AC supply what does reactive power in ac supply liberate?
Q. In AC supply there are real power and reactive power. Real power is consumed by heat meaning it liberate heat.Now my question is what does Reactive Power consume(liberate)?
Asked by alienx - Fri Aug 29 06:00:46 2008 - - 3 Answers - 0 Comments
A. Reactive power does not 'liberate' (transform) energy. Reactive power is the way in how electricity change from and electrical current into space distributed fields. You must remember that electricity in composed from electromagnetic field; the electric field is 'accumulated' in capacitors, and the magnetic field is accumulated in a coil. When you applied and AC current, some of the electricity would be store in the capacitor, as and electric field, and some in a coil, as a magnetic field, as long as current flows. When current cease the fields will return as currents into the circuit. This 'things' depends on capacitors and coils value, as well as AC frequencies, and is the base for telecommunications and signal processing. The… [cont.]
Answered by oapg2 - Fri Aug 29 06:23:40 2008
Q. In AC supply there are real power and reactive power. Real power is consumed by heat meaning it liberate heat.Now my question is what does Reactive Power consume(liberate)?
Asked by alienx - Fri Aug 29 06:00:46 2008 - - 3 Answers - 0 Comments
A. Reactive power does not 'liberate' (transform) energy. Reactive power is the way in how electricity change from and electrical current into space distributed fields. You must remember that electricity in composed from electromagnetic field; the electric field is 'accumulated' in capacitors, and the magnetic field is accumulated in a coil. When you applied and AC current, some of the electricity would be store in the capacitor, as and electric field, and some in a coil, as a magnetic field, as long as current flows. When current cease the fields will return as currents into the circuit. This 'things' depends on capacitors and coils value, as well as AC frequencies, and is the base for telecommunications and signal processing. The… [cont.]
Answered by oapg2 - Fri Aug 29 06:23:40 2008
Where does the reactive power go ?
Q. Power factor of an electrical circuit is the ratio of resistance to the impedance of the circuit. The reactive power is lost. My question is where does the reactive power go ?
Asked by i_oliver7 - Sat Feb 14 13:41:22 2009 - - 3 Answers - 0 Comments
A. Reactive power is not 'lost'. It is delivered to the motor where it sustains the electric field that enables the motor to convert the real power (electrical) into mechanical torque.
Answered by monophoto - Sat Feb 14 14:32:24 2009
Q. Power factor of an electrical circuit is the ratio of resistance to the impedance of the circuit. The reactive power is lost. My question is where does the reactive power go ?
Asked by i_oliver7 - Sat Feb 14 13:41:22 2009 - - 3 Answers - 0 Comments
A. Reactive power is not 'lost'. It is delivered to the motor where it sustains the electric field that enables the motor to convert the real power (electrical) into mechanical torque.
Answered by monophoto - Sat Feb 14 14:32:24 2009
what is the practical difference between apparent power and reactive power?
Q. what is the practical difference between apparent power and reactive power?
Asked by sujay s - Wed Jun 25 07:53:03 2008 - - 1 Answers - 0 Comments
A. Engineers use the following terms to describe energy flow in a system (and assign each of them a different unit to differentiate between them): Real power (P) [Unit: W - Watt] Reactive power (Q) [Unit: VAR - Volt-Ampere Reactive] Complex power (S) [Unit: VA - Volt-Ampere] Apparent Power (|S|) [Unit: VA]: i.e. the absolute value of complex power S. Ohms = Unit for Resistance. Resistance is something found in every wire, basically, it resists the flow of current on a circuit. Voltage = Difference in Electric Potential between two points. Basically, a Potential difference between two points will induce a current flow. A battery has different potential in both of it's terminals, so that's why you use batteries in circuits. Amps = Unit for… [cont.]
