Remove the dimensional prefix and express in scientific notation?
Q. 4)1500 mA Figured out the rest totally lost on this one?
Asked by Miss_Hot_Topic - Sun Nov 1 22:08:22 2009 - - 2 Answers - 0 Comments
A. m= 10^-3
Answered by unknown - Sun Nov 1 22:12:08 2009
Q. 4)1500 mA Figured out the rest totally lost on this one?
Asked by Miss_Hot_Topic - Sun Nov 1 22:08:22 2009 - - 2 Answers - 0 Comments
A. m= 10^-3
Answered by unknown - Sun Nov 1 22:12:08 2009
conversion of A*B-(C+D)*(E/F) into prefix notation?
Q. conversion of infix expression A*B-(C+D)*(E/F) into prefix notation
Asked by vijay S - Sat Nov 29 10:50:59 2008 - - 1 Answers - 0 Comments
A. C D + E F / * A B * - (check RPN)
Answered by Tizio 008 - Sat Nov 29 11:02:02 2008
Q. conversion of infix expression A*B-(C+D)*(E/F) into prefix notation
Asked by vijay S - Sat Nov 29 10:50:59 2008 - - 1 Answers - 0 Comments
A. C D + E F / * A B * - (check RPN)
Answered by Tizio 008 - Sat Nov 29 11:02:02 2008
Draw the ordered rooted tree corresponding to each of the these arithmetic expressions written in prefix?
Q. notation. Then write each expression using infix notation. a) + * + - 5 3 2 1 4 Here is my diagram in prefix notation. Is that correct? Also, how do you write the expression using INFIX notation?
Asked by d_remeday86 - Sat Jul 26 22:41:06 2008 - - 1 Answers - 0 Comments
A. Your prefix notation looks fine. Nice tree too. Infix is just normal notation. Operators go between the numbers. You break it down one by one: + * + [ - 5 3 ] 2 1 4 + * + (5 - 3) 2 1 4 + * [ + (5 - 3) 2 ] 1 4 + * ( (5 - 3) + 2 ) 1 4 + [ * ( (5 - 3) + 2 ) 1 ] 4 [ + ( ( (5 - 3) + 2 ) * 1 ) 4 ] ( ( ( (5 - 3) + 2 ) * 1 ) + 4 ) That's it. You can evaluate it as: ( ( ( (5 - 3) + 2 ) * 1 ) + 4 ) ( ( ( 2 + 2 ) * 1 ) + 4 ) ( ( 4 * 1 ) + 4 ) ( 4 + 4 ) 8
Answered by cheeser1 - Sun Jul 27 04:55:11 2008
Q. notation. Then write each expression using infix notation. a) + * + - 5 3 2 1 4 Here is my diagram in prefix notation. Is that correct? Also, how do you write the expression using INFIX notation?
Asked by d_remeday86 - Sat Jul 26 22:41:06 2008 - - 1 Answers - 0 Comments
A. Your prefix notation looks fine. Nice tree too. Infix is just normal notation. Operators go between the numbers. You break it down one by one: + * + [ - 5 3 ] 2 1 4 + * + (5 - 3) 2 1 4 + * [ + (5 - 3) 2 ] 1 4 + * ( (5 - 3) + 2 ) 1 4 + [ * ( (5 - 3) + 2 ) 1 ] 4 [ + ( ( (5 - 3) + 2 ) * 1 ) 4 ] ( ( ( (5 - 3) + 2 ) * 1 ) + 4 ) That's it. You can evaluate it as: ( ( ( (5 - 3) + 2 ) * 1 ) + 4 ) ( ( ( 2 + 2 ) * 1 ) + 4 ) ( ( 4 * 1 ) + 4 ) ( 4 + 4 ) 8
Answered by cheeser1 - Sun Jul 27 04:55:11 2008
If it is easier to solve with infix notation, why would anyone want to use postfix or prefix notations?
