The radius of a solid sphere is twice the radius of a second solid sphere. What is the ratio of?
Q. The radius of a solid sphere is twice the radius of a second solid sphere. What is the ratio of a) their volumes, b) their surface areas?
Asked by Jennifer T - Mon May 5 22:30:10 2008 - - 2 Answers - 0 Comments
A. vb/vx=(rb/rs)^3 vb:vs=9:1 ab/as=(rb/rs)^2 ab:as=4:1
Answered by someone else - Mon May 5 22:33:32 2008
Q. The radius of a solid sphere is twice the radius of a second solid sphere. What is the ratio of a) their volumes, b) their surface areas?
Asked by Jennifer T - Mon May 5 22:30:10 2008 - - 2 Answers - 0 Comments
A. vb/vx=(rb/rs)^3 vb:vs=9:1 ab/as=(rb/rs)^2 ab:as=4:1
Answered by someone else - Mon May 5 22:33:32 2008
How to differentiate radius and ulna in a bone diagram?
Q. Even my bio teacher get confused. We have some clues that ulna is thinner and longer than radius. And radius is often located next to the thumb. Is this true?
Asked by Rachel - Sun Mar 23 01:20:20 2008 - - 5 Answers - 0 Comments
A. Easy...the ulna, is thicker at the level of the elbow, and thin in the wrist, meanwhile the radius is completely the opposite: thin at the elbow level, and thick (very thick) at the level of the wrist...
Answered by Emilio Antar M - Sun Mar 23 01:36:19 2008
Q. Even my bio teacher get confused. We have some clues that ulna is thinner and longer than radius. And radius is often located next to the thumb. Is this true?
Asked by Rachel - Sun Mar 23 01:20:20 2008 - - 5 Answers - 0 Comments
A. Easy...the ulna, is thicker at the level of the elbow, and thin in the wrist, meanwhile the radius is completely the opposite: thin at the elbow level, and thick (very thick) at the level of the wrist...
Answered by Emilio Antar M - Sun Mar 23 01:36:19 2008
How do you find the radius of a circle given only a few parameters?
Q. I have a piece of metal with a very slight curve cut into the flat surface, creating a belly feature in the metal. I need to somehow find out the radius of the arc/curve. How can I use the horizontal length and the depth of the arc to find the radius of the arc?
Asked by Grant B - Thu May 22 20:08:07 2008 - - 1 Answers - 0 Comments
A. To find the radius, take two points on the curve and draw a line between them. Call the length of this line "b". Bisect this line (divide it by two) and draw a perpendicular line to intersect the arc. Call the length of this line "h". So, b = the horizontal length, and h = the depth of the arc. To find the radius use: r = (h^2 + b^2/4)/2h I derived this using some simple geometry and pythagorean's theorem.
Answered by proteus800 - Thu May 22 21:11:43 2008
Q. I have a piece of metal with a very slight curve cut into the flat surface, creating a belly feature in the metal. I need to somehow find out the radius of the arc/curve. How can I use the horizontal length and the depth of the arc to find the radius of the arc?
Asked by Grant B - Thu May 22 20:08:07 2008 - - 1 Answers - 0 Comments
A. To find the radius, take two points on the curve and draw a line between them. Call the length of this line "b". Bisect this line (divide it by two) and draw a perpendicular line to intersect the arc. Call the length of this line "h". So, b = the horizontal length, and h = the depth of the arc. To find the radius use: r = (h^2 + b^2/4)/2h I derived this using some simple geometry and pythagorean's theorem.
Answered by proteus800 - Thu May 22 21:11:43 2008
How can I find the radius of a cylinder when I am given the height and volume?