Answered by Dr.Shashikant - Fri Jun 27 22:08:40 2008
Q. what is the practical difference between apparent power and reactive power?
Asked by sujay s - Wed Jun 25 07:53:03 2008 - - 1 Answers - 0 Comments
A. Engineers use the following terms to describe energy flow in a system (and assign each of them a different unit to differentiate between them): Real power (P) [Unit: W - Watt] Reactive power (Q) [Unit: VAR - Volt-Ampere Reactive] Complex power (S) [Unit: VA - Volt-Ampere] Apparent Power (|S|) [Unit: VA]: i.e. the absolute value of complex power S. Ohms = Unit for Resistance. Resistance is something found in every wire, basically, it resists the flow of current on a circuit. Voltage = Difference in Electric Potential between two points. Basically, a Potential difference between two points will induce a current flow. A battery has different potential in both of it's terminals, so that's why you use batteries in circuits. Amps = Unit for… [cont.]
Answered by Dr.Shashikant - Fri Jun 27 22:08:40 2008
Why doesn't reactive power travel very far?
Q. We all know reactive power does not travel very far but why? Can you please explain it with forumlas and words?
Asked by Jack - Mon May 11 11:46:32 2009 - - 1 Answers - 0 Comments
A. Since power is a measure of the rate of energy transfer or conversion, the concept of power traveling does not seem very meaningful. Reactive power defines the rate at which energy circulates back and forth between the source and the load. It describes the flow of energy which is accumulated and stored by the source during one half of the AC energy flow waveform and returned to the source during the following half cycle. Unless the energy is stored in capacitors at some intermediate point, the energy travels back and forth between the power generating station and the load.
Answered by Retired EE - Mon May 11 14:30:30 2009
Q. We all know reactive power does not travel very far but why? Can you please explain it with forumlas and words?
Asked by Jack - Mon May 11 11:46:32 2009 - - 1 Answers - 0 Comments
A. Since power is a measure of the rate of energy transfer or conversion, the concept of power traveling does not seem very meaningful. Reactive power defines the rate at which energy circulates back and forth between the source and the load. It describes the flow of energy which is accumulated and stored by the source during one half of the AC energy flow waveform and returned to the source during the following half cycle. Unless the energy is stored in capacitors at some intermediate point, the energy travels back and forth between the power generating station and the load.
Answered by Retired EE - Mon May 11 14:30:30 2009
what is difference between active power and reactive power?
Q. what is difference between active power and reactive power?
Asked by sujay s - Fri Dec 19 23:06:43 2008 - - 6 Answers - 0 Comments
A. While reactive power may be the 'imaginary' part of your complex power, that is just for mathematical purposes; reactive power is a real concept and while it's hard to define it, there's a few ways to think of it. What you want out of the system - what causes machines to operate - is real power, P. But in order to get that, you have to compensate for, or overcome, the reactive power of the system; in this way, it is like an efficiency. Try this: draw two sinusoidal waves, one for current and one for voltage. Normally, we say power, P, has the equation: P = VI This is only for systems where there is no reactive power, Q. Q arises when there is a phase difference between V and I (meaning that the waveforms do not line up - ). When you… [cont.]
Answered by TheAnswerMyFriend - Sat Dec 20 00:01:42 2008
Q. what is difference between active power and reactive power?
Asked by sujay s - Fri Dec 19 23:06:43 2008 - - 6 Answers - 0 Comments
A. While reactive power may be the 'imaginary' part of your complex power, that is just for mathematical purposes; reactive power is a real concept and while it's hard to define it, there's a few ways to think of it. What you want out of the system - what causes machines to operate - is real power, P. But in order to get that, you have to compensate for, or overcome, the reactive power of the system; in this way, it is like an efficiency. Try this: draw two sinusoidal waves, one for current and one for voltage. Normally, we say power, P, has the equation: P = VI This is only for systems where there is no reactive power, Q. Q arises when there is a phase difference between V and I (meaning that the waveforms do not line up - ). When you… [cont.]
Answered by TheAnswerMyFriend - Sat Dec 20 00:01:42 2008
What is reactive power?
Q. I'm struggling to understand reactive power and the role it plays in AC generation, distribution, transmission and ultimately consumption. Please help!
Asked by woppers83 - Wed Aug 5 04:18:29 2009 - - 1 Answers - 0 Comments
Q. I'm struggling to understand reactive power and the role it plays in AC generation, distribution, transmission and ultimately consumption. Please help!
Asked by woppers83 - Wed Aug 5 04:18:29 2009 - - 1 Answers - 0 Comments
i need a bowling ball with medium reaction-between a brunswick power groove reactive and a black widow bite?
