Math/trivia?
Q. You go to a store and buy a bottle and a cork for it. The bottle cost one dollar more then the cork and the bill with out tax is $1.10. How much did both cost? Sorry you didn't like my wording. The price for each is was I was looking for and 1.05 and .05 is correct.
Asked by Mithrandir_black - Mon Mar 13 09:47:57 2006 - - 6 Answers - 0 Comments
A. ANSWER : The bottle costs $1.05, the cork costs $0.05. B = 1 + C B + C = 1.1 2C+1=1.1 2C = 0.1 C = 0.05 B = 1.05
Answered by rahidz2003 - Mon Mar 13 09:48:27 2006
Q. You go to a store and buy a bottle and a cork for it. The bottle cost one dollar more then the cork and the bill with out tax is $1.10. How much did both cost? Sorry you didn't like my wording. The price for each is was I was looking for and 1.05 and .05 is correct.
Asked by Mithrandir_black - Mon Mar 13 09:47:57 2006 - - 6 Answers - 0 Comments
A. ANSWER : The bottle costs $1.05, the cork costs $0.05. B = 1 + C B + C = 1.1 2C+1=1.1 2C = 0.1 C = 0.05 B = 1.05
Answered by rahidz2003 - Mon Mar 13 09:48:27 2006
I need help with this math/trivia question?
Q. Yesterday, Lindsay went for a long bicycle ride around the canyon. As the ride was quite long, she rode in various stages. In the first stage she rode half of the overall distance. Stage two saw half of the remaining distance plus 35 yards covered. Stage three covered three-quarters of the remaining distance. Stage four completed half of the remaining distance plus 75 yards. Stage five completed the journey with a final burst of 150 yards. How many yards did Lindsay cycle in total? Thank you!!!
Asked by KirKie - Mon Mar 17 12:25:41 2008 - - 3 Answers - 0 Comments
A. Work backwards. Stage 4 covered half the remaining distance plus 75 yards and left 150 yards for stage 5, so at the beginning of stage 4, there must have been 2 * (150+75) = 450 yards to go. Stage three covered 3/4 of the remainder at that time, so at the beginning of stage 3 there must have been 4 * 450 = 1800 yards to go. Stage two covered half of what was left at its beginning + 35 yards, so at the beginning of stage 2 there must have been 2 * (1800 + 35) = 3670 yards to go. The first stage covered half the total, so that 3670 covered in the last four stages is the other half, and the total is 7340 yards if my arithmetic is right.
Answered by unknown - Mon Mar 17 12:42:23 2008
Q. Yesterday, Lindsay went for a long bicycle ride around the canyon. As the ride was quite long, she rode in various stages. In the first stage she rode half of the overall distance. Stage two saw half of the remaining distance plus 35 yards covered. Stage three covered three-quarters of the remaining distance. Stage four completed half of the remaining distance plus 75 yards. Stage five completed the journey with a final burst of 150 yards. How many yards did Lindsay cycle in total? Thank you!!!
Asked by KirKie - Mon Mar 17 12:25:41 2008 - - 3 Answers - 0 Comments
A. Work backwards. Stage 4 covered half the remaining distance plus 75 yards and left 150 yards for stage 5, so at the beginning of stage 4, there must have been 2 * (150+75) = 450 yards to go. Stage three covered 3/4 of the remainder at that time, so at the beginning of stage 3 there must have been 4 * 450 = 1800 yards to go. Stage two covered half of what was left at its beginning + 35 yards, so at the beginning of stage 2 there must have been 2 * (1800 + 35) = 3670 yards to go. The first stage covered half the total, so that 3670 covered in the last four stages is the other half, and the total is 7340 yards if my arithmetic is right.
Answered by unknown - Mon Mar 17 12:42:23 2008
Math Trivia Question?
Q. I am hoping that someone can help me because I can't figure it out. Here's the question... There are 7 girls in a bus. Each girl has 7 backpacks. In each backpack, there are 7 big cats. For every big cat there are 7 little cats. Question: How many legs are there in the bus? The number of legs is the password to unlock the attached Excel spreadsheet. If you open it, add your name and send it on to see who else can unlock it. This is NOT a trick question... the number of seats on the bus has nothing to do with it... Math is hard! Thanks everyone for any help that you can give me.