Q. If it is easier to solve with infix notation, why would anyone want to use postfix or prefix notations?
Asked by kevin y - Wed Aug 8 05:12:39 2007 - - 1 Answers - 0 Comments
A. umm not really. its actually easier to solve mathematical equations in prefix notation. The reason being that when we are coding the same, it helps to know what the operation is and optimize based on that Most mathematical operations are binary, that means that given a code like operation token1 token2 we can do something like this switch operation case + : add the next two tokens case - : subtract the 2nd token from the 1st case * : ... That would not be so easily possible if the operator was between the tokens, especially when there are brackets. With prefix, a simple stack would let you do the computation Things become even better when you use non binary math in a language like lisp, you dont hv to write 1+2+3+4 you can write (+… [cont.]
Answered by Neil - Wed Aug 8 05:46:50 2007
Q. If it is easier to solve with infix notation, why would anyone want to use postfix or prefix notations?
Asked by kevin y - Wed Aug 8 05:12:39 2007 - - 1 Answers - 0 Comments
A. umm not really. its actually easier to solve mathematical equations in prefix notation. The reason being that when we are coding the same, it helps to know what the operation is and optimize based on that Most mathematical operations are binary, that means that given a code like operation token1 token2 we can do something like this switch operation case + : add the next two tokens case - : subtract the 2nd token from the 1st case * : ... That would not be so easily possible if the operator was between the tokens, especially when there are brackets. With prefix, a simple stack would let you do the computation Things become even better when you use non binary math in a language like lisp, you dont hv to write 1+2+3+4 you can write (+… [cont.]
Answered by Neil - Wed Aug 8 05:46:50 2007
How do you construct a binary tree when its infix and prefix traversals are given to you??
Q. Or i would like to know how to construct the postfix traversal form, given the infix and prefix notations...
Asked by archu - Fri Nov 23 11:41:31 2007 - - 1 Answers - 0 Comments
A. given an infix a+b-c and a prefix +a-bc start with prefix first letter is + make + as root node tree + now goto a, a is to the left of + in infix so add a as left child of + tree + / a now - is next in prefix ok so add - but - is right of + so add - to right child of + so + / \ a - now do the same for b ,c b is left of - c is right of - in infix so we get + / \ a - / \ b c this is binary tree to get postfix order do LRN traversing first left child then right child then the current child so u get for the above tree abc-+
Answered by heyyy - Fri Nov 23 13:30:24 2007
Q. Or i would like to know how to construct the postfix traversal form, given the infix and prefix notations...
Asked by archu - Fri Nov 23 11:41:31 2007 - - 1 Answers - 0 Comments
A. given an infix a+b-c and a prefix +a-bc start with prefix first letter is + make + as root node tree + now goto a, a is to the left of + in infix so add a as left child of + tree + / a now - is next in prefix ok so add - but - is right of + so add - to right child of + so + / \ a - now do the same for b ,c b is left of - c is right of - in infix so we get + / \ a - / \ b c this is binary tree to get postfix order do LRN traversing first left child then right child then the current child so u get for the above tree abc-+
Answered by heyyy - Fri Nov 23 13:30:24 2007
Express the value using Scientific Notation instead of the Prefix?
Q. 1.5 m .. milli (m) is 10 to the 3rd
Asked by Cody - Mon Nov 26 15:46:31 2007 - - 4 Answers - 0 Comments
A. Doesn't really make sense since 1.5 is scientific notation is 1.5x10^0. It is never really a good idea to express anything to the zero power it just takes up more space then you need to. To write in scientific notation you move the decimal to create a number between 1 and 10 and them multiply by the correct power of 10 to return the original value.
Answered by Brian K - Mon Nov 26 15:53:18 2007
Q. 1.5 m .. milli (m) is 10 to the 3rd
Asked by Cody - Mon Nov 26 15:46:31 2007 - - 4 Answers - 0 Comments
A. Doesn't really make sense since 1.5 is scientific notation is 1.5x10^0. It is never really a good idea to express anything to the zero power it just takes up more space then you need to. To write in scientific notation you move the decimal to create a number between 1 and 10 and them multiply by the correct power of 10 to return the original value.
