How do you add a logarithm equation, with base, in word 2007 with Micro Math?
Q. How do you add the base part of a logarithm in 2007 Word document? I have Microsoft Math as an add in, so it helps, but I don't know how to add the base part of a logarithm expression. I can write log 56, but I don't know how to put a base, such as 6, as a subscript. Thanks for any help.
Asked by Jordan!2332 - Sat Nov 7 20:33:47 2009 - - 1 Answers - 0 Comments
A. Hi: you can't directly write the other base in logarithm because the logarithm it has are base 10 for log( x) and 2.71828182845904523536028 74713527 for ln(x) you have to do a conversion by doing log( 56) / log(6) to get x for 6^x = 56 or ln( 56) / ln(6) to x for 6^56 Just to show you: I'm rounding it to 6 decimal place here: 2.718282/ 0.778151 = 2.246592 6^ 2.246592 = 56.00044730 - it close enough to be 56 due to my round it for the ln 4.025352/ 1.791760 = 2.246592 as you notice it's the same as the above answer for x if you want to change bases you must do the following : A^x= B log( B) / log(A) = x
Answered by iroc70 - Sat Nov 7 22:12:43 2009
Q. How do you add the base part of a logarithm in 2007 Word document? I have Microsoft Math as an add in, so it helps, but I don't know how to add the base part of a logarithm expression. I can write log 56, but I don't know how to put a base, such as 6, as a subscript. Thanks for any help.
Asked by Jordan!2332 - Sat Nov 7 20:33:47 2009 - - 1 Answers - 0 Comments
A. Hi: you can't directly write the other base in logarithm because the logarithm it has are base 10 for log( x) and 2.71828182845904523536028 74713527 for ln(x) you have to do a conversion by doing log( 56) / log(6) to get x for 6^x = 56 or ln( 56) / ln(6) to x for 6^56 Just to show you: I'm rounding it to 6 decimal place here: 2.718282/ 0.778151 = 2.246592 6^ 2.246592 = 56.00044730 - it close enough to be 56 due to my round it for the ln 4.025352/ 1.791760 = 2.246592 as you notice it's the same as the above answer for x if you want to change bases you must do the following : A^x= B log( B) / log(A) = x
Answered by iroc70 - Sat Nov 7 22:12:43 2009
How do you find natural logarithm of negative number?
Q. I am doing this question but am not sure how to get the answer, I know you can not take the log of a negative number. Could someone please help me? Find the natural logarithm of the number whose common logarithm is the given value of -3.45 thanks
Asked by adamskiii - Thu Mar 5 19:35:13 2009 - - 1 Answers - 0 Comments
A. what you want is if log x = -3.45 then what is ln x ? the concept is log {base a} x = log {base b} x / log {base b } a...thus log x = ln x / ln 10---> ln x = -3.45 ln 10
Answered by ted s - Thu Mar 5 19:44:12 2009
Q. I am doing this question but am not sure how to get the answer, I know you can not take the log of a negative number. Could someone please help me? Find the natural logarithm of the number whose common logarithm is the given value of -3.45 thanks
Asked by adamskiii - Thu Mar 5 19:35:13 2009 - - 1 Answers - 0 Comments
A. what you want is if log x = -3.45 then what is ln x ? the concept is log {base a} x = log {base b} x / log {base b } a...thus log x = ln x / ln 10---> ln x = -3.45 ln 10
Answered by ted s - Thu Mar 5 19:44:12 2009
How good is a calculator's base-10 Logarithm function?
Q. Is it sometimes necessary to generate a base-10 logarithm with better precision? Why? How good is "good enough" precision for most people using base-10 Logs? Can you recommend a book of logarithms that will serve well enough job in the absence of a calculator? Thanks people :)
Asked by unknown - Wed Sep 16 19:28:53 2009 - - 1 Answers - 0 Comments
A. Without knowing the practical problem involved, it is impossible to say if the function is "good enough". I would expect the function to be accurate to at least 14 digits, but different calculators will differ. An error of 10^-14 in the log10 function translates to an error 2.3 bigger in the antilog function. It would be rare to find a practical problem where you needed more accuracy than that. Murphys Law says that it will happen just when it is most important.