Asked by megan_janel - Wed Mar 12 20:18:12 2008 - - 13 Answers - 0 Comments
A. 7girls *2legs=14 legs 7girl*7backpacks=49 backpacks 49 bp*7bigcats=343big cats 343*4legs= 1 372 legs 343*7little cats= 2 401 little cats 2401 lc * 4legs = 9 604 legs 14+1372+9604=10 990 w/o the driver's legs... :-)
Answered by Rein - Wed Mar 12 23:04:07 2008
Q. I am hoping that someone can help me because I can't figure it out. Here's the question... There are 7 girls in a bus. Each girl has 7 backpacks. In each backpack, there are 7 big cats. For every big cat there are 7 little cats. Question: How many legs are there in the bus? The number of legs is the password to unlock the attached Excel spreadsheet. If you open it, add your name and send it on to see who else can unlock it. This is NOT a trick question... the number of seats on the bus has nothing to do with it... Math is hard! Thanks everyone for any help that you can give me.
Asked by megan_janel - Wed Mar 12 20:18:12 2008 - - 13 Answers - 0 Comments
A. 7girls *2legs=14 legs 7girl*7backpacks=49 backpacks 49 bp*7bigcats=343big cats 343*4legs= 1 372 legs 343*7little cats= 2 401 little cats 2401 lc * 4legs = 9 604 legs 14+1372+9604=10 990 w/o the driver's legs... :-)
Answered by Rein - Wed Mar 12 23:04:07 2008
Great Math TRIVIA question. First to get it, gets the 10!?
Q. There are 100 lockers and 100 boys. All lockers are closed. Boy 1 opens every locker. Boy 2, "reverses" every other locker ("reverses" means if it's opened, he closes it; if it's closed, he opens it.). Boy 3 reverses every THIRD locker. Boy 4 reverses every FOURTH locker..and so on... By the time Boy 100 is done, how many lockers are opened?
Asked by njmarknj - Sat Dec 29 23:00:59 2007 - - 27 Answers - 0 Comments
A. 10.
Answered by Filipe F - Sat Dec 29 23:05:57 2007
Q. There are 100 lockers and 100 boys. All lockers are closed. Boy 1 opens every locker. Boy 2, "reverses" every other locker ("reverses" means if it's opened, he closes it; if it's closed, he opens it.). Boy 3 reverses every THIRD locker. Boy 4 reverses every FOURTH locker..and so on... By the time Boy 100 is done, how many lockers are opened?
Asked by njmarknj - Sat Dec 29 23:00:59 2007 - - 27 Answers - 0 Comments
A. 10.
Answered by Filipe F - Sat Dec 29 23:05:57 2007
Easy Math Trivia Question - Find the cupcake with the key.?
Q. You have 27 cupcakes, they all weigh exactly the same, but one. Ths one has a key inside it, it looks exactly the same as the others, but weighs more. You have a balance. A balance is a scale that works like a see-saw. You put an object on each side and it tilts for the heavier side. Anyway... What is the least number of times it takes to use the balance, to find the cupcake that weighs more? In other words...how many times do you have to use the balance, to find the cupcake that weighs more? The least amount of uses.
Asked by Jesse B - Mon Jan 22 22:02:10 2007 - - 7 Answers - 0 Comments
A. You can do it in 3: (1) Put 9 on each side of the scale. If one group of 9 weighs more, keep that 9. If they balance, take the 9 not used in the weighing. (2) From the 9 left, put 3 on each side of the scale. If one group of 3 weighs more, keep that 3. If they balance, take the 3 not used in the weighing. (3) From the 3 left, put 1 on each side of the scale. If one weighs more, that is the heavy one. If they balance, the heavy one is the one not used in the weighing. * * * * * Ah, Ronin, I see you like my answer... LOL, I see the first poster does also. Quite amusing how everyone is in agreement now...