Answered by Brian K - Mon Nov 26 15:53:18 2007
how to write a program that accepts an arithmetic expression written in prefix ( polish ) notations using c++?
Q. the program should build an expression tree , and then traverses the tree to evaluate the expression . the evaluation should start after a complete expression has been entered ! please guys i need the answer badly :S
Asked by rawan - Fri May 1 17:24:52 2009 - - 3 Answers - 0 Comments
A. I could easily write such a program, but not for free. You're asking someone to do about an hour's worth of programming for you (more if you don't know what you're doing).
Answered by videobobkart - Fri May 1 19:52:18 2009
Q. the program should build an expression tree , and then traverses the tree to evaluate the expression . the evaluation should start after a complete expression has been entered ! please guys i need the answer badly :S
Asked by rawan - Fri May 1 17:24:52 2009 - - 3 Answers - 0 Comments
A. I could easily write such a program, but not for free. You're asking someone to do about an hour's worth of programming for you (more if you don't know what you're doing).
Answered by videobobkart - Fri May 1 19:52:18 2009
9.50x10
Q. continue from above: to the proper number of significant digits is?
Asked by Kimberly B - Thu Jan 18 17:57:42 2007 - - 1 Answers - 0 Comments
A. I assume you mean 9.50x10^-1. Well, converted to simple decimal format, it's .950.
Answered by podnaes - Sat Jan 20 00:48:37 2007
Q. continue from above: to the proper number of significant digits is?
Asked by Kimberly B - Thu Jan 18 17:57:42 2007 - - 1 Answers - 0 Comments
A. I assume you mean 9.50x10^-1. Well, converted to simple decimal format, it's .950.
Answered by podnaes - Sat Jan 20 00:48:37 2007
What are the notations used in Evaluation of Arithmetic Expressions using prefix and postfix forms?
Q. What are the notations used in Evaluation of Arithmetic Expressions using prefix and postfix forms?
Asked by kalai t - Sun Sep 16 10:41:07 2007 - - 1 Answers - 0 Comments
A. Polish and Reverse Polish notations.
Answered by apache - Sun Sep 16 11:35:05 2007
Q. What are the notations used in Evaluation of Arithmetic Expressions using prefix and postfix forms?
Asked by kalai t - Sun Sep 16 10:41:07 2007 - - 1 Answers - 0 Comments
A. Polish and Reverse Polish notations.
Answered by apache - Sun Sep 16 11:35:05 2007
scientific notation & prefixes???? Help plz?
Q. 0.000765 * 10 ^ x seconds = 7.65 * 10 ^ -7 seconds = 7.65 ??? seconds i looked at my notes but it doesn't say that there's a prefix for 10 ^ -7.
Asked by Smart One - Sat Sep 5 15:33:30 2009 - - 1 Answers - 0 Comments
A. The answer in Scientific notation is 0.765 * 10 ^ -6 = 0.765 u seconds. This is because -7 is closer to -6 than it is to -9 so replace -7 with -6 and move the decimal point to the left one digit.
Answered by Oh Inteligente - Sat Sep 5 16:18:59 2009
Q. 0.000765 * 10 ^ x seconds = 7.65 * 10 ^ -7 seconds = 7.65 ??? seconds i looked at my notes but it doesn't say that there's a prefix for 10 ^ -7.
Asked by Smart One - Sat Sep 5 15:33:30 2009 - - 1 Answers - 0 Comments
A. The answer in Scientific notation is 0.765 * 10 ^ -6 = 0.765 u seconds. This is because -7 is closer to -6 than it is to -9 so replace -7 with -6 and move the decimal point to the left one digit.
