do i code java to find the sum of the the numbers between two integers?
Q. How do i right a method in java to input 2 integers and find the sum of those two integers as well as all the integers in between. thanks!
Asked by The King - Wed Feb 11 09:35:17 2009 - - 3 Answers - 1 Comments
A. Call your variables a and b. Do b subtract a. Loop this may times. Keep a counter of how many times the loop has run, and a variable which is the total number. Each run of the loop, add to the total sum of a and the loop counter.
Answered by TCB - Wed Feb 11 09:40:21 2009
Q. How do i right a method in java to input 2 integers and find the sum of those two integers as well as all the integers in between. thanks!
Asked by The King - Wed Feb 11 09:35:17 2009 - - 3 Answers - 1 Comments
A. Call your variables a and b. Do b subtract a. Loop this may times. Keep a counter of how many times the loop has run, and a variable which is the total number. Each run of the loop, add to the total sum of a and the loop counter.
Answered by TCB - Wed Feb 11 09:40:21 2009
How many positive integers not exceeding 2011 are multiples of 3 and 4 but not 5?
Q. How many positive integers, not exceeding 2011, are multiples of 3 and 4 but not 5? All I know is that it's got something to do with the number '12'. Thanx in advance!
Asked by One stressed out teenager - Mon Dec 29 07:00:03 2008 - - 5 Answers - 1 Comments
A. 12 is the least common multiple of 3 and four. To find the largest multiple of twelve smaller than 2011, Divide 2011 by 12= 167... remainder Since every 5th multiple of 12 is divisible by 5, divide 167 by 5= 33 167-33 =134
Answered by hihifernanda - Mon Dec 29 07:06:59 2008
Q. How many positive integers, not exceeding 2011, are multiples of 3 and 4 but not 5? All I know is that it's got something to do with the number '12'. Thanx in advance!
Asked by One stressed out teenager - Mon Dec 29 07:00:03 2008 - - 5 Answers - 1 Comments
A. 12 is the least common multiple of 3 and four. To find the largest multiple of twelve smaller than 2011, Divide 2011 by 12= 167... remainder Since every 5th multiple of 12 is divisible by 5, divide 167 by 5= 33 167-33 =134
Answered by hihifernanda - Mon Dec 29 07:06:59 2008
How many positive three digit integers are upright?
Q. An integer is defined as upright if the sum of its first two digits equal its third digit. For example, 145 is an upright integer since 1 + 4=5. How many positive three digit integers are upright?
Asked by Tillo L - Sat Dec 20 10:16:14 2008 - - 3 Answers - 0 Comments
A. There are 10 ways to partition 9 into 2 non-negative integers, order counting. They are 0 + 9 1 + 8 2 + 7 3 + 6 4 + 5 5 + 4 6 + 3 7 + 2 8 + 1 9 + 0. We throw out the first own since 099 is not, technically, a three digit number. That leaves 9 ways to make an upright integer ending in 9. Similarly there there are 8 ways to end in 8, 7 for 7, and so on down to just one way to end in 1, namely 101. So the number of upright integers is the ninth triangular number, 45.
Answered by strange - Sat Dec 20 10:30:12 2008
Q. An integer is defined as upright if the sum of its first two digits equal its third digit. For example, 145 is an upright integer since 1 + 4=5. How many positive three digit integers are upright?
Asked by Tillo L - Sat Dec 20 10:16:14 2008 - - 3 Answers - 0 Comments
A. There are 10 ways to partition 9 into 2 non-negative integers, order counting. They are 0 + 9 1 + 8 2 + 7 3 + 6 4 + 5 5 + 4 6 + 3 7 + 2 8 + 1 9 + 0. We throw out the first own since 099 is not, technically, a three digit number. That leaves 9 ways to make an upright integer ending in 9. Similarly there there are 8 ways to end in 8, 7 for 7, and so on down to just one way to end in 1, namely 101. So the number of upright integers is the ninth triangular number, 45.
Answered by strange - Sat Dec 20 10:30:12 2008
How many different positive four-digit integers can be formed if the first digit must be 2 ,the last digit can?
Q. How many different positive four-digit integers can be formed if the first digit must be 2, the last digit cannot be 0 and digits may be repeated?
Asked by Elena T - Fri Jul 31 17:54:16 2009 - - 3 Answers - 0 Comments
A. 9x10^2 possibilities
Answered by Paulie Walnuts - Fri Jul 31 17:59:51 2009
Q. How many different positive four-digit integers can be formed if the first digit must be 2, the last digit cannot be 0 and digits may be repeated?
Asked by Elena T - Fri Jul 31 17:54:16 2009 - - 3 Answers - 0 Comments
A. 9x10^2 possibilities
Answered by Paulie Walnuts - Fri Jul 31 17:59:51 2009
How is the positive integers system represented in Group Theory?