Answered by zanti3 - Mon Jan 22 22:12:32 2007
Q. You have 27 cupcakes, they all weigh exactly the same, but one. Ths one has a key inside it, it looks exactly the same as the others, but weighs more. You have a balance. A balance is a scale that works like a see-saw. You put an object on each side and it tilts for the heavier side. Anyway... What is the least number of times it takes to use the balance, to find the cupcake that weighs more? In other words...how many times do you have to use the balance, to find the cupcake that weighs more? The least amount of uses.
Asked by Jesse B - Mon Jan 22 22:02:10 2007 - - 7 Answers - 0 Comments
A. You can do it in 3: (1) Put 9 on each side of the scale. If one group of 9 weighs more, keep that 9. If they balance, take the 9 not used in the weighing. (2) From the 9 left, put 3 on each side of the scale. If one group of 3 weighs more, keep that 3. If they balance, take the 3 not used in the weighing. (3) From the 3 left, put 1 on each side of the scale. If one weighs more, that is the heavy one. If they balance, the heavy one is the one not used in the weighing. * * * * * Ah, Ronin, I see you like my answer... LOL, I see the first poster does also. Quite amusing how everyone is in agreement now...
Answered by zanti3 - Mon Jan 22 22:12:32 2007
a confusing math trivia question?
Q. "The number feared by Pythagoreans, since it lies halfway between the only two integers that can be both the perimeter and the area of the same rectangle." its super confusing but if anybody knows the answer i would really appreciate it! thanks in advance :)
Asked by awoeheejtaw'j - Mon Jan 5 23:18:39 2009 - - 4 Answers - 0 Comments
A. Let's see what those rectangles can look like... Say x = length of one side, y = length of the other side. Area then is xy, and perimeter is 2(x+y) Since "Area = Perimeter", we need solutions to satisfy this: xy = 2(x+y) There are of course LOTS of solutions, but apparently only two of the solutions are integers. :D Assuming that only positive lengths are allowed, let's take a look... xy = 2(x+y) is the same as saying xy/2 = x + y <===> xy/2 - x = y <===> x(y/2 - 1) = y <===> x = y/(y/2 - 1) This means that y must be divisible by (y/2 - 1). Since the original equation was symmetric, this must also imply that x must be divisible by (x/2 - 1) as well. First check if x = 1 is possible: That means that y = y/2 - 1 <===> y/2 = -1 so not… [cont.]
Answered by Shaun - Mon Jan 5 23:24:07 2009
Q. "The number feared by Pythagoreans, since it lies halfway between the only two integers that can be both the perimeter and the area of the same rectangle." its super confusing but if anybody knows the answer i would really appreciate it! thanks in advance :)
Asked by awoeheejtaw'j - Mon Jan 5 23:18:39 2009 - - 4 Answers - 0 Comments
A. Let's see what those rectangles can look like... Say x = length of one side, y = length of the other side. Area then is xy, and perimeter is 2(x+y) Since "Area = Perimeter", we need solutions to satisfy this: xy = 2(x+y) There are of course LOTS of solutions, but apparently only two of the solutions are integers. :D Assuming that only positive lengths are allowed, let's take a look... xy = 2(x+y) is the same as saying xy/2 = x + y <===> xy/2 - x = y <===> x(y/2 - 1) = y <===> x = y/(y/2 - 1) This means that y must be divisible by (y/2 - 1). Since the original equation was symmetric, this must also imply that x must be divisible by (x/2 - 1) as well. First check if x = 1 is possible: That means that y = y/2 - 1 <===> y/2 = -1 so not… [cont.]
Answered by Shaun - Mon Jan 5 23:24:07 2009
math trivia question easy 10 pts?
Q. guys please answer this 1. What is the slope of the line that passes through (8, 4) and (6, 7)? 2 Which of the following pairs of coordinates are on a line with an undefined slope? (2, 3) (9, 8) (3, 1) (4, 1) (2, 3) (2, 10) 3. Write an equation in slope-intercept form of a line with a slope of 3 and a y-intercept of -2. Question 3 answers y = -2x + 3 y = 3x - 2 2y = 5x - 6 4.Write an equation of the line whose slope is 1/3 and whose y-intercept is 2. 5. Write an equation of a line that passes through (-12, -14) with slope 6. 6. Which equation describes the line that contains the points (6, 2) and (12, 4)?