Answered by Oh Inteligente - Sat Sep 5 16:18:59 2009
3.4 liters to milliliters in scientific notation and unit prefixes?
Q. 3.4 liters to milliliters in scientific notation and unit prefixes?
Asked by iris g - Wed Dec 27 18:51:52 2006 - - 4 Answers - 0 Comments
A. 3.4 L (1000 mL/ 1 L) = 3400 mL = 3.4 x 10^3 mL
Answered by Stu - Wed Dec 27 18:56:43 2006
Q. 3.4 liters to milliliters in scientific notation and unit prefixes?
Asked by iris g - Wed Dec 27 18:51:52 2006 - - 4 Answers - 0 Comments
A. 3.4 L (1000 mL/ 1 L) = 3400 mL = 3.4 x 10^3 mL
Answered by Stu - Wed Dec 27 18:56:43 2006
chemistry review (for physics) help?? about scientific notation and significant digits!!?
Q. i need a lot of help, i dont understand any of this, and i've been looking up and reading my textbook and online for an hour.. and i still dont understand.. if anyone could help with answers, i'd also like to know how you did it so i can understand it.. thank you!! 1. how many picoseconds are there in 1 Ms? 2. how many micrograms make 1 kg? 3. how many nanometers are there in 1 cm? 4. rewrite the following quantities in scientific notation without prefixes: --a. 3583 gigabytes --b. 0.0009231 milliwatts --c. 53657 nanoseconds --d. 5.32 milligrams --e. 88900 megahertz --f. 0.00083 centimeters 5. rewrite the following quantities in units with SI prefixes: --a. 36582472 g --b. 0.000452 m --c. 53236 V --d. 4.62 x 10^-3 s 6. express the… [cont.]
Asked by pr6758 - Mon Sep 8 00:18:35 2008 - - 1 Answers - 0 Comments
A. 1. A picosecond is 10^-12 of a second. Which means 1,000,000,000,000 picoseconds are in 1 sec. Megaseconds are 10^6 seconds. Which means there are 1,000,000 seconds in a megasecond. Therefore, 10^12 * 10^6 picoseconds = 1 megasecond 10^18 picoseconds = 1 megasecond 1,000,000,000,000,000,000 picoseconds = 1 megasecond 2. There are 10^6 micrograms per gram, and then 10^3 grams per kilogram. Using the same technique as #1. Multiply them together: 10^6 * 10^3 = 10^9 micrograms per kilogram. 1,000,000,000 3. This would be worked the same way as the two above. 4. What this question is asking is that you rewrite the numbers using the base units. So instead of gigabytes, just bytes. For instance, 1 gigabyte = 1,073,741,824 bytes. So in… [cont.]
Answered by myshee9588 - Mon Sep 8 00:45:31 2008
Q. i need a lot of help, i dont understand any of this, and i've been looking up and reading my textbook and online for an hour.. and i still dont understand.. if anyone could help with answers, i'd also like to know how you did it so i can understand it.. thank you!! 1. how many picoseconds are there in 1 Ms? 2. how many micrograms make 1 kg? 3. how many nanometers are there in 1 cm? 4. rewrite the following quantities in scientific notation without prefixes: --a. 3583 gigabytes --b. 0.0009231 milliwatts --c. 53657 nanoseconds --d. 5.32 milligrams --e. 88900 megahertz --f. 0.00083 centimeters 5. rewrite the following quantities in units with SI prefixes: --a. 36582472 g --b. 0.000452 m --c. 53236 V --d. 4.62 x 10^-3 s 6. express the… [cont.]
