Find the volume generated by revolving the lin y=5x+10 around the x axis. 0>x>2?
Q. Find the volume generated by revolving the lin y=5x+10 around the x axis. 0>x>2?
Asked by Dirtydave - Tue Apr 14 20:44:36 2009 - - 1 Answers - 0 Comments
A. /// piint x=0 to 2 of (5x+10)^2dx =25piintx^2+4x+4dx =25pi[x^3/3+2x^2+4x] sub in the value and get answer
Answered by vect - Wed Apr 15 20:43:05 2009
Q. Find the volume generated by revolving the lin y=5x+10 around the x axis. 0>x>2?
Asked by Dirtydave - Tue Apr 14 20:44:36 2009 - - 1 Answers - 0 Comments
A. /// piint x=0 to 2 of (5x+10)^2dx =25piintx^2+4x+4dx =25pi[x^3/3+2x^2+4x] sub in the value and get answer
Answered by vect - Wed Apr 15 20:43:05 2009
y=5x+10, please find perpendicular line slope of y=5x+10.?
Q. i think the anwse is is -.2 im not possitive though
Asked by Survivor - Thu Jan 24 20:16:19 2008 - - 1 Answers - 0 Comments
A. -1/5 y=mx+b m is slope Perpendicular has the negative, inverse slope
Answered by whatdoitypehere - Thu Jan 24 20:19:41 2008
Q. i think the anwse is is -.2 im not possitive though
Asked by Survivor - Thu Jan 24 20:16:19 2008 - - 1 Answers - 0 Comments
A. -1/5 y=mx+b m is slope Perpendicular has the negative, inverse slope
Answered by whatdoitypehere - Thu Jan 24 20:19:41 2008
how to you change the equation y= 5x-10 into standard form??
Q. please explain in detail...thanks!!
Asked by eazyboop - Sun Jun 3 17:41:57 2007 - - 6 Answers - 0 Comments
A. The standard form is ay + bx = c. For your equation, this would be y - 5x = -10.
Answered by unknown - Sun Jun 3 17:46:26 2007
Q. please explain in detail...thanks!!
Asked by eazyboop - Sun Jun 3 17:41:57 2007 - - 6 Answers - 0 Comments
A. The standard form is ay + bx = c. For your equation, this would be y - 5x = -10.
Answered by unknown - Sun Jun 3 17:46:26 2007
graph y=5x-10 SAT help?
Q. I am doing SAT prep and I need some help. Can you give me some quick steps on how to graph? Thanks!
Asked by A A - Mon Jun 1 22:56:44 2009 - - 2 Answers - 0 Comments
Q. I am doing SAT prep and I need some help. Can you give me some quick steps on how to graph? Thanks!
Asked by A A - Mon Jun 1 22:56:44 2009 - - 2 Answers - 0 Comments
Complete the ordered pairs for the equation y = 5x + 10. ( ,0), (4/5, ), (0, ), (-4/5, ).?
Q. Complete the ordered pairs for the equation y = 5x + 10. ( ,0), (4/5, ), (0, ), (-4/5, ).?
Asked by mom - Sat Jan 26 00:02:30 2008 - - 3 Answers - 0 Comments
A. (-2,0) (4/5, 14) (0, 10) (-4/5, 6)
Answered by gh rocker - Sat Jan 26 00:08:18 2008
Q. Complete the ordered pairs for the equation y = 5x + 10. ( ,0), (4/5, ), (0, ), (-4/5, ).?
Asked by mom - Sat Jan 26 00:02:30 2008 - - 3 Answers - 0 Comments
A. (-2,0) (4/5, 14) (0, 10) (-4/5, 6)
Answered by gh rocker - Sat Jan 26 00:08:18 2008
What are the x and y intercepts in these equations?
