What is the molecular mass of the solute?
Q. The osmotic pressure of a solution containing 15.0 grams of a solute is 0.200 atm at 25 degrees Celsius. If the total volume of the solution is 1.00 liter, what is the molecular mass of the solute?
Asked by prosser22 - Mon Jan 14 19:30:43 2008 - - 1 Answers - 0 Comments
A. it is a tv dinner right ? oh well i guess i'll just have to settle for being a butcher ! have a great day !
Answered by Dameon - Mon Jan 14 19:40:09 2008
Q. The osmotic pressure of a solution containing 15.0 grams of a solute is 0.200 atm at 25 degrees Celsius. If the total volume of the solution is 1.00 liter, what is the molecular mass of the solute?
Asked by prosser22 - Mon Jan 14 19:30:43 2008 - - 1 Answers - 0 Comments
A. it is a tv dinner right ? oh well i guess i'll just have to settle for being a butcher ! have a great day !
Answered by Dameon - Mon Jan 14 19:40:09 2008
How would water's properties as a solute change if a stable water molecule were H3O rather than H2O?
Q. A) This would have no effect on the properties of water as a solute. B) Water molecules would become more polar and dissolve solutes faster. C) Water molecules would become less polar and lose the ability to dissolve solutes. D) More hydrogen bonds would form, preventing water from interacting with solutes.
Asked by Ricky R - Thu Mar 6 18:04:36 2008 - - 3 Answers - 1 Comments
A. If I assume that H3O should be a neutral molecule with full octet, that would make H3O similar to NH3. However, O is more electronegative than N, so the O-H bonds should be more polar than N-H bonds. I would then guess that H3O would be more polar than NH3, but probably somewhat less polar than H2O. Whar more: You will have three H that could for H-bonds, but only one electron pair to bind to. Hence the total number og H-bonds in water would be reduced, which would reduce the meltig and boling points, as in NH3.
Answered by coco - Sat Mar 8 14:17:11 2008
Q. A) This would have no effect on the properties of water as a solute. B) Water molecules would become more polar and dissolve solutes faster. C) Water molecules would become less polar and lose the ability to dissolve solutes. D) More hydrogen bonds would form, preventing water from interacting with solutes.
Asked by Ricky R - Thu Mar 6 18:04:36 2008 - - 3 Answers - 1 Comments
A. If I assume that H3O should be a neutral molecule with full octet, that would make H3O similar to NH3. However, O is more electronegative than N, so the O-H bonds should be more polar than N-H bonds. I would then guess that H3O would be more polar than NH3, but probably somewhat less polar than H2O. Whar more: You will have three H that could for H-bonds, but only one electron pair to bind to. Hence the total number og H-bonds in water would be reduced, which would reduce the meltig and boling points, as in NH3.
Answered by coco - Sat Mar 8 14:17:11 2008
What effect would nonvolatile solute have on the vapor pressure of a solution?
Q. a) What effect would a nonvolatile solute have on the freezing point? b) what effect would a nonvolatile solute have on the boiling point?
Asked by Etro K - Mon Jul 6 15:41:02 2009 - - 3 Answers - 0 Comments
A. Chem Team is correct. A nonvolatile solute will not interact with the solvent whatsoever chemically, making it only have pure colligative properties. To freeze water, crystals form between the water molecules to form the solid called ice, but if there are molecules inbetween the water molecules, a lower temperature is required to freeze the solution, because the solute particles get in the way! Boiling Point: In order for water to boil, its vapor pressure must equal the atmospheric pressure (1 atm near sea level), but again if there are solute particles in the way, the vapor pushing up through the water hits the particles and gets trapped in a way, therefore the water only boils at a much higher temperature. Hope this helps
Answered by John T - Mon Jul 6 15:56:53 2009
Q. a) What effect would a nonvolatile solute have on the freezing point? b) what effect would a nonvolatile solute have on the boiling point?