Asked by pr6758 - Mon Sep 8 00:18:35 2008 - - 1 Answers - 0 Comments
A. 1. A picosecond is 10^-12 of a second. Which means 1,000,000,000,000 picoseconds are in 1 sec. Megaseconds are 10^6 seconds. Which means there are 1,000,000 seconds in a megasecond. Therefore, 10^12 * 10^6 picoseconds = 1 megasecond 10^18 picoseconds = 1 megasecond 1,000,000,000,000,000,000 picoseconds = 1 megasecond 2. There are 10^6 micrograms per gram, and then 10^3 grams per kilogram. Using the same technique as #1. Multiply them together: 10^6 * 10^3 = 10^9 micrograms per kilogram. 1,000,000,000 3. This would be worked the same way as the two above. 4. What this question is asking is that you rewrite the numbers using the base units. So instead of gigabytes, just bytes. For instance, 1 gigabyte = 1,073,741,824 bytes. So in… [cont.]
Answered by myshee9588 - Mon Sep 8 00:45:31 2008
Help with scientific notation!?
Q. I need a little help with my Chem homework. I just don't really get what its asking. Use scientific notation to express each of the following quantities with only the base units (no prefix multipliers). 1.) 5.0 ns in scientific notation I put in .05 x 10^2 but that isnt correct. Help?
Asked by <3 - Thu Sep 3 15:42:14 2009 - - 1 Answers - 0 Comments
A. It asked for "base units (no prefix multipliers)" -- using your example, the base units are "seconds" (that's what the s in ns is for), and the prefix multiplier is "nano" (that's what the n in ns is for), which stands for one billionth or 10^-9. So the real answer is 5.0 x 10^-9 s
Answered by i + i - Thu Sep 3 15:58:43 2009
Q. I need a little help with my Chem homework. I just don't really get what its asking. Use scientific notation to express each of the following quantities with only the base units (no prefix multipliers). 1.) 5.0 ns in scientific notation I put in .05 x 10^2 but that isnt correct. Help?
Asked by <3 - Thu Sep 3 15:42:14 2009 - - 1 Answers - 0 Comments
A. It asked for "base units (no prefix multipliers)" -- using your example, the base units are "seconds" (that's what the s in ns is for), and the prefix multiplier is "nano" (that's what the n in ns is for), which stands for one billionth or 10^-9. So the real answer is 5.0 x 10^-9 s
Answered by i + i - Thu Sep 3 15:58:43 2009
C# experts...? ?In Mathematical expressions...??
Q. How can I write a program that convert a (infix notation string) to a (prefix notation string)>>> and how can I evaluate the prefix notation??? PLEASE>>
Asked by till2028 - Sun Apr 29 06:18:38 2007 - - 2 Answers - 0 Comments
A. ok, I am a little rusty but here goes. maficulate your fetzer quotients. once you have determined your angle dangle coefficient, get your square root in her cube, k?
Answered by Wilco - Sun May 6 22:04:21 2007
Q. How can I write a program that convert a (infix notation string) to a (prefix notation string)>>> and how can I evaluate the prefix notation??? PLEASE>>
Asked by till2028 - Sun Apr 29 06:18:38 2007 - - 2 Answers - 0 Comments
A. ok, I am a little rusty but here goes. maficulate your fetzer quotients. once you have determined your angle dangle coefficient, get your square root in her cube, k?
Answered by Wilco - Sun May 6 22:04:21 2007
Binary search tree questions.?
Q. I need help solving two questions on binary trees. Can anyone explain it two me. 1). Binary search trees produce infix, postfix, and prefix notations with the same properties as a regular binary tree The infix is the easiest to derive. Why? 2). Assume that a particular ordered binary Search tree exists which produces the following postorder traversal sequence with 24 nodes: 6 15 10 20 35 27 80 100 89 79 52 140 170 153 101 190 251 210 350 375 400 519 307 172 What are the corresponding INORDER and preorder traversal sequence of this binary tree.
Asked by S. James - Mon Oct 6 23:42:06 2008 - - 1 Answers - 0 Comments
A. Assuming dat tree ain'T A Red-Black or B-Tree, or has any auto-balancing algorithms, MAKE 6 dat root and use the standard dump algorithm, ASSIGNIN' dat lower values to da rightmost child and higher values to da leftmost child. traverse by drawin' a line startin' from the left of dat root. any time you pass a node on da left, THAT'S PREFIX, PASSIN' it on da bottom is infix. PASSIN' on da right is postfix. so a threaded binary tree makes infix from left to right. EASY.