Answered by Morningfox - Wed Sep 16 19:41:49 2009
Q. Is it sometimes necessary to generate a base-10 logarithm with better precision? Why? How good is "good enough" precision for most people using base-10 Logs? Can you recommend a book of logarithms that will serve well enough job in the absence of a calculator? Thanks people :)
Asked by unknown - Wed Sep 16 19:28:53 2009 - - 1 Answers - 0 Comments
A. Without knowing the practical problem involved, it is impossible to say if the function is "good enough". I would expect the function to be accurate to at least 14 digits, but different calculators will differ. An error of 10^-14 in the log10 function translates to an error 2.3 bigger in the antilog function. It would be rare to find a practical problem where you needed more accuracy than that. Murphys Law says that it will happen just when it is most important.
Answered by Morningfox - Wed Sep 16 19:41:49 2009
How do you take derivative of logX with base b without using natural logarithm?
Q. d/dx(Log base b X) without using natural logarithm. So, how would you solve this without the knowledge of e. May be fundamental derivative formula?
Asked by AcE - Tue Feb 10 19:46:37 2009 - - 1 Answers - 0 Comments
A. d/dx(Log base b f(x)) = the derivative of f(x) / [ lnb * f(x)]
Answered by parakl tos - Fri Feb 13 07:21:01 2009
Q. d/dx(Log base b X) without using natural logarithm. So, how would you solve this without the knowledge of e. May be fundamental derivative formula?
Asked by AcE - Tue Feb 10 19:46:37 2009 - - 1 Answers - 0 Comments
A. d/dx(Log base b f(x)) = the derivative of f(x) / [ lnb * f(x)]
Answered by parakl tos - Fri Feb 13 07:21:01 2009
How can I write each expression as a logarithm of a single quantity?
Q. I have two problems and I can't figure them out, I can't figure it out w/ my math book and my teacher is really mean and never answers the questions I ask. This is the directions: Write each expression as a logarithm of a single quantity. 1.) 1/2Log (a+2) + Log b - 2 Log c 2.) 3 Log (a+1) - 2 Log (b+2) + 7 Log c
Asked by lol - Sun Nov 4 23:15:20 2007 - - 1 Answers - 0 Comments
A. You need to know the laws of logarithms. x log y = log x^y log x + log y = log xy log x - log y = log x/y 1/2Log (a+2) + Log b - 2 Log c = log [(a+2)^(1/2) X b] / c^2 3 Log (a+1) - 2 Log (b+2) + 7 Log c = log [(a+1)^3 X c^7] / (b+2)^2 Hope that helps!
Answered by greenwhite - Sun Nov 4 23:31:11 2007
Q. I have two problems and I can't figure them out, I can't figure it out w/ my math book and my teacher is really mean and never answers the questions I ask. This is the directions: Write each expression as a logarithm of a single quantity. 1.) 1/2Log (a+2) + Log b - 2 Log c 2.) 3 Log (a+1) - 2 Log (b+2) + 7 Log c
Asked by lol - Sun Nov 4 23:15:20 2007 - - 1 Answers - 0 Comments
A. You need to know the laws of logarithms. x log y = log x^y log x + log y = log xy log x - log y = log x/y 1/2Log (a+2) + Log b - 2 Log c = log [(a+2)^(1/2) X b] / c^2 3 Log (a+1) - 2 Log (b+2) + 7 Log c = log [(a+1)^3 X c^7] / (b+2)^2 Hope that helps!
Answered by greenwhite - Sun Nov 4 23:31:11 2007
How do you evaluate a logarithm?
Q. Evaluate: log(base3)36-log(base3)4 Please break down the steps to evaluate the logarithm.. I know the answer is two, but i dont know why its two.
Asked by Jay - Tue May 26 08:49:59 2009 - - 3 Answers - 0 Comments
Q. Evaluate: log(base3)36-log(base3)4 Please break down the steps to evaluate the logarithm.. I know the answer is two, but i dont know why its two.
Asked by Jay - Tue May 26 08:49:59 2009 - - 3 Answers - 0 Comments
How do you express 7(4log a (m) + 1/3log a (n)) as a single logarithm?
Q. (a) 7(4log a (m) + 1/3log a (n)) using the logarithm properties, what is the 1st step to finding the answer? (expressing as a single logarithm?