Q. x and y intercept please... I am having so much trouble! 2x-3y=4 and 7x+2y=15 and also how wold you put these in standard form?? y=2x+8 and y=-.5x-(10/3) (10/3 is ten over three... ten thirds)
Asked by nicholettei - Thu May 14 15:01:16 2009 - - 3 Answers - 0 Comments
A. the y-intercept is when x=0 the x-intercept is when y=0 for 2x - 3y = 4, when x = 0, -3y = 4, so the y-intercept is y = -4/3 and when y = 0, 2x = 4, so the x-intercept is x = 2 for 7x + 2y = 15 when x = 0, 2y = 15, so the y-intercept is y = 15/2 = 7.5 and when y = 0, 7x = 15, so the x-intercept is x = 15/7 = 2 + 1/7 and for the standard forms, just solve for the constant, y = 2x + 8 is the same as -2x + y = 8, and y = -(1/2)x - 10/3 is the same as (1/2)x + y = -10/3, which you could multiply by 6 to get 3x + 6y = -20.
Answered by twistor - Thu May 14 15:17:51 2009
Q. x and y intercept please... I am having so much trouble! 2x-3y=4 and 7x+2y=15 and also how wold you put these in standard form?? y=2x+8 and y=-.5x-(10/3) (10/3 is ten over three... ten thirds)
Asked by nicholettei - Thu May 14 15:01:16 2009 - - 3 Answers - 0 Comments
A. the y-intercept is when x=0 the x-intercept is when y=0 for 2x - 3y = 4, when x = 0, -3y = 4, so the y-intercept is y = -4/3 and when y = 0, 2x = 4, so the x-intercept is x = 2 for 7x + 2y = 15 when x = 0, 2y = 15, so the y-intercept is y = 15/2 = 7.5 and when y = 0, 7x = 15, so the x-intercept is x = 15/7 = 2 + 1/7 and for the standard forms, just solve for the constant, y = 2x + 8 is the same as -2x + y = 8, and y = -(1/2)x - 10/3 is the same as (1/2)x + y = -10/3, which you could multiply by 6 to get 3x + 6y = -20.
Answered by twistor - Thu May 14 15:17:51 2009
Finding x- and y- intercepts of a linear equation?
Q. i need help on knowing HOW to do the problem i've searched on the internet and im still having a hard time grasping how to do it 1.y=-5x+10 2.y=1/2x-4
Asked by jiblet49 - Mon Sep 1 17:46:31 2008 - - 1 Answers - 0 Comments
A. All you need to know, is in order to solve for the x intercept you set Y = 0 and to solve for the y intercept you set x= 0 If you wanted to solve for the y intercept in the first example set x = 0 y = 5(0) + 10 So the y intercept would be 10
Answered by shortydiaz526 - Mon Sep 1 18:02:50 2008
Q. i need help on knowing HOW to do the problem i've searched on the internet and im still having a hard time grasping how to do it 1.y=-5x+10 2.y=1/2x-4
Asked by jiblet49 - Mon Sep 1 17:46:31 2008 - - 1 Answers - 0 Comments
A. All you need to know, is in order to solve for the x intercept you set Y = 0 and to solve for the y intercept you set x= 0 If you wanted to solve for the y intercept in the first example set x = 0 y = 5(0) + 10 So the y intercept would be 10
Answered by shortydiaz526 - Mon Sep 1 18:02:50 2008
What is the equation of the line tangent to the graph of f(x) = 7x - x^2 at the point where f ' (x) = 3?
Q. I got the answer y = 3x + 8. Could someone confirm this for me? If this is incorrect here are the other options: a. y=5x-10 b. y=3x+4 c. y=3x+8 d. y=3x-10 e. y=3x-16 Thanks.
Asked by thecontemptibles - Sun Nov 25 14:42:55 2007 - - 3 Answers - 0 Comments
A. Power rule: f'(x) = 7 - 2x f'(x) = 3 = 7 - 2x -4 = -2x x = 2 so at 2, the tangent is line has a slope of 3... f(2) = 7(2) - (2)^2 = 14 - 4 f(2) = 10 y - 10 = 3(x-2) y = 3x -6 + 10 y = 3x +4 that is the equation of the line tangent... y = 3x + 4
Answered by sayamiam - Sun Nov 25 14:49:31 2007
Q. I got the answer y = 3x + 8. Could someone confirm this for me? If this is incorrect here are the other options: a. y=5x-10 b. y=3x+4 c. y=3x+8 d. y=3x-10 e. y=3x-16 Thanks.