Asked by Etro K - Mon Jul 6 15:41:02 2009 - - 3 Answers - 0 Comments
A. Chem Team is correct. A nonvolatile solute will not interact with the solvent whatsoever chemically, making it only have pure colligative properties. To freeze water, crystals form between the water molecules to form the solid called ice, but if there are molecules inbetween the water molecules, a lower temperature is required to freeze the solution, because the solute particles get in the way! Boiling Point: In order for water to boil, its vapor pressure must equal the atmospheric pressure (1 atm near sea level), but again if there are solute particles in the way, the vapor pushing up through the water hits the particles and gets trapped in a way, therefore the water only boils at a much higher temperature. Hope this helps
Answered by John T - Mon Jul 6 15:56:53 2009
What does it mean to say that a solution is saturated with a solute?
Q. (Select all that apply.) 1) A solution contains the maximum amount of solvent possible at a particular temperature. 2)A solute that is at equilibrium with undissolved solvent. 3)A solute without any bonding twists in its molecules. 4)A saturated solution is one that is at equilibrium with undissolved solute. 5)A solute that is at equilibrium with solvent. 6)A solution contains the maximum amount of solute possible at a particular temperature. 7)A solvent that is at equilibrium with solute. 8)A solvent without any bonding twists in its molecules.
Asked by ejonas - Tue Mar 24 22:13:14 2009 - - 1 Answers - 0 Comments
Q. (Select all that apply.) 1) A solution contains the maximum amount of solvent possible at a particular temperature. 2)A solute that is at equilibrium with undissolved solvent. 3)A solute without any bonding twists in its molecules. 4)A saturated solution is one that is at equilibrium with undissolved solute. 5)A solute that is at equilibrium with solvent. 6)A solution contains the maximum amount of solute possible at a particular temperature. 7)A solvent that is at equilibrium with solute. 8)A solvent without any bonding twists in its molecules.
Asked by ejonas - Tue Mar 24 22:13:14 2009 - - 1 Answers - 0 Comments
Does the rate of stirring and the size of solute particles affect solubility ability?
Q. And a second question. Does the rate of stirring and the size of solute particles affect the rate of dissolving?
Asked by Siew M - Sat Jul 19 10:30:07 2008 - - 3 Answers - 0 Comments
A. Yes
Answered by samgibz - Mon Jul 21 08:53:55 2008
Q. And a second question. Does the rate of stirring and the size of solute particles affect the rate of dissolving?
Asked by Siew M - Sat Jul 19 10:30:07 2008 - - 3 Answers - 0 Comments
A. Yes
Answered by samgibz - Mon Jul 21 08:53:55 2008
What is the molecular weight of the solute?
Q. The vapor pressure of benzene at 30oC is 121.8 torr. If 10.0 grams of a non-volatile solute dissolved in 100.0 grams of benzene lowers the vapor pressure 8.8 torr, what is the molecular weight of the solute?
Asked by Dr. Bodivine - Fri Feb 9 23:10:11 2007 - - 1 Answers - 0 Comments
A. Use Raoult's Law to get the mole fraction of the solute, then the moles of solute. From there, it's all downhill...divide the grams (10.0) by the moles to get the molecular weight.
Answered by rb42redsuns - Sat Feb 10 00:29:29 2007
Q. The vapor pressure of benzene at 30oC is 121.8 torr. If 10.0 grams of a non-volatile solute dissolved in 100.0 grams of benzene lowers the vapor pressure 8.8 torr, what is the molecular weight of the solute?
Asked by Dr. Bodivine - Fri Feb 9 23:10:11 2007 - - 1 Answers - 0 Comments
A. Use Raoult's Law to get the mole fraction of the solute, then the moles of solute. From there, it's all downhill...divide the grams (10.0) by the moles to get the molecular weight.
Answered by rb42redsuns - Sat Feb 10 00:29:29 2007
What is the molarity of the resulting solution assuming that all of the solute dissolves?