Asked by Randell P - Thu Dec 11 07:14:33 2008 - - 2 Answers - 0 Comments
A. These questions are very simple coordinate geometry questions. 1. Slope of the line refers to the gradient. (y1-y2) / (x1-x2) (7-4) / (6-8) 3 / -2 -3/2 2. Check the gradients. (2, 3) (9, 8). Grad = 5/7 (3, 1) (4, 1). Grad = 0/1 (2, 3) (2, 10). Grad = 7/0 The third line has undefined gradient because it's conceptually wrong to divide by zero. 3. y = 3x - 2 y=mx + c m is the gradient (slope), and c is the y-intercept. 4. y = (1/3)x + 2 5. y = 6x + c Substitute (-12, -14) -14 = 6(-12) + c c = 58 ans: y = 6x + 58 6. Gradient = 2/6= 1/3 y = (1/3)x + c 4 = (1/3)12 + c c = 0 ans: y = (1/3)x
Answered by craappiboy - Thu Dec 11 07:28:30 2008
Q. guys please answer this 1. What is the slope of the line that passes through (8, 4) and (6, 7)? 2 Which of the following pairs of coordinates are on a line with an undefined slope? (2, 3) (9, 8) (3, 1) (4, 1) (2, 3) (2, 10) 3. Write an equation in slope-intercept form of a line with a slope of 3 and a y-intercept of -2. Question 3 answers y = -2x + 3 y = 3x - 2 2y = 5x - 6 4.Write an equation of the line whose slope is 1/3 and whose y-intercept is 2. 5. Write an equation of a line that passes through (-12, -14) with slope 6. 6. Which equation describes the line that contains the points (6, 2) and (12, 4)?
Asked by Randell P - Thu Dec 11 07:14:33 2008 - - 2 Answers - 0 Comments
A. These questions are very simple coordinate geometry questions. 1. Slope of the line refers to the gradient. (y1-y2) / (x1-x2) (7-4) / (6-8) 3 / -2 -3/2 2. Check the gradients. (2, 3) (9, 8). Grad = 5/7 (3, 1) (4, 1). Grad = 0/1 (2, 3) (2, 10). Grad = 7/0 The third line has undefined gradient because it's conceptually wrong to divide by zero. 3. y = 3x - 2 y=mx + c m is the gradient (slope), and c is the y-intercept. 4. y = (1/3)x + 2 5. y = 6x + c Substitute (-12, -14) -14 = 6(-12) + c c = 58 ans: y = 6x + 58 6. Gradient = 2/6= 1/3 y = (1/3)x + c 4 = (1/3)12 + c c = 0 ans: y = (1/3)x
Answered by craappiboy - Thu Dec 11 07:28:30 2008
Math Trivia Question (show your work)?
Q. The edges of a small rectangular prism are half the length of the edges of a larger similar prism. If the volume of the large rectangular prism is 24 cubic centimeters, what is the volume of the small rectangular prism?
Asked by Malcolm C - Mon Apr 7 02:37:15 2008 - - 4 Answers - 0 Comments
A. Hi, The volume of the small rectangular prism is 3 cubic centimeters. Since the volume of a rectangular prism is V = LWH, then if the sides of the smaller prism are each half the length of the edges of a larger similar prism, then the new volume would be V = ( L)( W)( H) = LWH. The new volume is of the old volume. So if the old volume was 24 cubic centimeters, then the volume of the smaller rectangular prism is of 24 or 3 cubic centimeters. <== answer i hope that helps!! :-)
Answered by Pi R Squared - Mon Apr 7 02:45:09 2008
Q. The edges of a small rectangular prism are half the length of the edges of a larger similar prism. If the volume of the large rectangular prism is 24 cubic centimeters, what is the volume of the small rectangular prism?
Asked by Malcolm C - Mon Apr 7 02:37:15 2008 - - 4 Answers - 0 Comments
A. Hi, The volume of the small rectangular prism is 3 cubic centimeters. Since the volume of a rectangular prism is V = LWH, then if the sides of the smaller prism are each half the length of the edges of a larger similar prism, then the new volume would be V = ( L)( W)( H) = LWH. The new volume is of the old volume. So if the old volume was 24 cubic centimeters, then the volume of the smaller rectangular prism is of 24 or 3 cubic centimeters. <== answer i hope that helps!! :-)
Answered by Pi R Squared - Mon Apr 7 02:45:09 2008
I'm looking for a really hard math trivia question. Do anyone have a really good one(please include solution)?