Asked by thecontemptibles - Sun Nov 25 14:42:55 2007 - - 3 Answers - 0 Comments
A. Power rule: f'(x) = 7 - 2x f'(x) = 3 = 7 - 2x -4 = -2x x = 2 so at 2, the tangent is line has a slope of 3... f(2) = 7(2) - (2)^2 = 14 - 4 f(2) = 10 y - 10 = 3(x-2) y = 3x -6 + 10 y = 3x +4 that is the equation of the line tangent... y = 3x + 4
Answered by sayamiam - Sun Nov 25 14:49:31 2007
How to work these out??? <10 points>?
Q. I posted these questions yesterday and only got the answers. No one showed me step by step on how to work it out. Please help. 10 points for the best answer. Thank you. Please, I need step by step. And I know I don't have any graphs. But if you can just give me the points, it would be deeply appreciated. Graph each equation by using the x- and y- intercepts. 1.) y= 5x-10 **I was told the answer is -9 and -12*** 2.) 1/2x -2/3 y=-6 *** I was told the answer is -9 and -7.5*** Graph each equation by using the slope and point on the line. 3.) y+6= -3/2 (x+5) *** I was told the answer is m= -3/2 and the coordinates are (-5,-6)*** Graph each equation by using the slope and y-intercept. 4.) y= -3/4x +4 ***I was told the answer was… [cont.]
Asked by beautifully_broken_1994 - Fri Jan 30 15:15:13 2009 - - 2 Answers - 0 Comments
A. im not gonna write the whole process out but i can def help you. what you need to do is have all the equations in y=mx+b form. so that means get the y to one side. if you subtract it and the y by itself is negative then divide the other side of th equation by -1 so that y is positve. ok. so once you have done that...get a graphing calculator. this will be your best friend. go to the top left corner where the button says y=. once you put the equation in, push the graph button on the top right. hopefully this helped. sry i didnt look up the answers. also look on youtube to see if someone uploaded a video on how to help you with a graphing calcuator.
Answered by Ashley - Fri Jan 30 16:15:06 2009
Q. I posted these questions yesterday and only got the answers. No one showed me step by step on how to work it out. Please help. 10 points for the best answer. Thank you. Please, I need step by step. And I know I don't have any graphs. But if you can just give me the points, it would be deeply appreciated. Graph each equation by using the x- and y- intercepts. 1.) y= 5x-10 **I was told the answer is -9 and -12*** 2.) 1/2x -2/3 y=-6 *** I was told the answer is -9 and -7.5*** Graph each equation by using the slope and point on the line. 3.) y+6= -3/2 (x+5) *** I was told the answer is m= -3/2 and the coordinates are (-5,-6)*** Graph each equation by using the slope and y-intercept. 4.) y= -3/4x +4 ***I was told the answer was… [cont.]
Asked by beautifully_broken_1994 - Fri Jan 30 15:15:13 2009 - - 2 Answers - 0 Comments
A. im not gonna write the whole process out but i can def help you. what you need to do is have all the equations in y=mx+b form. so that means get the y to one side. if you subtract it and the y by itself is negative then divide the other side of th equation by -1 so that y is positve. ok. so once you have done that...get a graphing calculator. this will be your best friend. go to the top left corner where the button says y=. once you put the equation in, push the graph button on the top right. hopefully this helped. sry i didnt look up the answers. also look on youtube to see if someone uploaded a video on how to help you with a graphing calcuator.
Answered by Ashley - Fri Jan 30 16:15:06 2009
MATH, algebra 1 help. I need some help, 10 points best answer!!!?
Q. Okay so I need a little help. I know it says to graph them and since we are online you can't do that. So I don't know what to do...I'm so stuck. :( I'm hoping some of you math experts can help me. Please! Thanks, and God Bless. Graph each equation by using the x - and y - intercepts. #14. y=5x - 10 #16. 1/2x - 2/3 y= -6 Graph each equation by using the slope and a point on the line. #18. y + 6 = 3/2 (x+5) Graph each equation by using the slope and y - intercept. #20. y= -3/4 x + 4 #22. 5y+3= -5 Graph each equation #24. 6y+5 = 5y+3 #26. y= 2/3 x + 1 #30. 15x - 29y = 429 Thanks so much everyone!! I don't expect people to give me the answers...I just need help quickly. I have to have everything done by 6:45 and it in the mail!