Asked by beeboroachgoingon197 - Thu Mar 6 20:55:27 2008 - - 1 Answers - 1 Comments
A. First step is to use this fact x log (m) = log (m^x). this holds for any log such as log a (m). So. 4log a (m) = log a (m^4) and (1/3) log a (n) = log a (n^(1/3)) the next thing to use is the following log x + log y = log xy, this also holds for any a as long as both logs have the same a. so log a (m^4) + log a (n^(1/3)) = log a (m^4 n^(1/3) ) note this is m^4 times n^(1/3) now just multiply by that 7 in the original problem statement.
Answered by jquaff - Fri Mar 7 02:54:11 2008
Q. (a) 7(4log a (m) + 1/3log a (n)) using the logarithm properties, what is the 1st step to finding the answer? (expressing as a single logarithm?
Asked by beeboroachgoingon197 - Thu Mar 6 20:55:27 2008 - - 1 Answers - 1 Comments
A. First step is to use this fact x log (m) = log (m^x). this holds for any log such as log a (m). So. 4log a (m) = log a (m^4) and (1/3) log a (n) = log a (n^(1/3)) the next thing to use is the following log x + log y = log xy, this also holds for any a as long as both logs have the same a. so log a (m^4) + log a (n^(1/3)) = log a (m^4 n^(1/3) ) note this is m^4 times n^(1/3) now just multiply by that 7 in the original problem statement.
Answered by jquaff - Fri Mar 7 02:54:11 2008
how do you express and simplify a single logarithm?
Q. The logarithm is ln w - 3[4ln (w-6) - ln (w+6)] I know inside the brackets its supposed to be ln (w-6)^4/w+6) but after that I don't know what to do. Help!
Asked by Kinetik. - Sun Dec 7 12:32:10 2008 - - 1 Answers - 2 Comments
A. You're almost there, right so far. Recall that ln(a) - ln(b) = ln(a/b). This is what you need to use.
Answered by Didn't hire me? Your mistake - Sun Dec 7 12:51:49 2008
Q. The logarithm is ln w - 3[4ln (w-6) - ln (w+6)] I know inside the brackets its supposed to be ln (w-6)^4/w+6) but after that I don't know what to do. Help!
Asked by Kinetik. - Sun Dec 7 12:32:10 2008 - - 1 Answers - 2 Comments
A. You're almost there, right so far. Recall that ln(a) - ln(b) = ln(a/b). This is what you need to use.
Answered by Didn't hire me? Your mistake - Sun Dec 7 12:51:49 2008
What is a natural logarithm, and what is the difference between regular logarithms?
Q. I have been trying to find the answer to this question for a while. All I can find are vague explanations referring to a base e. Examples I've seen using these natural logarithms all use the same product, quotient and power laws as regular logarithms, so what's the deal? Thanks in advance.
Asked by Ray - Wed Jan 7 14:20:53 2009 - - 8 Answers - 0 Comments
A. The natural logarithm, formerly known as the hyperbolic logarithm,[1] is the logarithm to the base e, where e is an irrational constant approximately equal to 2.7182818 The natural logarithm function can also be defined as the inverse function of the exponential function, leading to the identities. natural logarithm and regular logarithms are one and the same.
Answered by Vishnu - Wed Jan 7 14:36:18 2009
Q. I have been trying to find the answer to this question for a while. All I can find are vague explanations referring to a base e. Examples I've seen using these natural logarithms all use the same product, quotient and power laws as regular logarithms, so what's the deal? Thanks in advance.
Asked by Ray - Wed Jan 7 14:20:53 2009 - - 8 Answers - 0 Comments
A. The natural logarithm, formerly known as the hyperbolic logarithm,[1] is the logarithm to the base e, where e is an irrational constant approximately equal to 2.7182818 The natural logarithm function can also be defined as the inverse function of the exponential function, leading to the identities. natural logarithm and regular logarithms are one and the same.
Answered by Vishnu - Wed Jan 7 14:36:18 2009
Can anyone provide me with a formula for a logarithm application that is simple?
Q. My teacher wants to prove to us that logarithms are used in real life so he is offering an extra credit assignment, but I can't one that I understand. Please don't offer the formula to find pH balances or the magnitudes of earthquakes because he taught those in class. I tried to figure out the formula for finding the brightness of stars but I couldn't figure it out. Thanks so much.
