RATIONAL EXPRESSIONS!!!!?????
Q. i really newed help!!! what are the steps to solving rational expressions by multiplying
Asked by Sammy - Tue Jun 9 20:23:01 2009 - - 2 Answers - 0 Comments
A. If it's an equation with rational expressions, you can multiply through by the common denominator. FACTOR first so you can determine the LCD. If it's NOT an equation, you need to get a common denominator the same way, but cannot multiply through. Just treat them like regular fractions -- combine numerators once you have a common denominator. that's it! ;) ~~~ if you'd give an example, it'd be easier to help you ~~~
Answered by Marley K - Tue Jun 9 20:31:16 2009
Q. i really newed help!!! what are the steps to solving rational expressions by multiplying
Asked by Sammy - Tue Jun 9 20:23:01 2009 - - 2 Answers - 0 Comments
A. If it's an equation with rational expressions, you can multiply through by the common denominator. FACTOR first so you can determine the LCD. If it's NOT an equation, you need to get a common denominator the same way, but cannot multiply through. Just treat them like regular fractions -- combine numerators once you have a common denominator. that's it! ;) ~~~ if you'd give an example, it'd be easier to help you ~~~
Answered by Marley K - Tue Jun 9 20:31:16 2009
What do you find challenging about working with rational expressions?
Q. What do you find challenging about working with rational expressions? What strategies do you develop to overcome these challenges?
Asked by George F - Thu Oct 12 22:27:24 2006 - - 3 Answers - 0 Comments
A. For my students, it is remembering not to cancel part of something that is added or subtracted, i.e. something that is not a factor; strategy is for me to tell them several times every day and show them why it doesn't work until they are sick of hearing me say it.
Answered by hayharbr - Thu Oct 12 22:37:48 2006
Q. What do you find challenging about working with rational expressions? What strategies do you develop to overcome these challenges?
Asked by George F - Thu Oct 12 22:27:24 2006 - - 3 Answers - 0 Comments
A. For my students, it is remembering not to cancel part of something that is added or subtracted, i.e. something that is not a factor; strategy is for me to tell them several times every day and show them why it doesn't work until they are sick of hearing me say it.
Answered by hayharbr - Thu Oct 12 22:37:48 2006
How would I multiply these rational expressions and show my steps?
Q. The first one is: Numerator: 6x^5y^3 Denominator: 5z^3 The Second: Numerator: 6x^4 Denominator: 5yz^4 How would I multiply these rational expressions and show my steps? Thank you!
Asked by C S - Mon Aug 18 12:23:16 2008 - - 2 Answers - 0 Comments
A. Wow, your questions look identical in style to the ones "G H" posted, who coincidentally has less than 10 points. You wouldn't happen to be registering multiple accounts, would you? Anyway, I just showed you how to do these types of problems less than 5 minutes ago:
Answered by Geezah - Mon Aug 18 12:28:20 2008
Q. The first one is: Numerator: 6x^5y^3 Denominator: 5z^3 The Second: Numerator: 6x^4 Denominator: 5yz^4 How would I multiply these rational expressions and show my steps? Thank you!
Asked by C S - Mon Aug 18 12:23:16 2008 - - 2 Answers - 0 Comments
A. Wow, your questions look identical in style to the ones "G H" posted, who coincidentally has less than 10 points. You wouldn't happen to be registering multiple accounts, would you? Anyway, I just showed you how to do these types of problems less than 5 minutes ago:
Answered by Geezah - Mon Aug 18 12:28:20 2008
math-When solving an equation containing rational expressions, it is permissible to remove the?
Q. When solving an equation containing rational expressions, it is permissible to remove the denominator by multiplying both sides of the equation by the LCD. Can we do the same when trying to simplify a rational expression by itself?