Asked by lauren. - Mon Jan 5 18:36:18 2009 - - 2 Answers - 0 Comments
A. Hope this helps.
Answered by anatoliy29 - Mon Jan 5 18:47:42 2009
Q. Okay so I need a little help. I know it says to graph them and since we are online you can't do that. So I don't know what to do...I'm so stuck. :( I'm hoping some of you math experts can help me. Please! Thanks, and God Bless. Graph each equation by using the x - and y - intercepts. #14. y=5x - 10 #16. 1/2x - 2/3 y= -6 Graph each equation by using the slope and a point on the line. #18. y + 6 = 3/2 (x+5) Graph each equation by using the slope and y - intercept. #20. y= -3/4 x + 4 #22. 5y+3= -5 Graph each equation #24. 6y+5 = 5y+3 #26. y= 2/3 x + 1 #30. 15x - 29y = 429 Thanks so much everyone!! I don't expect people to give me the answers...I just need help quickly. I have to have everything done by 6:45 and it in the mail!
Asked by lauren. - Mon Jan 5 18:36:18 2009 - - 2 Answers - 0 Comments
A. Hope this helps.
Answered by anatoliy29 - Mon Jan 5 18:47:42 2009
How do you find the area of the region enclosed by the graph of...?
Q. y= x+6 y= -5x+10 y= (2-x)/(5) please,, I can't get this problem done... I can't even find the integral... please help !!
Asked by Jinha S - Wed Apr 30 20:16:24 2008 - - 1 Answers - 0 Comments
A. If you have not already done so, I urge you to graph the three lines so you can see what the region looks like. It is a triangle whose vertices are (-14/3, 4/3), (2/3, 20/3) and (2, 0). Most importantly, the graph will show that two integrals are needed to calculate the area: one for x from -14/3 to 2/3, and one for x from 2/3 to 2. This is because the line y=x+6 serves as the upper boundary of the region for -14/3
Q. y= x+6 y= -5x+10 y= (2-x)/(5) please,, I can't get this problem done... I can't even find the integral... please help !!
Asked by Jinha S - Wed Apr 30 20:16:24 2008 - - 1 Answers - 0 Comments
A. If you have not already done so, I urge you to graph the three lines so you can see what the region looks like. It is a triangle whose vertices are (-14/3, 4/3), (2/3, 20/3) and (2, 0). Most importantly, the graph will show that two integrals are needed to calculate the area: one for x from -14/3 to 2/3, and one for x from 2/3 to 2. This is because the line y=x+6 serves as the upper boundary of the region for -14/3
State the equations of the horizontal and vertical asymptotes for the reciprocal function?
Q. State the equations of the horizontal and vertical asymptotes for the reciprocal functions of: a) y=5x-10 b) x^2-x-20
Asked by thomasgraham880 - Tue Nov 14 00:04:40 2006 - - 1 Answers - 0 Comments
A. your gettin me hot!!! dirty talk is a good thing.
Answered by 9888khgd6 - Tue Nov 14 00:08:14 2006
Q. State the equations of the horizontal and vertical asymptotes for the reciprocal functions of: a) y=5x-10 b) x^2-x-20
Asked by thomasgraham880 - Tue Nov 14 00:04:40 2006 - - 1 Answers - 0 Comments
A. your gettin me hot!!! dirty talk is a good thing.
Answered by 9888khgd6 - Tue Nov 14 00:08:14 2006
how do i find the domain and range of a straight line?
Q. I'm doing a math project where we need to describe the domain and range of a line. Does anyone know how i would fill out the table below with the given line? Help please! Equation ___Domain___ Range Y=5X +10___a < x < b___ c < y < d
Asked by Courtney B - Tue Nov 3 19:53:51 2009 - - 1 Answers - 0 Comments
A. use the chi square test
Answered by Etienne de Quercy, Tip Trop Top! - Sat Nov 7 18:38:01 2009
Q. I'm doing a math project where we need to describe the domain and range of a line. Does anyone know how i would fill out the table below with the given line? Help please! Equation ___Domain___ Range Y=5X +10___a < x < b___ c < y < d
Asked by Courtney B - Tue Nov 3 19:53:51 2009 - - 1 Answers - 0 Comments
A. use the chi square test
Answered by Etienne de Quercy, Tip Trop Top! - Sat Nov 7 18:38:01 2009
Solving Systems by Substitution?