Q. Trisodium phosphate, Na3PO4, is sold over the counter for use in households as a cleaning agent and a degreaser. You make a solution of trisodium phosphate by mixing 243 g of Na3PO4 in 2.00 L of water in a beaker. What is the molarity of the resulting solution assuming that all of the solute dissolves? Explain please
Asked by Dina - Wed Jan 23 02:04:46 2008 - - 1 Answers - 0 Comments
A. Mr of Na3PO4 = 3(23) + 31 + 4(16) = 148g That means 1 mol of Na3PO4 weights 148g Therefore 243g is 1.642 mol. 1.642mol dissolved in 2L of water means 0.821 mol is dissolved in 1L of water, giving the molarity 0.821M.
Answered by eugenics23 - Wed Jan 23 03:33:57 2008
Q. Trisodium phosphate, Na3PO4, is sold over the counter for use in households as a cleaning agent and a degreaser. You make a solution of trisodium phosphate by mixing 243 g of Na3PO4 in 2.00 L of water in a beaker. What is the molarity of the resulting solution assuming that all of the solute dissolves? Explain please
Asked by Dina - Wed Jan 23 02:04:46 2008 - - 1 Answers - 0 Comments
A. Mr of Na3PO4 = 3(23) + 31 + 4(16) = 148g That means 1 mol of Na3PO4 weights 148g Therefore 243g is 1.642 mol. 1.642mol dissolved in 2L of water means 0.821 mol is dissolved in 1L of water, giving the molarity 0.821M.
Answered by eugenics23 - Wed Jan 23 03:33:57 2008
What is the solute and solvent of 5% Benzaldehyde solution?
Q. What is the solute and solvent of 5% Benzaldehyde solution?
Asked by choco - Wed Mar 4 07:53:56 2009 - - 2 Answers - 0 Comments
A. I began to answer this question earlier and gave up. Unfortunately benzaldehyde does not dissolve sufficiently in water to enable you to make a solution 5g benzaldehyde and 95g water. I did not proceed further because I could not find a solvent for benzaldehyde, except possibly an ethylene glycol. However if you want a general answer, the 5% (5g) benzaldehyde would be the solute and the 95%(95g) solvent (whatever it is), would be the solvent
Answered by Trevor H - Wed Mar 4 13:30:38 2009
Q. What is the solute and solvent of 5% Benzaldehyde solution?
Asked by choco - Wed Mar 4 07:53:56 2009 - - 2 Answers - 0 Comments
A. I began to answer this question earlier and gave up. Unfortunately benzaldehyde does not dissolve sufficiently in water to enable you to make a solution 5g benzaldehyde and 95g water. I did not proceed further because I could not find a solvent for benzaldehyde, except possibly an ethylene glycol. However if you want a general answer, the 5% (5g) benzaldehyde would be the solute and the 95%(95g) solvent (whatever it is), would be the solvent
Answered by Trevor H - Wed Mar 4 13:30:38 2009
How to find the molecular mass of a solute?
Q. 3.9 grams of a covalent substance is added to 475 grams of water. The freezing point of the water lowers by 0.39 degrees celcius. calculate the molecular mass of the solute.
Asked by babs - Sun May 20 21:39:42 2007 - - 1 Answers - 0 Comments
A. Find the Kf of water. The change in temp is .39 .39 = Kf times molal. Use that to solve for molal (moles of solute over kg of solvent. Convert 475 g to kg by dividing by 1,000. molal (you solved for) = moles/.475 molar mass = grams/moles = 3.9/the moles you just found.
Answered by chemmie - Sun May 20 21:44:52 2007
Q. 3.9 grams of a covalent substance is added to 475 grams of water. The freezing point of the water lowers by 0.39 degrees celcius. calculate the molecular mass of the solute.