Asked by Patricia F - Tue Aug 28 20:48:42 2007 - - 1 Answers - 0 Comments
A. Dear Patricia, When simplifying equation, apart from multiplying both sides, you can also dividing both sides, adding both sides, substracting both sides, powering both sides by the power of 2,3,.. n root both sides (like squareroot, cuberoot, etc.) with the same numbers or variables or equations. Hope this helps. Kind regard, Ryonn
Answered by Mr. Math Contributor - Fri Aug 31 12:37:51 2007
Q. When solving an equation containing rational expressions, it is permissible to remove the denominator by multiplying both sides of the equation by the LCD. Can we do the same when trying to simplify a rational expression by itself?
Asked by Patricia F - Tue Aug 28 20:48:42 2007 - - 1 Answers - 0 Comments
A. Dear Patricia, When simplifying equation, apart from multiplying both sides, you can also dividing both sides, adding both sides, substracting both sides, powering both sides by the power of 2,3,.. n root both sides (like squareroot, cuberoot, etc.) with the same numbers or variables or equations. Hope this helps. Kind regard, Ryonn
Answered by Mr. Math Contributor - Fri Aug 31 12:37:51 2007
Reflect on what you have learned about rational expressions and their applications.?
Q. Consider how you might apply rational expressions to your daily life. Explain this application, and discuss what the equation might be. Did the study of these types of equations help you to understand the application better.
Asked by No Name - Mon Jan 21 22:05:34 2008 - - 1 Answers - 0 Comments
A. Obviously you haven't studied these types of equations. Do your own homework!
Answered by Hate the liars and the Lies - Thu Jan 24 09:51:28 2008
Q. Consider how you might apply rational expressions to your daily life. Explain this application, and discuss what the equation might be. Did the study of these types of equations help you to understand the application better.
Asked by No Name - Mon Jan 21 22:05:34 2008 - - 1 Answers - 0 Comments
A. Obviously you haven't studied these types of equations. Do your own homework!
Answered by Hate the liars and the Lies - Thu Jan 24 09:51:28 2008
Easy way to add/subtract rational expressions with different denominators?
Q. I desperately need an easy or somewhat easy way to add/subtract rational expressions with different denominators!! I just can't seem to figure it out. Can someone please help me? Thanks a billion =)
Asked by Mandy - Sat Nov 14 11:02:27 2009 - - 2 Answers - 0 Comments
A. The only way is to find common denominators. But you can use a shortcut if there are only two fractions involved. Multiply across and use these products as numerators. Multiply the denominators and use this as the denominator. Add the two numerators, and put over the common denominator. Reduce the answer if possible (and with this shortcut, it is usually possible). That is : If you need to find the sum of 3/2 and 1/6 : Do 3 * 6 for one numerator Do 2 * 1 for the other The denominator is 2 * 6 So this is 18 + 2 over 12 or 20/12 But you can reduce this by dividing both by 4 to get the answer in lowest terms : or 5/3 To do the sum of 1/(x) + 4/(5x) : Do 1 * 5x for one numerator Do x * 4 for the other The denominator is 5x * x So this is 5x… [cont.]
Answered by Don E Knows - Sat Nov 14 11:45:27 2009
Q. I desperately need an easy or somewhat easy way to add/subtract rational expressions with different denominators!! I just can't seem to figure it out. Can someone please help me? Thanks a billion =)
Asked by Mandy - Sat Nov 14 11:02:27 2009 - - 2 Answers - 0 Comments
A. The only way is to find common denominators. But you can use a shortcut if there are only two fractions involved. Multiply across and use these products as numerators. Multiply the denominators and use this as the denominator. Add the two numerators, and put over the common denominator. Reduce the answer if possible (and with this shortcut, it is usually possible). That is : If you need to find the sum of 3/2 and 1/6 : Do 3 * 6 for one numerator Do 2 * 1 for the other The denominator is 2 * 6 So this is 18 + 2 over 12 or 20/12 But you can reduce this by dividing both by 4 to get the answer in lowest terms : or 5/3 To do the sum of 1/(x) + 4/(5x) : Do 1 * 5x for one numerator Do x * 4 for the other The denominator is 5x * x So this is 5x… [cont.]