Q. i have a black widow bite as my normal strike ball and a power groove reactive as a spare ball...i need something in between the two to use as my strike ball when the lanes are dry and my black widow hooks too much
Asked by ty93 - Fri Jan 16 23:40:21 2009 - - 1 Answers - 0 Comments
A. I have the same situation with my Brunswick Red Zone and Hammer Black Widow Venom... In between, I use the Elite Black Label or Elite Gold Label, which work fine when the lanes break down or start out drier than usual. Also, my "arsenal" of medium hooking balls are as follows: Brunswick Smokin' Inferno Brunswick Smash Zone Storm T-Road Pearl Hammer Cherry Vibe Hope this helps! Also check out bowling.com, bowlingball.com, bowlersparadise.com for further information on hook ratings and bowling equipment. Good luck!
Answered by Michael M - Tue Jan 20 12:07:03 2009
Q. i have a black widow bite as my normal strike ball and a power groove reactive as a spare ball...i need something in between the two to use as my strike ball when the lanes are dry and my black widow hooks too much
Asked by ty93 - Fri Jan 16 23:40:21 2009 - - 1 Answers - 0 Comments
A. I have the same situation with my Brunswick Red Zone and Hammer Black Widow Venom... In between, I use the Elite Black Label or Elite Gold Label, which work fine when the lanes break down or start out drier than usual. Also, my "arsenal" of medium hooking balls are as follows: Brunswick Smokin' Inferno Brunswick Smash Zone Storm T-Road Pearl Hammer Cherry Vibe Hope this helps! Also check out bowling.com, bowlingball.com, bowlersparadise.com for further information on hook ratings and bowling equipment. Good luck!
Answered by Michael M - Tue Jan 20 12:07:03 2009
do residential electric meters also measure the reactive power in the incoming current?
Q. reactive power in a current is useless energy that will never be used, if it is also measured by the meter isn't that cheating the consumer since only real power is used from the electrical current
Asked by John A - Wed Dec 20 02:12:36 2006 - - 3 Answers - 1 Comments
A. Reactive power is useless power? Oh boy! Care to revise that statement? Reactive power is just as important as real power. Reactive power provides the energy for coils, motors, transformers, and supporting the electrical transmission and distribution system. Here's an analogy to help you understand what reactive power is... How do you move a wheelbarrow full of dirt? You pick it up first and then move it right? Imagine the wheelbarrow as the electrical system, with load from houses/etc, and you are the electrical power or generator. Reactive power is the power needed to first pick up the wheelbarrow. Even if you don't move, reactive power is still being used to hold the wheelbarrow up in the air. If you decide to move forward,… [cont.]
Answered by digitaldog88 - Wed Dec 20 06:55:48 2006
Q. reactive power in a current is useless energy that will never be used, if it is also measured by the meter isn't that cheating the consumer since only real power is used from the electrical current
Asked by John A - Wed Dec 20 02:12:36 2006 - - 3 Answers - 1 Comments
A. Reactive power is useless power? Oh boy! Care to revise that statement? Reactive power is just as important as real power. Reactive power provides the energy for coils, motors, transformers, and supporting the electrical transmission and distribution system. Here's an analogy to help you understand what reactive power is... How do you move a wheelbarrow full of dirt? You pick it up first and then move it right? Imagine the wheelbarrow as the electrical system, with load from houses/etc, and you are the electrical power or generator. Reactive power is the power needed to first pick up the wheelbarrow. Even if you don't move, reactive power is still being used to hold the wheelbarrow up in the air. If you decide to move forward,… [cont.]
Answered by digitaldog88 - Wed Dec 20 06:55:48 2006
how can we calculate reactive power supplied by a capacitor?
Q. how can we calculate reactive power supplied by a capacitor?
Asked by Julfi - Sat Apr 4 01:43:25 2009 - - 1 Answers - 0 Comments
A. This web site gives the formulas and has an on-line calculator for determining the KVARs that a capacitor will provide: Capacitors used for power-factor-correction purposes are rated in KVAR already. This web site explains how to apply capacitors to correct the power factor. The example it uses is correcting the power factor of a motor, but the same principle applies for correcting other reactive loads as well: Hope that helps.