Q. I'm looking for a really hard math trivia question. Do anyone have a really good one(please include solution)?
Asked by msbutterflyj - Thu Apr 26 10:54:29 2007 - - 1 Answers - 0 Comments
A. How do you multiply two numbers together without using multiplication tables? You may only double or take half of the numbers. Ancient Egyptian Method of Multiplication The ancient Egyptians were not aware of the concept of multiplication tables as we are. The following method of multiplying numbers was developed by them to serve their needs. For example, we will multiply 12 times 8. We all know the answer to this or --do we? The ancient Egyptians used the following method. Start two columns; one begins with 12, the second begins with 8. The first column will be divided by 2; ignore the remainder; the number in the second column will double with each iteration. Every place we have an even number in the first column we cross… [cont.]
Answered by Robert L - Thu Apr 26 11:14:09 2007
Q. I'm looking for a really hard math trivia question. Do anyone have a really good one(please include solution)?
Asked by msbutterflyj - Thu Apr 26 10:54:29 2007 - - 1 Answers - 0 Comments
A. How do you multiply two numbers together without using multiplication tables? You may only double or take half of the numbers. Ancient Egyptian Method of Multiplication The ancient Egyptians were not aware of the concept of multiplication tables as we are. The following method of multiplying numbers was developed by them to serve their needs. For example, we will multiply 12 times 8. We all know the answer to this or --do we? The ancient Egyptians used the following method. Start two columns; one begins with 12, the second begins with 8. The first column will be divided by 2; ignore the remainder; the number in the second column will double with each iteration. Every place we have an even number in the first column we cross… [cont.]
Answered by Robert L - Thu Apr 26 11:14:09 2007
Fun trivia math question...is there a way to solve this?
Q. There are two people that are 36 years apart. One is 15 and the other is 51 and these two numbers have opposite digits. How can you find out when this will occur again- when the two ages will have opposite digits. (i.e. 13, 31). Is there an equation?
Asked by Keri O - Mon Sep 22 18:09:14 2008 - - 5 Answers - 0 Comments
A. 10x + y = 10y + x - 36 9x = 9y - 36 x = y - 4 So, any time the difference in the digits of the older person is positive 4, this will still happen. For example, when the older is 62, the younger will be 26.
Answered by msteele42 - Mon Sep 22 18:14:15 2008
Q. There are two people that are 36 years apart. One is 15 and the other is 51 and these two numbers have opposite digits. How can you find out when this will occur again- when the two ages will have opposite digits. (i.e. 13, 31). Is there an equation?
Asked by Keri O - Mon Sep 22 18:09:14 2008 - - 5 Answers - 0 Comments
A. 10x + y = 10y + x - 36 9x = 9y - 36 x = y - 4 So, any time the difference in the digits of the older person is positive 4, this will still happen. For example, when the older is 62, the younger will be 26.
Answered by msteele42 - Mon Sep 22 18:14:15 2008
Math trivia question best answer goes to first answer....?
Q. measure of angle ACE = 6x+9 and the measure of angle CEF = 10x-5 what is x?
Asked by mm - Thu Oct 12 23:56:06 2006 - - 4 Answers - 0 Comments
A. 3
Answered by Haley - Fri Oct 13 00:00:19 2006
Q. measure of angle ACE = 6x+9 and the measure of angle CEF = 10x-5 what is x?
Asked by mm - Thu Oct 12 23:56:06 2006 - - 4 Answers - 0 Comments
A. 3
Answered by Haley - Fri Oct 13 00:00:19 2006
Math/Trivia Question?
Q. A man is on a game show with the top prize of 1,000,000. However, for every percent of money won he has to give that amount of money to taxes. (If he won 100,000, since it is 10% of 1,000,000 he would have to give away 10,000 and keep 90,000). What is the most amount of money he could possibly win if every money value is a possibility.