Answered by Don E Knows - Sat Nov 14 11:45:27 2009
can someone answer my question about dividing two rational expressions?
Q. Do you only multiply the numerators by the LCD everytime, or do you have to ever multiply the denominators by the LCD , in dividing two rational expressions?
Asked by Elisha B - Sat Apr 11 21:28:01 2009 - - 1 Answers - 0 Comments
A. You always multply the numerators by the LCD, with the intention of canceling out all denominators, making resulting calculations simpler. Even in this small example: x/2 + x/5 = 2 Multiply everything by the LCD like we did in your other one with the trinomial denominator: LCD is 10: 5x + 2x = 20 7x = 20 x = 20/7
Answered by llaffer - Sat Apr 11 22:11:55 2009
Q. Do you only multiply the numerators by the LCD everytime, or do you have to ever multiply the denominators by the LCD , in dividing two rational expressions?
Asked by Elisha B - Sat Apr 11 21:28:01 2009 - - 1 Answers - 0 Comments
A. You always multply the numerators by the LCD, with the intention of canceling out all denominators, making resulting calculations simpler. Even in this small example: x/2 + x/5 = 2 Multiply everything by the LCD like we did in your other one with the trinomial denominator: LCD is 10: 5x + 2x = 20 7x = 20 x = 20/7
Answered by llaffer - Sat Apr 11 22:11:55 2009
Equations with Rational Expressions in the Real World?
Q. Hi all. Need help with the following question: Come up with a real-world example from your work or personal life of using an equation with a rational expression to solve a real-world problem. Please give the example, setup the problem, then solve it, explaining your steps.
Asked by onecpudr - Tue Mar 18 12:26:04 2008 - - 2 Answers - 1 Comments
A. You have an amplifier with impedance R (this number can be found in the specifications printed in the instruction manual). You want to buy speakers which will give you the loudest possible volume. What should be the impedance of the speakers in order to maximize the power output across the speakers? (impedance is like "resistance", but for AC circuits) If E = the voltage out of your wall outlet (120 volts in most US outlets) I= the current flowing through the system R = impedance of the amplifier x = impedance of the speakers then Ohm's law says E = I (R + x) or I = E/(R + x) Power across the speakers is given by P = x I^2 = x E^2/(R + x)^2 the question is, for given values of E and R, what value of x will maximize the value of P.… [cont.]
Answered by Michael M - Tue Mar 18 13:06:39 2008
Q. Hi all. Need help with the following question: Come up with a real-world example from your work or personal life of using an equation with a rational expression to solve a real-world problem. Please give the example, setup the problem, then solve it, explaining your steps.
Asked by onecpudr - Tue Mar 18 12:26:04 2008 - - 2 Answers - 1 Comments
A. You have an amplifier with impedance R (this number can be found in the specifications printed in the instruction manual). You want to buy speakers which will give you the loudest possible volume. What should be the impedance of the speakers in order to maximize the power output across the speakers? (impedance is like "resistance", but for AC circuits) If E = the voltage out of your wall outlet (120 volts in most US outlets) I= the current flowing through the system R = impedance of the amplifier x = impedance of the speakers then Ohm's law says E = I (R + x) or I = E/(R + x) Power across the speakers is given by P = x I^2 = x E^2/(R + x)^2 the question is, for given values of E and R, what value of x will maximize the value of P.… [cont.]
Answered by Michael M - Tue Mar 18 13:06:39 2008
I need to find an online Rational Expressions calculator?
Q. A website that you can enter a problem and it will solve it for you?? it has to be a rational expression calculator- adding, subtracting, and multiplying. I don't want to graph it I just want the simplified answer.
Asked by yumm.bubblegum - Mon Dec 8 00:53:03 2008 - - 1 Answers - 0 Comments
A. He places your question in this powerful tool: I hope that it serves you, give yourself procedure and all that! Bye-bye and luck =).