Asked by babs - Sun May 20 21:39:42 2007 - - 1 Answers - 0 Comments
A. Find the Kf of water. The change in temp is .39 .39 = Kf times molal. Use that to solve for molal (moles of solute over kg of solvent. Convert 475 g to kg by dividing by 1,000. molal (you solved for) = moles/.475 molar mass = grams/moles = 3.9/the moles you just found.
Answered by chemmie - Sun May 20 21:44:52 2007
How is the high solute concentration of the inner renal medulla maintained?
Q. a. part of the collecting duct is permeable to urea allowing for its release into the medulla b. ions released in the loop of the nephron keep solute concentrations high c. ions released in the collecting duct keep solute concentration high d. urea released in the loop of the nephron keep solute concentration high e. part of collecting duct is permeable to sodium allowing for its release into the medulla
Asked by doglover0876 - Sun Dec 14 20:10:52 2008 - - 1 Answers - 0 Comments
A. I believe it is b. By the process of elimination. a. The whole point is to get rid of urea. Urea is actually secreted in the kidney. b. yes, this is where the magic happens. c. no, just water here. d. again, urea is secreted in the kidney, this is kind of a fundamental principle. e. NaCl is released but not sodium.
Answered by The Lazer - Thu Dec 18 11:58:12 2008
Q. a. part of the collecting duct is permeable to urea allowing for its release into the medulla b. ions released in the loop of the nephron keep solute concentrations high c. ions released in the collecting duct keep solute concentration high d. urea released in the loop of the nephron keep solute concentration high e. part of collecting duct is permeable to sodium allowing for its release into the medulla
Asked by doglover0876 - Sun Dec 14 20:10:52 2008 - - 1 Answers - 0 Comments
A. I believe it is b. By the process of elimination. a. The whole point is to get rid of urea. Urea is actually secreted in the kidney. b. yes, this is where the magic happens. c. no, just water here. d. again, urea is secreted in the kidney, this is kind of a fundamental principle. e. NaCl is released but not sodium.
Answered by The Lazer - Thu Dec 18 11:58:12 2008
What is the mole fraction of the solute?
Q. The partial pressure of water above a solution of water and a nonvolatile solute at 25oC is 18.6 mm Hg. What is the mole fraction of the solute?
Asked by coral - Thu Feb 12 00:46:13 2009 - - 1 Answers - 0 Comments
A. The vapor pressure of water at 25 C = 23.756 mm Hg The mole fraction of water is 18.6/23.756 = 0.783 The mole fraction of solute is 0.217 (1.000-0.783)
Answered by skipper - Thu Feb 12 00:52:23 2009
Q. The partial pressure of water above a solution of water and a nonvolatile solute at 25oC is 18.6 mm Hg. What is the mole fraction of the solute?
Asked by coral - Thu Feb 12 00:46:13 2009 - - 1 Answers - 0 Comments
A. The vapor pressure of water at 25 C = 23.756 mm Hg The mole fraction of water is 18.6/23.756 = 0.783 The mole fraction of solute is 0.217 (1.000-0.783)
Answered by skipper - Thu Feb 12 00:52:23 2009
Is it good practice to add the solute to the solvent instead of vice versa?
Q. Why not add the solute first, then the solvent? Wouldn't the solute go into solution faster that way? I'm aware that when dealing with acid dilutions, the acid should be added to the water, because otherwise the high initial acid concentrations can cause extreme heat and sometimes explosions (when dealing with certain acids). But apart from that (and apart from any other dangerous reactions), is there any general rule which governs reagent addition order?
Asked by kvr_neous - Thu Apr 27 23:23:12 2006 - - 2 Answers - 0 Comments
A. As you mentioned it is true in case of acids.. Add Acids to water but not the other way... (AA---Add Acid) To my knowledge there is no particular convention for solute to dissolve in solvent. Except fo hygroscopic solutes( absorbs atmospheric water), for which it is better to take them first and add water (since it will absorb water, it may effect the final volume if you mix vice versa. Except for hygroscopic solutes, theres no particular convention is this info helpful?