Q. The height of my cylinder is 25 ft and the volume is 935 ft^3. How do I go about finding the radius of this cylinder?
Asked by Stephanie S - Mon Feb 11 22:01:59 2008 - - 5 Answers - 0 Comments
A. the volume is V=pi r^2 h divide both sides by pih V/pih=r^2 take the square root of both sides to get only r r=square root of (V/pih) r=square root of 935/pi25 r=3.45
Answered by newtonnana - Mon Feb 11 22:13:11 2008
Q. The height of my cylinder is 25 ft and the volume is 935 ft^3. How do I go about finding the radius of this cylinder?
Asked by Stephanie S - Mon Feb 11 22:01:59 2008 - - 5 Answers - 0 Comments
A. the volume is V=pi r^2 h divide both sides by pih V/pih=r^2 take the square root of both sides to get only r r=square root of (V/pih) r=square root of 935/pi25 r=3.45
Answered by newtonnana - Mon Feb 11 22:13:11 2008
How can you find the radius from knowing the circumference of a circle?
Q. Okay, I am having a little trouble in math, And forgot to bring my textbook home. So The question is: The circumference of a circle is 56cm. What is the radius of the circle? If you could just show me the formulas or how to do the question, I'd be GREAT! Thanks again, Katie J.
Asked by Katie J - Sun Nov 16 19:03:29 2008 - - 5 Answers - 0 Comments
A. The first answerer gave you Pi r squared, which is to find the AREA of the circle. the 2pi(r) is the correct formula.
Answered by Novafury - Wed Nov 19 23:29:57 2008
Q. Okay, I am having a little trouble in math, And forgot to bring my textbook home. So The question is: The circumference of a circle is 56cm. What is the radius of the circle? If you could just show me the formulas or how to do the question, I'd be GREAT! Thanks again, Katie J.
Asked by Katie J - Sun Nov 16 19:03:29 2008 - - 5 Answers - 0 Comments
A. The first answerer gave you Pi r squared, which is to find the AREA of the circle. the 2pi(r) is the correct formula.
Answered by Novafury - Wed Nov 19 23:29:57 2008
What is the exact radius of the large cirlce?
Q. Three mutually tangent circles of radius 1 unit are surrounded by a large cirle that is simultaniously tangent to all 3. What is the exact radius of the large cirlce?
Asked by someone - Tue Oct 28 21:17:25 2008 - - 1 Answers - 0 Comments
A. A 30-60-90 triangle is formed when you connect the center of the large circle to the center of a small circle A, to the tangeant point of the small circle A to one of it's neighboring circles. The hypotenuse X of this 30-60-90 triangle is the distance between the center of the small circle A, to the center of the large circle, and can be calculated: cos(30) = 1/X x = 1/cos(30) = 1.1547 Now add the radius of the small circle A to get the radius R of the large circle: R = 1.1547 + 1 = 2.1547 or if you need the "exact" radius of the large circle, it would be: R = 1/cos(30) + 1
Answered by ourotheremailaccount - Wed Oct 29 01:37:33 2008
Q. Three mutually tangent circles of radius 1 unit are surrounded by a large cirle that is simultaniously tangent to all 3. What is the exact radius of the large cirlce?
Asked by someone - Tue Oct 28 21:17:25 2008 - - 1 Answers - 0 Comments
A. A 30-60-90 triangle is formed when you connect the center of the large circle to the center of a small circle A, to the tangeant point of the small circle A to one of it's neighboring circles. The hypotenuse X of this 30-60-90 triangle is the distance between the center of the small circle A, to the center of the large circle, and can be calculated: cos(30) = 1/X x = 1/cos(30) = 1.1547 Now add the radius of the small circle A to get the radius R of the large circle: R = 1.1547 + 1 = 2.1547 or if you need the "exact" radius of the large circle, it would be: R = 1/cos(30) + 1
Answered by ourotheremailaccount - Wed Oct 29 01:37:33 2008
How to find the radius of a sphere inscribed in a cone ?