Answered by unknown - Thu Dec 11 20:07:03 2008
Q. A website that you can enter a problem and it will solve it for you?? it has to be a rational expression calculator- adding, subtracting, and multiplying. I don't want to graph it I just want the simplified answer.
Asked by yumm.bubblegum - Mon Dec 8 00:53:03 2008 - - 1 Answers - 0 Comments
A. He places your question in this powerful tool: I hope that it serves you, give yourself procedure and all that! Bye-bye and luck =).
Answered by unknown - Thu Dec 11 20:07:03 2008
Rewrite these polynomials as rational expressions?
Q. Use the rule for the sum of the first "n" terms of a geometric series, write the following polynomials as a rational expressions. A. 1 + x + x^2 + x^3 +x^4 B. 3x + 6x^3 + 12x^5 + 24x^7 Please show as much of the work/process as is possible. Thank you!
Asked by metatextual - Thu Jan 22 14:38:12 2009 - - 1 Answers - 0 Comments
Q. Use the rule for the sum of the first "n" terms of a geometric series, write the following polynomials as a rational expressions. A. 1 + x + x^2 + x^3 +x^4 B. 3x + 6x^3 + 12x^5 + 24x^7 Please show as much of the work/process as is possible. Thank you!
Asked by metatextual - Thu Jan 22 14:38:12 2009 - - 1 Answers - 0 Comments
Math Homework- Could you give me problems for +,-,x,dividing and simplifying rational expressions?
Q. And the solution please? It's for rational expressions, I need a problem for each of the above with the answer and how you got there. (dividing, multiplying, simplifying, adding, and subtracting) Usually I do this work on my own, but the grading period ends soon and I need this project to help me pass the class, but I have no idea what on EARTH I'm doing! Help Please, and thank you all for your answers
Asked by Topanga - Sun Nov 9 21:18:45 2008 - - 1 Answers - 0 Comments
A. Simplifying: 5(x+3)(x^2-4) --- = (factorize) 3(x+2)(x^2+x-6) 5(x+3)(x+2)(x-2) --- = (take out common factors) 3(x+2)(x+3)(x-2) answer: 5/3 multiplication: x^2-x-20 1-x --- * --- = (factorize) x-1 x+4 (x+4)(x-5) (1-x) --- * --- = (reduce if posible) (x-1) (x+4) -1*(x-5)= -x+5= answer: 5-x division: x^+5x+4 x^2-4 ---/ --- = x^2-2x-3 x^2-6x+8 x^2+5x+4 x^2-6x+8 --- / --- = (factorize) x^2-2x-3 x^2-4 (x+4)(x+1) *(x-4)(x-2) --- --- = (x-3)(x+1) (x+2)(x-2) (x+4)(x-4) --- = (x-3)(x+2) answer: x^-16 --- x^2-x-6 Addition: (same denominator) (8) ( 1) ( 8+1) ( 9) ( 3) --- + --- = --- = --- (reduce)= --- 3(X-2) 3(x-2) 3(X-2) 3(x-2) x-2 substraction: (same… [cont.]
Answered by sofilita - Tue Nov 11 15:50:23 2008
Q. And the solution please? It's for rational expressions, I need a problem for each of the above with the answer and how you got there. (dividing, multiplying, simplifying, adding, and subtracting) Usually I do this work on my own, but the grading period ends soon and I need this project to help me pass the class, but I have no idea what on EARTH I'm doing! Help Please, and thank you all for your answers
Asked by Topanga - Sun Nov 9 21:18:45 2008 - - 1 Answers - 0 Comments
A. Simplifying: 5(x+3)(x^2-4) --- = (factorize) 3(x+2)(x^2+x-6) 5(x+3)(x+2)(x-2) --- = (take out common factors) 3(x+2)(x+3)(x-2) answer: 5/3 multiplication: x^2-x-20 1-x --- * --- = (factorize) x-1 x+4 (x+4)(x-5) (1-x) --- * --- = (reduce if posible) (x-1) (x+4) -1*(x-5)= -x+5= answer: 5-x division: x^+5x+4 x^2-4 ---/ --- = x^2-2x-3 x^2-6x+8 x^2+5x+4 x^2-6x+8 --- / --- = (factorize) x^2-2x-3 x^2-4 (x+4)(x+1) *(x-4)(x-2) --- --- = (x-3)(x+1) (x+2)(x-2) (x+4)(x-4) --- = (x-3)(x+2) answer: x^-16 --- x^2-x-6 Addition: (same denominator) (8) ( 1) ( 8+1) ( 9) ( 3) --- + --- = --- = --- (reduce)= --- 3(X-2) 3(x-2) 3(X-2) 3(x-2) x-2 substraction: (same… [cont.]