Answered by murthy - Thu Apr 27 23:28:50 2006
Q. Why not add the solute first, then the solvent? Wouldn't the solute go into solution faster that way? I'm aware that when dealing with acid dilutions, the acid should be added to the water, because otherwise the high initial acid concentrations can cause extreme heat and sometimes explosions (when dealing with certain acids). But apart from that (and apart from any other dangerous reactions), is there any general rule which governs reagent addition order?
Asked by kvr_neous - Thu Apr 27 23:23:12 2006 - - 2 Answers - 0 Comments
A. As you mentioned it is true in case of acids.. Add Acids to water but not the other way... (AA---Add Acid) To my knowledge there is no particular convention for solute to dissolve in solvent. Except fo hygroscopic solutes( absorbs atmospheric water), for which it is better to take them first and add water (since it will absorb water, it may effect the final volume if you mix vice versa. Except for hygroscopic solutes, theres no particular convention is this info helpful?
Answered by murthy - Thu Apr 27 23:28:50 2006
Determine the mass of solute that is needed for the following?
Q. Determine the mass of solute that is needed to prepare 325 ml of silver nitrate (AgNO3) solution with a concentration of 0.400 mol/L. What are the steps to do this problem?
Asked by Jada - Fri Jan 4 20:02:06 2008 - - 4 Answers - 0 Comments
A. Molarity is mol/L and you're given that molarity (.400 M) You want to find moles of AgNO3 first since you're given Molarity and volume: (.400 mol/L) * (.325L) = 0.130 mol AgNO3 Now you simply stoichiometrically convert the moles to grams! (.130mol)* (170 g/1mol) = 22.1 g AgNO3
Answered by Sir Dr. Professor - Fri Jan 4 20:09:47 2008
Q. Determine the mass of solute that is needed to prepare 325 ml of silver nitrate (AgNO3) solution with a concentration of 0.400 mol/L. What are the steps to do this problem?
Asked by Jada - Fri Jan 4 20:02:06 2008 - - 4 Answers - 0 Comments
A. Molarity is mol/L and you're given that molarity (.400 M) You want to find moles of AgNO3 first since you're given Molarity and volume: (.400 mol/L) * (.325L) = 0.130 mol AgNO3 Now you simply stoichiometrically convert the moles to grams! (.130mol)* (170 g/1mol) = 22.1 g AgNO3
Answered by Sir Dr. Professor - Fri Jan 4 20:09:47 2008
What volume is needed to obtain each of the following amounts of solute?
Q. What volume is needed to obtain each of the following amounts of solute? a) liters of 4.0 M KCl solution to obtain 0.100 mole of KCl (in 2 significant figures) b) lites of a 6.0 M HCl solution to obtain 5.0 moles of HCl (in 2 significant figures) c) milliliters of a 2.5 M K2SO4 solution to obtain 1.2 moles of K2SO4 (2 sig fig)
Asked by MetalGearJ - Tue Apr 7 21:49:31 2009 - - 1 Answers - 0 Comments
A. They are all done pretty much the same way. 1.0 liter of 4MKCl contains 4 moles of solute. 1 mole would be found in 0.25 liter or 250 cc; 0.1 mole will be found in 0.025 liter or 25 cc
Answered by Doc89891 - Tue Apr 7 21:59:30 2009
Q. What volume is needed to obtain each of the following amounts of solute? a) liters of 4.0 M KCl solution to obtain 0.100 mole of KCl (in 2 significant figures) b) lites of a 6.0 M HCl solution to obtain 5.0 moles of HCl (in 2 significant figures) c) milliliters of a 2.5 M K2SO4 solution to obtain 1.2 moles of K2SO4 (2 sig fig)
Asked by MetalGearJ - Tue Apr 7 21:49:31 2009 - - 1 Answers - 0 Comments
A. They are all done pretty much the same way. 1.0 liter of 4MKCl contains 4 moles of solute. 1 mole would be found in 0.25 liter or 250 cc; 0.1 mole will be found in 0.025 liter or 25 cc
Answered by Doc89891 - Tue Apr 7 21:59:30 2009
When the solvent temperature increases why does the time taken to dissolve the solute increase?