Q. When all you know is the radius and height of the cone ? help me please! Radius is 7, height is 24 .
Asked by gutta - Tue Feb 24 11:26:55 2009 - - 2 Answers - 0 Comments
A. Well, draw the cone as seen from the front - it's a triangle, then calculate the center of the circle inscribed in it - the intersection of the angle bisectors, then measure the length from the center to any of the sides of the triangles, that is your radius.
Answered by taurenthew - Tue Feb 24 11:37:46 2009
Q. When all you know is the radius and height of the cone ? help me please! Radius is 7, height is 24 .
Asked by gutta - Tue Feb 24 11:26:55 2009 - - 2 Answers - 0 Comments
A. Well, draw the cone as seen from the front - it's a triangle, then calculate the center of the circle inscribed in it - the intersection of the angle bisectors, then measure the length from the center to any of the sides of the triangles, that is your radius.
Answered by taurenthew - Tue Feb 24 11:37:46 2009
How do i find gravity given a radius and an altitude?
Q. Using g = m/r^2? What is the acceleration due to gravity at an altitude of 1.00 x 10^6 above the earth's surface, given that the radius of the earth is 6.38 x 10^6 m? How do i go about solving that?
Asked by Voldemort - Thu Dec 20 21:07:38 2007 - - 2 Answers - 1 Comments
A. Let's try this: First: Fg = GMm/r^2 So, if you are only changing r then write Fg1 = GMm/r1^2. Now write Fg1 / Fg2 = GMm/r1^2 divided by GMm/r2^2 Canceling gives Fg1 / Fg2 = r2^2/r1^2 Um ... you can do the same thing with g, since g = Fg/m .: g1/g2 = r2^2/r1^2 (you can work it out using the same procedure as in the previous paragraph. Maybe I should just have started with this, but I am figuring it out as I type). Since you know g1 = 9.81/m/s/s and r1=6.38E6 and r2=1.00E6 + r1 (you MUST add the earth's radius to the altitude. ALWAYS do this anytime you see the code word ALTITUDE), you know all of the variables in the equation except for g2 --- which is what you are trying to find.
Answered by mk_gecko - Thu Dec 20 21:23:21 2007
Q. Using g = m/r^2? What is the acceleration due to gravity at an altitude of 1.00 x 10^6 above the earth's surface, given that the radius of the earth is 6.38 x 10^6 m? How do i go about solving that?
Asked by Voldemort - Thu Dec 20 21:07:38 2007 - - 2 Answers - 1 Comments
A. Let's try this: First: Fg = GMm/r^2 So, if you are only changing r then write Fg1 = GMm/r1^2. Now write Fg1 / Fg2 = GMm/r1^2 divided by GMm/r2^2 Canceling gives Fg1 / Fg2 = r2^2/r1^2 Um ... you can do the same thing with g, since g = Fg/m .: g1/g2 = r2^2/r1^2 (you can work it out using the same procedure as in the previous paragraph. Maybe I should just have started with this, but I am figuring it out as I type). Since you know g1 = 9.81/m/s/s and r1=6.38E6 and r2=1.00E6 + r1 (you MUST add the earth's radius to the altitude. ALWAYS do this anytime you see the code word ALTITUDE), you know all of the variables in the equation except for g2 --- which is what you are trying to find.
Answered by mk_gecko - Thu Dec 20 21:23:21 2007
Physics: What is the ratio of the radius of the plunger to the radius of the piston?
Q. A dentist's chair with a patient in it weighs 2020 N. The output plunger of a hydraulic system begins to lift the chair, when the dentist's foot applies a force of 47.6 N to the input piston. Neglect any height difference between the plunger and the piston. What is the ratio of the radius of the plunger to the radius of the piston?
Asked by Eunice C - Tue Jul 10 17:13:59 2007 - - 2 Answers - 0 Comments
A. Well as a French guy named Pascal said, the pressure in a closed system is the same throughout, and we know that p=F/A and therefore F1/A1=F2/A2. Also, A=(pi)R^2 F1/F2=A1/A2 => F1/F2 = (pi)(R1)^2/(pi)(R2)^2 = (R1/R2)^2 R1/R2 = sqrt(F1/F2) = sqrt(2020/47.6) = 6.5, so the output plunger has a radius more than 6.5 times greater than the input piston.