Q. How is the positive integers system represented in Group Theory? How is the positive and negative integers system represented?
Asked by pemd70 - Mon Jul 23 16:13:33 2007 - - 4 Answers - 0 Comments
A. positive integers DO NOT form a group under standard sum or multiplication, since there are NO inverses. the integers form a group using the standard +
Answered by robert - Fri Jul 27 14:01:59 2007
Q. How is the positive integers system represented in Group Theory? How is the positive and negative integers system represented?
Asked by pemd70 - Mon Jul 23 16:13:33 2007 - - 4 Answers - 0 Comments
A. positive integers DO NOT form a group under standard sum or multiplication, since there are NO inverses. the integers form a group using the standard +
Answered by robert - Fri Jul 27 14:01:59 2007
How do I find three consecutive odd integers using unknowns?
Q. So if I need to find three consecutive odd integers such that twice the sum of the first and the second is equal to four times the sum of the second and the third, how do I solve?
Asked by Lena B - Tue Mar 3 18:46:37 2009 - - 1 Answers - 0 Comments
A. Ok we need to find three integers, let's call them x,y,z. If these integers are consecutive odd integers then: y = x + 2 z = x + 4 Then using the second part of your question: 2 ( x + y ) = 4 ( y + z) This is because the left-hand side is 2 times the sum of the first and second integerss and the right-hand side is 4 times the sum of the second and third integers. Then we substitute values into this equation to get: 2 ( x + x + 2) = 4 ( x + 2 + x + 4) 2 ( 2x + 2) = 4 (2x + 6) 4x + 4 = 8x + 24 4x = -20 x = -5 Which would give y = -3 and z = -1. You can now check this: 2 lots of -5 + -3 = 2 x -8 = -16 4 lots of -3 + -1 = 4 x -4 = -16 So your answer is -5, -3, -1 Hope that helps and I've explained it well for you :D
Answered by Fluorosive - Tue Mar 3 19:00:40 2009
Q. So if I need to find three consecutive odd integers such that twice the sum of the first and the second is equal to four times the sum of the second and the third, how do I solve?
Asked by Lena B - Tue Mar 3 18:46:37 2009 - - 1 Answers - 0 Comments
A. Ok we need to find three integers, let's call them x,y,z. If these integers are consecutive odd integers then: y = x + 2 z = x + 4 Then using the second part of your question: 2 ( x + y ) = 4 ( y + z) This is because the left-hand side is 2 times the sum of the first and second integerss and the right-hand side is 4 times the sum of the second and third integers. Then we substitute values into this equation to get: 2 ( x + x + 2) = 4 ( x + 2 + x + 4) 2 ( 2x + 2) = 4 (2x + 6) 4x + 4 = 8x + 24 4x = -20 x = -5 Which would give y = -3 and z = -1. You can now check this: 2 lots of -5 + -3 = 2 x -8 = -16 4 lots of -3 + -1 = 4 x -4 = -16 So your answer is -5, -3, -1 Hope that helps and I've explained it well for you :D
Answered by Fluorosive - Tue Mar 3 19:00:40 2009
The product of two consecutive positive even integers is 12,320. What are the two integers?
Q. The product of two consecutive positive even integers is 12,320. What are the two integers?
Asked by 3$co - Tue Dec 29 17:37:33 2009 - - 4 Answers - 0 Comments
A. 110, 112
Answered by Frin - Tue Dec 29 17:45:54 2009
Q. The product of two consecutive positive even integers is 12,320. What are the two integers?
Asked by 3$co - Tue Dec 29 17:37:33 2009 - - 4 Answers - 0 Comments
A. 110, 112
Answered by Frin - Tue Dec 29 17:45:54 2009
How many integers with 4 different digits are there between 1000 and 9999 such that the absolute value of the ?
Q. How many integers with 4 different digits are there between 1000 and 999 such that the absolute value of the difference between the first digit and the last digit is 2? please show works and thank you for all your help!
Asked by xD - Tue Dec 2 06:07:24 2008 - - 3 Answers - 0 Comments
A. answer = (2*8 - 1) * 8 * 7 = 15 * 8 * 7 = 840 8 is (2,0), (3,1), (4,2), (5,3), (6,4), (7,5), (8,6), (9,7). times 2 for they could chage place (thousands be ones and vice versa). but N > 1000, it cannot start with 0, so minus 1.
Answered by Momo & Lili - Tue Dec 2 06:14:05 2008
Q. How many integers with 4 different digits are there between 1000 and 999 such that the absolute value of the difference between the first digit and the last digit is 2? please show works and thank you for all your help!