Q. When the solvent temperature increases why does the time taken to dissolve the solute increase?
Asked by Angel Gigglez - Fri Apr 17 20:39:42 2009 - - 1 Answers - 0 Comments
A. This question doesn't make logical sense. As you heat the system, you can dissolve more solute. As the solute concentration begins to reach maximum concentration, the rate of dissolution slows down. So if I have two beakers of solvent, one at 20 C the other at 50 C, and I drop in 1 g of Solute 1, then it will absolutely dissolve faster in the warmer solvent. This is a direct result of kinetics - the warmer something is, the more molecular motions present, and the more collisions will occur between the solute and the solvent. I'm not sure what you were trying to ask, or if you were just mixed up, but there ya go.
Answered by Jess4352 - Fri Apr 17 22:04:37 2009
Q. When the solvent temperature increases why does the time taken to dissolve the solute increase?
Asked by Angel Gigglez - Fri Apr 17 20:39:42 2009 - - 1 Answers - 0 Comments
A. This question doesn't make logical sense. As you heat the system, you can dissolve more solute. As the solute concentration begins to reach maximum concentration, the rate of dissolution slows down. So if I have two beakers of solvent, one at 20 C the other at 50 C, and I drop in 1 g of Solute 1, then it will absolutely dissolve faster in the warmer solvent. This is a direct result of kinetics - the warmer something is, the more molecular motions present, and the more collisions will occur between the solute and the solvent. I'm not sure what you were trying to ask, or if you were just mixed up, but there ya go.
Answered by Jess4352 - Fri Apr 17 22:04:37 2009
When two aqueous solutions that differ in solute concentration are placed on either side of a semipermeable?
Q. membrane, and osmosis is allowed to take place, the water will a. exhibit an equal movement in both directions across the membrane. b. exhibit a net movement to the side with lower solute concentration. c. exhibit a net movement to the side with lower water concentration. d. exhibit a net movement to the side with higher water concentration. e. not cross the membrane.
Asked by gangster121 - Sat Sep 29 20:57:41 2007 - - 3 Answers - 0 Comments
A. c
Answered by Gabrielle - Sat Sep 29 21:05:54 2007
Q. membrane, and osmosis is allowed to take place, the water will a. exhibit an equal movement in both directions across the membrane. b. exhibit a net movement to the side with lower solute concentration. c. exhibit a net movement to the side with lower water concentration. d. exhibit a net movement to the side with higher water concentration. e. not cross the membrane.
Asked by gangster121 - Sat Sep 29 20:57:41 2007 - - 3 Answers - 0 Comments
A. c
Answered by Gabrielle - Sat Sep 29 21:05:54 2007
What is needed to convert molarity to molality assuming the identity of the solute and solvent are known?