Answered by P.S. - Tue Jul 10 18:59:02 2007
Q. A dentist's chair with a patient in it weighs 2020 N. The output plunger of a hydraulic system begins to lift the chair, when the dentist's foot applies a force of 47.6 N to the input piston. Neglect any height difference between the plunger and the piston. What is the ratio of the radius of the plunger to the radius of the piston?
Asked by Eunice C - Tue Jul 10 17:13:59 2007 - - 2 Answers - 0 Comments
A. Well as a French guy named Pascal said, the pressure in a closed system is the same throughout, and we know that p=F/A and therefore F1/A1=F2/A2. Also, A=(pi)R^2 F1/F2=A1/A2 => F1/F2 = (pi)(R1)^2/(pi)(R2)^2 = (R1/R2)^2 R1/R2 = sqrt(F1/F2) = sqrt(2020/47.6) = 6.5, so the output plunger has a radius more than 6.5 times greater than the input piston.
Answered by P.S. - Tue Jul 10 18:59:02 2007
What is the offical name for the critical radius in which rings can form a moon?
Q. I think it's called the Rouch radius. Anything within the Rouch radius will fall back to a planet but anything at the rouch radius will form a moon. Can someone please confirm my postulate? joylin You're not even answerings my damn question, quit copying stuff from wikipedia and posting it as answers!
Asked by Phillip - Sat Apr 21 01:49:15 2007 - - 3 Answers - 0 Comments
A. It's called the Roche limit. (Check the spelling; I've always seen it as "Roche" since I first an across the term 40 years ago.) A planet can actually have a moon within the Roche limit because Roche (after whom it's named) assumed that the materials forming the moon had no tensile strength but were held together by their gravitational attraction. He then calculated how close the moon would have to be to its primary for the tidal forces of the primary to prevail over the gravitational attraction of the moon's matter. He then expressed the limit in terms of the radius of the primary. There is no constant Roche limit as the size and denisty of the primary affect where the Roche limit is. A planet can have a small moon within its Roche… [cont.]
Answered by Isaac Laquedem - Sat Apr 21 02:58:14 2007
Q. I think it's called the Rouch radius. Anything within the Rouch radius will fall back to a planet but anything at the rouch radius will form a moon. Can someone please confirm my postulate? joylin You're not even answerings my damn question, quit copying stuff from wikipedia and posting it as answers!
Asked by Phillip - Sat Apr 21 01:49:15 2007 - - 3 Answers - 0 Comments
A. It's called the Roche limit. (Check the spelling; I've always seen it as "Roche" since I first an across the term 40 years ago.) A planet can actually have a moon within the Roche limit because Roche (after whom it's named) assumed that the materials forming the moon had no tensile strength but were held together by their gravitational attraction. He then calculated how close the moon would have to be to its primary for the tidal forces of the primary to prevail over the gravitational attraction of the moon's matter. He then expressed the limit in terms of the radius of the primary. There is no constant Roche limit as the size and denisty of the primary affect where the Roche limit is. A planet can have a small moon within its Roche… [cont.]
Answered by Isaac Laquedem - Sat Apr 21 02:58:14 2007
What is the radius of curvature of the mirror?
Q. When viewed in a convex mirror, the image of a setting sun is a virtual image. The image lies 12.0 cm behind the mirror. what is the radius of curvature of the mirror?
Asked by heffa - Mon Jun 29 15:17:45 2009 - - 2 Answers - 0 Comments
Q. When viewed in a convex mirror, the image of a setting sun is a virtual image. The image lies 12.0 cm behind the mirror. what is the radius of curvature of the mirror?