Asked by xD - Tue Dec 2 06:07:24 2008 - - 3 Answers - 0 Comments
A. answer = (2*8 - 1) * 8 * 7 = 15 * 8 * 7 = 840 8 is (2,0), (3,1), (4,2), (5,3), (6,4), (7,5), (8,6), (9,7). times 2 for they could chage place (thousands be ones and vice versa). but N > 1000, it cannot start with 0, so minus 1.
Answered by Momo & Lili - Tue Dec 2 06:14:05 2008
What are two integers with a sum of -9 and a difference of 5?
Q. Help me please. What are two integers with the sum of -9 and a difference of 5?
Asked by theann - Wed Oct 22 18:43:27 2008 - - 2 Answers - 0 Comments
A. x+y = - 9 x-y =5 Combine to get 2x= - 4 So x= - 2 so y= -7 It works! -2 + -7 =-9 and (-2) - (-7) =5
Answered by marshahb - Wed Oct 22 18:49:10 2008
Q. Help me please. What are two integers with the sum of -9 and a difference of 5?
Asked by theann - Wed Oct 22 18:43:27 2008 - - 2 Answers - 0 Comments
A. x+y = - 9 x-y =5 Combine to get 2x= - 4 So x= - 2 so y= -7 It works! -2 + -7 =-9 and (-2) - (-7) =5
Answered by marshahb - Wed Oct 22 18:49:10 2008
Find two conscutive odd integers such that the sum of the smaller and 3 times the larger is 234?
Q. Find two conscutive odd integers such that the sum of the smaller and 3 times the larger is 234. I need help. How do u do it Thanks "E"
Asked by BABA - Tue Sep 25 18:19:48 2007 - - 4 Answers - 0 Comments
A. Two consecutive odd integers = x, x + 2 Sooo... x + 3(x + 2) = 234 x + 3x + 6 = 234 4x = 228 x = 57 (And the other number was x + 2, or 59) Check: 57 + 3(59) = 234 57 + 177 = 234 234 = 234
Answered by E - Tue Sep 25 18:26:00 2007
Q. Find two conscutive odd integers such that the sum of the smaller and 3 times the larger is 234. I need help. How do u do it Thanks "E"
Asked by BABA - Tue Sep 25 18:19:48 2007 - - 4 Answers - 0 Comments
A. Two consecutive odd integers = x, x + 2 Sooo... x + 3(x + 2) = 234 x + 3x + 6 = 234 4x = 228 x = 57 (And the other number was x + 2, or 59) Check: 57 + 3(59) = 234 57 + 177 = 234 234 = 234
Answered by E - Tue Sep 25 18:26:00 2007
How do I write an equation in standard form using integers?
Q. Here is the question: Write the equation in standard form using integers. y=2x-6 How do I do this? Please explain step by step so I can undertsnad better. Also, are there any websites you know of that explain this kind of stuff step by step in an easy to understand way? Thank you so much!
Asked by Anon Delivers - Fri Apr 25 15:11:50 2008 - - 2 Answers - 0 Comments
A. Standard form is Ax + By = C y = 2x-6 -2x + y = -6 Can multiply by -1. 2x - y = 6
Answered by beedo - Fri Apr 25 15:15:33 2008
Q. Here is the question: Write the equation in standard form using integers. y=2x-6 How do I do this? Please explain step by step so I can undertsnad better. Also, are there any websites you know of that explain this kind of stuff step by step in an easy to understand way? Thank you so much!
Asked by Anon Delivers - Fri Apr 25 15:11:50 2008 - - 2 Answers - 0 Comments
A. Standard form is Ax + By = C y = 2x-6 -2x + y = -6 Can multiply by -1. 2x - y = 6
Answered by beedo - Fri Apr 25 15:15:33 2008
What is the difference between the first and last term of a sequence of 1000 Consecutive even integers?
Q. What is the difference between the first and last term of a sequence of 1000 Consecutive even integers? I think it would be 2000, but I am not sure. Can anybody explain this problem to me? Thanks! Yes, as one answerer pointed out, I thought that zero would be considered the first integer and got the wrong answer. (2000 haha). Oh well I got ever other math question right so I predict I got a 76 total math.
Asked by Tony - Wed Oct 15 15:44:40 2008 - - 3 Answers - 0 Comments
A. x is the first number x + 999 * 2 is the last number x + 1998 - x = 1998 2000 would be the difference between the first and last term of a sequence of 1001 consecutive even integers. If it was 3 consecutive even integers, and the numbers were 2, 4, 6, the difference would be 4, which is: x + (n - 1) * 2 - x = x + (3 - 1) * 2 - x = 2 * 2 = 4
Answered by Elmyr - Wed Oct 15 15:50:49 2008
Q. What is the difference between the first and last term of a sequence of 1000 Consecutive even integers? I think it would be 2000, but I am not sure. Can anybody explain this problem to me? Thanks! Yes, as one answerer pointed out, I thought that zero would be considered the first integer and got the wrong answer. (2000 haha). Oh well I got ever other math question right so I predict I got a 76 total math.