Asked by kaylie - Sun May 10 19:06:19 2009 - - 1 Answers - 0 Comments
A. Radioactive decay in carbon dating is one example. Another is finance.
Answered by unmasked - Sun May 10 19:12:09 2009
Q. My teacher wants to prove to us that logarithms are used in real life so he is offering an extra credit assignment, but I can't one that I understand. Please don't offer the formula to find pH balances or the magnitudes of earthquakes because he taught those in class. I tried to figure out the formula for finding the brightness of stars but I couldn't figure it out. Thanks so much.
Asked by kaylie - Sun May 10 19:06:19 2009 - - 1 Answers - 0 Comments
A. Radioactive decay in carbon dating is one example. Another is finance.
Answered by unmasked - Sun May 10 19:12:09 2009
Explain the difference between a logarithm of a product and the product of logarithms ?
Q. Explain the difference between a logarithm of a product and the product of logarithms and give examples of each.
Asked by Amy S - Mon Dec 8 17:30:52 2008 - - 3 Answers - 0 Comments
Q. Explain the difference between a logarithm of a product and the product of logarithms and give examples of each.
Asked by Amy S - Mon Dec 8 17:30:52 2008 - - 3 Answers - 0 Comments
How do you find the logarithm of square root 1000?
Q. I know the answer is 3/2, but how do you get it?
Asked by fizwidget01 - Sun Jun 8 23:37:14 2008 - - 5 Answers - 0 Comments
A. log(10 )^1/2 log10^3/2 bring down the exponent and the log and 10 cancel you get 3/2 hope that helps!!!
Answered by Mich - Sun Jun 8 23:57:16 2008
Q. I know the answer is 3/2, but how do you get it?
Asked by fizwidget01 - Sun Jun 8 23:37:14 2008 - - 5 Answers - 0 Comments
A. log(10 )^1/2 log10^3/2 bring down the exponent and the log and 10 cancel you get 3/2 hope that helps!!!
Answered by Mich - Sun Jun 8 23:57:16 2008
How to change the bases in Logarithm problems?
Q. I am facing a problem with one of the log sums having a base under root.
Asked by Poet dip - Sun Aug 17 12:18:31 2008 - - 2 Answers - 0 Comments
A. ~ log( base, function ) ~ log( a, f(x) ) = p f(x) = a^p * b is our new base log( b, f(x) ) = log( b, a^p ) log( b, f(x) ) = p*log( b, a ) log( b, f(x) ) / log( b, a ) = p I'm sure this proof means something to mathematicians who care. For example: log( 6, 4 ) = log( 10, 4 ) / log( 10, 6 ) * b = 10, I chose the common log, but you can choose e or anything else.
Answered by Nate - Sun Aug 17 12:29:53 2008
Q. I am facing a problem with one of the log sums having a base under root.
Asked by Poet dip - Sun Aug 17 12:18:31 2008 - - 2 Answers - 0 Comments
A. ~ log( base, function ) ~ log( a, f(x) ) = p f(x) = a^p * b is our new base log( b, f(x) ) = log( b, a^p ) log( b, f(x) ) = p*log( b, a ) log( b, f(x) ) / log( b, a ) = p I'm sure this proof means something to mathematicians who care. For example: log( 6, 4 ) = log( 10, 4 ) / log( 10, 6 ) * b = 10, I chose the common log, but you can choose e or anything else.
Answered by Nate - Sun Aug 17 12:29:53 2008
How do you work out a logarithm problem with two different bases?
Q. the problem ive been given is: log(base7)49 + 3log(base2)8 - 4 im completely stumped, could someone please show me how to do it with explanations about why you did certain things as well? I'd deeply appreciate it
Asked by Lukeyboi - Sun Mar 29 21:25:51 2009 - - 1 Answers - 0 Comments
A. log(base7)49=2 because 7^2=49 3log(base2)8=log(base2)(8 ^3) =log(base2)512 =9 because 2^9=512 The rest you can figure out. (2+9-4) Just learn your logarithm properties. You should have them in your textbook.
Answered by LisbethAlxndr - Sun Mar 29 21:36:48 2009
Q. the problem ive been given is: log(base7)49 + 3log(base2)8 - 4 im completely stumped, could someone please show me how to do it with explanations about why you did certain things as well? I'd deeply appreciate it
Asked by Lukeyboi - Sun Mar 29 21:25:51 2009 - - 1 Answers - 0 Comments
A. log(base7)49=2 because 7^2=49 3log(base2)8=log(base2)(8 ^3) =log(base2)512 =9 because 2^9=512 The rest you can figure out. (2+9-4) Just learn your logarithm properties. You should have them in your textbook.