Asked by Russel - Wed Jul 12 23:58:25 2006 - - 8 Answers - 0 Comments
A. He can keep $250,000 if he wins $500,000 (50%). That's the max.
Answered by Jim H - Thu Jul 13 00:13:27 2006
Q. A man is on a game show with the top prize of 1,000,000. However, for every percent of money won he has to give that amount of money to taxes. (If he won 100,000, since it is 10% of 1,000,000 he would have to give away 10,000 and keep 90,000). What is the most amount of money he could possibly win if every money value is a possibility.
Asked by Russel - Wed Jul 12 23:58:25 2006 - - 8 Answers - 0 Comments
A. He can keep $250,000 if he wins $500,000 (50%). That's the max.
Answered by Jim H - Thu Jul 13 00:13:27 2006
How bout this bit of math trivia. If the mighty Pats would have had even 1 loss, the chargers would still have
Q. 5 times more losses than the mighty Pats. With that many losses, the chargers are lucky they even made the playoffs. Boy, they be stinking up the NFL the chargers only beat 2 teams with winning records during the reg season, bozo the mighty Pats beat 7 teams with winning records
Asked by PETEY FILE - Mon Jan 14 17:25:41 2008 - - 7 Answers - 0 Comments
A. The Chargers are nothing special. They are arguably a better team this year despite the record. But The pats have upgraded on D, and O. The pats are going to beat up on the chargers, stuff the run, and easily cover the pass. Then to the Superbowl to dismantle the Packers. The Patriots > The rest of the NFL
Answered by baller86 - Mon Jan 14 17:35:37 2008
Q. 5 times more losses than the mighty Pats. With that many losses, the chargers are lucky they even made the playoffs. Boy, they be stinking up the NFL the chargers only beat 2 teams with winning records during the reg season, bozo the mighty Pats beat 7 teams with winning records
Asked by PETEY FILE - Mon Jan 14 17:25:41 2008 - - 7 Answers - 0 Comments
A. The Chargers are nothing special. They are arguably a better team this year despite the record. But The pats have upgraded on D, and O. The pats are going to beat up on the chargers, stuff the run, and easily cover the pass. Then to the Superbowl to dismantle the Packers. The Patriots > The rest of the NFL
Answered by baller86 - Mon Jan 14 17:35:37 2008
EZ Trivia Math Question 10 PTS?
Q. ax-3by=12 2ax-by=19 Solve the linear system for x and y in terms of the other variables. must use the linear combination. show all work :)
Asked by I Skiing - Sun Feb 1 20:47:33 2009 - - 1 Answers - 0 Comments
A. Hi, ax-3by=12 2ax-by=19 Multiply the first equation by -2. Then add equations and solve for y. -2(ax-3by=12) 2ax-by=19 -2ax + 6by = -24 2ax - by = 19 --- 5by = -5 y = -1/b ax-3by=12 2ax-by=19 Multiply the second equation by -3. Then add equations and solve for x. ax-3by=12 -3(2ax-by=19) ax - 3by = 12 -6ax + 3by = -57 --- -5ax = -45 x = 9/a (9/a, -1/b) <==Answer i hope that helps!! :-)
Answered by Pi R Squared - Sun Feb 1 20:58:16 2009
Q. ax-3by=12 2ax-by=19 Solve the linear system for x and y in terms of the other variables. must use the linear combination. show all work :)
Asked by I Skiing - Sun Feb 1 20:47:33 2009 - - 1 Answers - 0 Comments
A. Hi, ax-3by=12 2ax-by=19 Multiply the first equation by -2. Then add equations and solve for y. -2(ax-3by=12) 2ax-by=19 -2ax + 6by = -24 2ax - by = 19 --- 5by = -5 y = -1/b ax-3by=12 2ax-by=19 Multiply the second equation by -3. Then add equations and solve for x. ax-3by=12 -3(2ax-by=19) ax - 3by = 12 -6ax + 3by = -57 --- -5ax = -45 x = 9/a (9/a, -1/b) <==Answer i hope that helps!! :-)
Answered by Pi R Squared - Sun Feb 1 20:58:16 2009
Trivia math question??? 10 points!!?
Q. why is it impossible to algebraically solve(using elimination method or substitution method) the systems y=x^2+2x+4 y=x+1 why can u only solve this system by graphing it to find the number of solutions??