Answered by Violet W - Sun Apr 5 01:47:23 2009
Q. how can we calculate reactive power supplied by a capacitor?
Asked by Julfi - Sat Apr 4 01:43:25 2009 - - 1 Answers - 0 Comments
A. This web site gives the formulas and has an on-line calculator for determining the KVARs that a capacitor will provide: Capacitors used for power-factor-correction purposes are rated in KVAR already. This web site explains how to apply capacitors to correct the power factor. The example it uses is correcting the power factor of a motor, but the same principle applies for correcting other reactive loads as well: Hope that helps.
Answered by Violet W - Sun Apr 5 01:47:23 2009
reactive power (Q) is used for what?
Q. do anyone know reactive power (Q) is used for what?
Asked by yie - Fri Aug 1 11:10:07 2008 - - 3 Answers - 0 Comments
A. Reactive power is neccessary for the operation of electromagnetic devices such as AC motors, transformers and solenoids. Reactive power is the result of the magnetizing current in these devices.
Answered by Retired EE - Fri Aug 1 11:33:43 2008
Q. do anyone know reactive power (Q) is used for what?
Asked by yie - Fri Aug 1 11:10:07 2008 - - 3 Answers - 0 Comments
A. Reactive power is neccessary for the operation of electromagnetic devices such as AC motors, transformers and solenoids. Reactive power is the result of the magnetizing current in these devices.
Answered by Retired EE - Fri Aug 1 11:33:43 2008
wat is the diff between active,reactive,apparant power?
Q. wat is the diff between active,reactive,apparant power?
Asked by karthigeyan - Sat Apr 4 22:26:34 2009 - - 5 Answers - 0 Comments
Q. wat is the diff between active,reactive,apparant power?
Asked by karthigeyan - Sat Apr 4 22:26:34 2009 - - 5 Answers - 0 Comments
A motor wit a power factor of 0.8 absorbs an active power 1200W.Calculate the reactive power drawn from line?
Q. A motor wit a power factor of 0.8 absorbs an active power 1200W.Calculate the reactive power drawn from line?
Asked by K K - Thu Apr 17 01:36:24 2008 - - 3 Answers - 0 Comments
A. Power factor x Volts x Amperes = real power 0.8 x VI = 1200 watts of real power VI = 1200 / 0.8 = 1500 watts of apparent power Apparent power - real power = imaginary power(Reactive power) Reactive power =1500w - 1200 w = 300w
Answered by Mr. Un-couth - Thu Apr 17 02:20:27 2008
Q. A motor wit a power factor of 0.8 absorbs an active power 1200W.Calculate the reactive power drawn from line?
Asked by K K - Thu Apr 17 01:36:24 2008 - - 3 Answers - 0 Comments
A. Power factor x Volts x Amperes = real power 0.8 x VI = 1200 watts of real power VI = 1200 / 0.8 = 1500 watts of apparent power Apparent power - real power = imaginary power(Reactive power) Reactive power =1500w - 1200 w = 300w
Answered by Mr. Un-couth - Thu Apr 17 02:20:27 2008
Reactive power using Newtons third law?
Q. According to Newtons third law every action must have a equal and opposite reaction.so the active power being the action on a load,then reactive power produced by load is the reaction(is that right?),this reactive power is opposite to active power but not equal to active power so how is the Newtons third law satisfied.in the case of resistance there is no reactive power at all(here all the power i mention is AC)so what is the reaction for the action(power applied).
Asked by Hope C - Sat Aug 30 02:44:00 2008 - - 2 Answers - 0 Comments
Q. According to Newtons third law every action must have a equal and opposite reaction.so the active power being the action on a load,then reactive power produced by load is the reaction(is that right?),this reactive power is opposite to active power but not equal to active power so how is the Newtons third law satisfied.in the case of resistance there is no reactive power at all(here all the power i mention is AC)so what is the reaction for the action(power applied).
Asked by Hope C - Sat Aug 30 02:44:00 2008 - - 2 Answers - 0 Comments
Reactive Power Calculation?