Answered by LisbethAlxndr - Sun Mar 29 21:36:48 2009
how can i calculate logarithms without using a calculator or a giant logarithm table?
Q. i need to know how to calculate the negative log (-log) of a number without a calculator. i know theres a method for this i just dont know how to do it. can someone help me calculate these examples and explain how please? -log(2E-5) -log(7E-7) this is for a test and the only thing allowed on my desk will be my pencil and test paper.
Asked by Kevin R. - Wed Oct 28 18:40:50 2009 - - 2 Answers - 0 Comments
A. If you remember, E means "10 to the power of". So 2E-5 will be "2 times 10 to the power of -5" and 7E-7 means "7 times 10 to the power of -7". So you can re-write these both as: -log(2 x 10^-5) and -log(7 x 10^-7) Since log(ab) can be split up to log(a) + log(b), we can get: -[log(2) + log(10^-5)] and -[log(7) + log(10^-7)] <=> -log(2) + 5 and -log(7) + 7 Then, if you want, you can use log(2) -0.301 and log(7) -0.845 to get the approximate answers of 4.699 and 6.155, respectively. I hope this helps! EDIT: Sign mess up. Fixed it now =D
Answered by unknown - Wed Oct 28 18:46:28 2009
Q. i need to know how to calculate the negative log (-log) of a number without a calculator. i know theres a method for this i just dont know how to do it. can someone help me calculate these examples and explain how please? -log(2E-5) -log(7E-7) this is for a test and the only thing allowed on my desk will be my pencil and test paper.
Asked by Kevin R. - Wed Oct 28 18:40:50 2009 - - 2 Answers - 0 Comments
A. If you remember, E means "10 to the power of". So 2E-5 will be "2 times 10 to the power of -5" and 7E-7 means "7 times 10 to the power of -7". So you can re-write these both as: -log(2 x 10^-5) and -log(7 x 10^-7) Since log(ab) can be split up to log(a) + log(b), we can get: -[log(2) + log(10^-5)] and -[log(7) + log(10^-7)] <=> -log(2) + 5 and -log(7) + 7 Then, if you want, you can use log(2) -0.301 and log(7) -0.845 to get the approximate answers of 4.699 and 6.155, respectively. I hope this helps! EDIT: Sign mess up. Fixed it now =D
Answered by unknown - Wed Oct 28 18:46:28 2009
What is the application of natural logarithm in life?
Q. the application and the details such as equation (if included) and examples.
Asked by karen w - Sun Jan 21 03:20:38 2007 - - 4 Answers - 0 Comments
A. Engineers and Mathematicians use e^(x) and ln(x) quite often in working with different equations. One of the most common equations that I can think of is the equation used for exponential growth of a population. You could use it to figure out how many bacteria there will be x(t) in a certain amount of time (t) if you started out with x_0 amount of bacteria and they multiply at rate k here is the function: x(t)=x_0 e^(kt) sometimes it is written as Population Total = Population Initial * e^(rate * time) or Ptot= Pe^(rt)
Answered by Kyle - Sun Jan 21 03:58:22 2007
Q. the application and the details such as equation (if included) and examples.
Asked by karen w - Sun Jan 21 03:20:38 2007 - - 4 Answers - 0 Comments
A. Engineers and Mathematicians use e^(x) and ln(x) quite often in working with different equations. One of the most common equations that I can think of is the equation used for exponential growth of a population. You could use it to figure out how many bacteria there will be x(t) in a certain amount of time (t) if you started out with x_0 amount of bacteria and they multiply at rate k here is the function: x(t)=x_0 e^(kt) sometimes it is written as Population Total = Population Initial * e^(rate * time) or Ptot= Pe^(rt)
Answered by Kyle - Sun Jan 21 03:58:22 2007
Why are exponential and logarithm functions called inverse functions?
Q. I already know about how you can transform one into the other but I need the actual reason why they're each other's inverse.
Asked by Faye - Tue Nov 4 06:32:04 2008 - - 2 Answers - 0 Comments
A. ok this is what i know so far, and i hope it helps a little. I also have the same question. As you might recall, inverse is when you try to isolate x instead of y? no? Lets use an easy example. Let's say you are asked to find inverse of y = 2 x . to solve that you isolate x , and it becomes y/2 = x. Same for exponential function. If you are asked to find inverse of y = a ^x , then you try to isolate x. and to do that, you have to "log the x down" meaning take the log of both sides. => log (y) = log (a^x) => log (y) = x log (a ) => log (y) / log (a) = x Now using the 'change of base rule' : log (y) /log (a) = log y with base 'a' and that is equalled to "x" So this shows that when you isolate x (which is finding the inverse ) [cont.]