Asked by heffa - Mon Jun 29 15:17:45 2009 - - 2 Answers - 0 Comments
How fast is the rippled area increasing when the radius is 35cm and increasing at a rate of 9cm/sec?
Q. A stone is dropped into a pool causing the ripples to expand outward from the point of impact. How fast is the rippled area increasing when the radius is 35cm and increasing at a rate of 9cm/sec? Can you help me to understand how to use the chain rule with this question?
Asked by Udo - Thu Jul 2 17:03:29 2009 - - 4 Answers - 0 Comments
A. radius is increasing at 9cm/sec ie dR/dt = 9cm/sec area of the rippled region is: A = pi * R * R we need to find dA/dt when R = 35cm A = pi * R^2 differentiate both sides with respect to 't' left side is simply dA/dt to differentiate right side, we use the chain rule we use, dF/dt = dF/dR * dR/dt here F = pi * R^2 thus right hand side of equation is pi * (2R) * dR/dt so we now have dA/dt = pi * 2R * dR/dt dA/dt = 22/7 * 2 * 35 * 9 (assuming pi = 22/7 approx) dA/dt = 22 * 2 * 5 * 9 = 1980 cm^2 / sec
Answered by antidisestablishmentarianist - Thu Jul 2 17:21:52 2009
Q. A stone is dropped into a pool causing the ripples to expand outward from the point of impact. How fast is the rippled area increasing when the radius is 35cm and increasing at a rate of 9cm/sec? Can you help me to understand how to use the chain rule with this question?
Asked by Udo - Thu Jul 2 17:03:29 2009 - - 4 Answers - 0 Comments
A. radius is increasing at 9cm/sec ie dR/dt = 9cm/sec area of the rippled region is: A = pi * R * R we need to find dA/dt when R = 35cm A = pi * R^2 differentiate both sides with respect to 't' left side is simply dA/dt to differentiate right side, we use the chain rule we use, dF/dt = dF/dR * dR/dt here F = pi * R^2 thus right hand side of equation is pi * (2R) * dR/dt so we now have dA/dt = pi * 2R * dR/dt dA/dt = 22/7 * 2 * 35 * 9 (assuming pi = 22/7 approx) dA/dt = 22 * 2 * 5 * 9 = 1980 cm^2 / sec
Answered by antidisestablishmentarianist - Thu Jul 2 17:21:52 2009
What is the relationship between velocity and radius in central motion?
Q. for a physics lab, we whirled a ball on a string above our heads in circular motion, keeping the mass weighing down the string constant, but changing the radius per each trial. the results show that as radius increases, velocity increases? is that correct, or is the relationship supposed to be inverse? please answer asap!! thank you!
Asked by Nura - Sun Nov 15 13:13:57 2009 - - 0 Answers - 0 Comments
Q. for a physics lab, we whirled a ball on a string above our heads in circular motion, keeping the mass weighing down the string constant, but changing the radius per each trial. the results show that as radius increases, velocity increases? is that correct, or is the relationship supposed to be inverse? please answer asap!! thank you!
Asked by Nura - Sun Nov 15 13:13:57 2009 - - 0 Answers - 0 Comments
How do you find radius when given volume for a sphere?
Q. How do you find radius when given volume for a sphere?
Asked by ZVXO - Thu Sep 10 20:07:04 2009 - - 12 Answers - 0 Comments
A. The volume of a sphere is (4/3) * pi * (r^3), where r is the radius. So if you are given volume (v) you can reverse the formula. v = (4/3) * pi * (r^3) v * (3/4) = pi * (r^3) (v / pi) * (3/4) = r^3 take the cube root of both sides, and you'll have r. ~ Megan
Answered by unknown - Thu Sep 10 20:12:20 2009
Q. How do you find radius when given volume for a sphere?
Asked by ZVXO - Thu Sep 10 20:07:04 2009 - - 12 Answers - 0 Comments
A. The volume of a sphere is (4/3) * pi * (r^3), where r is the radius. So if you are given volume (v) you can reverse the formula. v = (4/3) * pi * (r^3) v * (3/4) = pi * (r^3) (v / pi) * (3/4) = r^3 take the cube root of both sides, and you'll have r. ~ Megan
Answered by unknown - Thu Sep 10 20:12:20 2009
What's the fretboard radius on an Epiphone LP-100 Les Paul guitar?