Q. The following is a delta connected load, connected to a 3 phase 240V 60Hz supply. A-B coil - Z = 12ohm pf= .7 B-C coil - Z = 20 ohm pf = .8 C-A coil - Z = 24 ohm pf = .7 Calculate the reactive power of phase A Please show all workings, thanks
Asked by just101more - Tue Feb 10 21:02:33 2009 - - 2 Answers - 0 Comments
A. Resolve the impedances into j notation form. You need to use the 'a' operator for 3 phase systems. i.e. If the 3 phase voltage is V and you take phase AC as the reference voltage then phase BA will be displaced 120 degrees and phase BC by 240 degrees. 120 degrees = -1/2 +j(sq rt 3)/2 = a 240 degrees = -1/2 -j(sq rt3)/2 =a^2 in your example using Voltage Vac across phase A-C as the reference voltage V then Vba =a*Vac and Vbc =a^2 Vac So Iac=V/Zac = 240/(16.8+17.14) ands Iba = a*240/(8.4+j8.570 now add Iac and iba together in their j notation forms and you will have the current in line A giving the active and reactive parts.
Answered by ANDREW A - Fri Feb 13 16:34:26 2009
Q. The following is a delta connected load, connected to a 3 phase 240V 60Hz supply. A-B coil - Z = 12ohm pf= .7 B-C coil - Z = 20 ohm pf = .8 C-A coil - Z = 24 ohm pf = .7 Calculate the reactive power of phase A Please show all workings, thanks
Asked by just101more - Tue Feb 10 21:02:33 2009 - - 2 Answers - 0 Comments
A. Resolve the impedances into j notation form. You need to use the 'a' operator for 3 phase systems. i.e. If the 3 phase voltage is V and you take phase AC as the reference voltage then phase BA will be displaced 120 degrees and phase BC by 240 degrees. 120 degrees = -1/2 +j(sq rt 3)/2 = a 240 degrees = -1/2 -j(sq rt3)/2 =a^2 in your example using Voltage Vac across phase A-C as the reference voltage V then Vba =a*Vac and Vbc =a^2 Vac So Iac=V/Zac = 240/(16.8+17.14) ands Iba = a*240/(8.4+j8.570 now add Iac and iba together in their j notation forms and you will have the current in line A giving the active and reactive parts.
Answered by ANDREW A - Fri Feb 13 16:34:26 2009
what is the imp of reactive power in power system?
Q. there are active and reactive power in power system. active power supports the load and do the useful work then ehy we need reactive power
Asked by Er. vijay kumar - Thu Sep 21 08:25:11 2006 - - 2 Answers - 0 Comments
A. Optimum allocation of reactive power for voltage stability improvement in AC-DC power systems The dependence of the system voltage stability on reactive power distribution forms the basis for reactive power optimisation. The technique attempts to utilise fully the reactive power sources in the system to improve the voltage stability and profile as well as meeting the reactive power requirements at the AC-DC terminals to facilitate the smooth operation of DC links. The method involves successive solution of steady-state power flows and optimisation of reactive power control variables using linear programming techniques
Answered by resurrectionnnn - Thu Sep 21 08:47:20 2006
Q. there are active and reactive power in power system. active power supports the load and do the useful work then ehy we need reactive power
Asked by Er. vijay kumar - Thu Sep 21 08:25:11 2006 - - 2 Answers - 0 Comments
A. Optimum allocation of reactive power for voltage stability improvement in AC-DC power systems The dependence of the system voltage stability on reactive power distribution forms the basis for reactive power optimisation. The technique attempts to utilise fully the reactive power sources in the system to improve the voltage stability and profile as well as meeting the reactive power requirements at the AC-DC terminals to facilitate the smooth operation of DC links. The method involves successive solution of steady-state power flows and optimisation of reactive power control variables using linear programming techniques
Answered by resurrectionnnn - Thu Sep 21 08:47:20 2006
what exactly reactive power,active power and its effects on alternator operation?