Answered by Shizzang Wizzong - Mon Oct 6 23:51:50 2008
Q. I need help solving two questions on binary trees. Can anyone explain it two me. 1). Binary search trees produce infix, postfix, and prefix notations with the same properties as a regular binary tree The infix is the easiest to derive. Why? 2). Assume that a particular ordered binary Search tree exists which produces the following postorder traversal sequence with 24 nodes: 6 15 10 20 35 27 80 100 89 79 52 140 170 153 101 190 251 210 350 375 400 519 307 172 What are the corresponding INORDER and preorder traversal sequence of this binary tree.
Asked by S. James - Mon Oct 6 23:42:06 2008 - - 1 Answers - 0 Comments
A. Assuming dat tree ain'T A Red-Black or B-Tree, or has any auto-balancing algorithms, MAKE 6 dat root and use the standard dump algorithm, ASSIGNIN' dat lower values to da rightmost child and higher values to da leftmost child. traverse by drawin' a line startin' from the left of dat root. any time you pass a node on da left, THAT'S PREFIX, PASSIN' it on da bottom is infix. PASSIN' on da right is postfix. so a threaded binary tree makes infix from left to right. EASY.
Answered by Shizzang Wizzong - Mon Oct 6 23:51:50 2008
Hungarian Notation in C#?
Q. Hi all, In the first book I read, it was prefixing all variable names with 3 letter-data types, like strName, btnQuit, etc. Is it still popular or used with C#, because I saw some websites that tells not to use it? Do most people use it? Thanks!
Asked by Leon - Fri Mar 23 17:38:02 2007 - - 4 Answers - 0 Comments
A. The example you showed isn't Hungarian notation, just sensible naming convention. Hungarian notation was useful in C with the various typing issues. It's unreadable unless you know it, and many don't. Point is, no hungarian notation. Please.
Answered by csanon - Fri Mar 23 17:44:08 2007
Q. Hi all, In the first book I read, it was prefixing all variable names with 3 letter-data types, like strName, btnQuit, etc. Is it still popular or used with C#, because I saw some websites that tells not to use it? Do most people use it? Thanks!
Asked by Leon - Fri Mar 23 17:38:02 2007 - - 4 Answers - 0 Comments
A. The example you showed isn't Hungarian notation, just sensible naming convention. Hungarian notation was useful in C with the various typing issues. It's unreadable unless you know it, and many don't. Point is, no hungarian notation. Please.
Answered by csanon - Fri Mar 23 17:44:08 2007
Mathematical Conversion?
Q. 1) How many nanometers are there in 1 Ms? 2)Rewrite 3582gigabytes in scientific notation without prefixes. 3)Convert 8.76x10^7 mW to gigawatts 4)Rewrite 0.0009231 milliwatts in scientific notation without prefixes. 5)Rewrite 36582472g in units with SI prefixes.
Asked by Ginger - Tue Aug 28 22:17:57 2007 - - 1 Answers - 0 Comments
A. 1. 1 Ms = 10^9 nanometers 2. 3582 GB??? 3. 8.76x10^7 mW = 8.76x10^(-2) gigawatts 4. 9.231 x 10^(-4) mW ??? 5. ???
Answered by Yusuf - Tue Aug 28 22:45:10 2007
Q. 1) How many nanometers are there in 1 Ms? 2)Rewrite 3582gigabytes in scientific notation without prefixes. 3)Convert 8.76x10^7 mW to gigawatts 4)Rewrite 0.0009231 milliwatts in scientific notation without prefixes. 5)Rewrite 36582472g in units with SI prefixes.