Answered by sofilita - Tue Nov 11 15:50:23 2008
how do you solve rational expressions by adding and subtracting?
Q. i know how to solve rat. expressions by multiplying and dividing, but i dont get how to do it by adding and subtracting. i need to know for algebra and no one can explain it clearly to me. can anyone help?
Asked by miss moocows - Thu Jan 21 10:15:15 2010 - - 2 Answers - 0 Comments
A. Let's say that you have two fractions, 1/2 and 2/3, and you want to add and subtract them. In order to do so, you have to have a common denominator. The least common denominator is a good one to work with, but any common denominator will do. The least common multiple of 2 and 3 is 6. In order to change the denominator to six without affecting the value of the fraction, we need to multiply the fraction by some form of 1. For example, with 1/2, we want the denominator to be 6. 2 x 3 = 6, but if we just write 1/6, though, that changes the value of the fraction. So what we do is multiply the fraction by 1 in the form of 3/3. So (1/2) * (3/3) = (1 * 3)/(2 * 3) = 3/6 We do the same with 2/3. 3 * 2 = 6, so we multiply (2/3) * (2/2) = (2… [cont.]
Answered by TychaBrahe - Thu Jan 21 10:26:51 2010
Q. i know how to solve rat. expressions by multiplying and dividing, but i dont get how to do it by adding and subtracting. i need to know for algebra and no one can explain it clearly to me. can anyone help?
Asked by miss moocows - Thu Jan 21 10:15:15 2010 - - 2 Answers - 0 Comments
A. Let's say that you have two fractions, 1/2 and 2/3, and you want to add and subtract them. In order to do so, you have to have a common denominator. The least common denominator is a good one to work with, but any common denominator will do. The least common multiple of 2 and 3 is 6. In order to change the denominator to six without affecting the value of the fraction, we need to multiply the fraction by some form of 1. For example, with 1/2, we want the denominator to be 6. 2 x 3 = 6, but if we just write 1/6, though, that changes the value of the fraction. So what we do is multiply the fraction by 1 in the form of 3/3. So (1/2) * (3/3) = (1 * 3)/(2 * 3) = 3/6 We do the same with 2/3. 3 * 2 = 6, so we multiply (2/3) * (2/2) = (2… [cont.]
Answered by TychaBrahe - Thu Jan 21 10:26:51 2010
How to multiply rational expressions?
Q. Does anybody have a good link for explaining how to multiply rational expressions. Or, if you could pop up an example and explain how to do it. I just don't get it. Thanks for all the help!!
Asked by Silencer_Krusty - Mon Dec 28 21:38:21 2009 - - 1 Answers - 0 Comments
A. See the link above to get the hang of multiplying rational expressions.
Answered by su u uo p - Mon Dec 28 21:42:27 2009
Q. Does anybody have a good link for explaining how to multiply rational expressions. Or, if you could pop up an example and explain how to do it. I just don't get it. Thanks for all the help!!
Asked by Silencer_Krusty - Mon Dec 28 21:38:21 2009 - - 1 Answers - 0 Comments
A. See the link above to get the hang of multiplying rational expressions.
Answered by su u uo p - Mon Dec 28 21:42:27 2009
Algebra help on rational expressions maybe easy to some but I need help please?