Asked by mom - Wed Apr 30 19:02:17 2008 - - 1 Answers - 0 Comments
A. Actually, it is possible to solve this system of equations algebraically, and it isn't hard at all. First, you can use the transitive property to create a third equation: x^2 + 2x + 4 = x + 1 Then, rearrange the equation to make it equal zero: x^2 + x + 3 = 0 Because this can't be factored, you have to use the quadratic formula: a=1, b=1, c=3 Quadratic Formula: x = (-b +/- sqrt(b^2 - 4ac)) / 2a x = (-(1) +/- sqrt((1)^2 - 4(1)(3))) / 2(1) x = (-1 +/- sqrt(-11)) / 2 Because there is a negative number in the square root, there are no real solutions. So if you graph both equations, the parabola and line will never intersect. It is possible to solve for the imaginary solutions: x = (-1/2) +/- sqrt(11)/2i
Answered by cheezguyty - Wed Apr 30 19:20:14 2008
Q. why is it impossible to algebraically solve(using elimination method or substitution method) the systems y=x^2+2x+4 y=x+1 why can u only solve this system by graphing it to find the number of solutions??
Asked by mom - Wed Apr 30 19:02:17 2008 - - 1 Answers - 0 Comments
A. Actually, it is possible to solve this system of equations algebraically, and it isn't hard at all. First, you can use the transitive property to create a third equation: x^2 + 2x + 4 = x + 1 Then, rearrange the equation to make it equal zero: x^2 + x + 3 = 0 Because this can't be factored, you have to use the quadratic formula: a=1, b=1, c=3 Quadratic Formula: x = (-b +/- sqrt(b^2 - 4ac)) / 2a x = (-(1) +/- sqrt((1)^2 - 4(1)(3))) / 2(1) x = (-1 +/- sqrt(-11)) / 2 Because there is a negative number in the square root, there are no real solutions. So if you graph both equations, the parabola and line will never intersect. It is possible to solve for the imaginary solutions: x = (-1/2) +/- sqrt(11)/2i
Answered by cheezguyty - Wed Apr 30 19:20:14 2008
please give me the BEST BEST best math trivia you know?
Q. Or at least a site of very good math trivias. I need a trivia for a math exhibit open for everybody--not for experts only!! Thank you very much!! ^_^ (
Asked by kevin! - Thu Aug 17 08:52:38 2006 - - 6 Answers - 0 Comments
A. 1/3 = 0.333,,, 1/3 + 1/3 + 1/3 = 0.999... But it doesn't. 1/3 + 1/3 + 1/3 = 1
Answered by LeAnne - Thu Aug 17 09:14:31 2006
Q. Or at least a site of very good math trivias. I need a trivia for a math exhibit open for everybody--not for experts only!! Thank you very much!! ^_^ (
Asked by kevin! - Thu Aug 17 08:52:38 2006 - - 6 Answers - 0 Comments
A. 1/3 = 0.333,,, 1/3 + 1/3 + 1/3 = 0.999... But it doesn't. 1/3 + 1/3 + 1/3 = 1
Answered by LeAnne - Thu Aug 17 09:14:31 2006
Math trivia: To what pages is the manuscript open if the product of the page numbers is 9,312?
Q. Math trivia: To what pages is the manuscript open if the product of the page numbers is 9,312?
Asked by Conor F - Thu Dec 20 01:39:05 2007 - - 3 Answers - 0 Comments
A. pages 96 and 97.
Answered by Jamishit - Thu Dec 20 01:43:40 2007
Q. Math trivia: To what pages is the manuscript open if the product of the page numbers is 9,312?
Asked by Conor F - Thu Dec 20 01:39:05 2007 - - 3 Answers - 0 Comments
A. pages 96 and 97.
Answered by Jamishit - Thu Dec 20 01:43:40 2007
Math Trivia. Like always, I already know the answer.?