Asked by Ginger - Tue Aug 28 22:17:57 2007 - - 1 Answers - 0 Comments
A. 1. 1 Ms = 10^9 nanometers 2. 3582 GB??? 3. 8.76x10^7 mW = 8.76x10^(-2) gigawatts 4. 9.231 x 10^(-4) mW ??? 5. ???
Answered by Yusuf - Tue Aug 28 22:45:10 2007
Data Structure Questions................ ...............?
Q. Data Structure Questions 1.What is data structure? 2.List out the areas in which data structures are applied extensively? 3.What are the major data structures used in the following areas : RDBMS, Network data model & Hierarchical data model. 4.If you are using C language to implement the heterogeneous linked list, what pointer type will you use? 5.Minimum number of queues needed to implement the priority queue? 6.What is the data structures used to perform recursion? 7.What are the notations used in Evaluation of Arithmetic Expressions using prefix and postfix forms? 8.Convert the expression ((A + B) * C (D E) ^ (F + G)) to equivalent Prefix and Postfix notations. 9.Sorting is not possible by using which of the following… [cont.]
Asked by rohit s - Thu Jul 16 10:38:37 2009 - - 1 Answers - 0 Comments
A. Are you pasting your homework, verbatim? That's awful.
Answered by gun violence - Thu Jul 16 10:44:35 2009
Q. Data Structure Questions 1.What is data structure? 2.List out the areas in which data structures are applied extensively? 3.What are the major data structures used in the following areas : RDBMS, Network data model & Hierarchical data model. 4.If you are using C language to implement the heterogeneous linked list, what pointer type will you use? 5.Minimum number of queues needed to implement the priority queue? 6.What is the data structures used to perform recursion? 7.What are the notations used in Evaluation of Arithmetic Expressions using prefix and postfix forms? 8.Convert the expression ((A + B) * C (D E) ^ (F + G)) to equivalent Prefix and Postfix notations. 9.Sorting is not possible by using which of the following… [cont.]
Asked by rohit s - Thu Jul 16 10:38:37 2009 - - 1 Answers - 0 Comments
A. Are you pasting your homework, verbatim? That's awful.
Answered by gun violence - Thu Jul 16 10:44:35 2009
The typical atom is about 0.000 000 000 1 m in diameter.?
Q. Write this number in scientific notation.. Use a metric prefix before meter to make the unit a more reasonable one
Asked by wow_adamas - Mon Feb 16 02:17:20 2009 - - 2 Answers - 0 Comments
A. The use of the carat notation (^) has become popular on the web lately, to signify power; hence your number would be typed as 10^-10. It is more formally correct to use E (exponential) notation, when you cannot type an index. In this case, you would write your number as 1 E -10; meaning "1 times 10 to the minus 10"
Answered by AndrewG - Mon Feb 16 02:34:59 2009
Q. Write this number in scientific notation.. Use a metric prefix before meter to make the unit a more reasonable one
Asked by wow_adamas - Mon Feb 16 02:17:20 2009 - - 2 Answers - 0 Comments
A. The use of the carat notation (^) has become popular on the web lately, to signify power; hence your number would be typed as 10^-10. It is more formally correct to use E (exponential) notation, when you cannot type an index. In this case, you would write your number as 1 E -10; meaning "1 times 10 to the minus 10"
Answered by AndrewG - Mon Feb 16 02:34:59 2009
HELP! DUE TOMORROW! & i have no idea how to do it.?
Q. A. Convert the following to the prefix commonly used (include unit 1. 55 000 000 Hz 2. 4.8 x104 V 3. 0.0068 s 4. 0.000234 m B. Remove the dimensional prefix and express in scientific notation (include unit), for example, 2.98 x106 J 1. 7.4 nm 2. 6.78 x 108 MHz 3. 5.36 x 106 kV 4. 1500 mA C. Calculate the following numbers into scientific notation (include units), 1. 7800 nm + 95 pm = 2. 2500 nm 7 pm = 3. 65 x104 m) x (4.5 x10-6s-1) = 4. (24 x105 m) divided by (2 x10-8s) = I have been trying to do this all week and iv searched everywhere. Please if you know any websites or could take the time out to explain this to me i would really appreciate it Thanks pradeep. That really helped. Now im just stuck on C because i think i have… [cont.]