Q. 1 List all numbers for which the rational expression is undefined. 4/b+7 #2 Multiply and, if possible, simplify. 9x^4y/2 = 4x^3/6y^2 #3 Multiply and, if possible, simplify. 2x+2/x+2 = 3x^2 + 12x + 12/x^2-1
Asked by Jackie - Wed Feb 17 20:53:23 2010 - - 0 Answers - 0 Comments
Q. 1 List all numbers for which the rational expression is undefined. 4/b+7 #2 Multiply and, if possible, simplify. 9x^4y/2 = 4x^3/6y^2 #3 Multiply and, if possible, simplify. 2x+2/x+2 = 3x^2 + 12x + 12/x^2-1
Asked by Jackie - Wed Feb 17 20:53:23 2010 - - 0 Answers - 0 Comments
Will you please help solving 2 rational expressions?
Q. Please help me with these 2 problems, i understand the rest of the rational expression chapter except these. Please help, thanks. -Solve the equation(s). Check for extraneous solutions in orginal equation. (i think i did that part right but please tell me if i did it wrong) 1) (z/z-2) - (1/z+5) = (7/z^2+3z-10) Extraneous solutions= 2, -5 2) (a+4)/2 = (a+4)/a no extraneous solutions... right?!? thanks again.
Asked by ahjd2007 - Wed Jan 30 05:20:04 2008 - - 1 Answers - 0 Comments
A. Multiply thro` by (z - 2)(z + 5): z(z + 5) - (z - 2) = 7 z^2 + 5z - z + 2 = 7 z^2 + 4z -5 = 0 (z + 5)(z - 1) = 0 z = -5 or z = 1 The only acceptable solution is z = 1. (a + 4)/2 = (a + 4)/a...multiply through by 2a: a(a + 4) = 2(a + 4) a^2 + 4a = 2a + 8 a^2 + 2a - 8 = 0 (a + 4)(a - 2) = 0 a = -4, or a = 2. If a = 0, (a + 4)/a is undefined. You seem confused about these ext solns. they occur in (1) because when x = 2, z/z-2 = z/0, which is undefined. Same with z = -5.
Answered by Twiggy - Wed Jan 30 05:38:32 2008
Q. Please help me with these 2 problems, i understand the rest of the rational expression chapter except these. Please help, thanks. -Solve the equation(s). Check for extraneous solutions in orginal equation. (i think i did that part right but please tell me if i did it wrong) 1) (z/z-2) - (1/z+5) = (7/z^2+3z-10) Extraneous solutions= 2, -5 2) (a+4)/2 = (a+4)/a no extraneous solutions... right?!? thanks again.
Asked by ahjd2007 - Wed Jan 30 05:20:04 2008 - - 1 Answers - 0 Comments
A. Multiply thro` by (z - 2)(z + 5): z(z + 5) - (z - 2) = 7 z^2 + 5z - z + 2 = 7 z^2 + 4z -5 = 0 (z + 5)(z - 1) = 0 z = -5 or z = 1 The only acceptable solution is z = 1. (a + 4)/2 = (a + 4)/a...multiply through by 2a: a(a + 4) = 2(a + 4) a^2 + 4a = 2a + 8 a^2 + 2a - 8 = 0 (a + 4)(a - 2) = 0 a = -4, or a = 2. If a = 0, (a + 4)/a is undefined. You seem confused about these ext solns. they occur in (1) because when x = 2, z/z-2 = z/0, which is undefined. Same with z = -5.
Answered by Twiggy - Wed Jan 30 05:38:32 2008
How do I use rational expressions to solve this problem?
Q. One machine can do a job in 5 hours alone. How many hours would it take a second machine to complete the job alone if both machines together can do the job in 3 hours?