Q. Welcome to my next trivia game. This is Math, but the last 2 will be a little harder. First to get 90%, unless someone gets 100%, wins. Rules are no editing and you cannot get best answer more than twice a week from me. 1) 1350 * 7507 = 2) What is this number? 1,000,000,000,000,000,000 ,000,000 (spell it out) 3) How many 0's are in one centillion? 4) 10^3 * 10^10 = 5) 5 - 3 = 6) 7 * 7 = 7) 9 * 9 + 8) 4 * 4 + 9) 7X +3 = 24 What is X? 10) 900X + 700 = 3,800 What is X? You are permited to use search engines. No editing your answer after you answer the question, because I may find out if you did so. On question 7 and 8, I hit + instead of =. sorry about that. First of, this is an easy level question for some of the questions.… [cont.]
Asked by Voterman - Fri Feb 23 19:34:49 2007 - - 5 Answers - 0 Comments
A. Okay, now that it is Sunday, I can answer this. 1) 10,134,450 2) One sextillion with what is showing, but with what is hidden by ... is one septillion. 3) 303 in American and 100 in European. 4) 10 trillion 5) 2 6) 49 7) 81 8) 16 9) 3 10) 3.444 repeating
Answered by coinman090388 - Sun Feb 25 00:16:26 2007
Q. Welcome to my next trivia game. This is Math, but the last 2 will be a little harder. First to get 90%, unless someone gets 100%, wins. Rules are no editing and you cannot get best answer more than twice a week from me. 1) 1350 * 7507 = 2) What is this number? 1,000,000,000,000,000,000 ,000,000 (spell it out) 3) How many 0's are in one centillion? 4) 10^3 * 10^10 = 5) 5 - 3 = 6) 7 * 7 = 7) 9 * 9 + 8) 4 * 4 + 9) 7X +3 = 24 What is X? 10) 900X + 700 = 3,800 What is X? You are permited to use search engines. No editing your answer after you answer the question, because I may find out if you did so. On question 7 and 8, I hit + instead of =. sorry about that. First of, this is an easy level question for some of the questions.… [cont.]
Asked by Voterman - Fri Feb 23 19:34:49 2007 - - 5 Answers - 0 Comments
A. Okay, now that it is Sunday, I can answer this. 1) 10,134,450 2) One sextillion with what is showing, but with what is hidden by ... is one septillion. 3) 303 in American and 100 in European. 4) 10 trillion 5) 2 6) 49 7) 81 8) 16 9) 3 10) 3.444 repeating
Answered by coinman090388 - Sun Feb 25 00:16:26 2007
canyou give trivia question in math?
Q. canyou give trivia question in math?
Asked by loislane - Tue Feb 14 06:52:11 2006 - - 4 Answers - 0 Comments
A. What do you call the line that intersects a circle in only 1 point?
Answered by J.A. - Tue Feb 14 06:58:20 2006
Q. canyou give trivia question in math?
Asked by loislane - Tue Feb 14 06:52:11 2006 - - 4 Answers - 0 Comments
A. What do you call the line that intersects a circle in only 1 point?
Answered by J.A. - Tue Feb 14 06:58:20 2006
math trivia straight from the SAT. can you figure this one out?
Q. Let a be the number of digits of 2^2001, and let b be the number of digits of 5^2001. Compute the sum of digits, a+b. (Hint: 2^5=32 which is 2 digits and 5^5=3125 which is 4 digits, therefore the sum of the digits is 6) i bet you cant figure this out~!
Asked by efil4zaggin17 - Tue Oct 17 10:36:05 2006 - - 5 Answers - 0 Comments
A. I always get counting wrong, but I got 2062. Why would it ask such a boring problem? Why don't we bring back Hollerith cards for programming if we want to frustrate people?
Answered by Bentley - Tue Oct 17 11:07:07 2006
Q. Let a be the number of digits of 2^2001, and let b be the number of digits of 5^2001. Compute the sum of digits, a+b. (Hint: 2^5=32 which is 2 digits and 5^5=3125 which is 4 digits, therefore the sum of the digits is 6) i bet you cant figure this out~!
Asked by efil4zaggin17 - Tue Oct 17 10:36:05 2006 - - 5 Answers - 0 Comments
A. I always get counting wrong, but I got 2062. Why would it ask such a boring problem? Why don't we bring back Hollerith cards for programming if we want to frustrate people?
Answered by Bentley - Tue Oct 17 11:07:07 2006
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