Q. plz b more clear in ur ans
Asked by venkateswarulu v - Tue Oct 7 06:39:16 2008 - - 2 Answers - 0 Comments
A. Active power is that which performs real work. Reactive power is the oscillatory component that does not perform real work but does consume capacity in the electrical system. Reactive power is associated with capacitors and inductors in the AC system. Consider that the ac voltage and current waveforms can have any arbitrary phase relationship. Apparent power is simply the multiplication of current and voltage magnitudes. (For 3-phase circuits, a sqrt(3) gets into the mix depending on your choice of voltage measurements.) Active power is the real component of apparent power, due to the component of the current that is in phase (or anti-phase) with the voltage. Reactive power is the imaginary component of apparent power, due to the… [cont.]
Answered by Steve W - Tue Oct 7 08:49:48 2008
Q. plz b more clear in ur ans
Asked by venkateswarulu v - Tue Oct 7 06:39:16 2008 - - 2 Answers - 0 Comments
A. Active power is that which performs real work. Reactive power is the oscillatory component that does not perform real work but does consume capacity in the electrical system. Reactive power is associated with capacitors and inductors in the AC system. Consider that the ac voltage and current waveforms can have any arbitrary phase relationship. Apparent power is simply the multiplication of current and voltage magnitudes. (For 3-phase circuits, a sqrt(3) gets into the mix depending on your choice of voltage measurements.) Active power is the real component of apparent power, due to the component of the current that is in phase (or anti-phase) with the voltage. Reactive power is the imaginary component of apparent power, due to the… [cont.]
Answered by Steve W - Tue Oct 7 08:49:48 2008
How would i calculate the phase angle difference in two ends of a line as well as reactive power at both ends?
Q. Consider a transmission line rated at 138 kV and with a reactance of 80 per phase. The resistance of this line is neglected. When this line carries 120 MW, voltages of 140 kV and 130 kV are measured respectively at the sending and receiving ends. Calculate the phase angle difference between the two ends of the line as well as the reactive power flow at both ends. Sorry, it is 120MVA rather than 120MW.
Asked by TheDave - Sat Apr 4 08:49:18 2009 - - 1 Answers - 0 Comments
A. I had a look at this problem and conclude that, unless we are given either the MVA or the power factor at one end of the line, a unique solution is not possible. If you care to check your question or to comment on my conclusion, please edit the question and I will try to respond. For example - is the 120MW you give really that and not 120 MVA? EDIT : I looked at it again and I'm afraid it's still not really soluble. The current in the line at the receiving end is 533A which makes the voltage drop in the 80 ohm line inductance 42kV. This is the vector difference between two voltages whose difference in magnitude is only 10/sqrt3 = 5.77 kV. I cannot achieve this in a realistic circuit. The conclusion is that the 80 ohm is much too… [cont.]
Answered by Bramble - Sat Apr 4 23:59:21 2009
Q. Consider a transmission line rated at 138 kV and with a reactance of 80 per phase. The resistance of this line is neglected. When this line carries 120 MW, voltages of 140 kV and 130 kV are measured respectively at the sending and receiving ends. Calculate the phase angle difference between the two ends of the line as well as the reactive power flow at both ends. Sorry, it is 120MVA rather than 120MW.
Asked by TheDave - Sat Apr 4 08:49:18 2009 - - 1 Answers - 0 Comments
A. I had a look at this problem and conclude that, unless we are given either the MVA or the power factor at one end of the line, a unique solution is not possible. If you care to check your question or to comment on my conclusion, please edit the question and I will try to respond. For example - is the 120MW you give really that and not 120 MVA? EDIT : I looked at it again and I'm afraid it's still not really soluble. The current in the line at the receiving end is 533A which makes the voltage drop in the 80 ohm line inductance 42kV. This is the vector difference between two voltages whose difference in magnitude is only 10/sqrt3 = 5.77 kV. I cannot achieve this in a realistic circuit. The conclusion is that the 80 ohm is much too… [cont.]
Answered by Bramble - Sat Apr 4 23:59:21 2009
what is apparent power, real power and reactive power, how to derive the power triangle?
Q. what is apparent power, real power and reactive power, how to derive the power triangle?
Asked by lito - Thu Oct 5 17:50:04 2006 - - 2 Answers - 0 Comments
A. If you think of a graph, the x axis(horizontal) is the apparent power(resistive), the y axis is the reactive power (capacitve or inductive), the power factor is the cosine of the angle of real power which originates from 0 and goes across the horizontal as far as the apparent power, up the vertical as far as the reactive power at the angle previously mentioned, thus forming a right angled triangle. A bit difficult to explain without the aid of diagrams, but I've given it a shot. Hope this helps.