Asked by tk3078 - Thu May 7 16:19:54 2009 - - 2 Answers - 0 Comments
A. Take the sum of the time worked together divided by time for each machine to do the job alone, and set it equal to 1: 3/5 + 3/x = 1 Solve for x: 3/x = 1 - 3/5 = 2/5 x/3 = 5/2 (Invert the fractions on each side; it's just easier): x = (5)(3)/2 = 15/2 = 7.5 hrs for the 2nd machine alone
Answered by Mike - Thu May 7 16:30:28 2009
Q. One machine can do a job in 5 hours alone. How many hours would it take a second machine to complete the job alone if both machines together can do the job in 3 hours?
Asked by tk3078 - Thu May 7 16:19:54 2009 - - 2 Answers - 0 Comments
A. Take the sum of the time worked together divided by time for each machine to do the job alone, and set it equal to 1: 3/5 + 3/x = 1 Solve for x: 3/x = 1 - 3/5 = 2/5 x/3 = 5/2 (Invert the fractions on each side; it's just easier): x = (5)(3)/2 = 15/2 = 7.5 hrs for the 2nd machine alone
Answered by Mike - Thu May 7 16:30:28 2009
How to simplify rational expressions when using square root of fractions 64 3/4?
Q. How do you simplify without a calculator, as on tests we do have too show our work.
Asked by KM - Mon Oct 12 08:17:12 2009 - - 1 Answers - 0 Comments
A. Rational expressions just used square root? Gimme a break...
Answered by Luke - Mon Oct 12 08:25:04 2009
Q. How do you simplify without a calculator, as on tests we do have too show our work.
Asked by KM - Mon Oct 12 08:17:12 2009 - - 1 Answers - 0 Comments
A. Rational expressions just used square root? Gimme a break...
Answered by Luke - Mon Oct 12 08:25:04 2009
How can I add and subtract Rational Expressions Need Help Please!?
Q. 1) 20 /c-2 - 20/2-c Subtraction of rational expressions 2) 3/v-5 + 4/(v-5)^2
Asked by missbe - Sun Jan 17 15:10:59 2010 - - 2 Answers - 0 Comments
Q. 1) 20 /c-2 - 20/2-c Subtraction of rational expressions 2) 3/v-5 + 4/(v-5)^2
Asked by missbe - Sun Jan 17 15:10:59 2010 - - 2 Answers - 0 Comments
simplifying rational expressions and multiply and divide of rational expressions?
Q. Need help asap with 2 problems. The first one is simplifying and that is 3x^2-6x-72/2x^2-8x-64? and this one is multiplying and dividing of rational expressions. 24x^3z^2/6y divided by 8xz^4/3y^4 need step by step so that I can finish my homework myself. thanks in advance.
Asked by conchitadavis - Wed Nov 12 10:44:06 2008 - - 2 Answers - 0 Comments
Q. Need help asap with 2 problems. The first one is simplifying and that is 3x^2-6x-72/2x^2-8x-64? and this one is multiplying and dividing of rational expressions. 24x^3z^2/6y divided by 8xz^4/3y^4 need step by step so that I can finish my homework myself. thanks in advance.
Asked by conchitadavis - Wed Nov 12 10:44:06 2008 - - 2 Answers - 0 Comments
Is there an expert out there to help with Radicals and Rational expressions?
Q. I have a review coming up for college math and I need a little help with it...
Asked by ice_berg_ant - Sat Nov 29 13:14:45 2008 - - 1 Answers - 0 Comments
A. Well I am in my final year of advanced actuarial studies and I majored in maths9042 back in the day in Australia is all about radicals, rational expressions etc. so just send me an email if you need help with something; will be working for my finals for the next few days so it may take a while to get back to u
Answered by AeternusVeritas - Mon Dec 1 04:31:27 2008
Q. I have a review coming up for college math and I need a little help with it...
Asked by ice_berg_ant - Sat Nov 29 13:14:45 2008 - - 1 Answers - 0 Comments
A. Well I am in my final year of advanced actuarial studies and I majored in maths9042 back in the day in Australia is all about radicals, rational expressions etc. so just send me an email if you need help with something; will be working for my finals for the next few days so it may take a while to get back to u
Answered by AeternusVeritas - Mon Dec 1 04:31:27 2008
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