Q. y= 3x+8 and y=5x-10 The first step is to solve for variable in at least one equation if nessasary. i dont know. im confused. can someone go through the steps with me on this problem?
Asked by Brooke - Tue Feb 10 19:04:19 2009 - - 4 Answers - 0 Comments
A. To solve for a variable, you want to have the variable by itself on one side of the equals sign, and the rest of the equation on the other. In this case, both equations have been solved for y. To solve the system by substitution, take one of the equations and substitute it into the other. ie, if you have y = 3x + 8 as one equation, substitute 3x + 8 for y in the second. Here, you'd get: 3x+8 = 5x-10 Now you want to solve for x, 8 + 10 = 5x - 3x (rearranging the terms) 18 = 2x (collecting like terms) 9 = x (divide both sides by 2) Now that you have the value for x, you can sub this into any of the original equations you have to find y. Using the first one yeilds: y = 3x + 8 y = 3(9) + 8 y = 27 + 8 y = 35 So, the solution to the… [cont.]
Answered by Jessica - Tue Feb 10 19:11:19 2009
Q. y= 3x+8 and y=5x-10 The first step is to solve for variable in at least one equation if nessasary. i dont know. im confused. can someone go through the steps with me on this problem?
Asked by Brooke - Tue Feb 10 19:04:19 2009 - - 4 Answers - 0 Comments
A. To solve for a variable, you want to have the variable by itself on one side of the equals sign, and the rest of the equation on the other. In this case, both equations have been solved for y. To solve the system by substitution, take one of the equations and substitute it into the other. ie, if you have y = 3x + 8 as one equation, substitute 3x + 8 for y in the second. Here, you'd get: 3x+8 = 5x-10 Now you want to solve for x, 8 + 10 = 5x - 3x (rearranging the terms) 18 = 2x (collecting like terms) 9 = x (divide both sides by 2) Now that you have the value for x, you can sub this into any of the original equations you have to find y. Using the first one yeilds: y = 3x + 8 y = 3(9) + 8 y = 27 + 8 y = 35 So, the solution to the… [cont.]
Answered by Jessica - Tue Feb 10 19:11:19 2009
Please help me on this one multiple choice question!?
Q. The question says: Determine which ordered pair is a solution of y= -5x+10 Answer choice: A. (-15,5) B. (2,0) C.(-1,-5) D. (3,25) please please help me!! Im having lots of trouble. Thanks :)
Asked by Whitney - Wed May 13 14:56:58 2009 - - 2 Answers - 0 Comments
A. This will actually be pretty easy for you. When they give you sets like that they want you to plug in the numbers and see what makes sense. Let's try the first one. (-15,5) We'll plug -15 into x and 5 into y 5= -5(-15)+10 5=75+10 5=85 That's obviously not true so A is not the answer. Let's try B! 0=-5(2)+10 0=-10+10 0=0 That is true so your answer is B. (2,0)
Answered by Nagato - Wed May 13 15:04:44 2009
Q. The question says: Determine which ordered pair is a solution of y= -5x+10 Answer choice: A. (-15,5) B. (2,0) C.(-1,-5) D. (3,25) please please help me!! Im having lots of trouble. Thanks :)
Asked by Whitney - Wed May 13 14:56:58 2009 - - 2 Answers - 0 Comments
A. This will actually be pretty easy for you. When they give you sets like that they want you to plug in the numbers and see what makes sense. Let's try the first one. (-15,5) We'll plug -15 into x and 5 into y 5= -5(-15)+10 5=75+10 5=85 That's obviously not true so A is not the answer. Let's try B! 0=-5(2)+10 0=-10+10 0=0 That is true so your answer is B. (2,0)
Answered by Nagato - Wed May 13 15:04:44 2009
Determine which two equations represent parallel lines?
Q. (a) y = x + 2 (b) y = x 7 (c) y = 5x + 10(d) y = 5x 2
Asked by missrandil - Thu May 31 23:25:26 2007 - - 11 Answers - 0 Comments
A. It would be a and b because in order to have parallel lines the slopes of the equations have 2 be the same. as u can see in a and b the slopes are both x which makes them both 1
Answered by CHris Brown Lover - Thu May 31 23:28:48 2007
Q. (a) y = x + 2 (b) y = x 7 (c) y = 5x + 10(d) y = 5x 2
Asked by missrandil - Thu May 31 23:25:26 2007 - - 11 Answers - 0 Comments
A. It would be a and b because in order to have parallel lines the slopes of the equations have 2 be the same. as u can see in a and b the slopes are both x which makes them both 1
Answered by CHris Brown Lover - Thu May 31 23:28:48 2007
The graphs of the 3 equations below enclose a region. Determine the area of the region. (Equations below)?