Answered by unknown - Thu Oct 5 22:39:45 2006
Q. what is apparent power, real power and reactive power, how to derive the power triangle?
Asked by lito - Thu Oct 5 17:50:04 2006 - - 2 Answers - 0 Comments
A. If you think of a graph, the x axis(horizontal) is the apparent power(resistive), the y axis is the reactive power (capacitve or inductive), the power factor is the cosine of the angle of real power which originates from 0 and goes across the horizontal as far as the apparent power, up the vertical as far as the reactive power at the angle previously mentioned, thus forming a right angled triangle. A bit difficult to explain without the aid of diagrams, but I've given it a shot. Hope this helps.
Answered by unknown - Thu Oct 5 22:39:45 2006
Loads that absorb active power and reactive power may be considered to be made up of what??
Q. num44
Asked by Circuiteer - Sun May 4 02:53:33 2008 - - 4 Answers - 0 Comments
A. Active power means used power which means that this power is consumed and transformed to another form of energy SO Active power means that there is a resistance (which is the case in all loads) so the resistance convert this power to heat Reactive power are (u can say) unusable power it goes back and forth between load and supply Reactive power means that there is an inductance and a capacitance in the load
Answered by No88oN - Sun May 4 02:59:59 2008
Q. num44
Asked by Circuiteer - Sun May 4 02:53:33 2008 - - 4 Answers - 0 Comments
A. Active power means used power which means that this power is consumed and transformed to another form of energy SO Active power means that there is a resistance (which is the case in all loads) so the resistance convert this power to heat Reactive power are (u can say) unusable power it goes back and forth between load and supply Reactive power means that there is an inductance and a capacitance in the load
Answered by No88oN - Sun May 4 02:59:59 2008
deferention of the reactive power with real power?
Q. deferention of the reactive power with real power?
Asked by mohammad_shah - Mon Jan 15 02:39:32 2007 - - 2 Answers - 0 Comments
A. Real power represents voltage in phase with current, and is real energy that the power company will charge you for. Reactive power is voltage ninety degrees out of phase with current; it can be either capacitive or inductive, depending on which is leading. Since there is no actual energy consumption, the power company can't bill you for it, but they will get irate if your load has significant reactive power, as that requires current which they aren't getting paid for. So, if you are running a steel mill with lots of big motors, and as a result have lots of inductive power, they may charge you extra.
Answered by rhsaunders - Mon Jan 15 02:52:04 2007
Q. deferention of the reactive power with real power?
Asked by mohammad_shah - Mon Jan 15 02:39:32 2007 - - 2 Answers - 0 Comments
A. Real power represents voltage in phase with current, and is real energy that the power company will charge you for. Reactive power is voltage ninety degrees out of phase with current; it can be either capacitive or inductive, depending on which is leading. Since there is no actual energy consumption, the power company can't bill you for it, but they will get irate if your load has significant reactive power, as that requires current which they aren't getting paid for. So, if you are running a steel mill with lots of big motors, and as a result have lots of inductive power, they may charge you extra.
Answered by rhsaunders - Mon Jan 15 02:52:04 2007
From Yahoo Answer Search: 'reactive power'
Sun Nov 15 05:31:28 2009 [ refresh local cache ]
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Chapter 2 : Centralised Reactive Power Compensation | Leonardo ENERGY
Isabelle Heriakian
Mon, 03 Nov 2008 14:55:25 GM
Practical Application of a Method for Determining Customer and Utility Harmonic Contributions, --- Reducing Heat in a Transformer and increasing its Loading Capacity, by decreasing the Percentage of Harmonics and . Reactive Power. ...
Isabelle Heriakian
Mon, 03 Nov 2008 14:55:25 GM
Practical Application of a Method for Determining Customer and Utility Harmonic Contributions, --- Reducing Heat in a Transformer and increasing its Loading Capacity, by decreasing the Percentage of Harmonics and . Reactive Power. ...
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