Answered by SpongeBob - Fri Nov 7 06:39:24 2008
Q. I already know about how you can transform one into the other but I need the actual reason why they're each other's inverse.
Asked by Faye - Tue Nov 4 06:32:04 2008 - - 2 Answers - 0 Comments
A. ok this is what i know so far, and i hope it helps a little. I also have the same question. As you might recall, inverse is when you try to isolate x instead of y? no? Lets use an easy example. Let's say you are asked to find inverse of y = 2 x . to solve that you isolate x , and it becomes y/2 = x. Same for exponential function. If you are asked to find inverse of y = a ^x , then you try to isolate x. and to do that, you have to "log the x down" meaning take the log of both sides. => log (y) = log (a^x) => log (y) = x log (a ) => log (y) / log (a) = x Now using the 'change of base rule' : log (y) /log (a) = log y with base 'a' and that is equalled to "x" So this shows that when you isolate x (which is finding the inverse ) [cont.]
Answered by SpongeBob - Fri Nov 7 06:39:24 2008
Where I can download a logarithm and antilogarithm table for free on the web?
Q. Please provise a link to the file downnload or website in Sources. Thank You! Please provide a link to the download or website in Sources. Thank You! I just want a free download of the tables, nothin' else!!!
Asked by Archit - Tue Jun 5 13:40:19 2007 - - 4 Answers - 0 Comments
A. Much better than log tables, get the MS Powertoy calculator. It will generate natural and Brigg's logs to 512 decimal places. ~
Answered by Heinz M - Tue Jun 5 13:48:49 2007
Q. Please provise a link to the file downnload or website in Sources. Thank You! Please provide a link to the download or website in Sources. Thank You! I just want a free download of the tables, nothin' else!!!
Asked by Archit - Tue Jun 5 13:40:19 2007 - - 4 Answers - 0 Comments
A. Much better than log tables, get the MS Powertoy calculator. It will generate natural and Brigg's logs to 512 decimal places. ~
Answered by Heinz M - Tue Jun 5 13:48:49 2007
How do you express the following logarithm as a single expression?
Q. 1/2ln(x) 3ln(x^8 + 6)?? I think the answer might be ln(sqrt(x)/root3(x^8+6)) Am I right?
Asked by Top of all Answers - Sun May 10 01:13:24 2009 - - 1 Answers - 0 Comments
A. ln[((x^.5)/((x^8+^)^3)]
Answered by jack m - Sun May 10 01:38:17 2009
Q. 1/2ln(x) 3ln(x^8 + 6)?? I think the answer might be ln(sqrt(x)/root3(x^8+6)) Am I right?
Asked by Top of all Answers - Sun May 10 01:13:24 2009 - - 1 Answers - 0 Comments
A. ln[((x^.5)/((x^8+^)^3)]
Answered by jack m - Sun May 10 01:38:17 2009
How do I solve a natural logarithm equation?
Q. I need someone to walk me through the process of solving for x. Here is a sample equation: ln(x+3)-7=3 thanks for your help! Algebra 3-4 is killing me...
Asked by gaga_head - Wed Oct 29 20:15:11 2008 - - 1 Answers - 0 Comments
A. Add 7. 10= ln (x+3) Now, ln is base e. And remember that if you have y=log(base n) (x) then n^y=x So, in this case, e^10=x+3 Now just solve like a regular equation. e^10-3=x
Answered by Alejo - Wed Oct 29 20:21:27 2008
Q. I need someone to walk me through the process of solving for x. Here is a sample equation: ln(x+3)-7=3 thanks for your help! Algebra 3-4 is killing me...
Asked by gaga_head - Wed Oct 29 20:15:11 2008 - - 1 Answers - 0 Comments
A. Add 7. 10= ln (x+3) Now, ln is base e. And remember that if you have y=log(base n) (x) then n^y=x So, in this case, e^10=x+3 Now just solve like a regular equation. e^10-3=x
Answered by Alejo - Wed Oct 29 20:21:27 2008
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