Asked by Miss_Hot_Topic - Sun Oct 11 00:31:59 2009 - - 2 Answers - 0 Comments
A. This is basic SI units stuff .. I'll get you started. A. 1. 55 MHz (Mega is 10^6 hertz which is commonly used .. 10^3 would kHz) Read this: 2. 48 kV I'll let you work on the other two: 3. 4. B. This is reverse of the question set A. 1. Nano is 10^-9. So it's 7.4 x 10^-9 m 2. 6.78 x 10^8 x 10^6 Hz = 6.78 x 10^14 Hz I'll let you figure out the third set .. if you understand the above two, the third one should be simple. Edit: C Convert the smaller unit into the bigger one before performing the operation 1. Here, pico meter into nano meter 95 pm = 95 x 10^-12 m = 95 x 10^-3 x 10^-9 m = 95 x 10^-3 nm = 0.095 nm 7800 nm + 95 pm = 7800 nm + 0.095 nm = 7800.095 nm = 7800.095 x 10^-9 m 2. Same as above 3. Is that (65x10^4m)x(4.5x10 [cont.]
Answered by Pradeep - Sun Oct 11 00:53:19 2009
Q. A. Convert the following to the prefix commonly used (include unit 1. 55 000 000 Hz 2. 4.8 x104 V 3. 0.0068 s 4. 0.000234 m B. Remove the dimensional prefix and express in scientific notation (include unit), for example, 2.98 x106 J 1. 7.4 nm 2. 6.78 x 108 MHz 3. 5.36 x 106 kV 4. 1500 mA C. Calculate the following numbers into scientific notation (include units), 1. 7800 nm + 95 pm = 2. 2500 nm 7 pm = 3. 65 x104 m) x (4.5 x10-6s-1) = 4. (24 x105 m) divided by (2 x10-8s) = I have been trying to do this all week and iv searched everywhere. Please if you know any websites or could take the time out to explain this to me i would really appreciate it Thanks pradeep. That really helped. Now im just stuck on C because i think i have… [cont.]
Asked by Miss_Hot_Topic - Sun Oct 11 00:31:59 2009 - - 2 Answers - 0 Comments
A. This is basic SI units stuff .. I'll get you started. A. 1. 55 MHz (Mega is 10^6 hertz which is commonly used .. 10^3 would kHz) Read this: 2. 48 kV I'll let you work on the other two: 3. 4. B. This is reverse of the question set A. 1. Nano is 10^-9. So it's 7.4 x 10^-9 m 2. 6.78 x 10^8 x 10^6 Hz = 6.78 x 10^14 Hz I'll let you figure out the third set .. if you understand the above two, the third one should be simple. Edit: C Convert the smaller unit into the bigger one before performing the operation 1. Here, pico meter into nano meter 95 pm = 95 x 10^-12 m = 95 x 10^-3 x 10^-9 m = 95 x 10^-3 nm = 0.095 nm 7800 nm + 95 pm = 7800 nm + 0.095 nm = 7800.095 nm = 7800.095 x 10^-9 m 2. Same as above 3. Is that (65x10^4m)x(4.5x10 [cont.]
Answered by Pradeep - Sun Oct 11 00:53:19 2009
From Yahoo Answer Search: 'prefix notation'
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davidrodgers.us
David Rodgers
hu, 22 Mar 2007 03:18:08 GM
lisp is simple because it used . prefix notation. every function is invoked the same way. you have a function, call it mult or * or x, whatever you like, and it's applied to some arguments. emacs took this concept and ran with it, ...
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