Q. A. density of the solvent B. density of the solute C. volume of the solvent D. density of the solution E. volume of the solution
Asked by jasettefawn - Mon Feb 4 20:25:03 2008 - - 1 Answers - 0 Comments
A. The answer is (D). Why? Molarity = moles of solute / liter of solution ( M = n / V) Molality = moles of solute / kg of solvent ( m = n / kg) Density = mass of solution / volume of solution ( d = mass/V) Suppose d = 1.5 g/mL and M = 3 mol/L Solvent = water (molar mass = 18 g/mol) Solute = NaOH (molar mass = 40 g/mol) Express d as kg / L which is 1.5 kg/L M / d = 3 mol/L / 1.5 kg/L = 2 mol/kg 1 kg solution contains 2 mol NaOH 2 mol NaOH = 2 mol x 40 g/mol = 80 g 1 kg = 1000 g solution contains 80 g NaOH Mass of water = 1000 - 80 = 920 g = 0.92 kg m = n / kg = 2 mo / 0.92 kg = 2.17 m
Answered by Guray T - Tue Feb 5 13:18:16 2008
Q. A. density of the solvent B. density of the solute C. volume of the solvent D. density of the solution E. volume of the solution
Asked by jasettefawn - Mon Feb 4 20:25:03 2008 - - 1 Answers - 0 Comments
A. The answer is (D). Why? Molarity = moles of solute / liter of solution ( M = n / V) Molality = moles of solute / kg of solvent ( m = n / kg) Density = mass of solution / volume of solution ( d = mass/V) Suppose d = 1.5 g/mL and M = 3 mol/L Solvent = water (molar mass = 18 g/mol) Solute = NaOH (molar mass = 40 g/mol) Express d as kg / L which is 1.5 kg/L M / d = 3 mol/L / 1.5 kg/L = 2 mol/kg 1 kg solution contains 2 mol NaOH 2 mol NaOH = 2 mol x 40 g/mol = 80 g 1 kg = 1000 g solution contains 80 g NaOH Mass of water = 1000 - 80 = 920 g = 0.92 kg m = n / kg = 2 mo / 0.92 kg = 2.17 m
Answered by Guray T - Tue Feb 5 13:18:16 2008
How do you calculate the number of grams of solute in a Solution?
Q. I'm trying to figure out how to do this problem here: Calculate the number of grames of solute in 0.250 L of 0.150 M KBr
Asked by dolphinlover1230 - Fri Mar 27 19:13:05 2009 - - 1 Answers - 0 Comments
A. A molar solution is defined as the number of moles in a liter of solution. A 0.15 M solution contains 0.15 moles in a liter of solution. .250 L of that solution contains 0.15/4 moles = 0.0375 moles since there are 4 0.25L portions in one liter. The molar mass of KBr (rounded off) is 80 + 39 = 119 g/mole. 0.0375 mole, then, is 0.0375 x 119 g/mole = 4.4625 grams in 250 mls.
Answered by Doc89891 - Fri Mar 27 19:24:29 2009
Q. I'm trying to figure out how to do this problem here: Calculate the number of grames of solute in 0.250 L of 0.150 M KBr
Asked by dolphinlover1230 - Fri Mar 27 19:13:05 2009 - - 1 Answers - 0 Comments
A. A molar solution is defined as the number of moles in a liter of solution. A 0.15 M solution contains 0.15 moles in a liter of solution. .250 L of that solution contains 0.15/4 moles = 0.0375 moles since there are 4 0.25L portions in one liter. The molar mass of KBr (rounded off) is 80 + 39 = 119 g/mole. 0.0375 mole, then, is 0.0375 x 119 g/mole = 4.4625 grams in 250 mls.
Answered by Doc89891 - Fri Mar 27 19:24:29 2009
Calculate the Ksp of the salt assuming that the solute dissociates completely into the cations and anions?
Q. The solubility of PbBr2 is 0.991487430001 g per 100.0 mL at 25 oC.Calculate the Ksp of the salt assuming that the solute dissociates completely into the cations and anions, and that these ions do not react with water.
Asked by HI - Fri Mar 27 20:35:59 2009 - - 1 Answers - 0 Comments
A. PbBr2(s) <--> Pb(aq) + 2Br(aq) Molarity of PbBr2: (.9914 g)(367.0 g/mol) / .1000 L = .02701 M Using the stochiometry of the equation: Molarity Pb = .02701 M PbBr2 * (1 mol Pb) / (1 mol PbBr2) = .02701 M Molarity Br = .02701 M PbBr2 * (2 mol Br) / (1 mol PbBr2) = .05402 M Set up the Ksp Formula: Ksp = [Pb][Br]^2 Solve: Ksp = [.02701][.05402]^2 Ksp = 7.882 e-5
Answered by EtrnlEvil - Fri Mar 27 20:58:21 2009
Q. The solubility of PbBr2 is 0.991487430001 g per 100.0 mL at 25 oC.Calculate the Ksp of the salt assuming that the solute dissociates completely into the cations and anions, and that these ions do not react with water.