Q. I can't find the fretboard radius info on Epiphone's website or any of the online dealers I've looked at.
Asked by wulfgyr - Tue Mar 4 10:32:30 2008 - - 2 Answers - 0 Comments
A. Me neither. I think you're going to have to contact Epiphone for the answer on this one. They probably don't mention it as it's the bottom of the line. Sorry. Kabum
Answered by unknown - Tue Mar 4 11:01:11 2008
Q. I can't find the fretboard radius info on Epiphone's website or any of the online dealers I've looked at.
Asked by wulfgyr - Tue Mar 4 10:32:30 2008 - - 2 Answers - 0 Comments
A. Me neither. I think you're going to have to contact Epiphone for the answer on this one. They probably don't mention it as it's the bottom of the line. Sorry. Kabum
Answered by unknown - Tue Mar 4 11:01:11 2008
How do u determine which one has the greater ionic radius between 2 or more elements?
Q. How do u determine the ionic radius. When u explain this please explain this in terms a 9th grader understands, because im a 9th grader taking chemistry.
Asked by Babii90sBabii - Tue Nov 4 13:44:27 2008 - - 1 Answers - 0 Comments
A. Simple: The trend for both atomic and ionic radii is that they increase as you move left and down on the periodic table, thus Francium has the highest and Helium has the lowest. Since it's high school I doubt the teacher will give you a question with any of the few exceptions.
Answered by HomicidalDonut - Wed Nov 5 22:17:13 2008
Q. How do u determine the ionic radius. When u explain this please explain this in terms a 9th grader understands, because im a 9th grader taking chemistry.
Asked by Babii90sBabii - Tue Nov 4 13:44:27 2008 - - 1 Answers - 0 Comments
A. Simple: The trend for both atomic and ionic radii is that they increase as you move left and down on the periodic table, thus Francium has the highest and Helium has the lowest. Since it's high school I doubt the teacher will give you a question with any of the few exceptions.
Answered by HomicidalDonut - Wed Nov 5 22:17:13 2008
Why does the atomic radius of transition elements change very little?
Q. Here is the question on my homework. "State a hypothesis to explain why the atomic radius of the transition elements changes very little on your graph (clue the d-orbital is involved)" I've tried google and wikipedia and nothing has helped so hopefully someone here can help me. Thanks.
Asked by scott m - Mon Nov 2 21:56:43 2009 - - 1 Answers - 0 Comments
A. the 'additional' electron for each successive element enters the the inner 3d sub shell where it provides a more effective shield between the nucleus and the outer 4s sub shell. hence, although each successive nucleus has one more proton, the extra positive charge is partly shielded by the extra electron in an underlying 3d sub shell.
Answered by unknown - Mon Nov 2 22:05:17 2009
Q. Here is the question on my homework. "State a hypothesis to explain why the atomic radius of the transition elements changes very little on your graph (clue the d-orbital is involved)" I've tried google and wikipedia and nothing has helped so hopefully someone here can help me. Thanks.
Asked by scott m - Mon Nov 2 21:56:43 2009 - - 1 Answers - 0 Comments
A. the 'additional' electron for each successive element enters the the inner 3d sub shell where it provides a more effective shield between the nucleus and the outer 4s sub shell. hence, although each successive nucleus has one more proton, the extra positive charge is partly shielded by the extra electron in an underlying 3d sub shell.
Answered by unknown - Mon Nov 2 22:05:17 2009
What is circumference of a circle of radius r drawn on hyperbolic plane?