Asked by Tony - Wed Oct 15 15:44:40 2008 - - 3 Answers - 0 Comments
A. x is the first number x + 999 * 2 is the last number x + 1998 - x = 1998 2000 would be the difference between the first and last term of a sequence of 1001 consecutive even integers. If it was 3 consecutive even integers, and the numbers were 2, 4, 6, the difference would be 4, which is: x + (n - 1) * 2 - x = x + (3 - 1) * 2 - x = 2 * 2 = 4
Answered by Elmyr - Wed Oct 15 15:50:49 2008
Can someone help me with equations and integers?
Q. I'm having trouble in math with integers and equations. Can someone give me helpful hints for them please?
Asked by danredirish - Thu Jun 1 20:29:19 2006 - - 4 Answers - 0 Comments
A. thats why you have a teacher
Answered by You Betcha! - Thu Jun 1 20:59:01 2006
Q. I'm having trouble in math with integers and equations. Can someone give me helpful hints for them please?
Asked by danredirish - Thu Jun 1 20:29:19 2006 - - 4 Answers - 0 Comments
A. thats why you have a teacher
Answered by You Betcha! - Thu Jun 1 20:59:01 2006
How do I write a C program reads a 5x5 two-dimensional array of integers and prints the row and column sums?
Q. How do I write a C program that reads a 5x5 two-dimensional array of integers and then prints its row sums and column sums?
Asked by Lora - Sun Oct 25 13:06:34 2009 - - 4 Answers - 0 Comments
A. And don't forget to use the debugger to single step through and makes sure the code is executing as intended!
Answered by John T - Sun Oct 25 13:18:26 2009
Q. How do I write a C program that reads a 5x5 two-dimensional array of integers and then prints its row sums and column sums?
Asked by Lora - Sun Oct 25 13:06:34 2009 - - 4 Answers - 0 Comments
A. And don't forget to use the debugger to single step through and makes sure the code is executing as intended!
Answered by John T - Sun Oct 25 13:18:26 2009
What is the equation to find the two integers?
Q. I'm confused about how to do this problem: The product of two consecutive odd integers decreased by three times the larger is 104. If x represents the smaller integer, which equation could be used to find the two integers? I used to be good at these, but I just haven't done them in quite a while... none of the answers so far are what i'm looking for. here are the choices: a) x^2-x-110=0 b) x^2+5x-104=0 c) x^2-x-104=0 d) x^2-x-98=0
Asked by jamie68117 - Tue May 29 00:56:11 2007 - - 4 Answers - 0 Comments
A. OK, x is the first integer; and x+2 is the second. The problem is translated into: x*(x+ 2)-3(x+2) = 104 this will give a quadratic which you can solve for; one answer is probably even and the other odd. --- OK, I solved it just for grins; x can be either 10 or 11, so the answer you're looking for is 11 and 13 (10 and 12 would work, but they're even, not odd).
Answered by Mark S, JPAA - Tue May 29 01:01:55 2007
Q. I'm confused about how to do this problem: The product of two consecutive odd integers decreased by three times the larger is 104. If x represents the smaller integer, which equation could be used to find the two integers? I used to be good at these, but I just haven't done them in quite a while... none of the answers so far are what i'm looking for. here are the choices: a) x^2-x-110=0 b) x^2+5x-104=0 c) x^2-x-104=0 d) x^2-x-98=0
Asked by jamie68117 - Tue May 29 00:56:11 2007 - - 4 Answers - 0 Comments
A. OK, x is the first integer; and x+2 is the second. The problem is translated into: x*(x+ 2)-3(x+2) = 104 this will give a quadratic which you can solve for; one answer is probably even and the other odd. --- OK, I solved it just for grins; x can be either 10 or 11, so the answer you're looking for is 11 and 13 (10 and 12 would work, but they're even, not odd).
Answered by Mark S, JPAA - Tue May 29 01:01:55 2007
From Yahoo Answer Search: 'Integers'
Wed Mar 17 20:09:13 2010 [ refresh local cache ]
[Hide]▼
news.google.com
Pueblo Chieftain
Students had 45 seconds to answer questions involving integers , coefficients, degrees of measure of polygons, increasing the surface space of a cube, etc. ...
and more »
redmine.ruby-lang.org
Marc-Andre Lafortune
ue, 02 Mar 2010 04:45:08 GM
Some methods of Ruby 1.9 expect . integers. /reals and call internally nurat_int_value/nurat_int_check. These functions raise an ArgumentError when the argument is not an . Integer. , instead of a TypeError. ...
[Hide]▲
