NounSingular tangent Plural tangents tangent (plural tangents)
Derived terms
Related termsFrom Wiktionary under the GNU Free Documentation License. In geometry, the tangent line (or simply the tangent) to a curve at a given point is the straight line that "just touches" the curve at that point (in the sense explained more precisely below). As it passes through the point of tangency, the tangent line is "going in the same direction" as the curve, and in this sense it is the best straight-line approximation to the curve at that point. The same definition applies to space curves and curves in n-dimensional Euclidean space. Similarly, the tangent plane to a surface at a given point is the plane that "just touches" the surface at that point. The concept of a tangent is one of the most fundamental notions in differential geometry and has been extensively generalized; see Tangent space. In trigonometry, tangent is the slope formula that combines the rise and run. The tangent function takes an angle and tells the slope when the length of the line is 1. For more information on the tangent function, see trigonometric functions. The word "tangent" comes from the Latin tangere, meaning "to touch". From Wikipedia under the
GNU Free Documentation License  gearlog.com Esten Hurtle 2009-06-16 14:06:41 Students will soon have a more energy-efficient way to play Oregon Trail and Mavis Beacon Teaches Typing with the release of the . Tangent. VITA LT, an all-in-one.  flickr.com (tangent) 2009-06-09 06:34:48 Few Data. Few Data by . tangent. . I'm one of the few photographers out there that avidly favors the left side of the histogram. To take full advantage of Flickr, you should use a JavaScript-enabled browser and ... . tangent's. photostream ...  debito.org debito 2009-05-31 03:44:18 13 Responses to Sunday . Tangent. : Shinjuku-ku issues its own quadralingual guidebook to life in Tokyo. Ken Says: May 31st, 2009 at 3:50 pm. >I don't suppose Shinjuku-ku would be kind enough to release a Guide to Living with Foreigners ... From Google Blog Search: "tangent"  manticornio.com 142px x 142px | 6.60kB [source page] Uno de los proyectos crossover mas afortunados del 2003 The TANGENT originalmente era el proyecto de album solista de Andy allison pues se trataba de From Yahoo Image Search: "tangent" How would I find the slope of the tangent line and equation of the tangent line of this derivative equation? Q. The equation is f(x) = x - x - 2x + 1, and I need to find the slope of the tangent line that goes through the point (3, 13) and the equation of this tangent line. Asked by Allen Z - Wed Mar 19 22:08:26 2008 - - 1 Answers - 0 Comments A. Take the derrivitive of each part on it's own. So the derrivitive of x^3 is 3x^2. The derrivitive of x^2 is 2x. The derrivitive of 2x is 2. And the derrivitive of all constants is 0 So the derrivitive is f'(x)=3x^2 - 2x - 2 + 0 This is your equation for the slope at any given x-value. So plug your x coordinate in (3). f'(3)= 3 (3)^2 - 2(3) - 2 =27-6-2 =19 <--- This is your slope at x=3 Now use y=mx + b with the point (3,13) y = m x + b 13 = 19 (3) + b 13 = 57 + b -44 = b <--- the y-intercept so using the m and b values put it back into y=mx+b y=19x - 44 <--- This is the equation of the tangent line at x=3 Answered by Andrew P - Wed Mar 19 22:22:10 2008 Can someone explain how to find the equations of tangent and normal lines? Q. Here is an sample problem: Find the equation of the tangent to the graph of y = (x^2+4x+4)^2 at x = -2. Asked by I am the walrus - Wed Jun 4 12:39:29 2008 - - 6 Answers - 0 Comments A. dy/dx = 2(x^2+4x+4)(2x+4) by the chain rule. at x = -2, dy/dx =0 so the tangent line is horizontal. The point of tangency is at (-2, 0) since y = ((-2)^2+4(-2)+4)^2 = 0. So the tangent line at x = -2 is y = 0 or the x-axis. The normal line is perpendicular to the tangent line. In this case, this means the normal line is vertical. Since it goes through (-2,0), the equation is x = -2. In general, find the slope of the tangent line by taking the derivative and evaluating it at the given x value. Find the point of tangency by evaluating the original function at the x-value. Then use the point-slope formula to find the equation of the line.To find the slope of normal line (if the tangent line is not horzontal) take the negative… [cont.] Answered by Math Nerd - Wed Jun 4 13:10:19 2008 Determine two points on the ellipse at which the tangent is horizontal?
Q. Hi. The question is: Determine two points on the ellipse at which the tangent is horizontal Slope: (10x-6y) / (-6x+10y) Please explain to me the steps to solve this. I will give best answer, thanks. Asked by myname_isalbert - Wed Apr 22 07:46:50 2009 - - 1 Answers - 0 Comments A. /// if the slope is what you have given 10x-6y=0 x=3y/5 sub it back to the original equa and solve for x and y to get the 2 points.If the equation is not give, then do differential equation to get the original equation by letting y=mx Answered by Ellipse - Thu Apr 23 07:44:51 2009 From Yahoo Answer Search: "tangent" |