Q. 360 ants sit on the rim of merry-go-round at equal angular separations 1 degree from each other. The merry-go-round is set in rapid rotation, each ant moving at speed v=0.8 speed of light. Then there is a circle of radius r = artanh(v) drawn on hyperbolic plane of unit negative curvature. What is lenght of circumference of the circle of radius r?
Asked by Garrett H - Mon Apr 28 13:49:45 2008 - - 1 Answers - 0 Comments
A. Where is your younger brother Alexander when we need him? Or maybe your first cousin Zo Maar? There are some interesting relativistic aspects to this problem -- but you put it in math and I don't know how to do hyperbolic planes. *** But if this relates to relativity, I'll bet the answer is either 1.2 pi or 3.333 pi.
Answered by Frst Grade Rocks! - Mon Apr 28 19:09:13 2008
Q. 360 ants sit on the rim of merry-go-round at equal angular separations 1 degree from each other. The merry-go-round is set in rapid rotation, each ant moving at speed v=0.8 speed of light. Then there is a circle of radius r = artanh(v) drawn on hyperbolic plane of unit negative curvature. What is lenght of circumference of the circle of radius r?
Asked by Garrett H - Mon Apr 28 13:49:45 2008 - - 1 Answers - 0 Comments
A. Where is your younger brother Alexander when we need him? Or maybe your first cousin Zo Maar? There are some interesting relativistic aspects to this problem -- but you put it in math and I don't know how to do hyperbolic planes. *** But if this relates to relativity, I'll bet the answer is either 1.2 pi or 3.333 pi.
Answered by Frst Grade Rocks! - Mon Apr 28 19:09:13 2008
What is the effect on the volume of a right cylinder if its radius is tripled?
Q. Ok so there's the question: What is the effect on the volume of a right cylinder if its radius is tripled? 10 points for best answer! I'M desperate please! :] What is the effect on the volume of a right cylinder if its radius is tripled?
Asked by ~ily~ - Mon Feb 2 22:47:17 2009 - - 1 Answers - 0 Comments
A. To calculate the volume you multiply the Base by the Height. Say the radius is 5cm and the height is 20cm 5x20 = 100cm cubed However if the radius is tripled it would become 15cm so change the equation to 15x20 = 300 cm cubed
Answered by Nick M - Mon Feb 2 23:01:13 2009
Q. Ok so there's the question: What is the effect on the volume of a right cylinder if its radius is tripled? 10 points for best answer! I'M desperate please! :] What is the effect on the volume of a right cylinder if its radius is tripled?
Asked by ~ily~ - Mon Feb 2 22:47:17 2009 - - 1 Answers - 0 Comments
A. To calculate the volume you multiply the Base by the Height. Say the radius is 5cm and the height is 20cm 5x20 = 100cm cubed However if the radius is tripled it would become 15cm so change the equation to 15x20 = 300 cm cubed
Answered by Nick M - Mon Feb 2 23:01:13 2009
How do you know which is the inner and outer radius?
Q. In disk integration and finding volumes by revolution, how do you know which is the inner and outer radius?
Asked by Joe B - Wed Apr 15 19:08:20 2009 - - 1 Answers - 0 Comments
A. without a specific problem to illustrate, just remember that the equation that defines the outside of the rotational object is the outer radius, and the equation the defines the inside is the inner radius. when you compute the volume integral, it's INT{ pi*(outer^2 - inner^2)}
Answered by unknown - Thu Apr 16 01:26:30 2009
Q. In disk integration and finding volumes by revolution, how do you know which is the inner and outer radius?
Asked by Joe B - Wed Apr 15 19:08:20 2009 - - 1 Answers - 0 Comments
A. without a specific problem to illustrate, just remember that the equation that defines the outside of the rotational object is the outer radius, and the equation the defines the inside is the inner radius. when you compute the volume integral, it's INT{ pi*(outer^2 - inner^2)}
Answered by unknown - Thu Apr 16 01:26:30 2009
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