Q. y = x + 7 y = -5x + 10 y = 2 - x/(5)
Asked by Lucy - Tue Apr 24 22:25:08 2007 - - 1 Answers - 0 Comments
A. A = int[-25/6 to 1/2] { (x + 7) - (2 - x/5) } + int[1/2 to 5/3] { (-5x + 10) - (2 - x/5) } A = int[-25/6 to 1/2] { (6/5)*x + 5) } + int[1/2 to 5/3] { (-24/5)*x + 8) } A = { (6/5)*(x^2)/2 + 5x + c) }, [x is from -25/6 to 1/2] + { (-24/5)*(x^2)/2 + 8x + c) }, [x is from 1/2 to 5/3]
Answered by sweetwater - Wed Apr 25 02:36:48 2007
Q. y = x + 7 y = -5x + 10 y = 2 - x/(5)
Asked by Lucy - Tue Apr 24 22:25:08 2007 - - 1 Answers - 0 Comments
A. A = int[-25/6 to 1/2] { (x + 7) - (2 - x/5) } + int[1/2 to 5/3] { (-5x + 10) - (2 - x/5) } A = int[-25/6 to 1/2] { (6/5)*x + 5) } + int[1/2 to 5/3] { (-24/5)*x + 8) } A = { (6/5)*(x^2)/2 + 5x + c) }, [x is from -25/6 to 1/2] + { (-24/5)*(x^2)/2 + 8x + c) }, [x is from 1/2 to 5/3]
Answered by sweetwater - Wed Apr 25 02:36:48 2007
General Form Equation?
Q. Please rewrite this equation in general form: y=-5x+10
Asked by MathIdiot - Wed Sep 16 07:14:24 2009 - - 4 Answers - 0 Comments
A. I think you mean this general form of a linear equation: ax + by + c = 0. If so, it's 5x + y - 10 = 0.
Answered by unknown - Wed Sep 16 07:21:23 2009
Q. Please rewrite this equation in general form: y=-5x+10
Asked by MathIdiot - Wed Sep 16 07:14:24 2009 - - 4 Answers - 0 Comments
A. I think you mean this general form of a linear equation: ax + by + c = 0. If so, it's 5x + y - 10 = 0.
Answered by unknown - Wed Sep 16 07:21:23 2009
solve by substitution?
Q. This is kinda confusing to me, how would i solve this problem? y=5x-10 y=3x+8 I have to find both x and y solving by substitution and check my answer. Please be detailed, im trying to learn how to do it. also 2r-3s-t=12 s+3t=10 t=4
Asked by poisonbliss - Thu Dec 11 18:42:19 2008 - - 1 Answers - 0 Comments
Q. This is kinda confusing to me, how would i solve this problem? y=5x-10 y=3x+8 I have to find both x and y solving by substitution and check my answer. Please be detailed, im trying to learn how to do it. also 2r-3s-t=12 s+3t=10 t=4
Asked by poisonbliss - Thu Dec 11 18:42:19 2008 - - 1 Answers - 0 Comments
some more algebra problems?
Q. 1. is 3y-x=15 and y+3x=10 parallell? 2. is y=5x + 10 and 2y + 10x=6 perpendicular?
Asked by Johnny - Thu Jan 8 18:46:54 2009 - - 1 Answers - 0 Comments
A. 1. No 2. No
Answered by michaelempeigne - Thu Jan 8 18:53:15 2009
Q. 1. is 3y-x=15 and y+3x=10 parallell? 2. is y=5x + 10 and 2y + 10x=6 perpendicular?
Asked by Johnny - Thu Jan 8 18:46:54 2009 - - 1 Answers - 0 Comments
A. 1. No 2. No
Answered by michaelempeigne - Thu Jan 8 18:53:15 2009
From Yahoo Answer Search: 'y=5x-10'
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