Asked by HI - Fri Mar 27 20:35:59 2009 - - 1 Answers - 0 Comments
A. PbBr2(s) <--> Pb(aq) + 2Br(aq) Molarity of PbBr2: (.9914 g)(367.0 g/mol) / .1000 L = .02701 M Using the stochiometry of the equation: Molarity Pb = .02701 M PbBr2 * (1 mol Pb) / (1 mol PbBr2) = .02701 M Molarity Br = .02701 M PbBr2 * (2 mol Br) / (1 mol PbBr2) = .05402 M Set up the Ksp Formula: Ksp = [Pb][Br]^2 Solve: Ksp = [.02701][.05402]^2 Ksp = 7.882 e-5
Answered by EtrnlEvil - Fri Mar 27 20:58:21 2009
What mass ( g ) of the solvent tetrahydrofuran should be combined with 0.6713 L of the solute diethyl ether to?
Q. What mass ( g ) of the solvent tetrahydrofuran should be combined with 0.6713 L of the solute diethyl ether to produce a solution that is 1.45 m diethyl ether.
Asked by wendy b - Tue May 5 02:51:26 2009 - - 1 Answers - 0 Comments
A. ___molality is moles of solute / kg solvent here THF is the solvent and Et2) is the solute moles solute = 671.3 ml * d Et2O g/ml / MW Et2O g/mole = ?? moles Et2O 1.45m = 1.45 moles / kg = ?? mole / x kg of solvent x g of solvent = 1000 g/kg * ?? mole Et2O /1.45 mole/kg = ?? g THF Plug missing info and SOLVE Basic mathematics is a prerequisite to chemistry I just try to help you with the methodology of solving the problem.
Answered by SciMann - Tue May 5 10:31:05 2009
Q. What mass ( g ) of the solvent tetrahydrofuran should be combined with 0.6713 L of the solute diethyl ether to produce a solution that is 1.45 m diethyl ether.
Asked by wendy b - Tue May 5 02:51:26 2009 - - 1 Answers - 0 Comments
A. ___molality is moles of solute / kg solvent here THF is the solvent and Et2) is the solute moles solute = 671.3 ml * d Et2O g/ml / MW Et2O g/mole = ?? moles Et2O 1.45m = 1.45 moles / kg = ?? mole / x kg of solvent x g of solvent = 1000 g/kg * ?? mole Et2O /1.45 mole/kg = ?? g THF Plug missing info and SOLVE Basic mathematics is a prerequisite to chemistry I just try to help you with the methodology of solving the problem.
Answered by SciMann - Tue May 5 10:31:05 2009
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Woodbury Co. Honors Fallen Law Enforcement Officials
KCAU, IA
Once a year, community members and officers gather to pray and solute the memory of those who passed away. Those honored were members of the Sioux City Police Department, Woodbury County Sherriff's Office, and the FBI. Although it's been nearly a ...
KCAU, IA
Once a year, community members and officers gather to pray and solute the memory of those who passed away. Those honored were members of the Sioux City Police Department, Woodbury County Sherriff's Office, and the FBI. Although it's been nearly a ...
The Various Types Of Water Solutions Being Used In Industries And ...
unknown
ue, 03 Nov 2009 13:31:51 GM
The importance of these solutions comes from their determined concentration which is basically ideal in appropriate measurements of the presence of a substance or . solute. in a solution. Standard solutions are expressed in their normality ...
unknown
ue, 03 Nov 2009 13:31:51 GM
The importance of these solutions comes from their determined concentration which is basically ideal in appropriate measurements of the presence of a substance or . solute. in a solution. Standard solutions are expressed in their normality ...
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